On Mon, 2005-11-21 at 16:57 +0100, Antje Döring wrote:
>
> Hi there,
>
>
>
> I have a question, which I thought is very easy to solve, but somehow
> I can't find a solution. Probably someone could help me quickly?
>
>
>
> Here it is:
>
>
>
> I have two matrices:
>
>
>
> a
>
>
On Thu, 2005-11-17 at 17:09 +0100, Matthieu Cornec wrote:
> Hello,
> I am importing the following file
> ;aa;bb;cc
> 1988;12;12;12
> 1989;78;78;12
> 1990;78;78;12
> 1991;78;78;12
> 1992;78;78;12
> 1993;78;78;12
> 1994;78;78;12
>
> data<-read.csv2(
On Thu, 2005-11-17 at 17:03 +0100, Florence Combes wrote:
> Dear all,
>
> We are facing this problem for long, and so ask for your help.
>
> We are plotting 2 graphs in a postscript device (left part -layout
> function-), and the common legend for these graphs on the right part.
> The legend in t
I have a feeling that Vasu wants (mistakenly) this:
dat <- read.table("clipboard", header = FALSE)
> dat
V1 V2 V3 V4
1 Name Weight Height Gender
2 Anne150 65 F
3Rob160 68 M
4 George180 65 M
5 Greg205 69 M
> str(dat)
On Wed, 2005-11-16 at 16:46 +, Jörg Schlingemann wrote:
> Hi!
>
>
>
> This is probably a very trivial question. Is there an easy way to invert the
> y-axis (low values on top) when using the function barplot()?
>
>
>
> Thanks,
>
> Jrg
You mean something like this?:
barplot(1:10, y
On Mon, 2005-11-14 at 19:01 +, William Astle wrote:
> Is there an R function analogous to the C function strtol?
> I would like to convert a binary string into an integer.
>
> Cheers for advice
>
> Will
There was some discussion in the past and you might want to search the
archive for a mo
On Mon, 2005-11-14 at 19:07 +0200, Brandt, T. (Tobias) wrote:
>
> >-Original Message-
> >From: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
> >Sent: 14 November 2005 06:21 PM
> >
> >On 11/14/05, Brandt, T. (Tobias) <[EMAIL PROTECTED]> wrote:
> >> Hi
> >>
> >> Given that things like the f
On Mon, 2005-11-14 at 15:55 +0100, Karin Lagesen wrote:
> I have found a bug/feature with barplot that at least to me shows
> undesireable behaviour. When using barplot and plotting fewer
> groups/levels/factors(I am unsure what they are called) than the number
> of colors stated in a col statement
On Wed, 2005-11-02 at 16:06 -0600, Michal Lijowski wrote:
> Hi,
>
> I have been trying draw tickmark labels along
> the y - axis perpendicular to the y axis while
> labels along the x - axis parallel to x axis
> while making box plot.
>
> Here is my test dataset.
>
> TData
>ID Ratio
> 1 0
One other option, just to throw it out there, though it involves a few
more steps.
