RE: [PHP] Can you do this

[Boget, Chris]

> What about using normal pass-by-value and returning the result?
> function MyFunc ($SomeVal) {
>   $SomeVal += 42;
>   return $SomeVal;
> }
> echo MyFunc ($StrangeVal);

I'm already using the return value for something else.
 
> Anyway - functions that get their parameters by reference and 
> modify them can cause much trouble, so better be careful with 
> that.

Well, the only thing that I'm using that argument for is to return
an error message, if any.

Chris

Re: [PHP] Can you do this

[Christian Reiniger]

On Wednesday 31 January 2001 16:03, Boget, Chris wrote:

> Now, say I have a function where one of the arguments
> is passed by reference and is modified within the function.
> I can call this function on one line
>
> myFunc( &$modifiedVariable );
>
> and print out the value (if any) of $modifiedVariable on
> the next
>
> echo $modifiedVariable.
>
> So what I am wondering is if you can turn those two
> statements into one?  The function is going to get evaluated
> first we already know,  but I am not certain how I could
> get the (new) value of $modifiedVariable.  

What about using normal pass-by-value and returning the result?

function MyFunc ($SomeVal)
{
  $SomeVal += 42;
  return $SomeVal;
}

echo MyFunc ($StrangeVal);

Anyway - functions that get their parameters by reference and modify them 
can cause much trouble, so better be careful with that.

-- 
Christian Reiniger
LGDC Webmaster (http://sunsite.dk/lgdc/)

I saw God - and she was black.

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