Dear R experts,
I would really appreciate if you had an idea on how to use more
efficiently the aggregate method:
More specifically, I would like to calculate the mean of certain
values on a data frame, grouped by various attributes, and then
create a new column in the data frame that will have
Hi Ross,
I'm still really confused about your question.
Let me ask you some specific questions (maybe someone more experienced
would understand at once, but I'm no expert; I hope I can still help
you! In any case, I would like to understand for myself ;) )
- is "seal_dist" the name of your d
Another option is to use the colsplit() function (in the reshape package):
testdata <- data.frame(sp = c("GenusA_SpeciesC_Tree",
"GenusA_SpeciesF_Tree", "GenusB_SpeciesA_Shrub"),
stringsAsFactors=FALSE)
library(reshape)
testdata <- cbind(testdata, colsplit(testdata$sp, split="_", names=c("Genus",
could you just give us the output of dput() for the data you copied in the
mail?
eg dput(seal_dist[,1:100])
and an example of how you want your output. I guess I get what you want to
do, but it's not what your code is doing. And it will be difficult to put
that in a matrix, as you have different
I am trying to understand R arima function. Any pointers would be
appreciated.
Thank you,
Shakira.
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Hi,
I want to simulate a simple wireless network in R.
There is a source and destination and source sends some data packets to
the destination and some routing table and so on.
Does anyone have any idea and knowledge about this or are there any
packages for this.
The thing that I am going to do is
This might not be the most elegant way of doing it, but it should probably
work, given that data is always separated by a "_".
string.1<-strsplit(c("GenusA_SpeciesC_Tree","GenusA_SpeciesF_Tree",
"GenusB_SpeciesA_Shrub"),"_")
matrix(unlist(string.1),ncol=3,byrow=TRUE)
2010/6/1 Joël Baumann
> He
Hi,
I don't know if it would help you since your goal is not really clear to
me, but here are some thoughts:
> x <- c("GenusA_SpeciesC_Tree", "GenusA_SpeciesF_Tree",
"GenusB_SpeciesA_Shrub")
> test <- strsplit(x, "_")
> test
[[1]]
[1] "GenusA" "SpeciesC" "Tree"
[[2]]
[1] "GenusA" "Specie
How about this:
testdata <- data.frame(sp = c("GenusA_SpeciesC_Tree",
"GenusA_SpeciesF_Tree", "GenusB_SpeciesA_Shrub"),
stringsAsFactors=FALSE)
# for one
unlist(strsplit(testdata[1,1], split="_"))
# for all of them
do.call(rbind, sapply(testdata[,1], strsplit, split="_"))
Sarah
On Tue, Jun 1,
You might consider starting your search with
?png
Sarah
On Tue, Jun 1, 2010 at 5:34 AM, thoeb wrote:
>
> Hello,
>
> is there an equivalent to write.csv for saving images to a folder? E.g. if I
> have a histogram or piechart I would need to write a command that saves the
> resulting image as png
There's something very unlogic in your code. You have the whole time the
same datafra
On Tue, Jun 1, 2010 at 1:51 PM, RCulloch wrote:
>
> Hi All,
>
> I am trying to run a loop that will have varying numbers of rows with each
> output.
>
> Previously I have had the same number of rows so I would
Hi fellow R developers/users,
I've recently revised a package called rtv, and now consider it
reasonably stable.
Description: A package for conveniently representing, manipulating and
visualising time data. Here, time is regarded as a random variable,
and objects are used to represent realisation
Hello!
I have the following problem:
I have a file in R that has in the first row three informations in one
row that I would like to in three different rows.
The first row looks like this:
GenusA_SpeciesC_Tree
GenusA_SpeciesF_Tree
GenusB_SpeciesA_Shrub
...
I tried with strsplit and and subs
Hello,
is there an equivalent to write.csv for saving images to a folder? E.g. if I
have a histogram or piechart I would need to write a command that saves the
resulting image as png or jpg into a certain folder (working directory).
