Re: [algogeeks] Re: Amazon Question make confused !!!!!!!
You could also get a unique solution if the car has speed of 72 63 56 in downhill, plain and uphill respectively. I think the speed Vd, Vp, Vu was chosen so that 2Vp = Vd + Vu. But for unique solution, it ought to be 2/Vp = 1/Vd + 1/Vu. Under this condition, we can get the unique S=x+y+z: From x/Vd + y/Vp + z/Vu = T1 x/Vu + y/Vp + z/Vd = T2 We get (1/Vu+1/Vd)(x+z)+2/Vp*y = T1+T2 Apply 2/Vp = 1/Vd + 1/Vu, then 2/Vp(x+y+z)=T1+T2 S=x+y+z = Vp(T1+T2)/2 On 2010-9-15 9:31, Gene wrote: This isn't right. Dropping both y terms is the same as setting y to zero. The answer you get is correct, but there are many others as has been said. You could get a unique solution if the route were constrained to be monotonic (level and up or else level and down). On Sep 14, 4:28 pm, Minotaurausanike...@gmail.com wrote: Actually the solution is unique. The middle part with the Ys is the same and therefore can be omitted out. Now you are left with 2 equations and 2 unknowns. I used time in minutes and I have x = 1.28, z = 0.30476 units (y can be found out). I guess the trick was 1. to write the equations that Yan did and 2. to recognize that the plain part is the same and hence can be cancelled. On Sep 14, 3:31 am, Yan Wangwangyanadam1...@gmail.com wrote: actually, there are many solutions, just pick up one from them... On Tue, Sep 14, 2010 at 3:23 AM, Abhilasha jain mail2abhila...@gmail.com wrote: how can u solve 3 variables using 2 equations? On Tue, Sep 14, 2010 at 3:44 PM, Yan Wangwangyanadam1...@gmail.com wrote: x/72 + y/64 + z/56 = 4 x/56 + y/64 + z/72 = 4+2/3 find a solution to this ... On Tue, Sep 14, 2010 at 2:31 AM, bittushashank7andr...@gmail.com wrote: Amazon Interview Question for Software Engineer / Developers A car has speed of 72 64 56 in downhill, plain and uphill respectively . A guy travels in the car from Pt. A to pt. B in 4 Hrs and pt. B to pt. A in 4 Hrs and 40 min. what is the distance between A and B? Regards Shashank -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.- Hide quoted text - - Show quoted text - -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Excellent Compilation of Interview Questions
http://tinyurl.com/2wjnofr -Regards Amit Agarwal On Wed, Sep 15, 2010 at 10:41 AM, saurabh singh saurabh.n...@gmail.comwrote: haha...no one knows now what was the true source of that solutionlot of stuff on same kind of problem is lying on web on tons of web-sitesthe only change in sol i can observe mostly is change in variable names :) On Tue, Sep 14, 2010 at 10:55 PM, TurksHead Education turksheadeducat...@gmail.com wrote: Shame on you.. you have copied the articles as it is from other sites. For example, the article http://www.cracktheinterview.org/2010/08/converting-a-tree-to-a-doubly-linked-list/; is an exact copy-paste from rawkam.com. So much so that the images still point to images of rawkam.com On Sat, Sep 11, 2010 at 1:26 AM, Shashank Krishna sasan...@gmail.comwrote: Excellent Compilation of Interview Questions Visit http://www.cracktheinterview.org/ -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Thanks Regards, Saurabh -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Yahoo!!!! Puzzle
This looked like a variant of the socks problem :) On Tue, Sep 14, 2010 at 5:20 PM, Sathaiah Dontula don.sat...@gmail.comwrote: How_to_Ace_the_Brainteaser_Interview.pdf find this book, this has good number of puzzles. Thanks, Sathaiah Dontula On Tue, Sep 14, 2010 at 3:01 PM, vishal raja vishal.ge...@gmail.comwrote: take out that one A pill that's there in the jar. take the half of all the four pills, that's how u'll make sure that u've had 1 of 'A' and 1 of 'B' pill. On Tue, Sep 14, 2010 at 2:52 PM, bittu shashank7andr...@gmail.comwrote: You are on a strict medical regimen that requires you to take two types of pills each day. You must take exactly one A pill and exactly one B pill at the same time. The pills are very expensive, and you don't want to waste any. So you open the bottle of A pills, and tap one out into your hand. Then you open the bottle of B pills and do the same thing -- but you make a mistake, and two B pills come out into your hand with the A pill. But the pills are all exactly identical. There is no way to tell A pills apart from B pills. How can you satisfy your regimen and take exactly one of each pill at the same time, without wasting any pills? Write Algorithm to Solve dis Problem in constant time..isn't it..??? Regard's Shashank Mani Narayan Don't Be Evil U Can Earn While U learn Computer Science Engineering Birla Institute of Technology,Mesra Cell No. +91-9166674831 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Amazon Question make confused !!!!!!!
