Rick DeNatale wrote:
On Tue, Jul 7, 2009 at 11:35 AM, Chris
Sund<ch...@silhouettesolutions.net> wrote:
Hey Everyone,
I've been working my way through the Rspec book trying to absorb and
understand everything. This is my first time with BDD and I'm just
trying to figure out some simple syntax stuff. My questions revolve
around some of the syntaxing used in the book. These are really simple
questions.
1.) Given /^the secret code is (. . . .)$/ do |code|
Is (. . . .) simply a place holder? could I use something like
(- - - -) instead, or does it actually mean something?
Yes it actually means something. the stuff between // is a regular
expression, and some of the characters have meaning.
^ means the beginning of the string
$ means the end of the string
Each . will mark a single character, any character will do.
The parens mark a group, the part of the string which marks the
group will be assigned to the code parameter.
So when the whole regex matches code will be set to the four
characters of the code separated by spaces.
2.) Then /^the mark should be (.*)$/ do |mark|
Similar question....what does .* represent?
it means zero or more arbitrary characters
3.) In the following example why don't I pass |guess| to the When
statement? I'm sure it has something to do with the (code.split)
syntax, I'm just not sure what.
When /^I guess (. . . .)$/ do |code|
@game.guess(code.split)
end
There isn't a variable named guess here. As I said in answer to the
first question, if the story says
When I guess 1 3 4 2
then when the step is executed the code parameter to the block will be
set to "1 3 4 2" and "1 3 4 2".split gives ["1", "3", "4", "2"]
4.) And finally what does ("\n") do?
Then /^the mark should be (.*)$/ do |mark|
@messenger.string.split("\n").should include(mark)
end
"\n" is a ruby string literal representing a new-line, so
@messenger.string.split("\n") results in an array comprising each
line within @messenger.string
Chris,
FYI, a good resource to learn and play around with reg exps in ruby is:
http://rubular.com/
-Ben
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