Re: [algogeeks] Max sum circular array

2012-07-10 Thread adarsh kumar
This is similar to maximum sum contiguous subarray problem. Consider the
circular array as a normal array, except that once you reach the end of the
array, if the sum found upto that element(using Kandane's algo, refer Wiki)
is negative, then try including elements from the beginning of the
array(circular fashion), until you find a sum that is greater. Keeping
track of the sum is obvious necessity. Finally return the sum.



On Tue, Jul 10, 2012 at 10:58 AM, deepikaanand swinyanand...@gmail.comwrote:

 What is best approach to find max sum in a circular array...

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[algogeeks] [India specific] KBookSearch - A book comparison engine.

2012-07-10 Thread mehnaaz mohiuddin
Hi Friends,

I know this is a little bit 'off-topic', but I think it would serve the
overall purpose to educate ourselves well. I will still apologize if this
seems like spam to you.

We'd like to present to you www.kbooksearch.com, a site that compares the
prices of a book across the different online booksellers in India. We
believe it is neat, elegant and quick and would serve you well in finding
out which site is offering you the best price for the book and expected
delivery times, there is also auto-suggest to help you remember the book in
case you just had the name on the tip of your ton??? (something of that
sorts).

We compare the prices from 11 bookstores to give you the best deal and do
so quickly! We would greatly appreciate if you use it, suggest feedback
(both bouquets and brickbats) and spread the word around!

As an illustration, the prices for the Complete Works of William
Shakespearehttp://goo.gl/dKxUI vary
quite a bit (almost by 400%) on different online booksellers.

Keep tuned for our updates:
Facebook - https://www.facebook.com/kbooksearch
Twitter - https://twitter.com/kbooksearch
G+ - https://plus.google.com/b/107572714465768003807/107572714465768003807

Regards

KBookSearch Team

-- 
Mehnaaz Mohiuddin

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Re: [algogeeks] Adobe interview question

2012-07-10 Thread Bhaskar Kushwaha
@himanshu making constructor protected is okay because even for abstract
base class u cannot create objects in derived class

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Re: [algogeeks] C o/p

2012-07-10 Thread rahul sharma
yeahu r ryt

On Tue, Jul 10, 2012 at 10:01 AM, Firoz Khursheed
firozkhursh...@gmail.comwrote:

 Well, when i compiled the code the output ie i is alway i=2,

 http://ideone.com/AFljo
 http://ideone.com/87waz

 This expression  is ambiguous, and compiler dependent.
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Re: [algogeeks] Adobe interview question

2012-07-10 Thread Bhaskar Kushwaha
If the constructor is made protected u cannot make object of that class
anywhere

On Tue, Jul 10, 2012 at 3:10 PM, Bhaskar Kushwaha 
bhaskar.kushwaha2...@gmail.com wrote:

 @himanshu making constructor protected is okay because even for abstract
 base class u cannot create objects in derived class




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regards,
Bhaskar Kushwaha
Student
Final year
CSE
M.N.N.I.T.  Allahabad

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Re: [algogeeks] Re: Directi question

2012-07-10 Thread algo bard
int no_of_steps[arr_length] = {MAX};

if ( (arr_length==0) || (arr[0] == 0) )   //if there are no elements or
the very first element is 0 - we can't jump anywhere
return MAX;

no_of_steps[0] = 0; //no jumps required to jump from element 0 to itself.

for (int i=1; iarr_length; i++)
{
   no_of_steps [i] = MAX;

   for(int j=0; ji; j++) //from 0th element till the element we need
to jump to.
   {
  if( arr[j] = (i - j) )//if it is possible for us to jump from
jth element to ith element.
  {
 if( no_of_steps[i]  no_of_steps[j] + 1)// if no. of steps to
reach the ith element recorded till now is greater than the no of
 {   //
steps reqd to reach jth element + 1, then replace.

 no_of_steps[i]  no_of_steps[j] + 1;
 }
  }
}

}

coutno_of_steps[n-1];

On Mon, Jul 9, 2012 at 8:32 PM, Mr.B sravanreddy...@gmail.com wrote:

 There is a greedy solution discussion about this approach. I don't have a
 formal proof for this.
 Any counter example will be helpful.

 at every place 'k' .. do the following.