the solution seems to be simple. Just try to imagine what is happening You have a road with downhill and uphill. So if u travel 5 km uphill and then 5 km on plain and then 5 km on downhill then time taken by you will be equal to 15 km on the plain road(that is solely due avg of speed of downhill and uphill is = speed on plain road) so the from A to B we reach 40 min earlier due to there more downhill road. while from A to B it is uphill. So let us take x km as the road distance which is not plain. t1 = time to travel x on downhill = x/72 t2 = time to travel x on uphill = x/56 but as given 40min = 2/3 hr = x/56 - x/72 so, x= 168. so it will take 3 hrs to climb while travelling from B to A and plain road distance = 5/3 * 64 = 106.67 km dist = 168 + 106.67 On Wed, Sep 15, 2010 at 8:21 AM, Terence technic@gmail.com wrote: You could also get a unique solution if the car has speed of 72 63 56 in downhill, plain and uphill respectively. I think the speed Vd, Vp, Vu was chosen so that 2Vp = Vd + Vu. But for unique solution, it ought to be 2/Vp = 1/Vd + 1/Vu. Under this condition, we can get the unique S=x+y+z: From x/Vd + y/Vp + z/Vu = T1 x/Vu + y/Vp + z/Vd = T2 We get (1/Vu+1/Vd)(x+z)+2/Vp*y = T1+T2 Apply 2/Vp = 1/Vd + 1/Vu, then 2/Vp(x+y+z)=T1+T2 S=x+y+z = Vp(T1+T2)/2 On 2010-9-15 9:31, Gene wrote: This isn't right. Dropping both y terms is the same as setting y to zero. The answer you get is correct, but there are many others as has been said. You could get a unique solution if the route were constrained to be monotonic (level and up or else level and down). On Sep 14, 4:28 pm, Minotaurausanike...@gmail.com wrote: Actually the solution is unique. The middle part with the Ys is the same and therefore can be omitted out. Now you are left with 2 equations and 2 unknowns. I used time in minutes and I have x = 1.28, z = 0.30476 units (y can be found out). I guess the trick was 1. to write the equations that Yan did and 2. to recognize that the plain part is the same and hence can be cancelled. On Sep 14, 3:31 am, Yan Wangwangyanadam1...@gmail.com wrote: actually, there are many solutions, just pick up one from them... On Tue, Sep 14, 2010 at 3:23 AM, Abhilasha jain mail2abhila...@gmail.com wrote: how can u solve 3 variables using 2 equations? On Tue, Sep 14, 2010 at 3:44 PM, Yan Wangwangyanadam1...@gmail.com wrote: x/72 + y/64 + z/56 = 4 x/56 + y/64 + z/72 = 4+2/3 find a solution to this ... On Tue, Sep 14, 2010 at 2:31 AM, bittushashank7andr...@gmail.com wrote: Amazon Interview Question for Software Engineer / Developers A car has speed of 72 64 56 in downhill, plain and uphill respectively . A guy travels in the car from Pt. A to pt. B in 4 Hrs and pt. B to pt. A in 4 Hrs and 40 min. what is the distance between A and B? Regards Shashank -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.- Hide quoted text - - Show quoted text - -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards, Rahul Patil -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Amazon Question
you dont have the structure of the node
typedef struct member node
{
int data;
struct member * next;
}ll;
On Tue, Sep 14, 2010 at 5:57 PM, soundar soundha...@gmail.com wrote:
From first linked list set flag value in each traversal of
node..then start from second linked list suppose if flag value is
already set that is the intersection point
correct me if i am wrong
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Re: [algogeeks] Re: Amazon Question make confused !!!!!!!
