[jQuery] Re: .animate() queue without pause between animations
I don't think so. The number of pixels is not a fixed number between the
positions in the menu. There are 5 icons and 5 positions, so I use an array
of 5 objects that contain css properties(left, top, zIndex, width, height
and opacity) of each position. The problem with calling .animate() once is
that each icon has to move through an adjacent position before moving on to
the destination. If I call .animate() only once with the final destination,
it will move in a direct line which is not a desired effect.
On Wed, Jan 14, 2009 at 5:52 AM, Karl Swedberg wrote:
> Is it possible to have a variable for the number of pixels by which the
> menu animates (and doubling it when necessary), rather than calling animate
> twice?
> Also, .animate() is part of jQuery core, so you've posted to the correct
> group. ;-)
>
> --Karl
>
>
> Karl Swedberg
> www.englishrules.com
> www.learningjquery.com
>
>
>
>
> On Jan 13, 2009, at 4:29 PM, Miloš Rašić wrote:
>
> Here's the function I use to rotate the menu:
> http://paste.pocoo.org/show/99509/
> The icons are located inside divs with ids 'pos_1' through 'pos_5', 'pos_1'
> being the leftmost icon, and 'pos_5' being the rightmost icon. The all have
> class 'pos'.
>
> The problematic case occurs when the user clicks on 'pos_1' or 'pos_5' and
> the menu has to be rotated by 2 steps. rotate() is then called twice, and so
> the call to .animate() is executed twice for each div. I can't use a single
> call to .animate() because then the divs would jump directly to their final
> destination instead of passing through adjacent positions.
>
> I've tried the following alternatives:
>
> 1) Using queue: false and using the second call with setTimeout so that it
> is executed just before the first animation completes.
>
> 2) Using queue: true as in original code but calling .stop() a fraction of
> a second before the first animation completes on its own so that it is
> interrupted and the second animation in the queue starts immediately.
>
> 3) Putting the second call to .animate() in the callback function of the
> first animate.
>
> All of these alternatives produced exactly the same results as the original
> code. The rotating menu makes a noticeable pause after the first animation
> before proceeding with the second.
>
> On Tue, Jan 13, 2009 at 8:20 PM, Nikola wrote:
>
>>
>> It's hard to tell without having a look at the code. You may want to
>> try http://paste.pocoo.org to post code like this.
>>
>> Are you chaining the animations? ie. $(this).animate({},speed).animate
>> ({},speed).animate({},speed);
>>
>> You could always try setting a delay on your second animation with
>> setTimeout.
>>
>> setTimeout ('$(this).animate({},speed)', 400);
>>
>> Hope that helps.
>> Nikola
>
>
>
>
[jQuery] Re: .animate() queue without pause between animations
Thanks a lot to you and Karl for help. The animation works smoothly now. I had to switch to animating without queue and using setTimeout for the second rotation. It would be nice if jQuery would provide some functionality to the queues where we could choose if we want a pause between animations and how long it should be. On Tue, Jan 13, 2009 at 11:05 PM, Nikola wrote: > > What about doing something similar to what Karl Swedberg did in his > animated scrolling example? > > http://www.learningjquery.com/2007/09/animated-scrolling-with-jquery-12
[jQuery] Re: .animate() queue without pause between animations
Ahh, sorry about that UI always comes to mind when I think of visual presentation, ie. fading, exploding, animating etc..
[jQuery] Re: .animate() queue without pause between animations
Is it possible to have a variable for the number of pixels by which
the menu animates (and doubling it when necessary), rather than
calling animate twice?
Also, .animate() is part of jQuery core, so you've posted to the
correct group. ;-)
--Karl
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Jan 13, 2009, at 4:29 PM, Miloš Rašić wrote:
Here's the function I use to rotate the menu: http://paste.pocoo.org/show/99509/
The icons are located inside divs with ids 'pos_1' through 'pos_5',
'pos_1' being the leftmost icon, and 'pos_5' being the rightmost
icon. The all have class 'pos'.
The problematic case occurs when the user clicks on 'pos_1' or
'pos_5' and the menu has to be rotated by 2 steps. rotate() is then
called twice, and so the call to .animate() is executed twice for
each div. I can't use a single call to .animate() because then the
divs would jump directly to their final destination instead of
passing through adjacent positions.
I've tried the following alternatives:
1) Using queue: false and using the second call with setTimeout so
that it is executed just before the first animation completes.
2) Using queue: true as in original code but calling .stop() a
fraction of a second before the first animation completes on its own
so that it is interrupted and the second animation in the queue
starts immediately.
3) Putting the second call to .animate() in the callback function of
the first animate.
All of these alternatives produced exactly the same results as the
original code. The rotating menu makes a noticeable pause after the
first animation before proceeding with the second.
On Tue, Jan 13, 2009 at 8:20 PM, Nikola wrote:
It's hard to tell without having a look at the code. You may want to
try http://paste.pocoo.org to post code like this.
Are you chaining the animations? ie. $(this).animate({},speed).animate
({},speed).animate({},speed);
You could always try setting a delay on your second animation with
setTimeout.
setTimeout ('$(this).animate({},speed)', 400);
Hope that helps.
Nikola
[jQuery] Re: .animate() queue without pause between animations
What about doing something similar to what Karl Swedberg did in his animated scrolling example? http://www.learningjquery.com/2007/09/animated-scrolling-with-jquery-12
[jQuery] Re: .animate() queue without pause between animations
Here's the function I use to rotate the menu:
http://paste.pocoo.org/show/99509/
The icons are located inside divs with ids 'pos_1' through 'pos_5', 'pos_1'
being the leftmost icon, and 'pos_5' being the rightmost icon. The all have
class 'pos'.
The problematic case occurs when the user clicks on 'pos_1' or 'pos_5' and
the menu has to be rotated by 2 steps. rotate() is then called twice, and so
the call to .animate() is executed twice for each div. I can't use a single
call to .animate() because then the divs would jump directly to their final
destination instead of passing through adjacent positions.
I've tried the following alternatives:
1) Using queue: false and using the second call with setTimeout so that it
is executed just before the first animation completes.
2) Using queue: true as in original code but calling .stop() a fraction of a
second before the first animation completes on its own so that it is
interrupted and the second animation in the queue starts immediately.
3) Putting the second call to .animate() in the callback function of the
first animate.
All of these alternatives produced exactly the same results as the original
code. The rotating menu makes a noticeable pause after the first animation
before proceeding with the second.
On Tue, Jan 13, 2009 at 8:20 PM, Nikola wrote:
>
> It's hard to tell without having a look at the code. You may want to
> try http://paste.pocoo.org to post code like this.
>
> Are you chaining the animations? ie. $(this).animate({},speed).animate
> ({},speed).animate({},speed);
>
> You could always try setting a delay on your second animation with
> setTimeout.
>
> setTimeout ('$(this).animate({},speed)', 400);
>
> Hope that helps.
> Nikola
[jQuery] Re: .animate() queue without pause between animations
Also, you might want to try posting questions like this one in the jQuery UI group as .animate is part of jQuery UI. http://groups.google.com/group/jquery-ui?hl=en&pli=1
[jQuery] Re: .animate() queue without pause between animations
It's hard to tell without having a look at the code. You may want to
try http://paste.pocoo.org to post code like this.
Are you chaining the animations? ie. $(this).animate({},speed).animate
({},speed).animate({},speed);
You could always try setting a delay on your second animation with
setTimeout.
setTimeout ('$(this).animate({},speed)', 400);
Hope that helps.
Nikola
