Re: [algogeeks] Re: swap objects without temp variable

2012-11-19 Thread abhinav gupta
we need to use + and - as operator overloading. so, that i will work f9 for
ur objects.

so make operator overloading for + and - operator.


On Sat, Nov 17, 2012 at 9:12 PM, AISHWARYA KUMAR aish@gmail.com wrote:


 in one line
  a=a^b^(b=a) ;

  --






-- 
*Thanks and Regards,*

Abhinav Kumar Gupta
Member Technical Staff | Oracle India Pvt. Lmt.
Bangalore (KA) - 560029.
+919060407434 | +918123065622
abhinav@gmail.com

-- 




[algogeeks] MS: searching problem......help me out...

2012-06-03 Thread abhinav gupta
  We have given a list 14 6 7 15 8 9 we have to find 15 in (log
n ) times.
-- 

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Abhinav Kumar Gupta
**abhinav@gmail.com

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Re: [algogeeks] MS: searching problem......help me out...

2012-06-03 Thread abhinav gupta
@Rahul: but for heapify, i need to build heap tree first from the list.
which will cost linear traversal of the elements, that will cost O(n). but
i need to search it in O(log n) or polylogrithmic complexity of (log n)
i.e. (log^2 n).

On Sun, Jun 3, 2012 at 8:55 AM, Rahul Kumar Patle patlerahulku...@gmail.com
 wrote:

 @abhinav: if you want to search just 15 in log(n) time then you can use
 the concept of heap tree.. apply one round of heapification (not for all
 elements but just one time it will be complete in log(n) times), and you
 will need to swap elements but when you got element 15 you can stop..
 although space complexity has increased... you will need one redundant
 array to use heap operation so that finally you will have original array as
 it is...

 Thanks and Regards:
 Rahul Kumar Patle


 On Sun, Jun 3, 2012 at 8:31 PM, abhinav gupta abhinav@gmail.comwrote:


   We have given a list 14 6 7 15 8 9 we have to find 15 in
 (log n ) times.
 --

 *Thanks and Regards,*

 Abhinav Kumar Gupta
 **abhinav@gmail.com

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++
*Technical Skill is the mastery of complexity, while Creativity is the master
of presence of mind. **  *









  - Morihei Ueshiba
++
*Thanks and Regards,*

Abhinav Kumar Gupta
*M. Tech. (Software Engineering)*
Motilal Nehru National Institute of Technology
Allahabad(UP)-211004
+919628358065
abhinav@gmail.com

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Re: [algogeeks] MS: searching problem......help me out...

2012-06-03 Thread abhinav gupta
@ Abhishek : Link that you have provided is for kth min element in the
unsorted array, but here i dont know the given value is of at what min
position.


On Sun, Jun 3, 2012 at 9:06 AM, abhinav gupta abhinav@gmail.com wrote:

 @Rahul: but for heapify, i need to build heap tree first from the list.
 which will cost linear traversal of the elements, that will cost O(n). but
 i need to search it in O(log n) or polylogrithmic complexity of (log n)
 i.e. (log^2 n).

 On Sun, Jun 3, 2012 at 8:55 AM, Rahul Kumar Patle 
 patlerahulku...@gmail.com wrote:

 @abhinav: if you want to search just 15 in log(n) time then you can use
 the concept of heap tree.. apply one round of heapification (not for all
 elements but just one time it will be complete in log(n) times), and you
 will need to swap elements but when you got element 15 you can stop..
 although space complexity has increased... you will need one redundant
 array to use heap operation so that finally you will have original array as
 it is...

 Thanks and Regards:
 Rahul Kumar Patle


 On Sun, Jun 3, 2012 at 8:31 PM, abhinav gupta abhinav@gmail.comwrote:


   We have given a list 14 6 7 15 8 9 we have to find 15 in
 (log n ) times.
 --

 *Thanks and Regards,*

 Abhinav Kumar Gupta
 **abhinav@gmail.com

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 --
 ++
 *Technical Skill is the mastery of complexity, while Creativity is the master
 of presence of mind. **  *









   - Morihei Ueshiba
 ++
 *Thanks and Regards,*

 Abhinav Kumar Gupta
 *M. Tech. (Software Engineering)*
 Motilal Nehru National Institute of Technology
 Allahabad(UP)-211004
 +919628358065
 abhinav@gmail.com




-- 
++
*Technical Skill is the mastery of complexity, while Creativity is the master
of presence of mind. **  *









  - Morihei Ueshiba
++
*Thanks and Regards,*

Abhinav Kumar Gupta
*M. Tech. (Software Engineering)*
Motilal Nehru National Institute of Technology
Allahabad(UP)-211004
+919628358065
abhinav@gmail.com

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Re: [algogeeks] ARICENT PATTERN

2012-02-21 Thread abhinav gupta
Aricent will not conduct test by itself. They'll have other organization
who will conduct the exams.
There are many test to be conducted in the time period of 2 or more. i just
forgot the time limit limit.
But the exams on apptitute, c language/java language either of
one, technical test, verbal reasoning, and many more but easy.
So just have basic concepts clear, and have strong hand on c...


On Wed, Feb 22, 2012 at 10:24 AM, vivek kumar kumarvivek1...@gmail.comwrote:

 hey guys plzz help me ..
 ARICENT is coming in my campus..
 plzz provide me some info ..
 Thanks in Advance!!

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Re: [algogeeks] Qualcomm

2011-09-23 Thread abhinav gupta
@vijay
 can u plz shar some ques which will help us

On Fri, Sep 23, 2011 at 5:20 PM, vijay singh vijaysinghb...@gmail.comwrote:

 Yes, it already visited..

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Re: [algogeeks] Re: error in c++ program

2011-09-22 Thread abhinav gupta
@rahul
+1

On Thu, Sep 22, 2011 at 11:20 PM, rahul vatsa vatsa.ra...@gmail.com wrote:

 time is a keyword in c/cpp, change time to any other string in ur code nd
 it will work.



 On Thu, Sep 22, 2011 at 12:27 PM, Rajesh Kumar testalgori...@gmail.comwrote:

 not working by changes provide by you


 On Thu, Sep 22, 2011 at 9:42 PM, payal gupta gpt.pa...@gmail.com wrote:

 #includeiostream.h

 class time
 {
 int m;
 int h;
 public:
 void set(int,int);
 void sum(time,time,time);
 void display();
 };
 void time::set(int x,int y)
 {
 m=x;
 h=y;
 }
 void time::sum(time t1,time t2,time t3)
 {
 m=t1.m+t2.m+t3.m;
 h=t1.h+t2.h+t3.h;
 }
 void time::display(void)
 {
 coutminute==mendl;
 couthours==hendl;
 }
 int main()
 {
 time a,b,c,d;
 a.set(1,2);
 b.set(2,4);
 c.set(4,8);
 d.sum(a,b,c);
 //display
 a.display();
 b.display();
 c.display();
 d.display();
 return 0;
 }



 dis does works...chk it  out!!!