Thanks
--
View this message in context:
http://r.789695.n4.na
On Tue, Jun 1, 2010 at 5:04 AM, Jessica Queree
wrote:
> My issue relates to adding text to a matrix and finding that the text is
> converted to a number.
>
A matrix can only hold one type of data. Since you started with character,
that's what you get.
A dataframe can hold different types of data
Can any one help it will be very kind, loop statements
I have this table and some more records, I want to reshape it
V1 V2 V3 V4 V5 V6 V7 V8 V9 V10
TP53 Dis1 Dis2 Dis3 Dis4 Dis5 Dis6
DCI New1 New2 New3 New4
FDI Hi2 H3 H4
GHD I1 I3 I4 I5 I6 I7 I8
I want my new table or matrix to be some thing lik
Sir,
Can you suggest some function for discriminant analysis for Binary response
having continuous as well as categorical regressors.
Thanks,
Suman Dhara
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Hi Ivan,
Thanks for your help, your initial suggestion did not work, but that is no
doubt down to my lack of making sense!
Here is a short example of my dataset. Basically the loop is set up to match
the ID with the TO column based on DIST = 0. So A1 = 2, A1.1 =1, A2 = 4,
A2.1 = 3. That is fin
My issue relates to adding text to a matrix and finding that the text is
converted to a number.
This is the section of code I'm having trouble with:
# First, I load in a list of names from a .csv file to 'names'
names <- read.csv(file("Names.csv"))
# Then I define a matrix which will be p
Dear readers of R-help
as most of you will *not* be aware, R-help has continued to work the
way it does, only thanks to a dozen of volunteers,
see https://stat.ethz.ch/mailman/listinfo/r-help .
The volunteers manually moderate e-mails that "look like spam" (and
sometimes are and sometimes are not
The closest "explanation" of the term "loess" I can find is in "Local
regression models" by Cleveland, W. S.; Grosse, E. & Shyu, W. M. (Chapter
8 of Statistical models in S (1992) by Chambers, J. M. & Hastie, T. J.)
... local regression models is called "loess," which is short for "local
regr
Hi,
I might be a bit tired so that I don't understand everything but I'm a
bit confused.
How would you like your DIST_LOOP matrix to look like?
What do you intend to use xdfrow1...xdfrow7? As I said, I might not be
at the best of my shape!
A sample dataset would really help to see what you ha
Hi All,
I am trying to run a loop that will have varying numbers of rows with each
output.
Previously I have had the same number of rows so I would use (and I
appreciate that this will no doubt achieve some gasps as being thoroughly
inefficient!):
xdfrow<-(0)
xdfrow1<-(1:32)
xdfrow2<-(33:64)
x
Can anyone tell me how to calculate a mid-p value for a chi-squared test
in R?
Many thanks,
Andrew Wilson
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Noah Silverman smartmediacorp.com> writes:
>
> I'm running a long MCMC chain that is generating samples for 22 variables.
>
> I have each run of the chain as a row in a matrix.
> So: Chain[,1] is the column with all the samples for variable one.
> Chain[,2] is the column with all the samples
Hi all,
Thanks to an offlist e-mail from Thomas (Lumley), I have spent the past few
days getting a bit more edumacated on additional restrictions on the
opportunity for R to appear on the iPhone/iPad. These in fact go well beyond
the GPL issue that I raised in my initial post, which in and of i
On 2010-06-01 5:01, khush wrote:
Dear All,
I am newbie to R, and I wanted to plot a barplots with R and in such a way
that It will also show me position which I can plot on the bar line.
Here is my code that I am using to plot,
chromosome<- c(40.2, 35.6, 36.1, 29.6, 31, 29.6, 31, 29.
On 06/01/2010 09:01 PM, khush wrote:
Dear All,
I am newbie to R, and I wanted to plot a barplots with R and in such a way
that It will also show me position which I can plot on the bar line.
