Robert Miller <rlmills...@gmail.com> writes:

>> BTW, shouldn't the generator of the automorphism group be presented
>> as "(0,2)(1,3)"?
>
> Good luck ever convincing the right systems that this should happen:
> GAP's permutation groups don't allow you to permute on the letter 0.
> See the translation option of automorphism_group on that... This has
> been a pain in the butt since day 1. Your "0" is probably the "4".
>
>> >>  sage: foo.edges()
>> >>  [(0, 1, 2), (0, 2, 1), (2, 3, 3)]
>> >>  sage: bar.edges()
>> >>  [(0, 1, 1), (0, 2, 2), (2, 3, 3)]
>> >>  sage: bar.is_isomorphic(foo, edge_labels = True)
>> >>  True
>
> Which version of Sage are you using? 

I tried this in a Sage 3.1.1 and in Sage 3.1.2

> The edge_labels option should return True if and only if there is a
> label-preserving isomorphism, as it does in your example in Sage
> 3.2.2:
>
> ----------------------------------------------------------------------
> | Sage Version 3.2.2, Release Date: 2008-12-18                       |
> | Type notebook() for the GUI, and license() for information.        |
> ----------------------------------------------------------------------
> sage: foo = Graph()
> sage: bar = Graph()
> sage: foo.add_edges([(0,1,2),(0,2,1),(2,3,3)])
> sage: bar.add_edges([(0,1,1),(0,2,2),(2,3,3)])
> sage: foo.edges()
> [(0, 1, 2), (0, 2, 1), (2, 3, 3)]
> sage: bar.edges()
> [(0, 1, 1), (0, 2, 2), (2, 3, 3)]
> sage: bar.is_isomorphic(foo, edge_labels=True)
> False

Great!  I'll upgrade and hopefully everything will be fine.  Thanks.

>>     2       1       3
>> 1 ----- 0 ----- 2 ----- 3
>>
>> OTOH bar looks like this:
>>
>>     1       2        3
>> 1 ----- 0 ----- 2 ----- 3
>
> You probably know, but you can do:
>
> sage: foo.plot(edge_labels=True)
>

Yeah, I know that but I kinda like ascii art :).

Thanks,
Nikos


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