1. Generate the R plots as EPS files.
2. Import them into Powerpoint onto the required slides. Resize and/or
place as required. Recent versions of Powerpoint will auto-generate a
bitmapped preview image upon import
On Fri, 2005-10-28 at 10:26 -0700, J.M. Breiwick wrote:
> Hello,
>
> I want to plot 3 boxplots [ par(mfrow=c(3,1)) ] but the first one has 8
> groups, the 2nd has 7 and the third has 6. But I the groups to line up:
>
> 1 2 3 4 5 6 7 8
>2 3 4 5 6 7 8
> 3 4 5 6 7 8
>
> where the number
On Thu, 2005-10-27 at 16:15 -0500, Na Li wrote:
> On 27 Oct 2005, Duncan Temple Lang wrote:
>
> > Yes, it is of interest and was sitting on my todo list at
> > some time. If you want to go ahead and provide code to do it,
> > that would be terrific. There are other areas where encryption
> > wou
On Tue, 2005-10-25 at 13:07 -0500, Marc Schwartz (via MN) wrote:
> On Tue, 2005-10-25 at 11:55 -0600, [EMAIL PROTECTED] wrote:
> > Does anyone know how I can set up R so that when I make a graphic, the
> > graphics window remains behind the console window? It's annoying to
&
On Tue, 2005-10-25 at 11:55 -0600, [EMAIL PROTECTED] wrote:
> Does anyone know how I can set up R so that when I make a graphic, the
> graphics window remains behind the console window? It's annoying to
> have to reach for the mouse every time I want to type another line of
> code (e.g., to add ano
On Mon, 2005-10-24 at 22:32 +0200, Dr. med. Peter Robinson wrote:
> Dear List,
>
> I am sorry if this perhaps a too basic question, but I have not found an
> answer in Google or in the R help system. I am trying to use R to do a
> very simple analysis of some data (RT-PCR and Western analysis) wit
On Fri, 2005-10-21 at 21:32 +, Ben Bolker wrote:
> As far as I can tell from reading The Fine Documentation
> (R Language Definition and Intro to R), matrices are supposed
> to be of homogeneous types. Yet giving matrix() an inhomogeneous
> list seems to work, although it produces a peculiar o
On Fri, 2005-10-21 at 21:13 +0200, Jan Sabee wrote:
> Dear all,
> I want to make three plot below to only one plot together with legend,
> how can I do that?
> I have tried with matplot function but I did not succeed.
> Thanks for your help.
> Sincerelly,
> Jan Sabee
>
> test.five.x <-
> c(0.02,0
On Thu, 2005-10-20 at 15:41 -0500, Marc Schwartz (via MN) wrote:
> On Thu, 2005-10-20 at 14:46 -0400, Keith Sabol wrote:
> > I am creating boxplots from a dataframe and would like to add to the
> > standard output a marker representing the value from a particular row in
> &g
On Thu, 2005-10-20 at 14:46 -0400, Keith Sabol wrote:
> I am creating boxplots from a dataframe and would like to add to the
> standard output a marker representing the value from a particular row in the
> dataframe.
>
> .And I apologize if the solution is as trivial as it seems it should be
On Thu, 2005-10-20 at 17:31 +0200, Christian Jones wrote:
>
> Hello, "urn:schemas-microsoft-com:office:office" />
>
> I would like to create a histogram from a data collumn consisting of 4
> classes (0; 0.05;0.5;25;75). Due to the difference in scale the
> classes 0;0.05 and 0.5 are displayed wit
On Thu, 2005-10-20 at 16:20 +0200, Peter Dalgaard wrote:
> "Nelson, Gary (FWE)" <[EMAIL PROTECTED]> writes:
>
> > Peter,
> >
> > Thank you for your response. I knew how close the values are to
> > integers, but I still don't understand why I don't have control over
> > how the numbers are display
On Wed, 2005-10-19 at 18:27 +0100, Rui Cardoso wrote:
> Hi,
>
> I have a problem about graphics. I would like to plot two graphs: a barplot
> and curve. Here is the code:
>
> > barplot(dpois(0:45,20),xlim=c(0,45),names=0:45)
> > curve(dnorm(x,20,sqrt(20)),from=0,to=45,add=T)
>
> Both graphs a
On Wed, 2005-10-19 at 06:47 +1000, Tim Churches wrote:
> Marc Schwartz (via MN) wrote:
>
> > There is also code for the Woolf test in ?mantelhaen.test
>
> Is there? How is it obtained? The documentation on mantelhaen.test in R
> 2.2.0 contains a note: "Currently, no i
On Tue, 2005-10-18 at 17:13 +0200, richard mendes wrote:
> hello everybody
>
> i'm very new at using R so probably this is a very stupid question.