 -- find max ( a[k+i]+i )  where 1 = i = a[i]

 for the given example:
 A = {4 0 0 3 6 5 4 7 1 0 1 2}

 initially a 4, the loop will be.
   0+1,0+2,3+3,6+4 -- 10 is max. jump to 6.
 now at 6. (since, you can't reach end.)
 5+1, 4+2, 7+3, 1+4, 0+5, 1 + 6, == 10 is max. jump to 7.
 make another step. (but you can reach the end.) so jump to last.

 this is greedy approach.. and a linear time soultion.


 On Monday, 9 July 2012 09:32:08 UTC-4, Akshat wrote:

 Given an array A and the elements stored in an array denotes how much
 jump an element can make from that array position. For example there is an
 array A = {4 0 0 3 6 5 4 7 1 0 1 2}

 Now Ist element which is 4 can make a jump to element 0, 0, 3 and 6. You
 are stuck if you end up at 0.
 You have to output the minimum number of jumps that can be made from
 starting position to end position of an array.

 --


 Akshat Sapra
 Under Graduation(B.Tech)
 IIIT-Allahabad(Amethi Campus)
 *--*
 sapraaks...@gmail.com
 akshatsapr...@gmail.com
 rit20009008@ rit20009...@gmail.comiiita.ac.in

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Re: [algogeeks] Directi question

2012-07-10 Thread Sumit Agarwal
This can be solved using  Dynamic Programming approach.

Let MinJump(n)  = Minimum number of Jumps required to reach the Nth index
of array A.

then, for 1 i  N,  MinJump(i) = Min{1 + MinJump(j)} for all j such that
(0= j  i) and (j + A[j] = i).

We can prepare an auxiliary array say MinJump[1..N] where for MinJump[i]
contains the minimum jump required to reach ith
index of array A and use MinJump[1...i] and A[1i] to calculate the
value of A[i+1] and so on..

HTH,
Sumit


On Mon, Jul 9, 2012 at 7:02 PM, Akshat Sapra sapraaks...@gmail.com wrote:

 Given an array A and the elements stored in an array denotes how much jump
 an element can make from that array position. For example there is an array
 A = {4 0 0 3 6 5 4 7 1 0 1 2}

 Now Ist element which is 4 can make a jump to element 0, 0, 3 and 6. You
 are stuck if you end up at 0.
 You have to output the minimum number of jumps that can be made from
 starting position to end position of an array.

 --


 Akshat Sapra
 Under Graduation(B.Tech)
 IIIT-Allahabad(Amethi Campus)
 *--*
 sapraaks...@gmail.com
 akshatsapr...@gmail.com
 rit20009008@ rit20009...@gmail.comiiita.ac.in

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Re: [algogeeks] Re: candies - interviewstreet -- how to go about solving this problem

2012-07-10 Thread Sumit Agarwal
@g4... : Is the sequence in which children are arranged is fixed or the
teacher can change the sequence to minimize the candies ?

On Mon, Jul 9, 2012 at 3:58 PM, Anshu Mishra anshumishra6...@gmail.comwrote:

 @sanjay it's not like that

 e.g : (3 5 6 7 8 4) 7
 1 2 3 4 5 1  2
 Yes we have to increase just by one, but while decreasing choose the
 lowest possible such that each trivial component, if it is in decreasing
 phase, should end with 1.

 On Mon, Jul 9, 2012 at 12:53 PM, sanjay pandey 
 sanjaypandey...@gmail.comwrote:

 does ur sol seems lyk incerasing 1 if next number is greater that prev n
 decreasing 1 if less..???