 Regards,
 PAYAL GUPTA,
 CSE-3rd yr,
 NIT_B

 On Thu, Sep 22, 2011 at 9:28 PM, Don dondod...@gmail.com wrote:

 Give us some help. What is the error? Syntax error? Logic error?
 Runtime error?

 On Sep 22, 10:47 am, Rajesh Kumar testalgori...@gmail.com wrote:
  how we can remove error ?
  #includeiostream
  using namespace std;
  class time
  {
  int m;
  int h;
  public:
  void set(int,int);
  void sum(time,time,time);
  void display();};
 
  void time::set(int x,int y)
  {
  m=x;
  h=y;}
 
  void time::sum(time t1,time t2,time t3)
  {
  m=t1.m+t2.m+t3.m;
  h=t1.h+t2.h+t3.h;}
 
  void time::display(void)
  {
  coutminute==mendl;
  couthours==hendl;}
 
  int main()
  {
  time a,b,c,d;
  a.set(1,2);
  b.set(2,4);
  c.set(4,8);
  d.sum(a,b,c);
  //display
  a.display();
  b.display();
  c.display();
  d.display();
 
  }
 
  Regards
  Rajesh Kumar

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Re: [algogeeks] C++ Query

2011-09-20 Thread abhinav gupta
Whenver you call copy constructor it has to pass reference parameter beacuse
you dont want constructor and destructor to be called twice.
Here is the reason why,

Suppose u have two objects of a class (let 'a' and 'b').
when u want to copy 'a' into 'b' you want current status of object 'a' to be
copied into 'b'.But if it is pass by value then object 'b' will call its own
constructor and u wont get the current status of object 'a' into 'b'.

And when destructor is called then same piece of allocated memory will be
deallocated twice.So it is necessary to have copy constructors as pass by
reference.
On Mon, Sep 19, 2011 at 10:22 PM, KARTHIKEYAN V.B. algo...@gmail.comwrote:

 Hi

 Can anyone say me which is the best hashing tecnicque which can store
 duplicates and minimize time complexity?

 Pls reply

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Re: [algogeeks] Re: prime factorization algo

2011-09-20 Thread abhinav gupta
@ Tammana : Can u explain the main logic of haveFactor() function inside
Prime.?

On Tue, Sep 20, 2011 at 11:28 AM, Tamanna Afroze afroze...@gmail.comwrote:

 haveFactor() function checked the factor of a number.
 if a number has a factor other than 1 and itself it isn't prime.
 Operation function does the rest of the thing, i.e. file reading and file
 writing and looping throgh the file's input.

 Does that make sense?

 Pz let me know.

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Re: [algogeeks] Re: prime factorization algo

2011-09-20 Thread abhinav gupta
Dats not the logic Tammana
you have to check whether there is any factor in between 2 to number/2;
if there is any no then u have to brak at that point.


On Tue, Sep 20, 2011 at 12:10 PM, Tamanna Afroze afroze...@gmail.comwrote:


 I checked whether th enuber s divisible by 2 nd 3 repeatedly...
 I got no other number which aren't divisible by these two numbers.
 nd I am done.
 Tht's all abhinav.

 Tamanna

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Re: [algogeeks] Re: prime factorization algo

2011-09-20 Thread abhinav gupta
Welcum ! I think we need to discuss this 1 in gtalk...I think u still need
sm clarification in this 1



On Tue, Sep 20, 2011 at 12:33 PM, Tamanna Afroze afroze...@gmail.comwrote:

 Thanks to all for the nice suggestions. thanks @abhianv and @siddhart.

 I will try all the suggestions..


 Tamanna

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Re: [algogeeks] Question --

2011-09-20 Thread abhinav gupta
I can tell you the logic.Take two arrays N and M, put their bits in
the array.
Now using i and j index replace the value of N[j] to n[i] by M[j] to M[i].
On Tue, Sep 20, 2011 at 12:33 PM, Ishan Aggarwal 
ishan.aggarwal.1...@gmail.com wrote:

 You are given two 32-bit numbers, N and M, and two bit positions, i and
 j.Write a method to set all bits between i and j in N equal to M (e.g., M
 becomes a substring of N located at i and starting at j).

 EXAMPLE:

 Input: N = 100, M = 10101, i = 2, j = 6

 Output: N = 10001010100

 --
 Kind Regards
 Ishan Aggarwal
 [image: Aricent Group]
 Presidency Tower-A, M.G.Road,Sector-14
 Gurgaon,Haryana.122015 INDIA
 Phone : +91-9654602663
 ishan2.aggar...@aricent.com puneet.ar...@aricent.com

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Re: [algogeeks] Question --

2011-09-20 Thread abhinav gupta
U can use single walker (from 0 till 31) to convert integers N and M into
array of bits, then
another walker from i to j to replace values.

for(k=31;k=0;k++)
{
N[k]=n  01;
M[k]=m 01;
n=1;
m=1;
}

for(k=i;k=j;k++)
N[k]=M[k];

On Tue, Sep 20, 2011 at 12:44 PM, abhinav gupta
guptaabhinav...@gmail.comwrote:

 I can tell you the logic.Take two arrays N and M, put their bits in
 the array.
 Now using i and j index replace the value of N[j] to n[i] by M[j] to M[i].
   On Tue, Sep 20, 2011 at 12:33 PM, Ishan Aggarwal 
 ishan.aggarwal.1...@gmail.com wrote:

 You are given two 32-bit numbers, N and M, and two bit positions, i and
 j.Write a method to set all bits between i and j in N equal to M (e.g., M
 becomes a substring of N located at i and starting at j).

 EXAMPLE:

 Input: N = 100, M = 10101, i = 2, j = 6

 Output: N = 10001010100

 --
 Kind Regards
 Ishan Aggarwal
 [image: Aricent Group]
 Presidency Tower-A, M.G.Road,Sector-14
 Gurgaon,Haryana.122015 INDIA
 Phone : +91-9654602663
 ishan2.aggar...@aricent.com puneet.ar...@aricent.com

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Re: [algogeeks] Re: prime factorization algo

2011-09-20 Thread abhinav gupta
yup i too think so..Dats y I need to discuss this qs wid u.


On Tue, Sep 20, 2011 at 12:36 PM, Tamanna Afroze afroze...@gmail.comwrote:


 @abhinav I think time complexity will be higher for that algorithm

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Re: [algogeeks] Question --

2011-09-20 Thread abhinav gupta
Its because o/p should look like dat.Bt dats simple you can do it
by multiplying bits to power(2, i) and
adding all expressions.Simple!
On Tue, Sep 20, 2011 at 1:09 PM, abhinav gupta guptaabhinav...@gmail.comwrote

 In the first loop bits are added into the array N and M .I have taken two
 integers n and m .
 Caution :
 declare


 int N[31]={0};
 int M[31]={0};
 int n,m,i,j;

   On Tue, Sep 20, 2011 at 1:02 PM, Ishan Aggarwal 
 ishan.aggarwal.1...@gmail.com wrote:

 What are u doing in the first loop running for k=31 to k =0?