> I have a problem calculating a p-value. When i do this with excel i
> can use the method CHIDIST for 1.2654 with 1 freedom degree i get the
> answer
On Tue, 2005-10-18 at 14:27 +0100, MJ Price, Social Medicine wrote:
> Dear all,
>
> I have been trying to find a function to calculate the Breslow-Day test for
> homogeneity of the odds ratio in R. I know the test can be preformed in SAS
> but i was wondering if anyone could help me to perform t
On Mon, 2005-10-17 at 16:51 +0200, Jorge Gaspar Sanz Salinas wrote:
> Hi all,
>
> This is my first post, I hope you will help me.
>
> I've some data to present with histograms. I have few values with almost 99%
> of
> the frequencies (thousands) and some other values with low frequencies (below
On Thu, 2005-10-13 at 15:20 -0600, Chris Buddenhagen wrote:
> Dear all
> I am using R to produce ordinations library(vegan) and the plot function
> produced looks great on the screen but when I send it to jpg or pdf or eps
> the resolution is not so good. Can you tell me how to get high resolution
On Fri, 2005-10-14 at 00:04 +0200, Benedykt P. Barszcz wrote:
> Dnia czwartek, 13 października 2005 23:25, Andrew Robinson napisał:
> > Marco,
> >
> > use the system command.
> >
> > ?system
> >
> > I hope that this helps,
>
> system(ls, intern = FALSE, ignore.stderr = TRUE)
> Error in as.characte
On Thu, 2005-10-13 at 14:28 -0600, Brian S Cade wrote:
> Ok so I see the problem that I'm having creating a new variable (LAG1DBC)
> in the example data transformation below is that tapply() is creating a
> list that is not dimensionally consistent with the data frame (data). So
> how do I go f
On Thu, 2005-10-13 at 19:47 +0200, Jan Sabee wrote:
> Is there any routine to generate for one vector matrix.
> If I have X I want to generate start from zero to maximum value each vector.
>
> For example, I have a vector x = (4,2,3,1,4)
> I want to generate n=6 times, for 4, start 0 to 4, then 2
On Thu, 2005-10-13 at 14:31 -0400, Duncan Murdoch wrote:
> On 10/13/2005 1:07 PM, Marc Schwartz (via MN) wrote:
> > On Thu, 2005-10-13 at 10:02 -0400, Duncan Murdoch wrote:
> >> Sorry, a typo in my previous message (parens in the wrong place in the
> >> convers
On Thu, 2005-10-13 at 10:02 -0400, Duncan Murdoch wrote:
> Sorry, a typo in my previous message (parens in the wrong place in the
> conversion).
>
> Here it is corrected:
>
> I'm doing a big slow computation, and profiling shows that it is
> spending a lot of time in match(), apparently because
On Thu, 2005-10-13 at 14:50 +0100, Luis Ridao Cruz wrote:
> R-help,
>
> I use the code below to plot some data by applying "apply" function.
> But I don't know how I can get the argument "type" or "col" on the
> "plot" function to distinguish the different lines
> in the graph:
>
> apply ( my.dat
On Wed, 2005-10-12 at 12:01 -0700, t c wrote:
> I have a dataset with three variables: date, var1, var2
> How can I calculate the correlation, by date, between var1 and var2?
>
> e.g.
>
>
> datevar1var2
> 1/1/200154
> 1/1/200185
> 1/1/200197
>
>
>
> 2/1/2001
On Wed, 2005-10-12 at 08:33 -0500, Charles Dupont wrote:
> Marc Schwartz (via MN) wrote:
> > On Tue, 2005-10-11 at 10:01 -0400, Rick Bilonick wrote:
> >
> >>I'm using R 2.2.0 on an up-to-date version of Fedora Core 4 with the
> >>latest version of Hmisc
Peter,
Good points all around.
Hopefully John will provide further clarification.
