[algogeeks] convert a vector containing octal representation of a number to decimal number
Hi,
I have a vectorint A or an array (for C guys) that contains the octal
representation of a number.
So the array can be something like: [1,5,7] or [7,7,5,6,3,4,2] etc
i.e no number in the array can be = 8.
Now given this array, I need to convert it its decimal representation.
The naive way to do it would be to scan array from left to right, take each
digit, multiply by 8 pow (x) where x is from 0 to ...n and compute sum.
i.e something like:
int oct = 1;
int num = 0;
for(array length){
num+= oct * A[i];
oct = oct * 8;
}
is there a faster way to do this? maybe using some STL container or algorithm. ?
thanks,
sarvesh
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Re: [algogeeks] convert a vector containing octal representation of a number to decimal number
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do.
On Sun, Aug 21, 2011 at 2:25 PM, sarvesh saran
aquarian.thun...@gmail.comwrote:
Hi,
I have a vectorint A or an array (for C guys) that contains the octal
representation of a number.
So the array can be something like: [1,5,7] or [7,7,5,6,3,4,2] etc
i.e no number in the array can be = 8.
Now given this array, I need to convert it its decimal representation.
The naive way to do it would be to scan array from left to right, take each
digit, multiply by 8 pow (x) where x is from 0 to ...n and compute sum.
i.e something like:
int oct = 1;
int num = 0;
for(array length){
num+= oct * A[i];
oct = oct * 8;
}
is there a faster way to do this? maybe using some STL container or
algorithm. ?
thanks,
sarvesh
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Re: [algogeeks] convert a vector containing octal representation of a number to decimal number
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do. Given the number is with in the range of integer.
On Sun, Aug 21, 2011 at 3:40 PM, Nitin Nizhawan nitin.nizha...@gmail.comwrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do.
On Sun, Aug 21, 2011 at 2:25 PM, sarvesh saran aquarian.thun...@gmail.com
wrote:
Hi,
I have a vectorint A or an array (for C guys) that contains the octal
representation of a number.
So the array can be something like: [1,5,7] or [7,7,5,6,3,4,2] etc
i.e no number in the array can be = 8.
Now given this array, I need to convert it its decimal representation.
The naive way to do it would be to scan array from left to right, take
each digit, multiply by 8 pow (x) where x is from 0 to ...n and compute sum.
i.e something like:
int oct = 1;
int num = 0;
for(array length){
num+= oct * A[i];
oct = oct * 8;
}
is there a faster way to do this? maybe using some STL container or
algorithm. ?
thanks,
sarvesh
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Re: [algogeeks] convert a vector containing octal representation of a number to decimal number
Hi Nitin,
thanks that makes sense. I will try that out.
I have another question. Is there a really fast way of converting a
hexadecimal string say 02F9A to its decimal representation in C++?
thanks,
Sarvesh
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 3:41 PM, Nitin Nizhawan nitin.nizha...@gmail.comwrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do. Given the number is with in the range of integer.
On Sun, Aug 21, 2011 at 3:40 PM, Nitin Nizhawan
nitin.nizha...@gmail.comwrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do.
On Sun, Aug 21, 2011 at 2:25 PM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi,
I have a vectorint A or an array (for C guys) that contains the octal
representation of a number.
So the array can be something like: [1,5,7] or [7,7,5,6,3,4,2] etc
i.e no number in the array can be = 8.
Now given this array, I need to convert it its decimal representation.
The naive way to do it would be to scan array from left to right, take
each digit, multiply by 8 pow (x) where x is from 0 to ...n and compute sum.
i.e something like:
int oct = 1;
int num = 0;
for(array length){
num+= oct * A[i];
oct = oct * 8;
}
is there a faster way to do this? maybe using some STL container or
algorithm. ?
thanks,
sarvesh
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Re: [algogeeks] convert a vector containing octal representation of a number to decimal number
Hi your intention was logical OR or BITWISE OR ?
u did Logical.
Sanju
:)
On Sun, Aug 21, 2011 at 3:30 AM, sarvesh saran
aquarian.thun...@gmail.comwrote:
Hi Nitin,
thanks that makes sense. I will try that out.
I have another question. Is there a really fast way of converting a
hexadecimal string say 02F9A to its decimal representation in C++?
thanks,
Sarvesh
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 3:41 PM, Nitin Nizhawan
nitin.nizha...@gmail.comwrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do. Given the number is with in the range of integer.
On Sun, Aug 21, 2011 at 3:40 PM, Nitin Nizhawan nitin.nizha...@gmail.com
wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do.
