On Apr 30, 2008, at 1:48 AM, kris wrote:
If I add a simple correlate feature to Query in 0.5, you can use
the
raw Table object to bypass the ORM meaning of Dataset and Base.
the query above is not quite complete but I can get an approximation
like this:
Is this functionality available
If I add a simple correlate feature to Query in 0.5, you can use the
raw Table object to bypass the ORM meaning of Dataset and Base.
the query above is not quite complete but I can get an approximation
like this:
Is this functionality available currently or am I waiting for
sqlalchemy 0.5?
If I
On Apr 18, 2008, at 10:42 PM, kris wrote:
select *
from nodes,
(select node2_id as id2
from assoc,
(select node2_id as id1
from assoc where relation = 'is-a'
and node1_id = 100)
as isa
where relation
On Apr 18, 2008, at 3:18 PM, kris wrote:
select item.id
from item,
(select dataset_me.something_id
from (select * from base, dataset
where base.id = dataset.id and
base.owner=me)
as dataset_me
where
On Apr 17, 2008, at 10:42 PM, kris wrote:
I am building a tree structure of D1 and D2 nodes..
I am progressively generating a query as before execution using
subqueries.
s = session.query(D1).filter (...)._values(D1.c.id).statement
...
q = session.query (D2).select_from (s).filter
The problem stems from a tree structure and creating self joins
on a very large base table.. I am trying to create datasets
of items and filter on the contents of datasets in single query
that it built up progressively.
base = Table ('base',
Column('id', Integer, primarykey=True)
On Apr 18, 2008, at 3:18 PM, kris wrote:
I think I want something like the following:
select item.id
from item,
(select dataset.something_id from base, dataset
where base.id = dataset.id and base.owner ='me'
tag.c.name=good and tag.c.parent_id == base.id
