Ron, et al,
    A corollary of Kirchhoff's law says that all currents are equal in a 
series circuit and all voltages are equal in a parallel circuit. Tapping a 
load across the lower battery represents a parallel circuit of the bottom 
battery and the load (radio) using 12 volts, and this parallel circuit is in 
series with the upper battery. If I supply 10 amps from the 24 volt charging 
circuit the upper battery receives 10 amps. However, if the load (radio) 
draws 5 amps the bottom battery can only get the other 5 amps to charge it. 
Hence the application of Kirchhoff's law of currents equal in a series 
circuit. There is no way for the bottom battery ever to be equally charged 
with the top battery as the radio has drawn away some of the current from 
the bottom battery. This current can never be replaced in this 
configuration.

    If the charging current drops to 5 amps then the top battery get 5 amps 
and the bottom battery gets none. If the charging device is off then the 
bottom battery continues to supply 5 amps to the load (for a while!)

    If this condition continues very long the terminal voltage of the bottom 
battery will be depressed towards 12 volts or lower but the 24 volt charging 
device doesn't know this and will attempt to apply full charging voltage 
(probably 28 volts or so) to the two seriesed batteries. If the depressed 
voltage on the bottom battery is down to 12 volts (typical) the top battery 
will get 16 volts, not a healthy situation! It only get worse as the 
condition continues.

    Now there are solutions. One can switch batteries (top with bottom) 
every few hours but who would actually do this? Or one could put a phantom 
load across the top battery, something that draws about the same current as 
the radio but this would be rather wasteful of energy and tricky to make 
work.

    Many 12 to 14 volt linear power supply circuits (Astron or ARRL 
handbook) can be adapted to convert the 24 - 28 volt source down to 12 - 14 
volts just by injecting the +24 volts into the power supply after the main 
rectifier diodes. But here again the power supply will use up about as much 
power as the load. (Kirchhoff's law again)

    If conserving power is important then a switching supply would be in 
order as some of them are more than 90 % efficient.

73,
Al, K9SI


>    Re: 24 vdc to 12 vdc
>    Posted by: "Ron Wright" [EMAIL PROTECTED] n9eerptr
>    Date: Tue Mar 25, 2008 5:04 am ((PDT))

>Depending on the load connecting across one battery, the one connected to 
>ground or the lower of the 2 12 batteries, will work.  I >would not do is 
>load is heavy because I am sure the charging system is for both batteries 
>and draining one much more than the other >could upset things.

>Kirchhoff's current law says the sum of the currents will be zero. 
>Kirchhoff's voltage law says sum of voltages will be zero.  Not sure >why 
>revelant here, but I am sure Kirchhoff had something else to do with 
>voltage and current sources.  Would like to know.

>73, ron, n9ee/r




>>From: Al Wolfe <[EMAIL PROTECTED]>
>>Date: 2008/03/24 Mon PM 04:36:54 CDT
>>To: Repeater-Builder@yahoogroups.com
>>Subject: [Repeater-Builder] Re: 24 vdc to 12 vdc

>
>>>This is a very common issue in aircraft. The most obvious question is
>>>does your jeep use 2 each 12 volt batteries? If so, simply connect
>>>your radio across one of 'em.
>
>>This is done all the time but is a very, very bad idea. Ever hear of
>>Kirchhoff's law? Check it out. It's a very quick way to ruin two 
>>batteries.
>
>>Get a real converter. The switching kind are much more efficient than the
>>linear voltage dropping kind.
>
>>Al, K9SI
 

Reply via email to