Re: Django ユーザー登録について

Thank you very much good idea! i'm was try but i'm have error when create new staff ! >>Request Method: POST >>Request URL: http://articles/create/ >>Django Version: 1.6.2 >>Exception Type: IntegrityError >>Exception Value: (1048, "Column 'user_id' cannot be null") >>Exception Location:

Re: New feature suggestion, but probably late to the party.

On Wed, Apr 23, 2014 at 6:52 AM, JJ Zolper wrote: > Hello everyone, > > I apologize if this suggestion has already been brought up, shot down etc, > but I would like to highlight a feature I think would be really cool to > have in Django. For this feature, I think an all in one

Re: django comment system - content_type

On Wed, Apr 23, 2014 at 4:54 AM, Adam Teale wrote: > Hi Guys, > > I'm attempting to replace the django.contrib comment app's "post_comment" > using a view in views.py. > > I have it working but I would like to check that I am doing it in an ok > django friendly way. > > The

New feature suggestion, but probably late to the party.

Hello everyone, I apologize if this suggestion has already been brought up, shot down etc, but I would like to highlight a feature I think would be really cool to have in Django. For this feature, I think an all in one standard that is appropriate for all users of django websites that can

Re: Django ユーザー登録について

On 23 April 2014 01:52, hito koto wrote: > thank you very much Each Staff can login. Each staff should only see their own page or dataset. > This is correct > > I want to create administrator page and each staff , > 1, i want , Staff can see the staff page with ID

django comment system - content_type

Hi Guys, I'm attempting to replace the django.contrib comment app's "post_comment" using a view in views.py. I have it working but I would like to check that I am doing it in an ok django friendly way. The content_type that the request.POST['content_type'] returns is: `myapp.mymodel` When I

Re: Django ユーザー登録について

thank you very much >>>Each Staff can login. >>>Each staff should only see their own page or dataset. This is correct I want to create administrator page and each staff , 1, i want , Staff can see the staff page with ID and PW that an administrator has issued 2, administrator can see all the

Re: Tutorial Part4: object_list() got an unexpected keyword argument 'object_id'

On Tue, Apr 22, 2014 at 8:10 AM, Okabe Kenji wrote: > > At the end of tutorial part 4, I got following error message and could not > get displayed the result page. > Request Method: GET > Request URL: http://127.0.0.1:8000/polls/1/result/ > Django Version: 1.3.1 Django 1.3

Re: Django ユーザー登録について

Hi! I don't know how many people on this list speak Japanese unfortunately. I'm not sure if you will get many responses. I read and speak a little Japanese, but had to use Google translate. I think you are asking: I have made a staff database. Each Staff can login. Each staff should only see

Django ユーザー登録について

初めまして、 Django でスタッフの管理ツールを開発しょうと始めたのですが、まったくできないです、誰かが教えてくださいませ！ 1,管理人は管理ログインのID/PWで入ってすべてのスタッフの情報を閲覧し管理できる 2,スタッフは管理者が発行してくれたID/PWでログインで入ってスタッフ個人個人のサイトでスタッフ個人個人の情報しか閲覧、管理できないこと 今はスタッフのID/PWで入ってもすべての情報を見てしまう！ なんかわからないです。教えてくださいませ！ 上記を作りとしたコード以下です。 こちらはstartprojectのUrls.py: from

Tutorial Part4: object_list() got an unexpected keyword argument 'object_id'

At the end of tutorial part 4, I got following error message and could not get displayed the result page. Request Method: GET Request URL: http://127.0.0.1:8000/polls/1/result/ Django Version: 1.3.1 Exception Type: TypeError Exception Value: object_list() got an unexpected keyword argument