Hey Andrew, > > I have been distracted from sage for quite some time but this morning I > started playing again and I came across the *reading_tableau *method of a > partition. The documentation for this method reads: > > Return the reading tableau of the reading word under the > Robinson-Schensted correspondence of the (standard) tableau `T` > labeled > down (in English convention) each column to the shape of ``self``. > > For an example of the tableau `T`, consider the partition > `\lambda = (3,2,1)`, then we have:: > > 1 4 6 > 2 5 > 3 > > For more, see :func:`~sage.combinat.rsk.RSK()`. > > EXAMPLES:: > > sage: Partition([3,2,1]).reading_tableau() > [[1, 3, 6], [2, 5], [4]] > > The example in the text and the example that is doc-test appear to > disagree. My guess is that the example in the text is what is expected. > Is this right? [In 5.8 the behaviour is as in the doc-test.] > > This is correct. The documentation is describing the tableau T, which then it takes the reading word (which is [3, 2, 5, 1, 4, 6]), and then runs RSK on that permutation and pulls the reading tableau. While the documentation is not the best, it is accurate (I had to read it a few times myself).
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