the form to disappear, use JS to submit the form
using AJAX and hide/change certain elements of the page.
On Thu, Sep 24, 2009 at 3:17 PM, Tony Thomas truet...@gmail.com wrote:
I have a controller function that's using $this-render('action') to
render a view that creates a CSV file after
I have a controller function that's using $this-render('action') to
render a view that creates a CSV file after submitting some info in a
form.
What I want to do is redirect the user after the CSV file is
downloaded. So the steps would be:
1. User submits data.
2. Queries are run and a CSV file
please see :
http://book.cakephp.org/view/410/Validating-Data-from-the-Controller
On Aug 10, 3:42 pm, Tony Thomas truet...@gmail.com wrote:
This is something that's so simple, I'm embarrassed to ask. But after
a few dozen Google searches, I'm going to swallow my pride and post my
question
This is something that's so simple, I'm embarrassed to ask. But after
a few dozen Google searches, I'm going to swallow my pride and post my
question here.
I have a simple ajax function in my controller and I want it to return
an error is the request is not successful. For example:
function
Thanks for this tip. It was exactly what I needed!
On Jul 26, 7:51 pm, brian bally.z...@gmail.com wrote:
I used this:
http://bakery.cakephp.org/articles/view/tree-helper-1
My nav is an element with:
div id=nav
?php
echo $tree-generate(
$section_nodes,
array(
I have a Pages table in my app with the following fields:
id
parent_id
lft
rght
title
body
created
modified
My model uses $actsAs = array('Tree')
All the data associations are correct and generatetreelist() returns
the appropriate values. What I'm looking for is a way to turn the tree
I want to build some options for use across several views, so a custom
HTML helper seems like the best option. However, I'm running into
problems. Here's the helper:
class PositionHelper extends AppHelper {
var $helpers = array('Html');
function getPositions() {
$yaxes =
mod_rewrite is enabled. Like I mentioned, I can run another CakePHP
app already using mod_rewrite with my current setup. It's only this
brand new one that's behaving bizarrely.
On Mar 20, 5:22 pm, Miles J mileswjohn...@gmail.com wrote:
Id first check your apache config files anyways, to make
I still don't know exactly what the problem was, but I downloaded a
new copy of cake and moved my models and controllers over and it
worked right away. Something must have happened when copying the files
over originally.
On Mar 21, 11:10 am, Tony Thomas truet...@gmail.com wrote:
mod_rewrite
I'm starting up a fresh project in Cake, so I downloaded the latest
version, built my models and controllers using $scaffold, but the app
is acting like mod_rewrite is not working. The .htaccess files are all
there.
I'm running a local setup using MAMP on OS X.
The odd thing is that I have
I have a simple hasMany relationship set up with CakePHP and I want to
retrieve a couple of fields from the parent table based on the count
of the child.
The scenario: I have boxes that hold 81 aliquots each. (Each box is
9X9.) I want to retrieve the id and description from the boxes table
of
:07 pm, Tony Thomas truet...@gmail.com wrote:
I've been working on a local copy of my CakePHP app that runs on a my
computer. Today I've only been working on a layout and the style
sheet. I took a break and went back to it which prompted a new login.
Suddenly I'm getting aredirectloop. Firefox
I'm trying to create navigation in CakePHP that uses this method with
CSS drop-downs:
http://www.webmonkey.com/tutorial/Add_CSS_Drop-Down_Menus
So, of course I want to leverage nestedList(), but since I have two
levels of nested lists, I'm getting unexpected results.
Here's what I want:
Main
I've been working on a local copy of my CakePHP app that runs on a my
computer. Today I've only been working on a layout and the style
sheet. I took a break and went back to it which prompted a new login.
Suddenly I'm getting a redirect loop. Firefox gives me this following
message:
Redirect
This problem just cropped up out of the blue for me. I made no changes
to the AppController where the helpers are defined. I can't figure it
out. The JavaScript file in question is clearly in the HTML, but
everything is broken.
I had made a simple change to a different controller that seemed to
I forgot to add that if I remove 'echo $javascript-link('js.js');'
nothing is rendered at all. Even if I hand code the link to the
JavaScript. It's truly bizarre and has broken my entire application.