 On Tue, Sep 20, 2011 at 12:50 PM, abhinav gupta 
 guptaabhinav...@gmail.com wrote:

 U can use single walker (from 0 till 31) to convert integers N and M into
 array of bits, then
 another walker from i to j to replace values.

 for(k=31;k=0;k++)
 {
 N[k]=n  01;
 M[k]=m 01;
 n=1;
 m=1;
 }

 for(k=i;k=j;k++)
 N[k]=M[k];

   On Tue, Sep 20, 2011 at 12:44 PM, abhinav gupta 
 guptaabhinav...@gmail.com wrote:

 I can tell you the logic.Take two arrays N and M, put their bits in
 the array.
 Now using i and j index replace the value of N[j] to n[i] by M[j] to
 M[i].
   On Tue, Sep 20, 2011 at 12:33 PM, Ishan Aggarwal 
 ishan.aggarwal.1...@gmail.com wrote:

 You are given two 32-bit numbers, N and M, and two bit positions, i and
 j.Write a method to set all bits between i and j in N equal to M (e.g., M
 becomes a substring of N located at i and starting at j).

 EXAMPLE:

 Input: N = 100, M = 10101, i = 2, j = 6

 Output: N = 10001010100

 --
 Kind Regards
 Ishan Aggarwal
 [image: Aricent Group]
 Presidency Tower-A, M.G.Road,Sector-14
 Gurgaon,Haryana.122015 INDIA
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Re: [algogeeks]

2011-09-20 Thread abhinav gupta
You can parse the array to find address of max element
then you can parse second time leaving that particular address to find
second largest element.



On Tue, Sep 20, 2011 at 12:36 PM, surender sanke surend...@gmail.comwrote:

 based on minmax in minimum number of comparisons..

 struct pa
 {
  int max;
  int secmax;
 };

 struct pa  getmm(int arr[], int low, int high)
 {
  struct pa  mm = {-1,-1}, mml, mmr;  int mid;

  /* If there is only on element */
  if(low == high)
  {
   mm.max = arr[low];
   mm.secmax = arr[low];
   return mm;
  }

  /* If there are two elements */
  if(high == low + 1)
  {
   if(arr[low]  arr[high])
   {
mm.max = arr[low];
mm.secmax = arr[high];
   }
   else
   {
mm.max = arr[high];
mm.secmax = arr[low];
   }
   return mm;
  }

  /* If there are more than 2 elements */
  mid = (low + high)/2;
  mml = getmm(arr, low, mid);
  mmr = getmm(arr, mid+1, high);

  /* compare maximums of two parts*/
  if(mml.max  mmr.max)
  {
   int temp = mm.max;
   mm.max = mml.max;
   if(mmr.maxtemp)
mm.secmax = mmr.max;
   else
mm.secmax = temp;
  }
  else
  {
   int temp = mm.max;
   mm.max = mmr.max;

   if(mml.maxtemp)
mm.secmax = mml.max;
   else
mm.secmax = temp;


  }

   return mm;
 }

 surender
   On Tue, Sep 20, 2011 at 7:48 AM, Sandy sandy.wad...@gmail.com wrote:

 @Utkarsh:  In Yogesh's code assigning a[1] to largest and second_largest
 in the beginning, -VE case will be handled.


 On Mon, Sep 19, 2011 at 12:10 PM, asdqwe ayushgoel...@gmail.com wrote:

 @Yogesh:fails for negative numbers..

 (though I am also confused with the ques)

 On Sep 19, 10:38 am, Yogesh Yadav medu...@gmail.com wrote:
  current position is index n (say)
  largest=0;
  second_largest=0;
 
  for(i=1;i=n;i++)
  {
  if(a[i]a[n])
  {
  if(a[i]largest)
  {
  second_largest=largest;
  largest=a[i];}
 
  elseif(a[i]second_largest)
  second_largest=a[i];
 
  }
  }
 
  
 
 
 
 
 
 
 
  On Mon, Sep 19, 2011 at 2:15 AM, sagar pareek sagarpar...@gmail.com
 wrote:
   Give some examples ,i m not getting ur question
 
   On Mon, Sep 19, 2011 at 1:45 AM, UTKARSH SRIVASTAV 
   usrivastav...@gmail.com wrote:
 
   how to find second largest element than current element in an array
 given
   condition that we have to find that second largest element from
 index 1 to
   the index of the current element
 
   --
   *UTKARSH SRIVASTAV
   CSE-3
   B-Tech 3rd Year
   @MNNIT ALLAHABAD*
 
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Re: [algogeeks] Question --

2011-09-20 Thread abhinav gupta
In the first loop bits are added into the array N and M .I have taken two
integers n and m .
Caution :
declare


int N[31]={0};
int M[31]={0};
int n,m,i,j;

On Tue, Sep 20, 2011 at 1:02 PM, Ishan Aggarwal 
ishan.aggarwal.1...@gmail.com wrote:

 What are u doing in the first loop running for k=31 to k =0?


 On Tue, Sep 20, 2011 at 12:50 PM, abhinav gupta guptaabhinav...@gmail.com
  wrote:

 U can use single walker (from 0 till 31) to convert integers N and M into
 array of bits, then
 another walker from i to j to replace values.

 for(k=31;k=0;k++)
 {
 N[k]=n  01;
 M[k]=m 01;
 n=1;
 m=1;
 }

 for(k=i;k=j;k++)
 N[k]=M[k];

   On Tue, Sep 20, 2011 at 12:44 PM, abhinav gupta 
 guptaabhinav...@gmail.com wrote:

 I can tell you the logic.Take two arrays N and M, put their bits in
 the array.
 Now using i and j index replace the value of N[j] to n[i] by M[j] to
 M[i].
   On Tue, Sep 20, 2011 at 12:33 PM, Ishan Aggarwal 
 ishan.aggarwal.1...@gmail.com wrote:

 You are given two 32-bit numbers, N and M, and two bit positions, i and
 j.Write a method to set all bits between i and j in N equal to M (e.g., M
 becomes a substring of N located at i and starting at j).

 EXAMPLE:

 Input: N = 100, M = 10101, i = 2, j = 6

 Output: N = 10001010100

 --
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Re: [algogeeks] Question --

2011-09-20 Thread abhinav gupta
You can also solve the problem by using bit operators. by using| !
.
Need sm thinking in dat..No time rite nw!

On Tue, Sep 20, 2011 at 1:12 PM, abhinav gupta guptaabhinav...@gmail.comwrote:

 Its because o/p should look like dat.Bt dats simple you can do it
 by multiplying bits to power(2, i) and
 adding all expressions.Simple!
 On Tue, Sep 20, 2011 at 1:09 PM, abhinav gupta 
 guptaabhinav...@gmail.comwrote

  In the first loop bits are added into the array N and M .I have taken two
 integers n and m .
 Caution :
 declare


 int N[31]={0};
 int M[31]={0};
 int n,m,i,j;

   On Tue, Sep 20, 2011 at 1:02 PM, Ishan Aggarwal 
 ishan.aggarwal.1...@gmail.com wrote:

 What are u doing in the first loop running for k=31 to k =0?