So if u travel 5 km uphill and then 5 km on plain and then 5 km on downhill then time taken by you will be equal to 15 km on the plain road This is not the truth. 5/72 + 5/64 + 5/56 - 15/64 = 5/72+5/56-10/64 = 10/63-10/64 0 (that is solely due avg of speed of downhill and uphill is = speed on plain road) This only leads to: if u travel 5 hrs uphill and then 5 hrs on plain and then 5 hrs on downhill then distance traveled by you will be equal to travel 15 hrs on the plain road. On 2010-9-15 15:07, rahul patil wrote: the solution seems to be simple. Just try to imagine what is happening You have a road with downhill and uphill. So if u travel 5 km uphill and then 5 km on plain and then 5 km on downhill then time taken by you will be equal to 15 km on the plain road(that is solely due avg of speed of downhill and uphill is = speed on plain road) so the from A to B we reach 40 min earlier due to there more downhill road. while from A to B it is uphill. So let us take x km as the road distance which is not plain. t1 = time to travel x on downhill = x/72 t2 = time to travel x on uphill = x/56 but as given 40min = 2/3 hr = x/56 - x/72 so, x= 168. so it will take 3 hrs to climb while travelling from B to A and plain road distance = 5/3 * 64 = 106.67 km dist = 168 + 106.67 On Wed, Sep 15, 2010 at 8:21 AM, Terence technic@gmail.com mailto:technic@gmail.com wrote: You could also get a unique solution if the car has speed of 72 63 56 in downhill, plain and uphill respectively. I think the speed Vd, Vp, Vu was chosen so that 2Vp = Vd + Vu. But for unique solution, it ought to be 2/Vp = 1/Vd + 1/Vu. Under this condition, we can get the unique S=x+y+z: From x/Vd + y/Vp + z/Vu = T1 x/Vu + y/Vp + z/Vd = T2 We get (1/Vu+1/Vd)(x+z)+2/Vp*y = T1+T2 Apply 2/Vp = 1/Vd + 1/Vu, then 2/Vp(x+y+z)=T1+T2 S=x+y+z = Vp(T1+T2)/2 On 2010-9-15 9:31, Gene wrote: This isn't right. Dropping both y terms is the same as setting y to zero. The answer you get is correct, but there are many others as has been said. You could get a unique solution if the route were constrained to be monotonic (level and up or else level and down). On Sep 14, 4:28 pm, Minotaurausanike...@gmail.com mailto:anike...@gmail.com wrote: Actually the solution is unique. The middle part with the Ys is the same and therefore can be omitted out. Now you are left with 2 equations and 2 unknowns. I used time in minutes and I have x = 1.28, z = 0.30476 units (y can be found out). I guess the trick was 1. to write the equations that Yan did and 2. to recognize that the plain part is the same and hence can be cancelled. On Sep 14, 3:31 am, Yan Wangwangyanadam1...@gmail.com mailto:wangyanadam1...@gmail.com wrote: actually, there are many solutions, just pick up one from them... On Tue, Sep 14, 2010 at 3:23 AM, Abhilasha jain mail2abhila...@gmail.com mailto:mail2abhila...@gmail.com wrote: how can u solve 3 variables using 2 equations? On Tue, Sep 14, 2010 at 3:44 PM, Yan Wangwangyanadam1...@gmail.com mailto:wangyanadam1...@gmail.com wrote: x/72 + y/64 + z/56 = 4 x/56 + y/64 + z/72 = 4+2/3 find a solution to this ... On Tue, Sep 14, 2010 at 2:31 AM, bittushashank7andr...@gmail.com mailto:shashank7andr...@gmail.com wrote: Amazon Interview Question for Software Engineer / Developers A car has speed of 72 64 56 in downhill, plain and uphill respectively . A guy travels in the car from Pt. A to pt. B in 4 Hrs and pt. B to pt. A in 4 Hrs and 40 min. what is the distance between A and B? Regards Shashank -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com mailto:algogeeks@googlegroups.com. To unsubscribe from this group, send email to
[algogeeks] Yahoo Question
You are given k sorted lists with total n inputs in all the lists devise a algorithm to merge them into one single sorted list in O(n logk) Regard's Shashank Mani Narayan Don't Be Evil U Can Earn While U learn Computer Science Engineering Birla Institute of Technology,Mesra Cell No. +91-9166674831 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Yahoo Question
1. Take single element from each list . Put it in array maintaining min heap property , 2. Copy the lowest element ( O(1) ) from the heap to the single sorted list thand delete the element from heap. 3. Insert a new element into the heap ( O(logk) ) from list belonging to the deleted element . 4. repeat 2 and 3 till all list are empty. Regards Rahul Singal 3rd yr , Computer Science Department Birla Institute of technology and Science , Pilani -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Amazon Interview