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Re: [algogeeks] Re: Given only a pointer to a node to be deleted in a singly linked list how you handle deleting last node

2012-07-10 Thread vaibhav shukla
For such case .. circular linked list will come handy to be able to delete
last node.

On Tue, Jul 10, 2012 at 8:28 AM, deepikaanand swinyanand...@gmail.comwrote:

 No there is no way to delete the last node in such a situation
 though u can replace the info part of such a last node with
 '#'though it wont delete the node but now u know that u can
 traverse the list while node-info != '#'

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best wishes!!
 Vaibhav

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Re: [algogeeks] Re: Directi question

2012-07-10 Thread algo bard
^  cout no_of_steps[arr_length -1];

On Mon, Jul 9, 2012 at 8:44 PM, algo bard algo.b...@gmail.com wrote:

 int no_of_steps[arr_length] = {MAX};

 if ( (arr_length==0) || (arr[0] == 0) )   //if there are no elements
 or the very first element is 0 - we can't jump anywhere
 return MAX;

 no_of_steps[0] = 0; //no jumps required to jump from element 0 to itself.

 for (int i=1; iarr_length; i++)
 {
no_of_steps [i] = MAX;

for(int j=0; ji; j++) //from 0th element till the element we need
 to jump to.
{
   if( arr[j] = (i - j) )//if it is possible for us to jump from
 jth element to ith element.
   {
  if( no_of_steps[i]  no_of_steps[j] + 1)// if no. of steps to
 reach the ith element recorded till now is greater than the no of
  {   //
 steps reqd to reach jth element + 1, then replace.

  no_of_steps[i]  no_of_steps[j] + 1;
  }
   }
 }

 }

 coutno_of_steps[n-1];


 On Mon, Jul 9, 2012 at 8:32 PM, Mr.B sravanreddy...@gmail.com wrote:

 There is a greedy solution discussion about this approach. I don't have a
 formal proof for this.
 Any counter example will be helpful.

 at every place 'k' .. do the following.

 -- find max ( a[k+i]+i )  where 1 = i = a[i]

 for the given example:
 A = {4 0 0 3 6 5 4 7 1 0 1 2}

 initially a 4, the loop will be.
   0+1,0+2,3+3,6+4 -- 10 is max. jump to 6.
 now at 6. (since, you can't reach end.)
 5+1, 4+2, 7+3, 1+4, 0+5, 1 + 6, == 10 is max. jump to 7.
 make another step. (but you can reach the end.) so jump to last.

 this is greedy approach.. and a linear time soultion.


 On Monday, 9 July 2012 09:32:08 UTC-4, Akshat wrote:

 Given an array A and the elements stored in an array denotes how much
 jump an element can make from that array position. For example there is an
 array A = {4 0 0 3 6 5 4 7 1 0 1 2}

 Now Ist element which is 4 can make a jump to element 0, 0, 3 and 6. You
 are stuck if you end up at 0.
 You have to output the minimum number of jumps that can be made from
 starting position to end position of an array.

 --


 Akshat Sapra
 Under Graduation(B.Tech)
 IIIT-Allahabad(Amethi Campus)
 *--*
 sapraaks...@gmail.com
 akshatsapr...@gmail.com
 rit20009008@ rit20009...@gmail.comiiita.ac.in

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Re: [algogeeks] seperate diff types of coins

2012-07-10 Thread Navin Kumar
Minimum no. weighings:

Divide 8 coins in group of 3, 3 and 2.

For minimum weighsing group1 's total weight is x units(say) --FIrst
weighing
Groups 2nd total weights is y units  Second weighing.
Lastly one more weighing among a unit and b unit coins.---3 rd weighing


So minimum 3 weighing is required.



On Tue, Jul 10, 2012 at 11:03 AM, payal gupta gpt.pa...@gmail.com wrote:

 You have 8 coins. 3 of them weigh x units, 3 y units, 1 a units and 1 b
 units. They are all mixed and look identical. What are the minimum no of
 weighings reqd to seperate the for types of coins???

