count no of 0s,1s and 2s.fill first 0s followed by 1s den 2s :)
On Thu, Aug 25, 2011 at 11:37 PM, icy` vipe...@gmail.com wrote:
not enough information, imo. Tell me more about the given string...
is the string made up of consecutive integers/characters ? Are there
always the same number of each character type? And the goal is to
braid , like the hairstyle, as much as possible (if the previous
answer is no, all braids cannot be the same)?
On Aug 25, 1:50 pm, sachin sabbarwal algowithsac...@gmail.com wrote:
one solution might be:
to traverse whole list counting no of zeros and 1's.
and then make another string(or overwrite the same) with the required
pattern,append any other characters(suppose all 0's exhausted and some
1's
and 2's were left) left at the end.
is there any better solution??
On Sat, Aug 20, 2011 at 4:20 PM, sukran dhawan sukrandha...@gmail.com
wrote:
i that .ink the soln for this problem is given in geeksforgeeks.com
On Sat, Aug 20, 2011 at 3:27 PM, Sanjay Rajpal srn...@gmail.com
wrote:
Suppose we are given a string .
Make it 012012012012 in O(n) time and O(1) space.
Sanju
:)
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