Best regards,
Marc
On Tue, 2005-10-11 at 19:46 +0200, Peter Dalgaard wrote:
> "Marc Schwartz (via MN)" <[EMAIL PROTECTED]> writes:
>
> > I suspect that John may be looking for ?fr
On Tue, 2005-10-11 at 10:01 -0400, Rick Bilonick wrote:
> I'm using R 2.2.0 on an up-to-date version of Fedora Core 4 with the
> latest version of Hmisc. When I run an example from the latex function I
> get the following:
>
> > x <- matrix(1:6, nrow=2, dimnames=list(c('a','b'),c('c','d','enLine
>
I suspect that John may be looking for ?friedman.test, which I believe
will allow for a two-way non-parametric test.
kruskal.test() will perform a non-parametric test on two or more samples
(or factor levels) as a generalization of wilcox.test() for one or two
samples (or factor levels).
HTH,
Ma
On Mon, 2005-10-10 at 16:01 +0100, Prof Brian Ripley wrote:
> On Mon, 10 Oct 2005, Marc Schwartz (via MN) wrote:
>
> > On Mon, 2005-10-10 at 10:37 -0400, Afshartous, David wrote:
> >>All,
> >>
> >>Is there are a wildcard in R for varible names as
On Mon, 2005-10-10 at 10:37 -0400, Afshartous, David wrote:
> All,
>
> Is there are a wildcard in R for varible names as in unix? For example,
>
> rm(results*)
>
> to remove all variable or function names that begin w/ "results"?
>
> cheers,
> Dave
>
On Mon, 2005-10-03 at 15:28 -0500, lforzani wrote:
> Hello, I am using library fda and I can not run a lot of functions because
> I receive the error:
>
> Error in bsplineS(evalarg, breaks, norder, nderiv) :
> couldn't find function "spline.des"
>
>
> do you know how I can fix that? Thn
On Tue, 2005-10-04 at 08:38 -0500, Robert Baer wrote:
> > > On 03-Oct-05 Marc Schwartz (via MN) wrote:
> > > > On Mon, 2005-10-03 at 16:31 -0300, Rolf Turner wrote:
> > > >> A student in one of my courses has asked me about getting R graphics
> > >
On Mon, 2005-10-03 at 22:00 +0100, Ted Harding wrote:
> Rolf (& Marc)
>
> On 03-Oct-05 Marc Schwartz (via MN) wrote:
> > On Mon, 2005-10-03 at 16:31 -0300, Rolf Turner wrote:
> >> A student in one of my courses has asked me about getting R graphics
> >> outp
On Mon, 2005-10-03 at 16:31 -0300, Rolf Turner wrote:
> A student in one of my courses has asked me about getting R graphics
> output (under Linux) into a Word document. I.e. she wants to do her
> R thing under Linux, but then do her word processing using Word.
>
> Scanning around the r-help arch
On Mon, 2005-10-03 at 18:01 +0100, Prof Brian Ripley wrote:
> On Mon, 3 Oct 2005, Daniel Pick wrote:
>
> > I have successfully downloaded the sources and built R as a shared
> > library on a Red Hat Enterprise Level 3 box. I am now trying to build the
> > GNOME GUI, but configure is barfing on
On Thu, 2005-09-29 at 18:08 -0400, Johann Park wrote:
> Hi to all,
>
> I am a PH.D Student doing statistical analysis.
> I am totally new to R. I previously use Stata and am changing into R. I
> ususally do with logit regression with binary dependent variable (war
> occurence:1 or 0).
>
> I j
On Thu, 2005-09-29 at 18:36 +0200, Jan Verbesselt wrote:
> Hi R-help,
>
>
>
> When using the package Design and the plot.Design function all the graphs of
> an lrm.fit (lrm()) are plotted without a frame (only with axes). How can the
> frame be added to these plots?
>
>
>
> In the plot.defa
On Thu, 2005-09-29 at 14:34 +0200, Volker Rehbock wrote:
> Is it possible to automatically display the underlying values of a
> piechart/barplot in the graphic? If so, which package/function/argument do I
> need for it?