Here is my code that I am using to plot,
chromosome<- c(40.2, 35.6, 36.1, 29.6, 31, 29.6, 31,
Hi,
If you want to draw lines on your barchart then
aa = barplot(chromosome, col="purple", xlab="Oryza sativa Chromosomes",
border
= NA, space = 5, ylim = c(0,45))
returns the midpoints of each bar in the vector aa and then you can use
the lines() function to do the drawing.
Martyn
-Origin
On 06/01/2010 04:16 AM, Noah Silverman wrote:
Hi,
Working on a report that is going to have a large number of graphs and
summaries. We have 80 "groups" with 20 variables each.
Ideally, I'd like to produce ONE page for each group. It would have two
columns of 10 graphs and then the 5 number su
On 06/01/2010 12:44 AM, Jie TANG wrote:
here ,I want to plot two lines in one figure.But I have two problems
1) how to move one of the y-axis to be the right ? I tried to the
command"axis(2)",But I failed.
2) how to add the axis information correctly.Since I have use the cmommand
"axis(1,at=1:6,l
Hi
r-help-boun...@r-project.org napsal dne 01.06.2010 13:01:38:
> Dear All,
>
> I am newbie to R, and I wanted to plot a barplots with R and in such a
way
> that It will also show me position which I can plot on the bar line.
>
> Here is my code that I am using to plot,
>
> > chromosome <- c(
Dear All,
I am newbie to R, and I wanted to plot a barplots with R and in such a way
that It will also show me position which I can plot on the bar line.
Here is my code that I am using to plot,
> chromosome <- c(40.2, 35.6, 36.1, 29.6, 31, 29.6, 31, 29.4, 28.2, 23, 23,
28.2)
>barplot (chromosom
On Jun 1, 2010, at 12:51 AM, suman dhara wrote:
Sir,
I have n p-dimensional regressor vectors corresponding to n
responses. I
want to plot n regressor vectors in R. Is it possible to plot them
in R?
If yes, please send me the code.
?matplot
Thanks,
Suman Dhara
David Winsemius, MD
We
On May 31, 2010, at 11:40 PM, Nevil Amos wrote:
Is it possible to print page numbers in pdf() with multiple pages?
?mtext
thanks
Nevil Amos
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First, this is not the list to discuss MacOS X binaries: that is
R-sig-mac.
Second, only one person really knows about the situation with package
binaries, the person who produces them (equally true for Windows and
for Mac OS X). And that person does not read R-help, having asked for
such is
On 2010-05-31 18:33, Steven Worthington wrote:
Dear R users,
I have recently begun to reuse some functions I made several months ago. The
scripts write to a .csv file using the 'write.csv' function with the append
option set to TRUE. This used to work fine, albeit with the warning
"appending co
On Tue, 1 Jun 2010, Peter Ehlers wrote:
On 2010-06-01 1:53, arnaud Gaboury wrote:
Brian,
If I do understand correctly, I must use in my function something else than
ddply() if I want to avoid any error each time my df has zero rows?
Am I correct?
You could define a function to handle the ze
Hi,
You could use melt from the reshape package to create a long format
data.frame. This is more easy to plot with lattice or ggplot2, and you
can then use facetting to arrange several plots on the same page. The
dummy example below produces 10 pages of output with 10 graphs per
page.
library(ggp
Is there a reason why append=TRUE should not be used?
I actually use it a lot; that way I have less csv files created. I can
output everything to a single file. Since some statistical tests returns
lists with different number of elements, it is not always possible to
export the output all at o
Patrick,
When apply to this following df :
futures <-
structure(list(DESCRIPTION = character(0), CREATED.DATE =
structure(numeric(0), class = "Date"),
QUANTITY = numeric(0), SETTLEMENT = character(0)), .Names =
c("DESCRIPTION",
"CREATED.DATE", "QUANTITY", "SETTLEMENT"), row.names = integer(
On 2010-06-01 1:53, arnaud Gaboury wrote:
Brian,
If I do understand correctly, I must use in my function something else than
ddply() if I want to avoid any error each time my df has zero rows?
Am I correct?
You could define a function to handle the zero-rows case:
f <- function(x){
if(nrow(
It may not be the nicest solution, but my suggestion should work.