 On Tue, Sep 20, 2011 at 12:50 PM, abhinav gupta 
 guptaabhinav...@gmail.com wrote:

 U can use single walker (from 0 till 31) to convert integers N and M
 into array of bits, then
 another walker from i to j to replace values.

 for(k=31;k=0;k++)
 {
 N[k]=n  01;
 M[k]=m 01;
 n=1;
 m=1;
 }

 for(k=i;k=j;k++)
 N[k]=M[k];

   On Tue, Sep 20, 2011 at 12:44 PM, abhinav gupta 
 guptaabhinav...@gmail.com wrote:

 I can tell you the logic.Take two arrays N and M, put their bits in
 the array.
 Now using i and j index replace the value of N[j] to n[i] by M[j] to
 M[i].
   On Tue, Sep 20, 2011 at 12:33 PM, Ishan Aggarwal 
 ishan.aggarwal.1...@gmail.com wrote:

 You are given two 32-bit numbers, N and M, and two bit positions, i
 and j.Write a method to set all bits between i and j in N equal to M 
 (e.g.,
 M becomes a substring of N located at i and starting at j).

 EXAMPLE:

 Input: N = 100, M = 10101, i = 2, j = 6

 Output: N = 10001010100

 --
 Kind Regards
 Ishan Aggarwal
 [image: Aricent Group]
 Presidency Tower-A, M.G.Road,Sector-14
 Gurgaon,Haryana.122015 INDIA
 Phone : +91-9654602663
 ishan2.aggar...@aricent.com puneet.ar...@aricent.com

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Re: [algogeeks] Re: Question --

2011-09-20 Thread abhinav gupta
Instead of Num[31] u should tk Num[32]

On Tue, Sep 20, 2011 at 2:16 PM, Ishan Aggarwal 
ishan.aggarwal.1...@gmail.com wrote:

 Hi,

 When I am running this program, I am getting segmentation fault. Can u plz
 confirm where is the error.

 #includestdio.h
 void main()
 {
 int Num[31]={0};
 int Mum[31]={0};
 int n = 64,m = 7  ,i=0,j=3,k;
 for(k=31;k=0;k++)
 {
 Num[k]=n  1;
 Mum[k]=m  1;
 n=n1;
 m=m1;
 }

 for(k=i;k=j;k++)
 Num[k]=Mum[k];

 for(k=0;k=31;k++)
 printf(%d , Num[k]);
 }


 On Tue, Sep 20, 2011 at 1:49 PM, tec technic@gmail.com wrote:

 mask = (1(j+1))-(1i);
 n = (n(~mask)) | m;


 On Sep 20, 3:43 pm, abhinav gupta guptaabhinav...@gmail.com wrote:
  You can also solve the problem by using bit operators. by using   
 | !
  .
  Need sm thinking in dat..No time rite nw!
 
  On Tue, Sep 20, 2011 at 1:12 PM, abhinav gupta 
 guptaabhinav...@gmail.comwrote:
 
 
 
 
 
 
 
 
 
   Its because o/p should look like dat.Bt dats simple you can do it
   by multiplying bits to power(2, i) and
   adding all expressions.Simple!
   On Tue, Sep 20, 2011 at 1:09 PM, abhinav gupta 
 guptaabhinav...@gmail.comwrote
 
In the first loop bits are added into the array N and M .I have taken
 two
   integers n and m .
   Caution :
   declare
 
   int N[31]={0};
   int M[31]={0};
   int n,m,i,j;
 
 On Tue, Sep 20, 2011 at 1:02 PM, Ishan Aggarwal 
   ishan.aggarwal.1...@gmail.com wrote:
 
   What are u doing in the first loop running for k=31 to k =0?
 
   On Tue, Sep 20, 2011 at 12:50 PM, abhinav gupta 
   guptaabhinav...@gmail.com wrote:
 
   U can use single walker (from 0 till 31) to convert integers N and
 M
   into array of bits, then
   another walker from i to j to replace values.
 
   for(k=31;k=0;k++)
   {
   N[k]=n  01;
   M[k]=m 01;
   n=1;
   m=1;
   }
 
   for(k=i;k=j;k++)
   N[k]=M[k];
 
 On Tue, Sep 20, 2011 at 12:44 PM, abhinav gupta 
   guptaabhinav...@gmail.com wrote:
 
   I can tell you the logic.Take two arrays N and M, put their bits
 in
   the array.
   Now using i and j index replace the value of N[j] to n[i] by M[j]
 to
   M[i].
 On Tue, Sep 20, 2011 at 12:33 PM, Ishan Aggarwal 
   ishan.aggarwal.1...@gmail.com wrote:
 
   You are given two 32-bit numbers, N and M, and two bit positions,
 i
   and j.Write a method to set all bits between i and j in N equal
 to M (e.g.,
   M becomes a substring of N located at i and starting at j).
 
   EXAMPLE:
 
   Input: N = 100, M = 10101, i = 2, j = 6
 
   Output: N = 10001010100
 
   --
   Kind Regards
   Ishan Aggarwal
   [image: Aricent Group]
   Presidency Tower-A, M.G.Road,Sector-14
   Gurgaon,Haryana.122015 INDIA
   Phone : +91-9654602663
   ishan2.aggar...@aricent.com puneet.ar...@aricent.com
 
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Re: [algogeeks] getting segmentation fault..

2011-09-20 Thread abhinav gupta
What are the values of n and m you are providing???

On Tue, Sep 20, 2011 at 7:02 PM, deependra dsdeependraprat...@gmail.comwrote:

 long int n,m;
  cinnm;
 long int a[n][m];
  a[0][0]=1;
  for(long int i=1;in;i++)
  a[i][0]=0;
  for(long int i=1;im;i++)
  a[0][i]=0;
   long int z=0;
  for(long int i=1;in;i++)
  {
  for( long int j=1;jm;j++)
  {
  a[i][j]=(j*(a[i-1][j]) + a[i-1][j-1] );
  z=a[i][j];
  }
  }
  int mod= z%2;
   coutmodendl;

 m getting segmentation fault error at run time in the above code.
 can any one explain segmentation fault and how to remove it??

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Re: [algogeeks] getting segmentation fault..

2011-09-20 Thread abhinav gupta
Beacuse memory requird to store (1000 * 1000) bytes is more than stack can
hold for the program..Dats y its giving segmentation fault...

On Tue, Sep 20, 2011 at 7:29 AM, Deependra pratap singh 
dsdeependraprat...@gmail.com wrote:

 for  n1000 , m1000... m getting the fault. but lesser than that code is
 working fine...

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Re: [algogeeks] stack

2011-09-20 Thread abhinav gupta
stfu !

On Tue, Sep 20, 2011 at 10:27 AM, prasanth n nprasnt...@gmail.com wrote:

 In the classic problem of the Towers of Hanoi, you have 3 rods and N disks
 of different sizes which can slide onto any tower. The puzzle starts with
 disks sorted in ascending order of size from top to bottom (e.g., each disk
 sits on top of an even larger one). You have the following constraints:
 (A) Only one disk can be moved at a time.
 (B) A disk is slid off the top of one rod onto the next rod.
 (C) A disk can only be placed on top of a larger disk.
 Write a program to move the disks from the first rod to the last using
 Stacks.