> Thanks,
> Volker
Using pie charts are not a particularly good way of disp
On Thu, 2005-09-29 at 15:28 +0200, Karin Lagesen wrote:
> "Petr Pikal" <[EMAIL PROTECTED]> writes:
>
> > Hi Karin
> >
> > I did not have seen any answer for your question yet so here is a
> > try.
> >
> > I gues you want the horizotal layout or your boxplot.
> >
> > boxplot(split(rnorm(30), rep(1
On Thu, 2005-09-29 at 06:57 +1000, Stephen Choularton wrote:
> Hi
>
> I am trying to produce a little table like this:
>
> 0 1
> 0 601 408
> 1 290 2655
>
> but I cannot get the syntax right.
>
> Can anyone help.
>
> Stephen
Do you hav
On Tue, 2005-09-27 at 19:12 +0200, Søren Højsgaard wrote:
> In data OME in MASS I would like to extract the first 5 observations
> per subject (=ID). So I do
>
> library(MASS)
> OMEsub <- split(OME, OME$ID)
> OMEsub <- lapply(OMEsub,function(x)x[1:5,])
> unsplit(OMEsub, OME$ID)
>
> - which resul
On Mon, 2005-09-26 at 17:45 +0200, Shengzhe Wu wrote:
> Hello,
>
> In the Unix environment, I open a window by x11(). May I specify the
> position of this window by specifying the position of the top left of
> the window as in Windows environment? Or some other parameters can be
> used to do that?
On Thu, 2005-09-22 at 10:44 -0400, Elisabetta Manduchi wrote:
> Can anybody tell me if there is an R implementation of the
> Fligner-Policello robust rank test?
> Thanks,
> Elisabetta
I don't know about the Fligner-Policello test, but the Fligner-Killeen
test has been implemented in fligner.test
On Mon, 2005-09-19 at 12:30 -0700, shanmuha boopathy wrote:
> Dear sir,
> i have a matrix like
> x<-c(1:20)
> A<-matrix(x,4,5)
> > A
> [,1] [,2] [,3] [,4] [,5]
> [1,]159 13 17
> [2,]26 10 14 18
> [3,]37 11 15 19
> [4,]48 12 16 20
>
>
On Fri, 2005-09-16 at 10:34 -0700, Martin Lam wrote:
> Hi,
>
> I was wondering if it's possible to get the row
> numbers from a filtering. Here's an example:
>
> # give me the rows with sepal.length == 6.2
> iris[(iris[,1]==6.2),]
>
> # output
> Sepal.Length Sepal.Width Petal.Length Petal.Wi
On Thu, 2005-09-15 at 10:43 -0400, Tyler Smith wrote:
> Hi,
>
> I'm working on a MEPIS (Debian-based Linux) computer, using the
> emacs/ESS package to do my R work. I've got some plots that I label
> interactively using the locate function. With the Windows GUI there is
> an option to take a sn
On Wed, 2005-09-14 at 20:17 +0200, Par Leijonhufvud wrote:
> I'm trying to create histogram (using hist()) that fullfill the following
> criteria:
>
> * data is on a ordinal scale (1, 2, 3, 4, 5)
> * I want bars centered over the number on the x-axis
> * I want 5 bars of eq
On Thu, 2005-09-01 at 21:51 +0200, Knut Krueger wrote:
> scaling<-4
> xywidth<-480
> resolution<-150
> png(filename = "c:/r/anschluss/plots/4.png", width = xywidth*scaling,
> height = xywidth*scaling,pointsize = 12, bg = "white", res =
> resolution*scaling)
> ..
>
> barplot(xrow,col = barcol
On Thu, 2005-09-01 at 16:58 +0100, [EMAIL PROTECTED] wrote:
> hy,
>
> I need to have the 0 on the bottom left corner of the graph being
> joined , not with this little hole between x axis and y axis...
>
> I've saw this question with the answer one time but i'm unable to find
> it again..