On Friday afternoon no less. :-(
On Feb 27, 1:42 pm, Tony Thomas truet...@gmail.com wrote
with the server.
On Feb 27, 1:51 pm, brian bally.z...@gmail.com wrote:
On Fri, Feb 27, 2009 at 2:42 PM, Tony Thomas truet...@gmail.com wrote:
This problem just cropped up out of the blue for me. I made no changes
to the AppController where the helpers are defined. I can't figure it
out
I moved my CakePHP app to a new server and everything is working fine
except the one area where I have to allow public access.
The controller I want to allow is 'report', so in the pertinent
controller, I have this:
function beforeFilter() {
$this-Auth-allow('report');
}
using for this?
And, are you certain that the both servers have an identical routes.php?
On Fri, Feb 13, 2009 at 1:07 PM, Tony Thomas truet...@gmail.com wrote:
I moved my CakePHP app to a new server and everything is working fine
except the one area where I have to allow public access
I'm moving my CakePHP app onto to a Media Temple Dedicated Virtual
server and my paths are all wrong.
There seem to be two issues, one more severe than the other:
First, the paths to webroot don't work, so the head of my document
links my stylesheet like so:
link rel=stylesheet type=text/css
Aha! After further investigation, the .htaccess from cake's root was
missing. Once I created that, all was fixed.
On Jan 22, 10:20 am, Tony Thomas truet...@gmail.com wrote:
I'm moving my CakePHP app onto to a Media Temple Dedicated Virtual
server and my paths are all wrong.
There seem
figured out how.
I could loop through and define each checkbox separately, but making a
multiple selection is difficult in that scenario unless I abandon the
form helpers altogether and just hand code the form.
On Thu, Jan 15, 2009 at 5:02 PM, Tony Thomas truet...@gmail.com wrote:
I follow you up
#0
'{n}.Specimen.type', // Field #1
'{n}.Specimen.draw_date' // Field #2
),
'{n}.Specimen.type'
));
// view
echo $form-input('Aliquot', array('options' = 'aliquots', 'multiple'
= 'checkbox'));
hth
grigri
On Jan 20, 2:32 pm, Tony Thomas truet...@gmail.com wrote:
On Jan 16
I'm building a list of checkboxes like so:
echo $form-input('Aliquot.id', array( 'label' = FALSE,
'type' = 'select',
'multiple' =
it, building each checkbox one at a time
instead of my example below. Or am I missing something?
On Jan 15, 11:01 am, grigri j...@hendersonwebdesign.com wrote:
You need to set the $displayField property inside your `Aliquot` model
to whatever field you want for the label.
On Jan 15, 4:47 pm, Tony
-
From: cake-php@googlegroups.com [mailto:cake-...@googlegroups.com] On Behalf
Of Tony Thomas
Sent: Thursday, January 15, 2009 4:52 PM
To: CakePHP
Subject: Re: Label information for Multiple Checkboxes
The complicating factor here is that Aliquot belongs to Specimen in my
model and I want
I tried that very thing, but it didn't produce the expected results.
Maybe find('list', $options) isn't meant to accommodate more than a
single field. I'm not sure.
On Jan 15, 11:34 am, David Coleman david.cole...@connaxis.com
wrote:
You could also do something like this in your controller:
I follow you up to this bit:
?php
echo $form-input(
'Category',
array(
'type'='select',
'multiple'='checkbox',
'options'=$ids,
'label'=false
)
);
?
This doesn't seem to solve the problem of getting the
I'm working on an application to store information on lab specimens.
The lab receive specimens which are divided into aliquots which are
then put into boxes and in turn stored in freezers.
I want to create a function to find all unstored aliquots and display
a message on every page to alert the
http://www.google.com/jsapi; doesn't appear to be a valid URL for the
library you're trying to use.
On Dec 9, 7:30 am, Juan [EMAIL PROTECTED] wrote:
I'm trying to use the Google Visualization API with my CakePHP app.
The two first obstacles are:
- how to link an external JS library?
I try
Fantastic. That worked!
