=~ s/solar([^]*)\/solar/$1\n/g;
Let us know how you get on.
--
Matthew Bassett hewb...@gmail.com
Sorry about the top posting- am replying from my phone.
-Original Message-
From: LeeGroups
Sent: 12/07/2010 22:55:38
Subject: Re: [ubuntu-uk] [OT] Quick Perl question...
$solar_info =~ s
;
--
Matthew Bassett hewb...@gmail.com
Sorry about the top posting- am replying from my phone.
-Original Message-
From: Matt Wheeler
Sent: 12/07/2010 23:46:32
Subject: Re: [ubuntu-uk] [OT] Quick Perl question...
[some pruned text]
You could remove both the start and end tags with something like
New line characters in the substitution string, perhaps? Dot doesn't match
those unless you modify the line:
$solar_info =~ s/\/solar.*/,/s;
--
Kevin Safford
--
ubuntu-uk@lists.ubuntu.com
https://lists.ubuntu.com/mailman/listinfo/ubuntu-uk
https://wiki.ubuntu.com/UKTeam/
On 12 July 2010 21:12, LeeGroups mailgro...@varga.co.uk wrote:
$solar_info =~ s/\/solar.*/,/;
From my tinkerings, this should find the string /solar in the string
$solar_info, and then remove it and any number of following characters
(the .*) and then replace them with a ,.
Except that it
$solar_info =~ s/\/solar.*/,/;
From my tinkerings, this should find the string /solar in the string
$solar_info, and then remove it and any number of following characters
(the .*) and then replace them with a ,.
Except that it doesn't. It hacks out the /solar and replaces it with a
, but
So, why not do /solar(.*)\/solar/ ?
--
Jon TheNiceGuy Spriggs
On 12 Jul 2010 22:56, LeeGroups mailgro...@varga.co.uk wrote:
$solar_info =~ s/\/solar.*/,/;
From my tinkerings, this should find the string /solar...
What's the input string? The following code simply prints , for me
not
On 12 July 2010 22:55, LeeGroups mailgro...@varga.co.uk wrote:
This input solar8,27.31,28.68,28.81,0.00,0.00,0/solar
It need to be --
8,27.31,28.68,28.81,0.00,0.00,0
Another line chops off the solar.
The problem is that occasionally there is rubbish on the end of the
line, or even another
