I think component is the way to go. I've done a Cart component based on the example in the rails book but I lost it when my harddrive cecided to die :(On 6/10/06,
brandags <[EMAIL PROTECTED]> wrote:
I'm trying to make a simple shopping cart - just basically a way tostore product id's in the sessio
I'm trying to make a simple shopping cart - just basically a way to
store product id's in the session, and maybe a function that calls a
view to display the cart.
Should I be doing this as a regular controller, or should I make a
component for it? Either way, how can I make the cart (as well as t
Thanks clemos, it's all starting to make sense :)
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Well I just answered my own question by doing this:
$this->set('data', $this->Session->read('Transaccion'));
Once againg:
CAKE RULES!
On 6/10/06, Carlos Mauricio Samour <[EMAIL PROTECTED]> wrote:
> On the wiki I read that if you wanted to save an array with the
> session component you do this:
>
Yep I really like it. I spotted a few glitches in Cameleon I'll put up
some bug fixes this night or tomorrow morning.
If you've some comment on general design of the code, feel free...
RosSoft wrote:
> Cool, you're using HeadHelper :)
>
>
> >
>
>
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Of course, that solution does work, as one would expect. In fact, I am
going to make this my standard install method, since it is more secure.
However, after searching the apache error_log, I saw this:
[Sat Jun 10 13:35:23 2006] [error] [client x.x.x.x] Negotiation:
discovered file(s) matching r
On the wiki I read that if you wanted to save an array with the
session component you do this:
$this->Session->write( 'Transaccion\'][\'0' ,
$this->params['data']['Transaccion']);
How do you read this session data?
Y tried:
$dtos = $this->Session->read('[Transaccion]');
and it gives me nothing ba
Could you please explain what you did to store the session info in the
database? I am trying to set up something just like that.
Thanks
On 5/29/06, Dave <[EMAIL PROTECTED]> wrote:
>
> What I ended up doing was creating my own database-driven solution.
> Turns out to be pretty simple. You don't ne
first, try changing DocumentRoot to /var/www//htdocs/app/webroot
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Cool, you're using HeadHelper :)
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This is a very strange problem. I cannot the second rule in the root
.htaccess file to process:
RewriteRule (.*)app/webroot/$1 [L]
However the first rule works fine:
RewriteRule ^$app/webroot/ [L]
I know, because I renamed the root index.php file, and I was still
routed to app/webroot/in
I will add it to the enhancement list then.The only reason I might consider it a bug is that if you bake the views/model/controller and the enum column is in your table, the code that is generated renders errors because of it. I have not tested it with scaffolding however, but I assume the same wo
Chris Kausel created a class called Icing which I have not tried but I believe is trying to address some of the concerns that you have.You can view the code at
http://cakeforge.org/snippet/detail.php?type=snippet&id=67Cake does not have built in support for the traditional "Theme" idea which I bel
I was getting the same problems as this earlier post:
http://groups.google.com/group/cake-php/browse_thread/thread/74829e6c96bd3ba0/eca31f5fe023547b?q=internal+server+error&rnum=1#eca31f5fe023547b
I made the suggested changes to my .htaccess files and it then worked
perfectly! Can any apache g
Without Itune:http://www.apple.com/quicktime/download/standalone.htmlWithout Quicktime (with Media Player Classic):
http://www.free-codecs.com/download/QuickTime_Alternative.htm2006/6/9, nate <[EMAIL PROTECTED]>:
Per the screencast page:Download the latest QuickTime:http://www.apple.com/quicktime/d
For those who are bored,
I've released a alpha "preview" package of Cameleon - the tiny
tree-based CMS.
http://cakeforge.org/projects/cameleon/
The application seems to have reached some stability, even if a lot of
things
are missing or need to be completed. It is not-at-all-production-ready.
Thank you nate for your help.
I think that I have to work on Cake.
Regards,
Krzysiek
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The one thing you can do, although this may make it harder to debug
your app, is set var $persistModel = true; in your controller. This
will cache your constructed model files.
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kiniu wrote:
> So how deep this relation goes?
All the way down.
> But if I don't need all of them and only A, B, C how to do this?
You don't.
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So how deep this relation goes? if I've Model A related to B and C,
model B to D, C to E and E to F all models are required. But if I don't
need all of them and only A, B, C how to do this?
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Yes, if I'm loading Model A, which is related to Models B and C, then
all three are required. However, if Model D is not related to A, B or
C, then it is not required.
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nate wrote:
> All model files are loaded, but only the required model classes are
> constructed. Besides that, this is typically the one of the
> lower-overhead operations in the request. The best thing to focus on
> are your views and view caching.
I added to AppModel class this function
All model files are loaded, but only the required model classes are
constructed. Besides that, this is typically the one of the
lower-overhead operations in the request. The best thing to focus on
are your views and view caching.
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Hi,
My application has ~30 model. Each time I request some action it takes
0.5 - 1s to generate view.
Each time Cake loads all models but I don't need each time all of them.
My question is: Is there in Cake any possibility to construct only
these models which I actually need. Some variable in co
ConnectionManager::getDataSource('default')->config['prefix'] =
this->Session->read('User.database_table_prefix');
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I don't really see it as a bug, since Cake makes the data available, as
in the solution above, but I could see doing some sort of enhancement.
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To pos
Hi,
is it possible to set the table prefix to use in a model from a session
variable? I tried to set the tablePrefix variable from the controller
in the beforeFilter() function like this
$this->Model->tablePrefix =
$this->Session->read('User.database_table_prefix');
but it didn't seem to work
Hi.
Is there a way of automatically render a view from another controller? If
i use requestAction('/somecontroller/someaction', array('return')) i still
nedd to have a view on the current controller with a placeholder for the
rendered view. What i would like to do is to show only the rendered act
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