>
>
>
On Tue, 2005-08-30 at 12:28 -0700, Isotta Felli wrote:
> Dear list.
>
> New to R, I'm looking for a way of using crosstab to output
> low-dimensional (higher than 2) contingency tables (frequencies,
> per-cents by rows, % by columns, mean, quantiles) I'm looking for
> something of the followi
On Mon, 2005-08-29 at 12:58 -0400, Doran, Harold wrote:
> Dear list:
>
> I have some data for which I am generating a series of barplots for
> percentages. One issue that I am dealing with is that I am trying to get
> the legend to print in a fixed location for each chart generated by the
> data.
On Fri, 2005-08-26 at 22:39 +0530, A Mani wrote:
> Hello,
> Easy ways to "unpaste"?
> xp <- paste(x2, x3) # x2, x3 are two non-numeric columns.
> .
> .
> xfg <- data.frame(xp,sc1, sc2, sc3) # sc1,sc2, sc3 are numeric cols.
>
> I want xp to be split up t
.29 0.02 0.58 0.04 "names<-"
>0.29 0.02 0.29 0.02 "names<-.default"
>0.29 0.02 0.29 0.02 "names"
>
> so almost all the time is in qchisq.
>
>
> On Fri, 26 Aug 2005, Marc Schwartz (
On Fri, 2005-08-26 at 15:25 +0200, Peter Dalgaard wrote:
> Marc Schwartz <[EMAIL PROTECTED]> writes:
>
> > x <- c(0.005, 0.010, 0.025, 0.05, 0.1, 0.5, 0.9,
> >0.95, 0.975, 0.99, 0.995)
> >
> > df <- c(1:100)
> >
> > mat <- sapply(x, qchisq, df)
> >
> > > dim(mat)
> > [1] 100 11
> >
>
, it would appear that the use of lmList would be
advantageous over the use of by().
Marc
On Thu, 2005-08-25 at 11:52 -0500, Marc Schwartz (via MN) wrote:
> That works also (using the example in ?lmList)
>
> library(lme4)
>
> ?lmList
>
> fm1 <- lmList(breaks ~ wo
That works also (using the example in ?lmList)
library(lme4)
?lmList
fm1 <- lmList(breaks ~ wool | tension, warpbreaks)
However, one still would need to use either sapply() or lapply() as
below to get the details that Krishna is looking for.
'fm1' above is a list of models (S4 class 'lmList'
On Wed, 2005-08-24 at 13:06 -0400, Doran, Harold wrote:
> Dear List:
>
> I'm creating a series of barplots using Sweave that must assume a
> standard format. This is student achievement data and the x-axis must
> include all grades 3 to 8. In some cases, the data for a grade (or more
> than one gr
On Tue, 2005-08-23 at 10:12 -0500, Greg Blevins wrote:
> Hello,
>
> I have struggled, for longer than I care to admit, with this seemingly
> simple problem, but I cannot find a solution other than the use of
> long drawn out ifelse statements. I know there has to be a better
> way. Here is strip
On Mon, 2005-08-22 at 12:58 -0400, [EMAIL PROTECTED] wrote:
> I have used the 'par' command to
> overlay one plot on another. But how
> do I overlay it with the x-values
> plotted at the same points on the
> x-axis?