A file is given with many 0s stored in continuous way , store it in another file such that when you store try saving the space by using minimum amount of space. When you want to create the original file , you should be able to do so with the new file created -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Amazon intern Question
bump!! On Sep 5, 8:42 pm, Arun yourarunb...@gmail.com wrote: Hi friends, Sorry that I am so late to reply. Thanks much responses have come regarding finding the similarity between words. Now what about the searching algorithm from the 'millions of words'. I think they expected an answer like hashing or more multi-level hashing. But I cant figureout an idea regarding the hash function and also about multi-level hashing, Regards -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Amazon Interview
-- One can store the binary equivalent of the number of zeros in each line... and carry on from there -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Amazon Question
Propose a data structure that would store numbers, without any knowledge about them, and allow to perform the operations: insert, get median, as efficiently as possible same as before, only this time the numbers are from a group V, which is |V|n -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Amazon Question
The following algorithm traversals both lists twice to find the
intersection point, without modification to the original nodes.
The only assumptions:
1) Head pointer of two list: La, Lb
2) .next point to the next node.
3) .next of the tail node is NULL
intersect(La,Lb)
{
// Find the length difference of two lists
for (pA = La, pB = Lb; pA != NULL pB != NULL; pA = pA-next, pB =
pB-next);
// Discard the beginning of the longer list, to get equal length as
the shorter one.
if(pA != NULL) {
for(pC = pA, pA = La; pC != NULL; pA = pA-next, pC = pC-next);
pB = Lb;
} else if(pB != NULL) {
for(pC = pB, pB = Lb; pC != NULL; pB = pB-next, pC = pC-next);
pA = La;
}
// Traversal both list, until we get a common node, return this node.
// If no such intersection, NULL is returned. (pA,pB will get NULL at
the same time)
for( ; pA != pB; pA = pA-next, pB = pB-next);
return pA;
}
On 2010-9-15 15:50, sharad kumar wrote:
you dont have the structure of the node
typedef struct member node
{
int data;
struct member * next;
}ll;
On Tue, Sep 14, 2010 at 5:57 PM, soundar soundha...@gmail.com
mailto:soundha...@gmail.com wrote:
From first linked list set flag value in each traversal of
node..then start from second linked list suppose if flag value is
already set that is the intersection point
correct me if i am wrong
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Re: [algogeeks] Yahoo Question
Use k way merging On Wed, Sep 15, 2010 at 3:30 PM, bittu shashank7andr...@gmail.com wrote: You are given k sorted lists with total n inputs in all the lists devise a algorithm to merge them into one single sorted list in O(n logk) Regard's Shashank Mani Narayan Don't Be Evil U Can Earn While U learn Computer Science Engineering Birla Institute of Technology,Mesra Cell No. +91-9166674831 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Yahoo Question
use heap.. k node min / max heap. On Wed, Sep 15, 2010 at 3:30 PM, bittu shashank7andr...@gmail.com wrote: You are given k sorted lists with total n inputs in all the lists devise a algorithm to merge them into one single sorted list in O(n logk) Regard's Shashank Mani Narayan Don't Be Evil U Can Earn While U learn Computer Science Engineering Birla Institute of Technology,Mesra Cell No. +91-9166674831 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- With Regards Ankur Aggarwal +91-7838289304 Software Engineer Slideshare Delhi INDIA. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Excellent Compilation of Interview Questions
@TurksHead gimme a break dude!..as if all the content u host is legit n copyrighted Regards, Sasank Krishna http://krishna-shashank.co.nr/ http://krishna-shashank.co.nr/http://www.cracktheinterview.org/ On Tue, Sep 14, 2010 at 10:55 PM, TurksHead Education turksheadeducat...@gmail.com wrote: Shame on you.. you have copied the articles as it is from other sites. For example, the article http://www.cracktheinterview.org/2010/08/converting-a-tree-to-a-doubly-linked-list/; is an exact copy-paste from rawkam.com. So much so that the images still point to images of rawkam.com On Sat, Sep 11, 2010 at 1:26 AM, Shashank Krishna sasan...@gmail.comwrote: Excellent Compilation of Interview Questions Visit http://www.cracktheinterview.org/ -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.comalgogeeks%2bunsubscr...@googlegroups.com . For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Amazon Question make confused !!!!!!!
