Kevin,
It worked.
Thanks, a lot.
On Jul 6, 3:33 pm, Kevin Horton <khorto...@rogers.com> wrote:
> Maybe you can use:
>
> sage: RealNumber=float; Integer=int
>
> or, explicitly define the number type when calling the scipy function.
>
> Good luck,
>
> Kevin Horton
>
> On 6 Jul 2009, at 15:57, Mikie wrote:
>
>
>
>
>
> > Ahmed,
>
> > Looks good, but I am creating a function in python that is called.
> > And 1r, .56r ,etc. does not pass. I am taking these parameters from a
> > form and then using the function.
> > Is there a work-a-round?
> > Thanks
>
> > On Jul 3, 6:19 pm, Ahmed Fasih <wuzzyv...@gmail.com> wrote:
> >> This is also an excellent resource: "How To Ask Questions The Smart
> >> Way," by the peerless Eric Steven
> >> Raymond:http://catb.org/esr/faqs/smart-questions.html
>
> >> On Jul 3, 8:17 pm, Ahmed Fasih <wuzzyv...@gmail.com> wrote:
>
> >>> Writing your own is a good way to understand the implementation
> >>> issues
> >>> that we sometimes unthinkingly rely on, but for production code,
> >>> it's
> >>> always a good idea to default to the pre-packaged implementation.
>
> >>> In this case, I think it's the standard issue with Scipy not
> >>> understanding Sage types. This problem is described
> >>> inhttp://wiki.sagemath.org/faq#Typeissuesusingscipy.2Ccvxoptornumpyfrom
> >>> ...
>
> >>> sage: import scipy.stats as stats
> >>> sage: stats.binom.pmf(1,10,.56,0)
> >>> ---------------------------------------------------------------------------
> >>> TypeError Traceback (most recent
> >>> call
> >>> last)
> >>> <snip>
> >>> TypeError: unsupported operand type(s) for *: 'numpy.ndarray' and
> >>> 'numpy.bool_'
>
> >>> There are numerous fixes to this problem, one of which is:
>
> >>> sage: stats.binom.pmf(1r,10r,.56r,0r)
> >>> 0.0034614823012532187
>
> >>> As an alternative, if you plan on doing everything in Scipy/Numpy
> >>> and
> >>> don't mind a fat-fisted approach, you may want to use IPython in
> >>> Pylab
> >>> mode: start Sage with "sage -ipython -pylab" and you don't have to
> >>> worry about the preprocessor.
>
> >>> On Jul 3, 3:30 pm, Mikie <thephantom6...@hotmail.com> wrote:
>
> >>>> I am trying to use the binomial pmf function in Scipy. Forget the
> >>>> question I will write my own.
> >>>> Thanx
>
> >>>> On Jul 3, 9:32 am, William Stein <wst...@gmail.com> wrote:
>
> >>>>> On Fri, Jul 3, 2009 at 5:27 PM,
> >>>>> Mikie<thephantom6...@hotmail.com> wrote:
>
> >>>>>> What is the syntax to get the binomial function in Scipy to
> >>>>>> calculate?
> >>>>>> I have tried stats.binom.pmf(1,10,.56,0) etc.
> >>>>>> Thanks for the help.
>
> >>>>> (1) I don't understand the question. What does your question
> >>>>> mean?
>
> >>>>> (2) Possibly you should also ask on the scipy support list, where
> >>>>> there are likely to be more scipy experts...
>
> >>>>> --
> >>>>> William Stein
> >>>>> Associate Professor of Mathematics
> >>>>> University of Washingtonhttp://wstein.org-Hide quoted text -- Hide
> >>>>> quoted text -
>
> - Show quoted text -
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