On Sun, Aug 21, 2011 at 2:25 PM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi,
I have a vectorint A or an array (for C guys) that contains the octal
representation of a number.
So the array can be something like: [1,5,7] or [7,7,5,6,3,4,2] etc
i.e no number in the array can be = 8.
Now given this array, I need to convert it its decimal representation.
The naive way to do it would be to scan array from left to right, take
each digit, multiply by 8 pow (x) where x is from 0 to ...n and compute
sum.
i.e something like:
int oct = 1;
int num = 0;
for(array length){
num+= oct * A[i];
oct = oct * 8;
}
is there a faster way to do this? maybe using some STL container or
algorithm. ?
thanks,
sarvesh
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Re: [algogeeks] convert a vector containing octal representation of a number to decimal number
A[i]3*i
why is it needed to convert from base 8 to base 10??
On Sun, Aug 21, 2011 at 4:07 PM, Sanjay Rajpal srn...@gmail.com wrote:
Hi your intention was logical OR or BITWISE OR ?
u did Logical.
Sanju
:)
On Sun, Aug 21, 2011 at 3:30 AM, sarvesh saran aquarian.thun...@gmail.com
wrote:
Hi Nitin,
thanks that makes sense. I will try that out.
I have another question. Is there a really fast way of converting a
hexadecimal string say 02F9A to its decimal representation in C++?
thanks,
Sarvesh
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 3:41 PM, Nitin Nizhawan nitin.nizha...@gmail.com
wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do. Given the number is with in the range of integer.
On Sun, Aug 21, 2011 at 3:40 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do.
On Sun, Aug 21, 2011 at 2:25 PM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi,
I have a vectorint A or an array (for C guys) that contains the octal
representation of a number.
So the array can be something like: [1,5,7] or [7,7,5,6,3,4,2] etc
i.e no number in the array can be = 8.
Now given this array, I need to convert it its decimal representation.
The naive way to do it would be to scan array from left to right, take
each digit, multiply by 8 pow (x) where x is from 0 to ...n and compute
sum.
i.e something like:
int oct = 1;
int num = 0;
for(array length){
num+= oct * A[i];
oct = oct * 8;
}
is there a faster way to do this? maybe using some STL container or
algorithm. ?
thanks,
sarvesh
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Re: [algogeeks] convert a vector containing octal representation of a number to decimal number
Hi Prakash,
I'll paste the exact description of the problem:
A non-empty array A of N elements contains octal representation of a
non-negative integer K, i.e. each element of A belongs to the interval [0;
7] (both ends included).
Write a function that returns the number of bits set to 1 in the binary
representation of K.
thanks,
Sarvesh
i.e take any decimal number, convert to base 8 and then store each digit of
base 8 representation in an array.
So the question is, given such an array get back the original number.
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 4:13 PM, Prakash D cegprak...@gmail.com wrote:
A[i]3*i
why is it needed to convert from base 8 to base 10??
On Sun, Aug 21, 2011 at 4:07 PM, Sanjay Rajpal srn...@gmail.com wrote:
Hi your intention was logical OR or BITWISE OR ?
u did Logical.
Sanju
:)
On Sun, Aug 21, 2011 at 3:30 AM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi Nitin,
thanks that makes sense. I will try that out.
I have another question. Is there a really fast way of converting a
hexadecimal string say 02F9A to its decimal representation in C++?
thanks,
Sarvesh
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 3:41 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do. Given the number is with in the range of integer.
On Sun, Aug 21, 2011 at 3:40 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do.
On Sun, Aug 21, 2011 at 2:25 PM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi,
I have a vectorint A or an array (for C guys) that contains the
octal representation of a number.
So the array can be something like: [1,5,7] or [7,7,5,6,3,4,2] etc
i.e no number in the array can be = 8.
Now given this array, I need to convert it its decimal representation.
The naive way to do it would be to scan array from left to right, take
each digit, multiply by 8 pow (x) where x is from 0 to ...n and compute
sum.
i.e something like:
int oct = 1;
int num = 0;
for(array length){
num+= oct * A[i];
oct = oct * 8;
}
is there a faster way to do this? maybe using some STL container or
algorithm. ?
thanks,
sarvesh
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Re: [algogeeks] convert a vector containing octal representation of a number to decimal number
@sanjay, oops, my intention was bitwise OR
On Sun, Aug 21, 2011 at 4:25 PM, sarvesh saran
aquarian.thun...@gmail.comwrote:
Hi Prakash,
I'll paste the exact description of the problem:
A non-empty array A of N elements contains octal representation of a
non-negative integer K, i.e. each element of A belongs to the interval [0;
7] (both ends included).