No. Two linear equations in three unknowns will always yield many solutions (or zero solutions). These are essentially plane equations. Two planes intersect in a line (unless they are parallel). You might get a de facto unique solution for some values of Vu, Vd, Vu, T1, T2 from the constraints x,y,z = 0. It would have to lie on an axis. For example, you can aways pick z and find x and y. Using your notation, x/Vd + y/Vp + z/Vu = T1 x/Vu + y/Vp + z/Vd = T2 Subtract to get: x(1/Vd - 1/Vu) + z(1/Vu - 1/Vd) = T1 - T2 then x = [ (T1 - T2) - z(1/Vu - 1/Vd) ] / (1/Vd - 1/Vu) So now you can pick any z and get x. Once you have both of these, plug them in here: y = Vp (T1 - x/Vd - z/Vu) As long as x,y,z = 0, you are in business. On Sep 14, 10:51 pm, Terence technic@gmail.com wrote: You could also get a unique solution if the car has speed of 72 63 56 in downhill, plain and uphill respectively. I think the speed Vd, Vp, Vu was chosen so that 2Vp = Vd + Vu. But for unique solution, it ought to be 2/Vp = 1/Vd + 1/Vu. Under this condition, we can get the unique S=x+y+z: From x/Vd + y/Vp + z/Vu = T1 x/Vu + y/Vp + z/Vd = T2 We get (1/Vu+1/Vd)(x+z)+2/Vp*y = T1+T2 Apply 2/Vp = 1/Vd + 1/Vu, then 2/Vp(x+y+z)=T1+T2 S=x+y+z = Vp(T1+T2)/2 On 2010-9-15 9:31, Gene wrote: This isn't right. Dropping both y terms is the same as setting y to zero. The answer you get is correct, but there are many others as has been said. You could get a unique solution if the route were constrained to be monotonic (level and up or else level and down). On Sep 14, 4:28 pm, Minotaurausanike...@gmail.com wrote: Actually the solution is unique. The middle part with the Ys is the same and therefore can be omitted out. Now you are left with 2 equations and 2 unknowns. I used time in minutes and I have x = 1.28, z = 0.30476 units (y can be found out). I guess the trick was 1. to write the equations that Yan did and 2. to recognize that the plain part is the same and hence can be cancelled. On Sep 14, 3:31 am, Yan Wangwangyanadam1...@gmail.com wrote: actually, there are many solutions, just pick up one from them... On Tue, Sep 14, 2010 at 3:23 AM, Abhilasha jain mail2abhila...@gmail.com wrote: how can u solve 3 variables using 2 equations? On Tue, Sep 14, 2010 at 3:44 PM, Yan Wangwangyanadam1...@gmail.com wrote: x/72 + y/64 + z/56 = 4 x/56 + y/64 + z/72 = 4+2/3 find a solution to this ... On Tue, Sep 14, 2010 at 2:31 AM, bittushashank7andr...@gmail.com wrote: Amazon Interview Question for Software Engineer / Developers A car has speed of 72 64 56 in downhill, plain and uphill respectively . A guy travels in the car from Pt. A to pt. B in 4 Hrs and pt. B to pt. A in 4 Hrs and 40 min. what is the distance between A and B? Regards Shashank -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.-Hide quoted text - - Show quoted text -- Hide quoted text - - Show quoted text - -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] num to words
display a num in words ex: 38 = thirty eight; 4567 = four thousand five hundred sixty seven. give me algo Thanks Raj -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algoge...@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Recursion!!!!!!!!!!! Always Stuck
Recursion:
http://www.rawkam.com/?p=283
http://www.rawkam.com/?p=283Tower Of Hanoi:
http://www.rawkam.com/?p=917
http://www.rawkam.com/?p=917 http://www.rawkam.com/?p=941
http://www.rawkam.com/?p=941
On Fri, Sep 10, 2010 at 1:11 AM, albert theboss alberttheb...@gmail.comwrote:
Its easy only
tower of hanoi consist of three pegs peg A,peg B,peg C.