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Re: [algogeeks] Re: Algorithm page

2012-07-10 Thread Wladimir Tavares
http://translate.google.com.br/translate?sl=pttl=enjs=nprev=_thl=pt-BRie=UTF-8layout=2eotf=1u=http%3A%2F%2Fmarathoncode.blogspot.com.br%2F2012%2F07%2Fquebra-cabecas-indutivos.html


http://translate.googleusercontent.com/translate_c?hl=pt-BRie=UTF8prev=_trurl=translate.google.com.brsl=pttl=entwu=1u=http://marathoncode.blogspot.com.br/2012/07/pilha-umapilha-e-uma-das-varias.htmlusg=ALkJrhj059Lg0n3irAidNipyRDh7UpI4nA


http://translate.googleusercontent.com/translate_c?hl=pt-BRie=UTF8prev=_trurl=translate.google.com.brsl=pttl=entwu=1u=http://marathoncode.blogspot.com.br/2012/07/3n1.htmlusg=ALkJrhglAJwrFEt5u5P2V8l8P6Ez3FHXBQ


Wladimir Araujo Tavares
*Federal University of CearĂ¡ http://lia.ufc.br/%7Ewladimir/
Homepage http://lia.ufc.br/%7Ewladimir/ |
Maratonahttps://sites.google.com/site/quixadamaratona/|
*

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[algogeeks] Re: Secure computation of Intersection of two sets

2012-07-10 Thread Mr.B
But again.. this can be reconstructed at the sever. taking first number and 
adding the differences.

On Monday, 9 July 2012 23:54:23 UTC-4, enchantress wrote:

 Give the first first number and set of cosecutive diffrence. 

 On Sunday, 8 July 2012 10:55:55 UTC+5:30, Sairam wrote:

 How do you find the intersection of two sets in a secured way? 
 Which means imagine a situation where there is a client  who has got a 
 set S1={1,2,3}, and there is a  server who has got a set S2[{2,3}. Client 
 wants to find the count of intersection which is |S1 intersection S2| = 2. 
 But, it doesn't want to give the set S1 directly to the server? How should 
 the client give the set S1, such that server computes the intersection of 
 S1 and S2 and gives the count to client.



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Re: [algogeeks] seperate diff types of coins

2012-07-10 Thread payal gupta
@navin...Sorry didnt get you how come u were able to segregate all the
coins by the proposed method??


On 7/10/12, Navin Kumar algorithm.i...@gmail.com wrote:
 Minimum no. weighings:

 Divide 8 coins in group of 3, 3 and 2.

 For minimum weighsing group1 's total weight is x units(say) --FIrst
 weighing
 Groups 2nd total weights is y units  Second weighing.
 Lastly one more weighing among a unit and b unit coins.---3 rd weighing


 So minimum 3 weighing is required.



 On Tue, Jul 10, 2012 at 11:03 AM, payal gupta gpt.pa...@gmail.com wrote:

 You have 8 coins. 3 of them weigh x units, 3 y units, 1 a units and 1 b
 units. They are all mixed and look identical. What are the minimum no of
 weighings reqd to seperate the for types of coins???

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Re: [algogeeks] seperate diff types of coins

2012-07-10 Thread Navin Kumar
Let we have 8 coins named (for simplicity) x1, x2, x3, y1, y2, y3, a, b

According to your question 3 of them weigh x units : x1+x2+x3 =x

3 of them weigh y units: y1+y2+y3 =y

now consider the case when i grouped  (x1, x2 x3) in single group

(y1,y2 ,y3) in one group and (a,b) in one group.

Now we will measure weight of 1st group (x1, x2, x3) :It will give x then
we conclude that all elements in this group are those element whose total
weight is x :Type 1 element.

similarly for y.

and for the last group we will pick up any element and measure its weight
..its weight will be either a or b. Depending upon outcome we will
categorize them a and b.

So 3 weighing is required.

