I'm using will_paginate on my app and it's working fine. The problem came when I had to put search field. After the search, the first page comes according to the parameter passed, but when I go to the second page, it don't brings me the second page, but a new search with no search parameter restriction. I tried everything, but didn't work. Could somebody help me?
Thanks, Pedro Gemfile: gem "rails", "2.3.8" gem "will_paginate", "2.3.15" CONTROLLER: @cursos = Curso.paginate :per_page => 12, :page => params[:page], :conditions => ['nome like ?', "%#{params[:search]} %"], :order =>'nome, dia_semana' VIEW: <% tabnav :embaixada do %> <% form_tag :url => '/embaixada/cursos', :method => 'get' do %> <%= text_field_tag :search, params[:search], :value => nil %> <%= submit_tag "Busca", :name => nil , :disable_with => "Aguarde..."%> <%end%> <br/> <div id="full_name"> <%= render :partial => "embaixada/cursos" , :locals => { :cursos => @cursos } %> </div> <br> <span class="edit_link"><%= link_to "Adicionar novo curso", :controller => "curso" , :action => "new" , :embaixada_id =>@embaixada.id %></span> <% end %> PARTIAL: <% if @cursos and not @cursos.empty? %> <table class="curso" id="cursos"> <tr class="header"> <th>Curso</th><th>Dia Semana</th><th>Local</th> <th>Horário de início</th> <th>Horário de fim</th> <th>Professor</th> </tr> <% @cursos.each do |curso| %> <tr class="<%= cycle('odd', 'even') %>"> <td><%= link_to curso.nome, :controller => :curso, :action => "edit" ,:embaixada_id => @embaixada.id, :curso_id => curso.id %></td> <td><%= curso.dia_semana.capitalize %></td> ... ... ... </table> <% end %> <p> <div style="font-size: small"> <%= will_paginate @cursos %> </div> -- You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-talk@googlegroups.com. To unsubscribe from this group, send email to rubyonrails-talk+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/rubyonrails-talk?hl=en.