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Re: [algogeeks] Re: random function

2011-09-19 Thread abhinav gupta
for that u have rand() function in c programming just go through it


On Mon, Sep 19, 2011 at 8:42 PM, prasanth n nprasnt...@gmail.com wrote:

 @don:
 suppose if give like random(5)- it must give any number between 0 and 5..


 On Mon, Sep 19, 2011 at 8:22 PM, Don dondod...@gmail.com wrote:

 You mean a pseudo-random generator.
 Without special hardware you won't get a real random generator.
 Use Mersenne Twister.

 Don

 On Sep 19, 9:43 am, prasanth n nprasnt...@gmail.com wrote:
  anyone give an algorithm of how to generate a random number..probability
 of
  occurrence of each no should be the same..
 
  --
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Re: [algogeeks] Re: random function

2011-09-19 Thread abhinav gupta
int i;
i=random(5);


int random(int x)
{
return (rand(x) % 5);
}


rand() is inbuilt function in c/c++;


On Mon, Sep 19, 2011 at 9:24 PM, Don dondod...@gmail.com wrote:


 The most common way that it works would be that random(n) returns the
 equivalent of a random integer mod n, so 0=xn. But there is no
 standard for how they work, so know what you are dealing with.

 Don

  On Sep 19, 10:12 am, prasanth n nprasnt...@gmail.com wrote:
  @don:
  suppose if give like random(5)- it must give any number between 0 and
 5..
 
 
 

   On Mon, Sep 19, 2011 at 8:22 PM, Don dondod...@gmail.com wrote:
   You mean a pseudo-random generator.
   Without special hardware you won't get a real random generator.
   Use Mersenne Twister.
 
   Don
 
   On Sep 19, 9:43 am, prasanth n nprasnt...@gmail.com wrote:
anyone give an algorithm of how to generate a random
 number..probability
   of
occurrence of each no should be the same..
 
--
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Re: [algogeeks] Re: prime factorization algo

2011-09-19 Thread abhinav gupta
@Tammana can u pls give me the logic of the above code !

On Tue, Sep 20, 2011 at 8:35 AM, Tamanna Afroze afroze...@gmail.com wrote:


 I don't know whether my one is good algorithm or not, but it gives somewhat
 good output. It is in Java.

 /*
  * To change this template, choose Tools | Templates
  * and open the template in the editor.
  */
 package prime;

 /**
  *
  * @author Tamanna Afroze
  */

 import java.io.File;
 import java.io.FileReader;
 import java.io.FileWriter;
 import java.io.BufferedReader;
 import java.io.BufferedWriter;
 import java.io.IOException;
 import java.util.StringTokenizer;

 public class Prime {

 /**
  * @param args the command line arguments
  */
 boolean haveFactor(int iNumber){
 int iFactors[] = new int[1];
 int iIndex = 0;
 iFactors[iIndex] = 1;
 iIndex++;
 iFactors[iIndex] = iNumber;
 iIndex++;

 if(iNumber != 2  (iNumber%2)==0){
 iFactors[iIndex] = 2;
 iIndex++;
 iNumber /=2;
 if( iNumber != 2 ){
 iFactors[iIndex] = iNumber;
 iIndex++;
 }
 int iLoop = 2;
 if( iNumber != 2 ){
 while((iNumber%2) != 1){
 iFactors[iIndex] = 2*iLoop;
 //System.out.println(Here : + iFactors[iIndex]);
 iIndex++;
 iNumber /= 2;
 iFactors[iIndex] = iNumber;
 iIndex++;
 iLoop *= 2;
 }
 }
 if(iNumber != 3  (iNumber%3)==0){
 iFactors[iIndex] = 3;
 iIndex++;
 iNumber /=3;
 if( iNumber != 3 ){
 iFactors[iIndex] = iNumber;
 iIndex++;
 }
 iLoop = 3;
 if( iNumber != 3 ){
 while((iNumber%3) != 1){
 iFactors[iIndex] = 3*iLoop;
 //System.out.println(Here : + iFactors[iIndex]);
 iIndex++;
 iNumber /= 3;
 if( iNumber != 3 ){
 iFactors[iIndex] = iNumber;
 iIndex++;
 }
 iLoop *= 3;
 }
 }
 }
 for(int i =0; iiIndex; i++){
 //System.out.println(iFactors[i]);
 }
 return true;
 }
 else if(iNumber != 3  (iNumber%3)==0){
 iFactors[iIndex] = 3;
 iIndex++;
 iNumber /=3;
 if( iNumber != 3 ){
 iFactors[iIndex] = iNumber;
 iIndex++;
 }
 int iLoop = 3;
 while(iNumber != 3  (iNumber%3) != 1){
 iFactors[iIndex] = 3*iLoop;
 //System.out.println(Here : + iFactors[iIndex]);
 iIndex++;
 iNumber /= 3;
 if( iNumber != 3 ){
 iFactors[iIndex] = iNumber;
 iIndex++;
 }
 iLoop *= 3;
 }
 for(int i =0; iiIndex; i++){
 //System.out.println(iFactors[i]);
 }
 return true;
 }
 else{
 return false;
 }
 }

 public void Operation(){
 String number,numberofinput,first,second;
 int index = 0,iFirst = 0,iSecond = 0, iNumberOfInput = 0;

 try{
 File file = new File(input.txt);
 FileReader fileReader = new FileReader(file);
 BufferedReader bufferedReader = new BufferedReader(fileReader);

 FileWriter fileWriter = new FileWriter(output.txt);
 BufferedWriter bufferedWriter = new BufferedWriter(fileWriter);

 while((number = bufferedReader.readLine()) != null){
 if(index == 0){
 numberofinput = number;
 iNumberOfInput = Integer.parseInt(numberofinput);
 }
 else{
 StringTokenizer tokenizer = new
 StringTokenizer(number);
 while(tokenizer.hasMoreTokens()){
 first = tokenizer.nextToken();
 second = tokenizer.nextToken();
 System.out.println(First:  + first +  Second: 
 + second);
 iFirst = Integer.parseInt(first);
 iSecond = Integer.parseInt(second);
 }
 System.out.println(Integer Version First:  + iFirst +
  Second:  + iSecond);
 if(iFirst = 1  iSecond = iFirst  iSecond =
 10  iSecond-iFirst = 10){

 for(int k = iFirst; k=iSecond ; k++ ){
 

Re: [algogeeks] Plz explain the output..........

2011-09-17 Thread abhinav gupta
@yogesh :ya u right.

On Sat, Sep 17, 2011 at 11:58 AM, sukran dhawan sukrandha...@gmail.comwrote:

 x== 9 is not an error !!! it simply returns a non zero value if its true
 and 0 if its false

 On Sat, Sep 17, 2011 at 11:39 AM, praveen raj praveen0...@gmail.comwrote:

 This will show syntax error due to x==9 and otherwise since memory address
 given at the declarAtion there fore  x value will. Change at every
 assignment , but i m not sure printf will give an error or not . Plz reply.