Have you tried plot(type="n",...), plotting the axes with axis(), and
plotting the data with lines()?
Ivan
Le 6/1/2010 10:10, Jie TANG a écrit :
> thanks for your reply.
> I have tried to use rseek.org.But still some problems.
>
As noted in the help file under CSV files:
These wrappers are deliberately inflexible: they are designed to
ensure that the correct conventions are used to write a valid file.
Attempts to change append, col.names, sep, dec or qmethod are ignored,
with a warning.
On Mon, May 31, 2010 at 8:33 PM,
Hi,
Try with:
par(mfrow=c(11,2))
It should work better!
Remember that mfrow is an argument of the function par(), not a function
itself.
One other tip: think about using pdf, ps, png, or SVG devices, I find it
easier and nicer.
HTH,
Ivan
Le 6/1/2010 10:02, Noah Silverman a écrit :
I'm ru
On 1 June 2010 11:34, Peter Ehlers wrote:
> Or, for a very slight further reduction in time in
> the case of larger matrices/vectors:
>
> as.vector(tcrossprod(V, xyzs))
>
> I mention this merely to remind new users of the
> excellent speed of [t]crossprod().
>
> -Peter Ehlers
Thanks, I've been
On 2010-06-01 0:16, bill.venab...@csiro.au wrote:
xyzs<- matrix(rnorm(3*10,0,1),ncol=3)
V<- c(2,3,4)
system.time(vx<- apply(t(xyzs) * V, 2 ,sum))
user system elapsed
1.060.021.08
system.time(wx<- as.vector(xyzs %*% V))
user system elapsed
0 0 0
a
Dear group,
Here is my data frame:
futures <-
structure(list(DESCRIPTION = c("CORN Jul/10", "CORN Jul/10",
"CORN Jul/10", "CORN Jul/10", "CORN Jul/10", "LIVE CATTLE Aug/10",
"LIVE CATTLE Aug/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 Jul/10",
"SUGAR NO.11 Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO
Thank you
Ben Bolker a écrit :
> Gildas Mazo curie.fr> writes:
>
>
>> Is there a simple way to save my figures in png instead of pdf with
>> Sweave ??
>>
>
>
> See
>
> http://sites.google.com/site/thibautjombart/r-packages
>
> (scroll to the bottom)
>
> ___
Hi
r-help-boun...@r-project.org napsal dne 01.06.2010 10:20:35:
> On 31/05/2010, Gabor Grothendieck wrote:
> > Use read.csv or read.table(..., sep = ","). Also note that if you
> > delete the first comma of the header (as in the second example below)
> > you won't have to specify row.names sinc
On 31/05/2010, Gabor Grothendieck wrote:
> Use read.csv or read.table(..., sep = ","). Also note that if you
> delete the first comma of the header (as in the second example below)
> you won't have to specify row.names since it can figure it out from
> the fact that there is one fewer column name
thanks for your reply.
I have tried to use rseek.org.But still some problems.
When I add "axis(4)" and axis(1,at=1:6,labels=gradeinfo$gradenam),the old
tick or labels still
are there as shown in the figure,how could I delete them( the old tick
information in x-axis and left y axis )
My script is s
I'm running a long MCMC chain that is generating samples for 22 variables.
I have each run of the chain as a row in a matrix.
So: Chain[,1] is the column with all the samples for variable one.
Chain[,2] is the column with all the samples for variable 2, etc.
I'd like to fit all 22 on a single
Dear group,
I have noticed that the MacOS X binary for lme4 is not available on
CRAN at the moment. I am aware that it may be possible to install from
source but I am not very familiar with that procedure and would rather
avoid it. But I need the package for a statistics course next week. So
can a
Brian,
If I do understand correctly, I must use in my function something else than
ddply() if I want to avoid any error each time my df has zero rows?
Am I correct?
TY
> -Original Message-
> From: Prof Brian Ripley [mailto:rip...@stats.ox.ac.uk]
> Sent: Tuesday, June 01, 2010 9:47 AM
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