Write a function that returns the number of bits set to 1 in the binary
representation of K.
thanks,
Sarvesh
i.e take any decimal number, convert to base 8 and then store each digit of
base 8 representation in an array.
So the question is, given such an array get back the original number.
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 4:13 PM, Prakash D cegprak...@gmail.com wrote:
A[i]3*i
why is it needed to convert from base 8 to base 10??
On Sun, Aug 21, 2011 at 4:07 PM, Sanjay Rajpal srn...@gmail.com wrote:
Hi your intention was logical OR or BITWISE OR ?
u did Logical.
Sanju
:)
On Sun, Aug 21, 2011 at 3:30 AM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi Nitin,
thanks that makes sense. I will try that out.
I have another question. Is there a really fast way of converting a
hexadecimal string say 02F9A to its decimal representation in C++?
thanks,
Sarvesh
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 3:41 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do. Given the number is with in the range of integer.
On Sun, Aug 21, 2011 at 3:40 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do.
On Sun, Aug 21, 2011 at 2:25 PM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi,
I have a vectorint A or an array (for C guys) that contains the
octal representation of a number.
So the array can be something like: [1,5,7] or [7,7,5,6,3,4,2] etc
i.e no number in the array can be = 8.
Now given this array, I need to convert it its decimal
representation.
The naive way to do it would be to scan array from left to right,
take each digit, multiply by 8 pow (x) where x is from 0 to ...n and
compute
sum.
i.e something like:
int oct = 1;
int num = 0;
for(array length){
num+= oct * A[i];
oct = oct * 8;
}
is there a faster way to do this? maybe using some STL container or
algorithm. ?
thanks,
sarvesh
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Re: [algogeeks] convert a vector containing octal representation of a number to decimal number
@Nitin : could u explain ur logic ?
Sanju
:)
On Sun, Aug 21, 2011 at 9:24 AM, Nitin Nizhawan nitin.nizha...@gmail.comwrote:
@sanjay, oops, my intention was bitwise OR
On Sun, Aug 21, 2011 at 4:25 PM, sarvesh saran aquarian.thun...@gmail.com
wrote:
Hi Prakash,
I'll paste the exact description of the problem:
A non-empty array A of N elements contains octal representation of a
non-negative integer K, i.e. each element of A belongs to the interval [0;
7] (both ends included).
Write a function that returns the number of bits set to 1 in the binary
representation of K.
thanks,
Sarvesh
i.e take any decimal number, convert to base 8 and then store each digit
of base 8 representation in an array.
So the question is, given such an array get back the original number.
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 4:13 PM, Prakash D cegprak...@gmail.com wrote:
A[i]3*i
why is it needed to convert from base 8 to base 10??
On Sun, Aug 21, 2011 at 4:07 PM, Sanjay Rajpal srn...@gmail.com wrote:
Hi your intention was logical OR or BITWISE OR ?
u did Logical.
Sanju
:)
On Sun, Aug 21, 2011 at 3:30 AM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi Nitin,
thanks that makes sense. I will try that out.
I have another question. Is there a really fast way of converting a
hexadecimal string say 02F9A to its decimal representation in C++?
thanks,
Sarvesh
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 3:41 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do. Given the number is with in the range of
integer.
On Sun, Aug 21, 2011 at 3:40 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do.
On Sun, Aug 21, 2011 at 2:25 PM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi,
I have a vectorint A or an array (for C guys) that contains the
octal representation of a number.
So the array can be something like: [1,5,7] or [7,7,5,6,3,4,2] etc
i.e no number in the array can be = 8.
Now given this array, I need to convert it its decimal
representation.
The naive way to do it would be to scan array from left to right,
take each digit, multiply by 8 pow (x) where x is from 0 to ...n and
compute
sum.
i.e something like:
int oct = 1;
int num = 0;
for(array length){
num+= oct * A[i];
oct = oct * 8;
}
is there a faster way to do this? maybe using some STL container or
algorithm. ?
thanks,
sarvesh
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Re: [algogeeks] convert a vector containing octal representation of a number to decimal number
I guess, earlier sarvan simply wanted to calculate
result = SUM {0=i N } A[i]*(8^i)
in which
8^i = 2^(3*i) which is equivalent to right shifting 3*i
since each A[i] is octal it is just 3bits long , we need not add we can
simply shift and do OR.
On Sun, Aug 21, 2011 at 10:16 PM, Sanjay Rajpal srn...@gmail.com wrote:
@Nitin : could u explain ur logic ?