 On 17-Sep-2011 1:13 AM, Anshul AGARWAL anshul.agarwa...@gmail.com
 wrote:
 
  #includestdio.h
  int  main()
  {float t;
  long x;
 
 
  t=98;
  printf(%d\n,t);
printf(%f\n,x);
  {
  x=1;
  printf(%f\n,x);
  {
 
  x=30;
  printf(%f\n,x);
  }
  printf(%f\n,x);
  }
  x==9;
  printf(%f\n,x);
 
  }
  
  ---
  Anshul Agarwal
  Nit Allahabad
  Computer Science
 
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Re: [algogeeks] Math Puzzle

2011-09-15 Thread abhinav gupta
Above expression will be

(p^3+q^3+r^3)/pqr

if a+b+c=0, then a^3+b^3+c^3 = 3abc

so,

3pqr/pqr=3



On Thu, Sep 15, 2011 at 10:59 AM, rahul sharma rahul23111...@gmail.comwrote:

 hw?


 On Thu, Sep 15, 2011 at 10:57 AM, Tamanna Afroze afroze...@gmail.comwrote:

 yah the ans is 3

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Re: [algogeeks] Re: Math Puzzle

2011-09-15 Thread abhinav gupta
Shut up...its 3,,

On Thu, Sep 15, 2011 at 9:43 AM, Don dondod...@gmail.com wrote:

 It might be 3, but it doesn't have to be 3.
 Don

 On Sep 14, 11:56 pm, NAGARAJAN SIVARAMAN naga4...@gmail.com wrote:
  if P+Q+R= 0  then P2 /QR  + Q2/PR + R2/PQ = ??
 
  how to solve this??

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Re: [algogeeks] Re: Math Puzzle

2011-09-15 Thread abhinav gupta
u cnt divide a number by 0..that thing is self undrstod

On Thu, Sep 15, 2011 at 9:49 AM, Piyush Grover piyush4u.iit...@gmail.comwrote:

 Don is right

 if R = 0, P = 1 and Q = -1 then the given expression is UNDEFINED!!!



 On Thu, Sep 15, 2011 at 10:16 PM, abhinav gupta guptaabhinav...@gmail.com
  wrote:

 Shut up...its 3,,


 On Thu, Sep 15, 2011 at 9:43 AM, Don dondod...@gmail.com wrote:

 It might be 3, but it doesn't have to be 3.
 Don

 On Sep 14, 11:56 pm, NAGARAJAN SIVARAMAN naga4...@gmail.com wrote:
  if P+Q+R= 0  then P2 /QR  + Q2/PR + R2/PQ = ??
 
  how to solve this??

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Re: [algogeeks] Re: Math Puzzle

2011-09-15 Thread abhinav gupta
dude dats outside the domain of the qs...dont be oversmart.

On Thu, Sep 15, 2011 at 9:49 AM, Don dondod...@gmail.com wrote:

 No, not at all. Here is a trivial counterexample:

 P = Q = R = 0

 Don

 On Sep 15, 11:46 am, abhinav gupta guptaabhinav...@gmail.com wrote:
  Shut up...its 3,,
 
 
 
  On Thu, Sep 15, 2011 at 9:43 AM, Don dondod...@gmail.com wrote:
   It might be 3, but it doesn't have to be 3.
   Don
 
   On Sep 14, 11:56 pm, NAGARAJAN SIVARAMAN naga4...@gmail.com wrote:
if P+Q+R= 0  then P2 /QR  + Q2/PR + R2/PQ = ??
 
how to solve this??
 
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Re: [algogeeks] Microsoft coming to PEC on 19th, any specific pattern for written test

2011-09-15 Thread abhinav gupta
y u all r worried abt MS...open up ur own cmpny...
On Thu, Sep 15, 2011 at 10:13 AM, vivek goel vivek.thapar2...@gmail.comwrote:

 hey ankur.

 wat's eligibility criteria..
 and eligible branches...
 *mca* is eligible ??.

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Re: [algogeeks] Interview Questions

2011-09-15 Thread abhinav gupta
Runtime error.. x pointing to unintialised memory..and then initialised,,,

On Thu, Sep 15, 2011 at 11:02 AM, SAMMM somnath.nit...@gmail.com wrote:

 #includecstdio
 #includeiostream
 using namespace std;

 int main()
 {
  int w=10;
  int *p=w;
  int *x;
  *x=1000;
  int *y;
  *y=100;
  printf(%d %d %d,*x,*p,*y);
  return 0;
 }


 Wht is the o/p  ??

 1)1000 10 100
 2)1000 10 10
 3)Compilation Error
 4)Run Time Error

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Re: [algogeeks] Re: Interview Questions

2011-09-15 Thread abhinav gupta
Runtime error

On Thu, Sep 15, 2011 at 11:16 AM, SAMMM somnath.nit...@gmail.com wrote:

 OK Now try this ...


 #includecstdio
 #includeiostream
 using namespace std;

 int main()
 {
  int w=10;
  int *p=w;
  int *x;
  *x=1000;
  printf(%d %d ,*x,*p);
  return 0;
 }

 Wht is the o/p  ??

 1)1000 10
 2)1000 100
 3)Compilation Error
 4)Run Time Error

 Any Difference ??

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Re: [algogeeks] Re: Interview Questions

2011-09-15 Thread abhinav gupta
I dont knw man wat d hell is dis?
On Thu, Sep 15, 2011 at 11:19 AM, SAMMM somnath.nit...@gmail.com wrote:

 No check It once more in  G++  Compiler

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Re: [algogeeks] find the error

2011-09-14 Thread abhinav gupta
file not closed.

On Wed, Sep 14, 2011 at 5:56 PM, ravi maggon maggonr...@gmail.com wrote:

 Something like this was asked in written test of Tally. We had to find the
 cause why this program crased during run time.
 File *f;
 int count=0;
 if(f=fopen(file.txt,r))
 {
   while(f.get()!=EOF)
   {
 count++;
   }
 }

 --
 Regards
 Ravi Maggon
 B.E. CSE, Final Year
 Thapar University

 www.algorithmguru.com

 *Failure is the opportunity to begin again more intelligently*

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Re: [algogeeks] program

2011-09-14 Thread abhinav gupta
Create a structure
with num,count(of num) and link
parse the array and create nodes (nodes are created with id=num).
when the no of nodes == 3 print the nodes data and count.

On Wed, Sep 14, 2011 at 5:13 PM, parag khanna khanna.para...@gmail.comwrote:


 find the frequencies of each alphabet ... n store it in an array
 corressponding to the ascii value of the alphabet as a index of array ... n
 store its count ... then sort the array in decreasing order ... and return
 the top 3 index value of the array in integer form




 --

 Parag Khanna
 B.tech Final Year
 NIT,Kurukshetra


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Re: [algogeeks] Re: informatica pattern and question of interview

2011-09-14 Thread abhinav gupta
Informatica sucks.I have topped in its offcampus written test still they din
call me.

