[algogeeks] Re: Spiral number
Use the property that one of the diagonals has squares of odd numbers. So given a co-ordinate in that diagonal you know the number at that position. For positions not on that diagonal you can add/subtract appropriately and obtain the number you need. -Dhyanesh On 10/18/07, mukesh tiwari [EMAIL PROTECTED] wrote: Hello everybody , i am trying to solve this(http://online- judge.uva.es/ p/v9/903.html) problem and input constrants are such that it is not possible to store the the numbers in the array and print those numbers. So i use the algorithm 1)get the number and return its coordinate 2) take the input all adjacent coordiantes and return the number belonging to that coordinate . i am facing the problem in second part that is if i have given coordiante how to get the number belonging to that coordinate, lets consider the spiral 21 22 23 24 25 26 20 7 8 9 10 19 6 1 2 11 18 5 4 3 12 17 16 15 14 13 let the coordinate of 1 is (0,0) ie origin then coordinate of 11 will be (2,0) and so on . now my problem is if i give coordiante (2,-1) then my program should return 12 . thnkx in advance --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/algogeeks -~--~~~~--~~--~--~---
[algogeeks] Re: Spiral number
On 10/18/07, mukesh tiwari [EMAIL PROTECTED] wrote: 21 22 23 24 25 26 20 7 8 9 10 19 6 1 2 11 18 5 4 3 12 17 16 15 14 13 let the coordinate of 1 is (0,0) ie origin then coordinate of 11 will be (2,0) and so on . now my problem is if i give coordiante (2,-1) then my program should return 12 . well, why are considering 1's co-ord as (0,0) ? I didn't have a look at the original problem , but this looks like a moving window function (w) . and your window length happens to be 5 (b) . -V -- Blog @ http://blizzardzblogs.blogspot.com --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/algogeeks -~--~~~~--~~--~--~---
[algogeeks] Re: Spiral number
Check out these 2 links which discuss the same problem. Some codes are also posted. http://groups.google.com/group/programming-challenges/browse_thread/thread/88bcbea02029c2bf http://groups.google.com/group/programming-challenges/browse_thread/thread/9acf71cb87e9ffd3 This is a good group discussing some of the ACM problems too. On 10/21/07, Dhyanesh (ધયાનેશ) [EMAIL PROTECTED] wrote: Use the property that one of the diagonals has squares of odd numbers. So given a co-ordinate in that diagonal you know the number at that position. For positions not on that diagonal you can add/subtract appropriately and obtain the number you need. -Dhyanesh On 10/18/07, mukesh tiwari [EMAIL PROTECTED] wrote: Hello everybody , i am trying to solve this(http://online- judge.uva.es/ p/v9/903.html) problem and input constrants are such that it is not possible to store the the numbers in the array and print those numbers. So i use the algorithm 1)get the number and return its coordinate 2) take the input all adjacent coordiantes and return the number belonging to that coordinate . i am facing the problem in second part that is if i have given coordiante how to get the number belonging to that coordinate, lets consider the spiral 21 22 23 24 25 26 20 7 8 9 10 19 6 1 2 11 18 5 4 3 12 17 16 15 14 13 let the coordinate of 1 is (0,0) ie origin then coordinate of 11 will be (2,0) and so on . now my problem is if i give coordiante (2,-1) then my program should return 12 . thnkx in advance -- Ciao, Ajinkya --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/algogeeks -~--~~~~--~~--~--~---
