On Sat, Jan 21, 2023 at 8:43 AM Jonathan Thornburg <jthorn4...@gmail.com> wrote:
>
>
> Maple reports the same result for your first testcase:
>
> But, I think Maple and Sage/Giac are both wrong: consider the *definite*
> integral (latex notation) $I = \int_0^{3/2} \lfloor x \rfloor^2 \, dx$:
>
Lol, a cross-CAS exploit.
I doubt sage and maple share source code, could
they share a buggy paper?
Here is a geometric disprove of the closed form.
Plot floor(x)^2 from 1 to 3. The area of the definite
integral is 1^2+2^2=5, which agrees with
integrate(floor(x)^2,x,1,3)
but disagrees with the indefinite integral.
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