On Tue, Jul 10, 2012 at 7:05 PM, payal gupta gpt.pa...@gmail.com wrote:

 @navin...Sorry didnt get you how come u were able to segregate all the
 coins by the proposed method??


 On 7/10/12, Navin Kumar algorithm.i...@gmail.com wrote:
  Minimum no. weighings:
 
  Divide 8 coins in group of 3, 3 and 2.
 
  For minimum weighsing group1 's total weight is x units(say) --FIrst
  weighing
  Groups 2nd total weights is y units  Second weighing.
  Lastly one more weighing among a unit and b unit coins.---3 rd weighing
 
 
  So minimum 3 weighing is required.
 
 
 
  On Tue, Jul 10, 2012 at 11:03 AM, payal gupta gpt.pa...@gmail.com
 wrote:
 
  You have 8 coins. 3 of them weigh x units, 3 y units, 1 a units and 1 b
  units. They are all mixed and look identical. What are the minimum no of
  weighings reqd to seperate the for types of coins???
 
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Re: [algogeeks] balanced tree

2012-07-10 Thread jatin sethi
for complete tree tree at last level can have left child and no right 
child , thus condition shd be somewhat like this...
if(node[right]==NULLnode[left]==NULL)
return true;
if(node[right]!=NULL) // if the node Rchild!=NULL then there shd be Lchild 
present.
 if(node[left]==NULL)
 return FALSE;
 

On Wednesday, 4 July 2012 18:24:54 UTC+5:30, amrit harry wrote:

 bool checkTree(Tree node)
 {
 if(node[right]==NULLnode[left]==NULL)
 return true;

 if(node[right]==NULLnode[left]!=NULL||node[left]==NULLnode[right]!=NULL)
 return false;
 else
 return checkTree(node[right])checkTree(node[left]);
 }

 i think this algo can solve problem just traverse the node and keep eye on 
 that either a node have 2 childs or no child

 On Wed, Jul 4, 2012 at 3:08 PM, Ashish Goel ashg...@gmail.com wrote:

 i think checking full is easy, find height(0to h) and then check if level 
 h has 2^(h+1) nodes

 how to check if it is complete..level order traversal? ensure that every 
 node has two children or left for the last one just before first leaf( till 
 you find the first leaf). Now on, every node should be a leaf.


 Best Regards
 Ashish Goel
 Think positive and find fuel in failure
 +919985813081
 +919966006652


 On Wed, Jul 4, 2012 at 2:36 PM, Ashish Goel ashg...@gmail.com wrote:

 ok, lets modify the problem to find if the tree is complete binary tree

 The tree is a complete binary tree; that is, all levels of the tree, 
 except possibly the last one (deepest) are fully filled, and, if the last 
 level of the tree is not complete, the nodes of that level are filled from 
 left to right



 Best Regards
 Ashish Goel
 Think positive and find fuel in failure
 +919985813081
 +919966006652


 On Wed, Jul 4, 2012 at 11:09 AM, atul anand atul.87fri...@gmail.comwrote:

 http://www.geeksforgeeks.org/archives/5230
 modify this to meet the requirnment.

 On 7/4/12, Ashish Goel ashg...@gmail.com wrote:
  WAP to find if a tree is balanced/fully balanced?
 
  Best Regards
  Ashish Goel
  Think positive and find fuel in failure
  +919985813081
  +919966006652
 
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 Thanks  Regards
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[algogeeks] Re: seperate diff types of coins

2012-07-10 Thread Dave
@Gupta: You haven't defined the problem sufficiently. 
 
What type of scale do we have, a balance scale or one that gives a numeric 
reading? 
 
Do we know x, y, a, and b, or are you just saying that one set of three 
coins weigh the same, another set of three also weigh the same but have 
different weight that the first set, and the remaining two weigh different 
amounts than each other and the two sets?
 
