yea i dunno to say, i dont care, peace..
On Sun, Aug 22, 2021, 22:48 Lawrence Velázquez wrote:
> On Sun, Aug 22, 2021, at 4:38 PM, Alex fxmbsw7 Ratchev wrote:
> > last time again
>
> You promise?
>
> > one pair quotes, not more
>
> Except you're wrong.
>
> $ val=foo
> $ declare "$val"='x'
> $ de
On Sun, Aug 22, 2021, at 4:38 PM, Alex fxmbsw7 Ratchev wrote:
> last time again
You promise?
> one pair quotes, not more
Except you're wrong.
$ val=foo
$ declare "$val"='x'
$ declare -p "$val"
declare -- foo="x"
$ val=bar
$ declare -a "$val"='(baz quux)'
$ declare -p "$val"
declare -a bar=([0]
as i said how to make it work, last time again, one pair quotes, not more
On Sun, Aug 22, 2021, 22:37 Chet Ramey wrote:
> On 8/21/21 6:02 PM, Hunter Wittenborn wrote:
> >> As an end user I would expect the unquoted `('
> >
> >> operator to cause a syntax error, just as it does in `echo ('.
> >
>
On 8/21/21 6:02 PM, Hunter Wittenborn wrote:
As an end user I would expect the unquoted `('
operator to cause a syntax error, just as it does in `echo ('.
Well I'm expecting '(' to be part of the shell's syntax (when unquoted; so
likewise not cause a syntax error), but when looking at thi
22 Ağustos 2021 Pazar tarihinde Hunter Wittenborn <
hun...@hunterwittenborn.com> yazdı:
>
> Well I'm expecting '(' to be part of the shell's syntax (when unquoted; so
> likewise not cause a syntax error), but when looking at things like the
> left side of a variable assignment, I'm sure you'll agre
On Sat, Aug 21, 2021, at 6:02 PM, Hunter Wittenborn wrote:
> In my head, something like this (where 'value' is equal to 'y'):
>
> `declare "${value}"="x"`
>
> becomes this (which it appears to do so):
>
> `declare "y"="x"`
Almost. The argument parses without issue ('=' has no special
meaning h
i wrote, i write again
declare "var=value"
not
declare "var"="value"
On Sun, Aug 22, 2021, 00:02 Hunter Wittenborn
wrote:
> > As an end user I would expect the unquoted `('
>
> > operator to cause a syntax error, just as it does in `echo ('.
>
>
>
> Well I'm expecting '(' to be part of the shell
> As an end user I would expect the unquoted `('
> operator to cause a syntax error, just as it does in `echo ('.
Well I'm expecting '(' to be part of the shell's syntax (when unquoted; so
likewise not cause a syntax error), but when looking at things like the left
side of a variable assignme
20 Ağustos 2021 Cuma tarihinde Hunter Wittenborn <
hun...@hunterwittenborn.com> yazdı:
>
> So, in my opinion, this should logically work (from the view of an end
> user):
>
>
>
> declare "var"=("i" "j")
>
`"var"=("i" "j")' doesn't qualify as an assignment statement as the
variable name is quoted.
The
general consensus seems to be that this isn't really a bug (from what
I've understood), but it looks like I can use a variable reference to
solve the issue nevertheless.
Regardless,
I'm still wanting to almost classify this as a bug (or possibly a
feature request; it feels like it's get
On 8/14/21 8:45 PM, Hunter Wittenborn wrote:
> Hi,
>
>
>
> I was doing some testing for some additions to a rather big Bash script I'm
> working on, and the following code kept failing whenever I attempted to run
> it:
>
>
>
> "
>
> variable="hello"
>
>
>
> declare -g "${variable}"=("wo
Le 15/08/2021 à 02:45, Hunter Wittenborn écrivait :
- declare -g "${variable}"=("world" "me")
- declare -g ${variable}=("world" "me")
- declare -g "hello"=("world" "me")
Invalid because the string "${variable}" cannot be assigned = the scalar
("world" "me")
If you want to dynamically compose
Hi,
I was doing some testing for some additions to a rather big Bash script I'm
working on, and the following code kept failing whenever I attempted to run it:
"
variable="hello"
declare -g "${variable}"=("world" "me")
"
When run, it's complaining about a syntax error near "(", appea
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