Hi Brent, Thanks for your suggestion, but I am not looking for a bash/awk command. I was looking for an OVAL definition, and with the help of Gabe I was able to do it.
-- Rodolfo Martínez On Wed, Jun 8, 2016 at 3:18 PM, Brent Kimberley <[email protected]> wrote: > awk -F : '$3 >= 500 {print $1}' /etc/passwd > > > > Works as well ;-) > > > > *From:* Brent Kimberley > > *From:* Rodolfo Martínez [mailto:[email protected] <[email protected]>] > > My question is much simpler now: > > How can get all usernames from /etc/passwd that have UID greater or equal > to 500 without using password_object? I have been trying to do this for > many days now without any luck. > > Thanks for your time > > > > THIS MESSAGE IS FOR THE USE OF THE INTENDED RECIPIENT(S) ONLY AND MAY > CONTAIN INFORMATION THAT IS PRIVILEGED, PROPRIETARY, CONFIDENTIAL, AND/OR > EXEMPT FROM DISCLOSURE UNDER ANY RELEVANT PRIVACY LEGISLATION. No rights to > any privilege have been waived. If you are not the intended recipient, you > are hereby notified that any review, retransmission, dissemination, > distribution, copying, conversion to hard copy, taking of action in > reliance on or other use of this communication is strictly prohibited. If > you are not the intended recipient and have received this message in error, > please notify me by return e-mail and delete or destroy all copies of this > message. > > -- > SCAP Security Guide mailing list > [email protected] > > https://lists.fedorahosted.org/admin/lists/[email protected] > https://github.com/OpenSCAP/scap-security-guide/ > >
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