On Wed, Sep 14, 2011 at 7:05 PM, ravi maggon maggonr...@gmail.com wrote:

 In Thapar Criteria was
 BE CSE and I think MCA was also eligible but for interviews only BE CSE
 were shortlisted.
 Package: 7.75 lpa

 On Wed, Sep 14, 2011 at 6:56 PM, sush57 sushaant...@gmail.com wrote:

 many i know what's the criteria and package for the company...

 regards
 sushaanth
 BE-computer science
 Madras Institute of technology


 On Sep 14, 3:02 pm, Ankit Agarwal ankuagarw...@gmail.com wrote:
  2  question
 
  numbers are (a1+1)*a2*a3... an = a1*a2*a3...an + a2*a3...an
  the first term is same...
  for second term is (a1*a2...an)/(a1)
  now we have to find max of ( ((a1*a2..an)/a1),  (a1*a2...an)/a2)
  so the question of max becomes min of( a1, a2, a3... an)
 
  --
  Ankit Agarwal
  Computer Science  Engg.
  Integrated Dual Degree, V yr
  Department of Electronics  Computer Engineering
  Indian Institute of Technology Roorkee
  Ph. no. +91-9580098805

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 www.algorithmguru.com

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Re: [algogeeks] Re: branching factor when BFS and DFS of a graph is same

2011-09-14 Thread abhinav gupta
@siddharam:

i think the above example is isomorphic
because in isomopic we check for the degree of each node in one tree to the
corresponding degree of another tree is present or not .

like eg:-

p-q--r---s

is isomorphic with


a--b--c---d




On Thu, Sep 15, 2011 at 10:15 AM, siddharam suresh
siddharam@gmail.comwrote:

 as per your example

  preorder  inorder
 tree1: ab  ba
 tree2: ab  ab

 both are not isomorphic.

 its easy to extend preorder/DFS to
 replace two calls to children with for loop considering the graph is
 N-array tree.



 Thank you,
 Sid.



 On Wed, Sep 14, 2011 at 5:50 PM, bugaboo bharath.sri...@gmail.com wrote:

 @siddharam:

 Performing inorder and pre/postorder will still have false positives.

 Consider 2 trees one with root node a with node b as left child,
 another tree with root node a with node b as its right child.

 Anyway, for binary trees, I am aware of a recursive solution to find
 out similarity or isomorphism. Not sure how this extends for a graph.
 Always thought a DFS and/or BFS should suffice but apparently not.

 On Sep 14, 1:43 am, siddharam suresh siddharam@gmail.com wrote:
  bharath.sriram,
  perform inorder traversal and peorder/postorder traversal on both tree
 then
  compare both the result of two tree.
  Thank you,
  Sid.
 
 
 
 
 
 
 
  On Wed, Sep 14, 2011 at 10:22 AM, bugaboo bharath.sri...@gmail.com
 wrote:
   This brings up another interesting question. How do you find out if 2
   graphs are identical? (By identical, I mean exact similarity and NOT
   isomorphism). Clearly, checking to see if both the DFS traversal and
   BFS traversal match seem to have false positives as Bharathkumar
   mentioned.
 
   On Sep 13, 12:50 am, bharatkumar bagana bagana.bharatku...@gmail.com
 
   wrote:
@nishaanth:
ex:
   1
23
 4
5
bfs:12345
dfs:12345
branching factor of this tree  is not 1 ..
 
On Tue, Sep 13, 2011 at 9:38 AM, nishaanth nishaant...@gmail.com
   wrote:
 yes branching factor should be 1. it can be not equal to 1 only
 for the
 penultimate node. by penultimate node i mean whose children are
 the
   leaves
 of the tree. rest all cases it should be 1.
 
 On Tue, Sep 13, 2011 at 9:24 AM, siddharam suresh 
   siddharam@gmail.com
  wrote:
 
 cant say if there more than one leaf element
 still both the algo give same result
 Thank you,
 Sid.
 
 On Tue, Sep 13, 2011 at 7:52 AM, Sundi sundi...@gmail.com
 wrote:
 
 if the dfs and bfs of a graph is same, does it mean that if the
 branching factor of a graph is one?
 
 abcd
 
 example: both dfs abd bfs are same here
 
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Re: [algogeeks] plzzzzzzzz heeeppppp!!!!!!!!!!1

2011-09-14 Thread abhinav gupta
in my opinion developer profile is better than testing...one

On Thu, Sep 15, 2011 at 10:57 AM, rahul sharma rahul23111...@gmail.comwrote:

 hey guys plz tell the difference b/w testing n develp.  profile ??? n
 joing i n testing profile has growth as much as in develpoer???plz
 tell soon..?should i go in testing profile in lagre industry or in
 developer in medium scale...plz hepl

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Re: [algogeeks] samsung engineering lab interview..

2011-09-13 Thread abhinav gupta
they'll ask question on mostly on c programming and O.S. on thread, process
concepts

On Tue, Sep 13, 2011 at 6:46 PM, sourabh jain sourabhjain...@gmail.comwrote:

 if any one who have selected for samsung ,please tell me the type of
 ques.that can be ask by tech interview..



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Re: [algogeeks] SAMSUNG INDIA SOFTWARE OPERATIONS PVT LTD (SISO)

2011-09-13 Thread abhinav gupta
NIT ALLAHABAD...

On Tue, Sep 13, 2011 at 7:45 PM, navneet kumar
kumarnavneet@gmail.comwrote:

 which college??

 On Tue, Sep 13, 2011 at 7:41 PM, abhinav gupta abhinav@gmail.comwrote:

 any one plzz tell me what they will ask in written test...
 and which type of question...basically??

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 Department of Information Technology,
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 INDIA

 Contact no.:+91-9977935740

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Re: [algogeeks] String

2011-09-12 Thread abhinav gupta
First reverse the whole string then reverse the individual words .Simple !



On Mon, Sep 12, 2011 at 11:08 AM, guna sekaran vgun...@gmail.com wrote:

 String Reverse:

 input :

  welcome to all

 output:

  all to welcome

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Re: [algogeeks] plz help for C output

2011-09-10 Thread abhinav gupta
a) 100

On Sat, Sep 10, 2011 at 12:40 AM, abhishek abhishek.ma...@gmail.com wrote:

 (a)

 #define f(g,g2) g##g2
 int main()
 {
  int var12=100;
  printf(%d,f(var,12));
getch();
}

 what will be the output??

 (b)

 main()
 {
 int i=400,j-300;
 printf(%d...%d);
 }

 (c)

 void main()
 {
 char far *farther,* farthest ;
 printf(%d..%d,sizeof(father),sizeof(farthest));
 }

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Re: [algogeeks] Re: How can we find second largest element in an array... in O(n+logn-2)... give me proof.....

2011-09-10 Thread abhinav gupta
temp2 is second largest element.

