A. M. Archibald wrote:
> Hi,
>
> Vectorize is a very handy function, but it has at least one pitfall:
>
> def f(x):
> if 1.3 return sqrt(x)
> else:
> return 0
>
> Now vectorize(f)(2)=1.41421356237 but vectorize(f)(array([1,2]))=array([0,1]).
>
> The problem is that, when given an array as input, vectorize feeds in
> the first element, looks at the return type, and returns an array of
> that type - and I didn't put a "." after the zero.
>
> This should perhaps be in the docstring of vectorize, since I can't
> see any way to work around it, but it can easily lead to
> difficult-to-find bugs. It may seem like an artificial example, but it
> came up with a function I was working on. But it's confusing
> behaviour.
>
> vectorize appears to support an "otypes" argument, but it doesn't take
> standard numpy type objects, and it doesn't do anything obvious.
>
It takes old "type-codes" as one big string so you say
vectorize(f,otypes='d')
This should be modernized to handle a list of dtype objects.
I've fixed vectorize in SVN.
-Travis
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