> First attempt: loop through each term and try to n() the coefficient. > Madness.
Based on a suggestion Mike Hansen once gave me -- http://ask.sagemath.org/question/411/substituting-expressions-for-numbers -- I tend to use subclasses of Converter when I need to do something like this, so as not to get lost in the madness. :^) Something like: from sage.symbolic.expression_conversions import Converter class Evaluator(Converter): def arithmetic(self, ex, operator): return reduce(operator, map(self, ex.operands())) def pyobject(self, ex, obj): return ex.n() sage: E = Evaluator() sage: var("u x") (u, x) sage: q = ((314069483520)*sqrt(3/(sin(u+2)))*u - 80295755776*x + 4831838208)/(1953125*x^63) sage: q 33554432/1953125*(9360*sqrt(3)*u*sqrt(1/sin(u + 2)) - 2393*x + 144)/x^63 sage: E(q) 17.179869183999998*(16211.99555884469*u*(1/sin(u + 2.0))^0.5 - 2393.0*x + 144.0)/x^63.0 Doug -- To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URL: http://www.sagemath.org
