Anyone know how to can make un function pointer in c++ to subclass member
function ?
Example
class Class_1
{
void (*nomFunc) (int);
...
}
class Class_2: public Class_1
{
void foo (int x);
Class_2 ();
}
Class_2::Class_2 ()
{
nomFunc = Class_2.foo;
}
Regards,
--
Check this
http://andreinc.net/2010/09/30/generic-data-structures-in-c/
On Tue, Sep 6, 2011 at 10:02 PM, Puneet Ginoria punnu.gino...@gmail.comwrote:
i am getting things in C++ but i need all this to be done in C.
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i didn't go you..
It will be helpful if you could give me some running example or give me some
link..
Thnx in Advance..
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Hi,
Google Template classes in c++ (or) generic classes in c++ you will get
lots of example
Regards,
S.C.Harish
Associate Software Engineer,
Cordys RD http://www.cordys.com/,
Hyderabad
On Mon, Sep 5, 2011 at 5:11 PM, kARTHIK R k4rth...@gmail.com wrote:
For sending the type, you dont have to
i am getting things in C++ but i need all this to be done in C.
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I have to pass a general array in a function whose type will also be
passed and also a function pointer for or .
e.g.
void function(type , type array, pointer for or )
how will you write it in C?
Thanxx in Advance
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For sending the type, you dont have to denote it explicitly. Use templates.
templatetypename T void func (T *a) {
// business logic
}
I dont think you can pass operators directly.
For arithmetic operators, you could use something like this : [refer some
site for exact syntax]