Sanju
:)
On Sun, Aug 21, 2011 at 9:24 AM, Nitin Nizhawan
nitin.nizha...@gmail.comwrote:
@sanjay, oops, my intention was bitwise OR
On Sun, Aug 21, 2011 at 4:25 PM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi Prakash,
I'll paste the exact description of the problem:
A non-empty array A of N elements contains octal representation of a
non-negative integer K, i.e. each element of A belongs to the interval [0;
7] (both ends included).
Write a function that returns the number of bits set to 1 in the binary
representation of K.
thanks,
Sarvesh
i.e take any decimal number, convert to base 8 and then store each digit
of base 8 representation in an array.
So the question is, given such an array get back the original number.
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 4:13 PM, Prakash D cegprak...@gmail.com wrote:
A[i]3*i
why is it needed to convert from base 8 to base 10??
On Sun, Aug 21, 2011 at 4:07 PM, Sanjay Rajpal srn...@gmail.comwrote:
Hi your intention was logical OR or BITWISE OR ?
u did Logical.
Sanju
:)
On Sun, Aug 21, 2011 at 3:30 AM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi Nitin,
thanks that makes sense. I will try that out.
I have another question. Is there a really fast way of converting a
hexadecimal string say 02F9A to its decimal representation in C++?
thanks,
Sarvesh
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 3:41 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do. Given the number is with in the range of
integer.
On Sun, Aug 21, 2011 at 3:40 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do.
On Sun, Aug 21, 2011 at 2:25 PM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi,
I have a vectorint A or an array (for C guys) that contains the
octal representation of a number.
So the array can be something like: [1,5,7] or [7,7,5,6,3,4,2] etc
i.e no number in the array can be = 8.
Now given this array, I need to convert it its decimal
representation.
The naive way to do it would be to scan array from left to right,
take each digit, multiply by 8 pow (x) where x is from 0 to ...n and
compute
sum.
i.e something like:
int oct = 1;
int num = 0;
for(array length){
num+= oct * A[i];
oct = oct * 8;
}
is there a faster way to do this? maybe using some STL container or
algorithm. ?
thanks,
sarvesh
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Re: [algogeeks] convert a vector containing octal representation of a number to decimal number
ok. got it Nitin. thanx :)
Sanju
:)
On Sun, Aug 21, 2011 at 10:06 AM, Nitin Nizhawan
nitin.nizha...@gmail.comwrote:
I guess, earlier sarvan simply wanted to calculate
result = SUM {0=i N } A[i]*(8^i)
in which
8^i = 2^(3*i) which is equivalent to right shifting 3*i
since each A[i] is octal it is just 3bits long , we need not add we can
simply shift and do OR.
On Sun, Aug 21, 2011 at 10:16 PM, Sanjay Rajpal srn...@gmail.com wrote:
@Nitin : could u explain ur logic ?
Sanju
:)
On Sun, Aug 21, 2011 at 9:24 AM, Nitin Nizhawan nitin.nizha...@gmail.com
wrote:
@sanjay, oops, my intention was bitwise OR
On Sun, Aug 21, 2011 at 4:25 PM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi Prakash,
I'll paste the exact description of the problem:
A non-empty array A of N elements contains octal representation of a
non-negative integer K, i.e. each element of A belongs to the interval [0;
7] (both ends included).
Write a function that returns the number of bits set to 1 in the binary
representation of K.
thanks,
Sarvesh
i.e take any decimal number, convert to base 8 and then store each digit
of base 8 representation in an array.
So the question is, given such an array get back the original number.
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 4:13 PM, Prakash D cegprak...@gmail.comwrote:
A[i]3*i
why is it needed to convert from base 8 to base 10??
On Sun, Aug 21, 2011 at 4:07 PM, Sanjay Rajpal srn...@gmail.comwrote:
Hi your intention was logical OR or BITWISE OR ?
u did Logical.
Sanju
:)
On Sun, Aug 21, 2011 at 3:30 AM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi Nitin,
thanks that makes sense. I will try that out.
I have another question. Is there a really fast way of converting a
hexadecimal string say 02F9A to its decimal representation in C++?
thanks,
Sarvesh
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 3:41 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do. Given the number is with in the range of
integer.
On Sun, Aug 21, 2011 at 3:40 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do.
On Sun, Aug 21, 2011 at 2:25 PM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi,
I have a vectorint A or an array (for C guys) that contains the
octal representation of a number.