Is there any known relationship between x, y, a, and b? We can assume 
without loss of generality that x  y and a  b, but what about the 
relationships between x and a, x and b, y and a, and y and b? Knowing more 
will allow a solution with fewer weighings than knowing less.
 
Dave

On Tuesday, July 10, 2012 12:33:47 AM UTC-5, payal gupta wrote:

 You have 8 coins. 3 of them weigh x units, 3 y units, 1 a units and 1 b 
 units. They are all mixed and look identical. What are the minimum no of 
 weighings reqd to seperate the for types of coins???


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[algogeeks] Re: candies - interviewstreet -- how to go about solving this problem

2012-07-10 Thread g4ur4v
@sumit the sequence is fixed

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[algogeeks] Google : Print in interleaved fashion

2012-07-10 Thread Navin Kumar
Given two strings .Print all the interleavings of the two strings.
Interleaving means that the if B comes after A .It should also come after A 
in the interleaved string.
ex-
AB and CD
ABCD
ACBD
ACDB
CABD
CADB
CDAB

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Re: [algogeeks] Google : Print in interleaved fashion

2012-07-10 Thread atul anand
http://www.geeksforgeeks.org/archives/17743

On Tue, Jul 10, 2012 at 11:16 PM, Navin Kumar algorithm.i...@gmail.comwrote:

 Given two strings .Print all the interleavings of the two strings.
 Interleaving means that the if B comes after A .It should also come after
 A in the interleaved string.
 ex-
 AB and CD
 ABCD
 ACBD
 ACDB
 CABD
 CADB
 CDAB

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[algogeeks] how to print tata from tatapower using only strcat and strcpy???

2012-07-10 Thread amrit harry


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Re: [algogeeks] C o/p

2012-07-10 Thread vikas
he is right.

On Tue, Jul 10, 2012 at 3:13 PM, rahul sharma rahul23111...@gmail.comwrote:

 yeahu r ryt


 On Tue, Jul 10, 2012 at 10:01 AM, Firoz Khursheed 
 firozkhursh...@gmail.com wrote:

 Well, when i compiled the code the output ie i is alway i=2,

 http://ideone.com/AFljo
 http://ideone.com/87waz

 This expression  is ambiguous, and compiler dependent.
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Re: [algogeeks] Re: candies - interviewstreet -- how to go about solving this problem

2012-07-10 Thread bala bharath
can u explain ur algorithm for the sequence
*
  5 4 3 2 1*

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Re: [algogeeks] C o/p

2012-07-10 Thread Kapil Agrawal
++i/i++= 6/6
++i * i++ = 36.00
http://ideone.com/j4n0Q


On Tue, Jul 10, 2012 at 3:13 PM, rahul sharma rahul23111...@gmail.comwrote:

 yeahu r ryt


 On Tue, Jul 10, 2012 at 10:01 AM, Firoz Khursheed 
 firozkhursh...@gmail.com wrote:

 Well, when i compiled the code the output ie i is alway i=2,

 http://ideone.com/AFljo
 http://ideone.com/87waz

 This expression  is ambiguous, and compiler dependent.
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Re: [algogeeks] Re: candies - interviewstreet -- how to go about solving this problem

2012-07-10 Thread Sravan Kumar Reddy Ganta
for your example
5 4 3 2 1
5 4 3 2 1 -- candies assignement.
(since the length of the longest decreasing sequence is 4,
and length of increasing seq. before it is 0.
its max(0+1,4)+1 = 5

--Sravan Reddy



On Tue, Jul 10, 2012 at 8:09 AM, bala bharath bagop...@gmail.com wrote:


 can u explain ur algorithm for the sequence

 *
   5 4 3 2 1*

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Re: [algogeeks] Directi Interview Ques

2012-07-10 Thread Akshat Sapra
Here you have to first sort both the arrays A and B and merge both the
arrays to form the sorted array C

-- 


Akshat Sapra
Under Graduation(B.Tech)
IIIT-Allahabad(Amethi Campus)
*--*
sapraaks...@gmail.com
akshatsapr...@gmail.com
rit20009008@ rit20009...@gmail.comiiita.ac.in

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Re: [algogeeks] Directi Interview Ques

2012-07-10 Thread Mr.B
I think you missed the question:
Its a stable merge. (order of elements in each array should be same)
Sorting will destroy the original order.