On Dec 9, 9:30 am, Jon Bennett [EMAIL PROTECTED] wrote:
I would:
* create a method in your model to fetch the data
* create a method in your controller to access this data
* create an element that calls via 'requestAction' the data from the
controller
*
I have a scenario where I want to update multiple records
simultaneously. In this case, I have a form with check boxes next to
ids from the table I want to update. These are aliquots stored in a
lab.
updateAll seems like a natural solution, except I can't quite get my
head around defining the
Has something changed with the CakePHP Cookbook's search
(book.cakephp.org)? Over the last few days every search turns up no
results. I just tried a search for model and it returned no results.
Anyone who works on that know anything?
--~--~-~--~~~---~--~~
You
', 'action'
= 'login');
$this-Auth-autoRedirect = FALSE;
}
Okto.Silaban.Net
On Fri, Sep 26, 2008 at 10:00 PM, Tony Thomas [EMAIL PROTECTED] wrote:
This gives me an unexpected T_VARIABLE error on the line with $this-
Auth-autoRedirect = FALSE;
I think the algorithm might be right
' = 'index');
$this-Auth-autoRedirect = FALSE; // so after logging in we're not auto
redirected
}
then manually set
function login() {
$this-redirect('somewhere');
exit();
}
On Tue, Sep 9, 2008 at 10:12 PM, Tony Thomas [EMAIL PROTECTED] wrote:
If someone is familiar with a post
be the case
It's really not difficult :-)
And its a very powerful solution once you understand how it works.
On Sep 16, 1:46 am, Tony Thomas [EMAIL PROTECTED] wrote:
Thanks. I was afraid that might be the case.
On Sep 15, 7:42 pm, Dardo Sordi Bogado [EMAIL PROTECTED] wrote:
You can't
Plus, the problem I ran into with this solution is that the logout
function goes into an infinite loop.
I will note that I didn't have problems with redirect until I started
using database sessions stopped using mod_rewrite because of
restrictions on the shared server I'm using.
On Jul 15,
If someone is familiar with a post to this group or blog entry that
addresses this issue, please let me know. I've spent the morning
scouring both with no satisfactory results.
I have a cakePHP app on a shared server. In local testing, everything
worked fine. But mod_rewrite did not function
On Jul 3, 6:23 pm, francky06l [EMAIL PROTECTED] wrote:
I do not understand the on the fly there ..
Meaning I don't want to have to statically define who can do what.
Instead of something like:
if ($this-Auth-user('username') == 'User1') {
// allow them to do stuff
} else {
// kick
I spent a long time on this so I thought I'd share it with the
community. I was wracking my brain trying to get Auth to work properly
on a site I'm testing locally in Firefox 3. No matter what I did, the
application locked me out with a message stating You are not
authorized I read several
); // prints 'array([0] = 1, [1] = 2
...)'
On 16 May 2008, at 22:26, Tony Thomas wrote:
No. It's simply looping through and echoing the array, but once it
does, the contents of the array are no longer available. As soon as I
looped through using while(list($key, $value
Hi All,
I'm building a CakePHP app for tracking clinic patients, their visits,
their symptoms and questionnaire answers. The barrier I've encountered
is that each patient has many visits AND many symptoms. I want to view
the patient record and their aggregate visits and symptoms.
I've defined a
print_r($patient['M5Symptom']) results in the expected list of
symptoms:
Array
(
[0] = Array
(
[id] = 19
[patient_id] = 5007
[symptom] = Stuffy Nose
[start_date] = 12/18/2006
[end_date] = 12/21/2006
[severity] =
, Tony Thomas [EMAIL PROTECTED] wrote:
Hi All,
I'm building a CakePHP app for tracking clinic patients, their visits,
their symptoms and questionnaire answers. The barrier I've encountered
is that each patient has many visits AND many symptoms. I want to view
the patient record
the same Undefined index message. How can I preserve that
array to reuse it to make a second table?
On May 15, 12:35 pm, Tony Thomas [EMAIL PROTECTED] wrote:
debug($patient) produces:
Array
(
[Patient] = Array
(
[id] = 5007
[med_hist_id] = 0
[gender
the foreach() operates on a copy of
the array and list($key, $value) = each($array) doesn't.
http://us2.php.net/foreach
http://us2.php.net/manual/en/function.list.php
(Links for reference to those who might come upon this in the future.
Hello from the past.)
On May 15, 2:26 pm, Tony Thomas [EMAIL
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