On Sat, Sep 10, 2011 at 8:00 AM, abhinav gupta guptaabhinav...@gmail.comwrote:

 I can solve this problem in O(n)
 i=0;
 temp1=arr[0];

 while(i != len)
 {
 if(arr[i]  temp1)
 {
 temp2=temp1;
 temp1=arr[i]
 }
 i++;
 }

 On Sat, Sep 10, 2011 at 7:42 AM, Dave dave_and_da...@juno.com wrote:

 @Replying to my own posting: remove the words one of the numbers that
 lost to, so that the explanation reads

 The question should be How can we find the second largest element in
 an array in n + ceiling(log_2(n)) - 2 comparisons? The answer is to
 use a tournament to select the largest number. The second largest
 number will have lost to the largest. It takes n - 1 comparisons to
 determine the largest number. There are ceiling(log_2(n)) numbers that
 have lost to the largest, and it takes ceiling(log_2(n)) - 1
 comparisons to find the largest of them.

 Dave

 On Sep 10, 9:28 am, Dave dave_and_da...@juno.com wrote:
  @Praveen: The question should be How can we find the second largest
  element in an array in n + ceiling(log_2(n)) - 2 comparisons? The
  answer is to use a tournament to select the largest number. The second
  largest number will have lost to one of the numbers that lost to the
  largest. It takes n - 1 comparisons to determine the largest number.
  There are ceiling(log_2(n)) numbers that have lost to the maximum, and
  it takes ceiling(log_2(n)) - 1 comparisons to find the largest of
  them.
 
  Dave
 
  On Sep 10, 9:18 am, praveen raj praveen0...@gmail.com wrote:
 
 
 
   How can we find second largest element in an array... in O(n
   +logn-2)... give me proof.- Hide quoted text -
 
  - Show quoted text -

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Re: [algogeeks] Re: How can we find second largest element in an array... in O(n+logn-2)... give me proof.....

2011-09-10 Thread abhinav gupta
Oops ..no u hav to quicksort it.

On Sat, Sep 10, 2011 at 8:24 AM, Dave dave_and_da...@juno.com wrote:

 @Abhinav: Does it work correctly on {1, 3, 2}, or, for that matter, on
 any array where the second largest comes after the largest?

 Dave

 On Sep 10, 10:16 am, abhinav gupta guptaabhinav...@gmail.com wrote:
  temp2 is second largest element.
 
  On Sat, Sep 10, 2011 at 8:00 AM, abhinav gupta 
 guptaabhinav...@gmail.comwrote:
 
 
 
 
 
   I can solve this problem in O(n)
   i=0;
   temp1=arr[0];
 
   while(i != len)
   {
   if(arr[i]  temp1)
   {
   temp2=temp1;
   temp1=arr[i]
   }
   i++;
   }
 
   On Sat, Sep 10, 2011 at 7:42 AM, Dave dave_and_da...@juno.com wrote:
 
   @Replying to my own posting: remove the words one of the numbers that
   lost to, so that the explanation reads
 
   The question should be How can we find the second largest element in
   an array in n + ceiling(log_2(n)) - 2 comparisons? The answer is to
   use a tournament to select the largest number. The second largest
   number will have lost to the largest. It takes n - 1 comparisons to
   determine the largest number. There are ceiling(log_2(n)) numbers that
   have lost to the largest, and it takes ceiling(log_2(n)) - 1
   comparisons to find the largest of them.
 
   Dave
 
   On Sep 10, 9:28 am, Dave dave_and_da...@juno.com wrote:
@Praveen: The question should be How can we find the second largest
element in an array in n + ceiling(log_2(n)) - 2 comparisons? The
answer is to use a tournament to select the largest number. The
 second
largest number will have lost to one of the numbers that lost to the
largest. It takes n - 1 comparisons to determine the largest number.
There are ceiling(log_2(n)) numbers that have lost to the maximum,
 and
it takes ceiling(log_2(n)) - 1 comparisons to find the largest of
them.
 
Dave
 
On Sep 10, 9:18 am, praveen raj praveen0...@gmail.com wrote:
 
 How can we find second largest element in an array... in O(n
 +logn-2)... give me proof.- Hide quoted text -
 
- Show quoted text -
 
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  - Show quoted text -

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Re: [algogeeks] Re: How can we find second largest element in an array... in O(n+logn-2)... give me proof.....

2011-09-10 Thread abhinav gupta
sort it in quicksort (descending order)...den take arr[1] --second largest


On Sat, Sep 10, 2011 at 8:34 AM, Akhilesh Vedhera akhileshn...@gmail.comwrote:

 Then the complexity will be nlogn not n and if it is the worst case
 then it would be O(n^2)...

 On Sat, Sep 10, 2011 at 8:58 PM, abhinav gupta 
 guptaabhinav...@gmail.comwrote:

 Oops ..no u hav to quicksort it.


 On Sat, Sep 10, 2011 at 8:24 AM, Dave dave_and_da...@juno.com wrote:

 @Abhinav: Does it work correctly on {1, 3, 2}, or, for that matter, on
 any array where the second largest comes after the largest?

 Dave

 On Sep 10, 10:16 am, abhinav gupta guptaabhinav...@gmail.com wrote:
  temp2 is second largest element.
 
  On Sat, Sep 10, 2011 at 8:00 AM, abhinav gupta 
 guptaabhinav...@gmail.comwrote:
 
 
 
 
 
   I can solve this problem in O(n)
   i=0;
   temp1=arr[0];
 
   while(i != len)
   {
   if(arr[i]  temp1)
   {
   temp2=temp1;
   temp1=arr[i]
   }
   i++;
   }
 
   On Sat, Sep 10, 2011 at 7:42 AM, Dave dave_and_da...@juno.com
 wrote:
 
   @Replying to my own posting: remove the words one of the numbers
 that
   lost to, so that the explanation reads
 
   The question should be How can we find the second largest element
 in
   an array in n + ceiling(log_2(n)) - 2 comparisons? The answer is to
   use a tournament to select the largest number. The second largest
   number will have lost to the largest. It takes n - 1 comparisons to
   determine the largest number. There are ceiling(log_2(n)) numbers
 that
   have lost to the largest, and it takes ceiling(log_2(n)) - 1
   comparisons to find the largest of them.
 
   Dave
 
   On Sep 10, 9:28 am, Dave dave_and_da...@juno.com wrote:
@Praveen: The question should be How can we find the second
 largest
element in an array in n + ceiling(log_2(n)) - 2 comparisons? The
answer is to use a tournament to select the largest number. The
 second
largest number will have lost to one of the numbers that lost to
 the
largest. It takes n - 1 comparisons to determine the largest
 number.
There are ceiling(log_2(n)) numbers that have lost to the maximum,
 and
it takes ceiling(log_2(n)) - 1 comparisons to find the largest of
them.
 
Dave
 
On Sep 10, 9:18 am, praveen raj praveen0...@gmail.com wrote:
 
 How can we find second largest element in an array... in O(n
 +logn-2)... give me proof.- Hide quoted text -
 
- Show quoted text -
 
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