Thanks,
Mr.B
[Please include complexities and pseudo-code]

On Tuesday, 10 July 2012 16:18:04 UTC-4, Akshat wrote:

 Here you have to first sort both the arrays A and B and merge both the 
 arrays to form the sorted array C
  
 -- 


 Akshat Sapra
 Under Graduation(B.Tech)
 IIIT-Allahabad(Amethi Campus)
 *--*
 sapraaks...@gmail.com
 akshatsapr...@gmail.com
 rit20009008@ rit20009...@gmail.comiiita.ac.in


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[algogeeks] Re: [Google] Finds all the elements that appear more than n/3 times

2012-07-10 Thread Mr.B
I found a similar solution looking somewhere else.

The solution for this problem is:
a. There can be atmost 3 elements (only 3 distinct elements with each 
repeating n/3 times) -- check for this and done. -- O(n) time.
b. There can be atmost 2 elements if not above case.

1. Find the median of the input. O(N)
2. Check if median element is repeated N/3 times or more -- O(n) - *{mark 
for output if yes}*
3. partition the array based on median found above. - O(n)  -- {partition 
is single step in quicksort}
4. find median in left partition from (3). - O(n)
5. check if median element is repeared n/3 times or more - O(n)  *{mark for 
output if yes}* 
6. find median in right partition from (3). - O(n)
7.  check if median element is repeared n/3 times or more - O(n)  *{mark 
for output if yes}*  

its 7*O(N) = O(N) solution. Constant space.

we need not check further down or recursively. {why? reason it.. its simple}


On Wednesday, 27 June 2012 18:35:12 UTC-4, Navin Kumar wrote:


 Design an algorithm that, given a list of n elements in an array, finds 
 all the elements that appear more than n/3 times in the list. The algorithm 
 should run in linear time

 ( n =0 ).

 You are expected to use comparisons and achieve linear time. No 
 hashing/excessive space/ and don't use standard linear time deterministic 
 selection algo.



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Re: [algogeeks] Re: seperate diff types of coins

2012-07-10 Thread payal gupta
@ Dave sir
 the balance considered here is simple balance scale incapable of
giving any numeric reading and the we are unaware of any relationship
between x,y,a,b or any kind denominations prioirity in terms of
weights...
@navin..
3 of them weigh x means 3 of the coins individually weigh x gms,it
isnt the cumulative sum of the coins as u considered ,thats what i got
from the question..
Correct me if i'm wrong.
Could it  be done it done in lesser than 8 weighings??

Regards,
PAYAL GUPTA.

On 7/10/12, Dave dave_and_da...@juno.com wrote:
 @Gupta: You haven't defined the problem sufficiently.

 What type of scale do we have, a balance scale or one that gives a numeric
 reading?

 Do we know x, y, a, and b, or are you just saying that one set of three
 coins weigh the same, another set of three also weigh the same but have
 different weight that the first set, and the remaining two weigh different
 amounts than each other and the two sets?

 Is there any known relationship between x, y, a, and b? We can assume
 without loss of generality that x  y and a  b, but what about the
 relationships between x and a, x and b, y and a, and y and b? Knowing more
 will allow a solution with fewer weighings than knowing less.

 Dave

 On Tuesday, July 10, 2012 12:33:47 AM UTC-5, payal gupta wrote:

 You have 8 coins. 3 of them weigh x units, 3 y units, 1 a units and 1 b
 units. They are all mixed and look identical. What are the minimum no of
 weighings reqd to seperate the for types of coins???


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Re: [algogeeks] Directi Interview Ques

2012-07-10 Thread arumuga abinesh
http://www.geeksforgeeks.org/archives/17743

Using the above problem we get all possible merges , at each possible
merge, we can calculate the sum.