which is used as BEG,AUX,END
Let n be 5 for example...
wat u r going to do is
step 1 : move the top n-1 (4) disks from BEG to AUX...
in this case END will be used as auxiliary.
step 2: move the n th disk from BEG to END .
use AUX as auxiliary in this case
step 3: move the n-1(4) disks from AUX to END that is moved in step 1
use BEG as auxiliary in this step
Actual code is
void tower(int n,char beg,char aux,char end)
{
if(n0)
{
tower(n-1,beg,end,aux); // move n-1 disks from beg to
aux
printf(%c-%c,beg,aux,end);//equivalent to
tower(1,beg,aux,end)move 1 disk from beg to end
tower(n-1,aux,beg,end) // move disks from aux to end
}
}
again that n-1 disks are moved to end which is called recursively.
Still u have doubt???
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[algogeeks] Re: Google Interview Question
Some people have sent email asking what the stack looks like as the
program runs. It's pretty silly to worry about this. If you really
want to know, it's easy to modify the program to print a stack
trace.
Here you go:
#include stdio.h
// Buffer for strings of ().
char buf[1000];
typedef struct stack_record_s {
struct stack_record_s *prev;
int need, open, tail;
} STACK_RECORD;
void dump_state(STACK_RECORD *sr)
{
int i = 0;
printf(\nstate: buf=%.*s\n, sr-tail, buf);
while (sr) {
printf(%d: need=%d, open=%d, tail=%d\n,
i++, sr-need, sr-open, sr-tail);
sr = sr-prev;
}
}
// Continue the printing of bracket strings.
// need is the number of ('s still needed in our string.
// open is tne number of ('s already used _without_ a matching ).
// tail is the buffer location to place the next ) or (.
void cont(STACK_RECORD *sr)
{
// Dump the entire program state as we enter the continuation.
dump_state(sr);
// If nothing needed or open, we're done. Print.
if (sr-need == 0 sr-open == 0) {
printf(output: %s\n, buf);
return;
}
// If still a need for (, add a ( and continue.
if (sr-need 0) {
STACK_RECORD new_sr[1] = {{ sr, sr-need - 1, sr-open + 1, sr-
tail + 1 }};
buf[sr-tail] = '(';
cont(new_sr);
}
// If still an open (, add a ) and continue.
