On Oct 8, 7:54 pm, Nils Bruin <nbr...@sfu.ca> wrote:
> If you define x,y,z to be functions of m, it does what you want:
>
> sage: var("m")
> sage: x=function("x",m)
> sage: y=function("y",m)
> sage: z=function("z",m)
> sage: diff(f,m)
> cos(z(m))*D[0](z)(m) + 2*x(m)*D[0](x)(m) + D[0](y)(m)Yes, but the point of total differentiation is that the parameter m should be arbitrary. We should be able to handdle the differentials without the need to specify with respect to what we are differentiating, for instance: In[1]:= Dt[x y] Out[1]= y Dt[x] + x Dt[y] Before reading your reply I had though it would be easy to implement total differentiation in sage with the stuff we've already got, but on a second thought i don't think sage can express diffrentials by themselves right now... Oscar -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
