Travis,

Any reasonable definition of reading word of tableau will have the property 
that the result of
inserting the reading word of the tableau, is the original tableau.

So I think there is a problem somewhere here.

--Mark

> Hey Andrew,
>  
> 
> >
> > I have been distracted from sage for quite some time but this morning I 
> > started playing again and I came across the *reading_tableau *method of a 
> > partition. The documentation for this method reads:
> >
> >         Return the reading tableau of the reading word under the
> >         Robinson-Schensted correspondence of the (standard) tableau `T` 
> > labeled
> >         down (in English convention) each column to the shape of ``self``.
> >
> >         For an example of the tableau `T`, consider the partition
> >         `\lambda = (3,2,1)`, then we have::
> >
> >             1 4 6
> >             2 5
> >             3
> >
> >         For more, see :func:`~sage.combinat.rsk.RSK()`.
> >
> >         EXAMPLES::
> >
> >             sage: Partition([3,2,1]).reading_tableau()
> >             [[1, 3, 6], [2, 5], [4]]
> >
> > The example in the text and the example that is doc-test appear to 
> > disagree. My guess is that the example in the text is what is expected. 
> > Is this right?  [In 5.8 the behaviour is as in the doc-test.]
> >
> > This is correct. The documentation is describing the tableau T, which then 
> it takes the reading word (which is [3, 2, 5, 1, 4, 6]), and then runs RSK 
> on that permutation and pulls the reading tableau. While the documentation 
> is not the best, it is accurate (I had to read it a few times myself).
> 
> Best,
> Travis
>  
> 
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