if (sr-open 0) {
STACK_RECORD new_sr[1] = {{ sr, sr-need, sr-open - 1, sr-tail +
1 }};
buf[sr-tail] = ')';
cont(new_sr);
}
}
void Brackets(int n)
{
STACK_RECORD sr[1] = {{ NULL, n, 0, 0 }};
cont(sr);
}
int main(void)
{
Brackets(3);
return 0;
}
When you run it, you get this output:
state: buf=
0: need=3, open=0, tail=0
state: buf=(
0: need=2, open=1, tail=1
1: need=3, open=0, tail=0
state: buf=((
0: need=1, open=2, tail=2
1: need=2, open=1, tail=1
2: need=3, open=0, tail=0
state: buf=(((
0: need=0, open=3, tail=3
1: need=1, open=2, tail=2
2: need=2, open=1, tail=1
3: need=3, open=0, tail=0
state: buf=((()
0: need=0, open=2, tail=4
1: need=0, open=3, tail=3
2: need=1, open=2, tail=2
3: need=2, open=1, tail=1
4: need=3, open=0, tail=0
state: buf=((())
0: need=0, open=1, tail=5
1: need=0, open=2, tail=4
2: need=0, open=3, tail=3
3: need=1, open=2, tail=2
4: need=2, open=1, tail=1
5: need=3, open=0, tail=0
state: buf=((()))
0: need=0, open=0, tail=6
1: need=0, open=1, tail=5
2: need=0, open=2, tail=4
3: need=0, open=3, tail=3
4: need=1, open=2, tail=2
5: need=2, open=1, tail=1
6: need=3, open=0, tail=0
output: ((()))
state: buf=(()
0: need=1, open=1, tail=3
1: need=1, open=2, tail=2
2: need=2, open=1, tail=1
3: need=3, open=0, tail=0
state: buf=(()(
0: need=0, open=2, tail=4
1: need=1, open=1, tail=3
2: need=1, open=2, tail=2
3: need=2, open=1, tail=1
4: need=3, open=0, tail=0
state: buf=(()()
0: need=0, open=1, tail=5
1: need=0, open=2, tail=4
2: need=1, open=1, tail=3
3: need=1, open=2, tail=2
4: need=2, open=1, tail=1
5: need=3, open=0, tail=0
state: buf=(()())
0: need=0, open=0, tail=6
1: need=0, open=1, tail=5
2: need=0, open=2, tail=4
3: need=1, open=1, tail=3
4: need=1, open=2, tail=2
5: need=2, open=1, tail=1
6: need=3, open=0, tail=0
output: (()())
state: buf=(())
0: need=1, open=0, tail=4
1: need=1, open=1, tail=3
2: need=1, open=2, tail=2
3: need=2, open=1, tail=1
4: need=3, open=0, tail=0
state: buf=(())(
0: need=0, open=1, tail=5
1: need=1, open=0, tail=4
2: need=1, open=1, tail=3
3: need=1, open=2, tail=2
4: need=2, open=1, tail=1
5: need=3, open=0, tail=0
state: buf=(())()
0: need=0, open=0, tail=6
1: need=0, open=1, tail=5
2: need=1, open=0, tail=4
3: need=1, open=1, tail=3
4: need=1, open=2, tail=2
5: need=2, open=1, tail=1
6: need=3, open=0, tail=0
output: (())()
state: buf=()
0: need=2, open=0, tail=2
1: need=2, open=1, tail=1
2: need=3, open=0, tail=0
state: buf=()(
0: need=1, open=1, tail=3
1: need=2, open=0, tail=2
2: need=2, open=1, tail=1
3: need=3, open=0, tail=0
state: buf=()((
0: need=0, open=2, tail=4
1: need=1, open=1, tail=3
2: need=2, open=0, tail=2
3: need=2, open=1, tail=1
4: need=3, open=0, tail=0
state: buf=()(()
0: need=0, open=1, tail=5
1: need=0, open=2, tail=4
2: need=1, open=1, tail=3
3: need=2, open=0, tail=2
4: need=2, open=1, tail=1
5: need=3, open=0, tail=0
state: buf=()(())
0: need=0, open=0, tail=6
1: need=0, open=1, tail=5
2: need=0, open=2, tail=4
3: need=1, open=1, tail=3
4: need=2, open=0, tail=2
5: need=2, open=1, tail=1
6: need=3, open=0, tail=0
output: ()(())
state: buf=()()
0: need=1, open=0, tail=4
1: need=1, open=1, tail=3
2: need=2, open=0, tail=2
3: need=2, open=1, tail=1
4: need=3, open=0, tail=0
state: buf=()()(
0: need=0, open=1, tail=5
1: need=1, open=0, tail=4
2: need=1, open=1, tail=3
3: need=2, open=0, tail=2
4: need=2, open=1, tail=1
5: need=3, open=0, tail=0
state: buf=()()()
0: need=0, open=0, tail=6
1: need=0, open=1, tail=5
2: need=1, open=0, tail=4
3: need=1, open=1, tail=3
4: need=2, open=0, tail=2
5: need=2, open=1, tail=1
6: need=3, open=0, tail=0
output: ()()()
On Sep 14,