On 7/11/12, Mr.B sravanreddy...@gmail.com wrote:
 I think you missed the question:
 Its a stable merge. (order of elements in each array should be same)
 Sorting will destroy the original order.

 Thanks,
 Mr.B
 [Please include complexities and pseudo-code]

 On Tuesday, 10 July 2012 16:18:04 UTC-4, Akshat wrote:

 Here you have to first sort both the arrays A and B and merge both the
 arrays to form the sorted array C

 --


 Akshat Sapra
 Under Graduation(B.Tech)
 IIIT-Allahabad(Amethi Campus)
 *--*
 sapraaks...@gmail.com
 akshatsapr...@gmail.com
 rit20009008@ rit20009...@gmail.comiiita.ac.in


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Re: [algogeeks] Re: seperate diff types of coins

2012-07-10 Thread Navin Kumar
@payal:

In this case too i think minimum number of weighing required is 3.

Slightly change in my previous solution. x1+x2+x3 = 3x and y1+y2+y3 = 3y.

On Wed, Jul 11, 2012 at 8:00 AM, payal gupta gpt.pa...@gmail.com wrote:

 @ Dave sir
  the balance considered here is simple balance scale incapable of
 giving any numeric reading and the we are unaware of any relationship
 between x,y,a,b or any kind denominations prioirity in terms of
 weights...
 @navin..
 3 of them weigh x means 3 of the coins individually weigh x gms,it
 isnt the cumulative sum of the coins as u considered ,thats what i got
 from the question..
 Correct me if i'm wrong.
 Could it  be done it done in lesser than 8 weighings??

 Regards,
 PAYAL GUPTA.

 On 7/10/12, Dave dave_and_da...@juno.com wrote:
  @Gupta: You haven't defined the problem sufficiently.
 
  What type of scale do we have, a balance scale or one that gives a
 numeric
  reading?
 
  Do we know x, y, a, and b, or are you just saying that one set of three
  coins weigh the same, another set of three also weigh the same but have
  different weight that the first set, and the remaining two weigh
 different
  amounts than each other and the two sets?
 
  Is there any known relationship between x, y, a, and b? We can assume
  without loss of generality that x  y and a  b, but what about the
  relationships between x and a, x and b, y and a, and y and b? Knowing
 more
  will allow a solution with fewer weighings than knowing less.
 
  Dave
 
  On Tuesday, July 10, 2012 12:33:47 AM UTC-5, payal gupta wrote:
 
  You have 8 coins. 3 of them weigh x units, 3 y units, 1 a units and 1 b
  units. They are all mixed and look identical. What are the minimum no of
  weighings reqd to seperate the for types of coins???
 
 
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Re: [algogeeks] Directi Interview Ques

2012-07-10 Thread Karthikeyan Muthu
pls discuss about prilims, online coding round too !!

regards,
Karthikeyan.M

On 7/11/12, arumuga abinesh arumugaabin...@gmail.com wrote:
 http://www.geeksforgeeks.org/archives/17743

 Using the above problem we get all possible merges , at each possible
 merge, we can calculate the sum.

 On 7/11/12, Mr.B sravanreddy...@gmail.com wrote:
 I think you missed the question:
 Its a stable merge. (order of elements in each array should be same)
 Sorting will destroy the original order.

 Thanks,
 Mr.B
 [Please include complexities and pseudo-code]

 On Tuesday, 10 July 2012 16:18:04 UTC-4, Akshat wrote:

 Here you have to first sort both the arrays A and B and merge both the
 arrays to form the sorted array C

 --


 Akshat Sapra
 Under Graduation(B.Tech)
 IIIT-Allahabad(Amethi Campus)
 *--*
 sapraaks...@gmail.com
 akshatsapr...@gmail.com
 rit20009008@ rit20009...@gmail.comiiita.ac.in


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