Hi Troels,

Do you have a literature reference where this is inverted?  Have a
look at Art Palmer's 2001 review:

  - Palmer, A. G. III, Kroenke, C. D. and Loria J. P. (2001)  Nuclear
Magnetic Resonance Methods for Quantifying Microsecond-to-Millisecond
Motions in Biological Macromolecules.  Methods Enzymol., 339, 204-238.
(http://dx.doi.org/10.1016/S0076-6879(01)39315-1).

Specifically at the top of page 216 where you can see:

tan(theta) = omega1 / Omega.

Therefore:

theta = arctan(omega1 / Omega).

So it should be correct in relax using the atan2() function.  Or am I
missing something?

Regards,

Edward






On 25 July 2014 19:45, Troels Emtekær Linnet <[email protected]> wrote:
> Hi Edward.
>
> I was stumpling over the expression
> theta = atan2(omega1, Delta_omega)
>
> in:
> specific_analyses/relax_disp/data.py in return_offset_data().
>
> atan2 requires:
> math.atan2(y, x)
> Return atan(y / x), in radians. The result is between -pi and pi. The
> vector in the plane from the origin to point (x, y) makes this angle
> with the positive X axis. The point of atan2() is that the signs of
> both inputs are known to it, so it can compute the correct quadrant
> for the angle. For example, atan(1) and atan2(1, 1) are both pi/4, but
> atan2(-1, -1) is -3*pi/4.
>
> But what is y, and x?
>
> If I look at my own figure at:
> http://wiki.nmr-relax.com/images/1/12/Fig1_Palmer_Massi_2006.png
>
> I would say that y is Delta_omega, and x is omega1.
>
> Have I done this wrong earlier?
>
> Best
> Troels
>
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