mark mcclure wrote:

> (%i1) integrate(1/x^3, x, 1, inf);
>
> Integral is divergent

It's been fixed in CVS, so it will be in the next release.
Sorry for the bother.

> (%i2) assume(p>1);
> (%o2)                 [p > 1]
> (%i3) integrate(1/x^p, x, 1, inf);
> (%o3)                 1/(p-1)

Literal constants are handled separately from symbolic constants
in many cases. I don't know whether a unification is possible,
or desirable, if possible.

Robert Dodier

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