>
> Thank you,
> Steven
The specific answer depends to an extent on the grap
On Wed, 2005-08-17 at 12:02 -0700, Martin Lam wrote:
> Hi,
>
> I am trying to use a vector of indices to select some
> rows from a matrix. But before I can do that I somehow
> need to convert 'combinations' into a list, since
> 'mode(combinations)' says it's 'numerical'. Any idea
> how I can do th
On Tue, 2005-08-16 at 13:18 -0400, Allan Strand wrote:
> Hi All,
>
> I'm trying to take a numerical vector and produce a new vector of the
> same length where each element in the first is placed into a category
> given by a 'breaks-like' vector. The values in the result should equal
> the low
On Mon, 2005-08-08 at 11:57 -0700, Kerry Bush wrote:
> suppose I have the following data
>
> x<-c(rep(.1,5),rep(.2,6),rep(.4,10),rep(.5,20))
> y<-c(rep(.5,3),rep(.6,8),rep(1.2,8),rep(2.5,18),rep(3,4))
>
> If I plot(x,y) in R, I will only get seven distinct
> points. What I want to do is to use di
On Tue, 2005-07-26 at 15:48 -0400, [EMAIL PROTECTED] wrote:
> Hi,
>
> I am looking for an elegant way to transform a vector into percentages of
> values
> that meet certain criteria.
>
> store<-c(1,1.4,3,1.1,0.3,0.6,4,5)
>
> # now I want to get the precentages of values
> # that fall into the c
On Tue, 2005-07-26 at 08:58 +0700, [EMAIL PROTECTED] wrote:
> Hello,
>
> Is there any way to use plot() horizontally similar to
> boxplot(., horiz=TRUE)? I want to use to illustrate
> the distribution of y-values on an adjacent plot using
> layout().
>
> Thanks in advance for any help.
>
>
Ok guys,
So I played around with this a bit, going back to Dan's original
requirements and using Thomas' do.call() approach with legend(). Gabor's
approach using sapply() will also work here. I have the following:
# Note the leading spaces here for alignment in the table
# This could be automated
On Fri, 2005-07-22 at 16:26 +0200, Christian Bieli wrote:
> Dear all
>
> I've got some problems submitting a manuscript, because I can't
> manage
> creating the favourable eps-file of a graph created in R. The
> journal's
> graphic requirements are as followed:
> format: eps
> width: max. 6 inch
[Note: the initial posts have been re-arranged to attempt to maintain
the flow from top to bottom]
> >Dan Bolser writes:
> > >
> > > I would like to annotate my plot with a little box containing the slope,
> > > intercept and R^2 of a lm on the data.
> > >
> > > I would like it to look like...
>
On Thu, 2005-07-21 at 16:18 +0200, Clark Allan wrote:
> hi all
>
> a very simple question.
>
> i have plot(x,y)
>
> but i would like to add in on the plot the observation number associated
> with each point.
>
> how can this be done?
>
> /
> allan
If you mean the unique observation number ass
On Tue, 2005-07-19 at 13:08 -0500, Marc Schwartz (via MN) wrote:
> For the TAB delimited columns, adjust the 'sep' argument to:
>
> read.table("data.gct", skip = 2, header = TRUE, sep = "\t")
>
> The 'quote' argument is by default:
>
..
>
> How do I get R to read the data as tab delemited, but read in the 2nd
> coloumn as one value based on the quotation marks..
>
> thanks..
>
> On 7/19/05, Marc Schwartz (via MN) <[EMAIL PROTECTED]> wrote:
> > On Tue, 2005-07-19 at
On Tue, 2005-07-19 at 13:16 -0400, mark salsburg wrote:
> ok so the gct file looks like this:
>
> #1.2 (version number)
> 7283 19 (matrix size)
> Name Description Values
> ... ..
>
> How can I tell R to disregard the first two lines and start reading
> the 3rd line i
On Tue, 2005-07-19 at 12:28 -0400, Duncan Murdoch wrote:
> On 7/19/2005 12:10 PM, mark salsburg wrote:
> > I have two files to compare, one is a regular txt file that I can read
> > in no prob.
> >
> > The other is a .gct file (How do I read in this one?)
