Hi Ed.

You are correct.

I got confused yesterday, and thought the theta angle was between
X, Z axis instead of the Z,X axis.

Best
Troels

2014-07-28 11:29 GMT+02:00 Edward d'Auvergne <[email protected]>:
> Hi Troels,
>
> Do you have a literature reference where this is inverted?  Have a
> look at Art Palmer's 2001 review:
>
>   - Palmer, A. G. III, Kroenke, C. D. and Loria J. P. (2001)  Nuclear
> Magnetic Resonance Methods for Quantifying Microsecond-to-Millisecond
> Motions in Biological Macromolecules.  Methods Enzymol., 339, 204-238.
> (http://dx.doi.org/10.1016/S0076-6879(01)39315-1).
>
> Specifically at the top of page 216 where you can see:
>
> tan(theta) = omega1 / Omega.
>
> Therefore:
>
> theta = arctan(omega1 / Omega).
>
> So it should be correct in relax using the atan2() function.  Or am I
> missing something?
>
> Regards,
>
> Edward
>
>
>
>
>
>
> On 25 July 2014 19:45, Troels Emtekær Linnet <[email protected]> wrote:
>> Hi Edward.
>>
>> I was stumpling over the expression
>> theta = atan2(omega1, Delta_omega)
>>
>> in:
>> specific_analyses/relax_disp/data.py in return_offset_data().
>>
>> atan2 requires:
>> math.atan2(y, x)
>> Return atan(y / x), in radians. The result is between -pi and pi. The
>> vector in the plane from the origin to point (x, y) makes this angle
>> with the positive X axis. The point of atan2() is that the signs of
>> both inputs are known to it, so it can compute the correct quadrant
>> for the angle. For example, atan(1) and atan2(1, 1) are both pi/4, but
>> atan2(-1, -1) is -3*pi/4.
>>
>> But what is y, and x?
>>
>> If I look at my own figure at:
>> http://wiki.nmr-relax.com/images/1/12/Fig1_Palmer_Massi_2006.png
>>
>> I would say that y is Delta_omega, and x is omega1.
>>
>> Have I done this wrong earlier?
>>
>> Best
>> Troels
>>
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