> >
> > I tried a simple
> >
> > read.ta
On Tue, 2005-07-19 at 17:29 +0200, Dirk Enzmann wrote:
> Although I tried to find an answer in the manuals and archives, I cannot
> solve this (please excuse that my English and/or R programming skills
> are not good enough to state my problem more clearly):
>
> I want to write a function with a
On Fri, 2005-07-15 at 15:40 -0500, David Groos wrote:
> I'm trying to figure out R, a piece at a time, hours at a time... I
> was trying to copy the sample function in, "An Introduction to R" (for
> version 2.1.0) by W. N. Venables, D. M. Smith, page 42. Section 10.1
> "Simple examples" provi
On Thu, 2005-07-14 at 15:08 -0500, Deepayan Sarkar wrote:
> On 7/14/05, Marc Schwartz (via MN) <[EMAIL PROTECTED]> wrote:
> > On Thu, 2005-07-14 at 12:30 -0500, Deepayan Sarkar wrote:
> > > On 7/14/05, Kerry Bush <[EMAIL PROTECTED]> wrote:
> > > > Thank
On Thu, 2005-07-14 at 12:30 -0500, Deepayan Sarkar wrote:
> On 7/14/05, Kerry Bush <[EMAIL PROTECTED]> wrote:
> > Thank you for thinking about the problem for me.
> > However, I have found that your method doesn't work at
> > all.
> >
> > You may test the following example:
> >
> > x1=c(0.6,0.4,.
On Tue, 2005-07-12 at 14:37 -0300, Rogério Rosa da Silva wrote:
> Dear list,
>
> I will like to learn how to read a lower triangular matrix in R. The
> input file *.txt have the following format:
>
> A B C D E
> A 0
> B 10
> C 250
> D 3680
> E
On Tue, 2005-07-12 at 16:22 +0200, ecoinfo wrote:
> Hi R users,
> Maybe the question is too simple.
> In a IF ... ELSE ... statement "if(cond) cons.expr else alt.expr", IF and
> ELSE should be at the same line?
> For example,
> if (x1==12)
> {
> y1 <- 5
> }else
> {
> y1 <- 3
> }
> is right,
On Thu, 2005-07-07 at 10:20 -0700, Mikkel Grum wrote:
> I have a situation where I'm filling out a dataframe
> from a database. Sometimes the database query doesn't
> get anything, so I end up trying to place NULL in the
> dataframe like below.
>
> > temp <- NULL
> > xmat <- as.data.frame(matrix(N
On Thu, 2005-07-07 at 11:47 -0400, [EMAIL PROTECTED] wrote:
> Any ideas about the following problem:
>
> I have a matrix (A) that looks like this:
>
> gene_names values
> hsa-mir-124 0.3
> hsa-mir-234 0.1
> hsa-mir-344 0.4
> hsa-mir-333
On Fri, 2005-07-01 at 19:40 +0800, ronggui wrote:
> I write a function to get the frequency and prop of a variable.
>
> freq<-function(x,digits=3)
> {naa<-is.na(x)
> nas<-sum(naa)
> if (any(naa))
> x<-x[!naa]
> n<-length(x)
> ta<-table(x)
> prop<-prop.table(ta)*100
> res<-rbind(ta,prop)
> rownames
On Thu, 2005-06-30 at 23:05 +0200, [EMAIL PROTECTED] wrote:
> Hi all,
>
> - how can I do a barplot with rotated axis labels? I've seen the example for
> just a plot in the FAQ, but I'll missing the coordinates to plot my text at
> the right position beneath the bars.
> Is there any (easy?) soluti
On Tue, 2005-06-28 at 17:23 -0400, Anna Oganyan wrote:
> Dear List,
> How can I convert a list with elements being character strings, like:
> "c(1,2,3,4)", “c(1,3,4,2) … to a list with elements as numerical
> vectors: c(1,2,3,4), c(1,3,4,2)…?
> Thanks!
> Anna
> l <- list("c(1,2,3,4)", "c(1,3,4,2
On Tue, 2005-06-28 at 13:03 -0400, ferdinand principia wrote:
> Hi,
>
> I need to calculate Kendall's tau for large data
> vectors (length > 100'000).
> Is somebody aware of a faster algorithm or package
> function than "cor(, method="kendall")"?
> There are ties in the data to be considered (Ke
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