So the array can be something like: [1,5,7] or [7,7,5,6,3,4,2] etc
i.e no number in the array can be = 8.
Now given this array, I need to convert it its decimal
representation.
The naive way to do it would be to scan array from left to right,
take each digit, multiply by 8 pow (x) where x is from 0 to ...n and
compute
sum.
i.e something like:
int oct = 1;
int num = 0;
for(array length){
num+= oct * A[i];
oct = oct * 8;
}
is there a faster way to do this? maybe using some STL container or
algorithm. ?
thanks,
sarvesh
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Re: [algogeeks] convert a vector containing octal representation of a number to decimal number
Hi Sarvesh,
For this problem this is my solution.
A=[1,5,6]
n=len(A)
Ans=[0,1,1,2,1,2,2,3]
count=0
for i in range(0,n):
count=count+Ans[A[i]]
print count
Is there any flaw?
Thanks Regards,
Anantha Krishnan
On Sun, Aug 21, 2011 at 4:25 PM, sarvesh saran
aquarian.thun...@gmail.comwrote:
Hi Prakash,
I'll paste the exact description of the problem:
A non-empty array A of N elements contains octal representation of a
non-negative integer K, i.e. each element of A belongs to the interval [0;
7] (both ends included).
Write a function that returns the number of bits set to 1 in the binary
representation of K.
thanks,
Sarvesh
i.e take any decimal number, convert to base 8 and then store each digit of
base 8 representation in an array.
So the question is, given such an array get back the original number.
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 4:13 PM, Prakash D cegprak...@gmail.com wrote:
A[i]3*i
why is it needed to convert from base 8 to base 10??
On Sun, Aug 21, 2011 at 4:07 PM, Sanjay Rajpal srn...@gmail.com wrote:
Hi your intention was logical OR or BITWISE OR ?
u did Logical.
Sanju
:)
On Sun, Aug 21, 2011 at 3:30 AM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi Nitin,
thanks that makes sense. I will try that out.
I have another question. Is there a really fast way of converting a
hexadecimal string say 02F9A to its decimal representation in C++?
thanks,
Sarvesh
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 3:41 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do. Given the number is with in the range of integer.
On Sun, Aug 21, 2011 at 3:40 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do.
On Sun, Aug 21, 2011 at 2:25 PM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi,
I have a vectorint A or an array (for C guys) that contains the
octal representation of a number.
So the array can be something like: [1,5,7] or [7,7,5,6,3,4,2] etc
i.e no number in the array can be = 8.
Now given this array, I need to convert it its decimal
representation.
The naive way to do it would be to scan array from left to right,
take each digit, multiply by 8 pow (x) where x is from 0 to ...n and
compute
sum.
i.e something like:
int oct = 1;
int num = 0;
for(array length){
num+= oct * A[i];
oct = oct * 8;
}
is there a faster way to do this? maybe using some STL container or
algorithm. ?
thanks,
sarvesh
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Re: [algogeeks] convert a vector containing octal representation of a number to decimal number
This will print the no. of bits set, not the decimal equivalent of the
number.
Sanju
:)
On Sun, Aug 21, 2011 at 11:18 AM, Anantha Krishnan
ananthakrishnan@gmail.com wrote:
Hi Sarvesh,
For this problem this is my solution.
A=[1,5,6]
n=len(A)
Ans=[0,1,1,2,1,2,2,3]
count=0
for i in range(0,n):
count=count+Ans[A[i]]
print count
Is there any flaw?
Thanks Regards,
Anantha Krishnan
On Sun, Aug 21, 2011 at 4:25 PM, sarvesh saran aquarian.thun...@gmail.com
wrote:
Hi Prakash,
I'll paste the exact description of the problem:
A non-empty array A of N elements contains octal representation of a
non-negative integer K, i.e. each element of A belongs to the interval [0;
7] (both ends included).
Write a function that returns the number of bits set to 1 in the binary
representation of K.
thanks,
Sarvesh
i.e take any decimal number, convert to base 8 and then store each digit
of base 8 representation in an array.
So the question is, given such an array get back the original number.
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 4:13 PM, Prakash D cegprak...@gmail.com wrote:
A[i]3*i
why is it needed to convert from base 8 to base 10??
On Sun, Aug 21, 2011 at 4:07 PM, Sanjay Rajpal srn...@gmail.com wrote:
Hi your intention was logical OR or BITWISE OR ?
u did Logical.
Sanju
:)
On Sun, Aug 21, 2011 at 3:30 AM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi Nitin,
thanks that makes sense. I will try that out.
I have another question. Is there a really fast way of converting a
hexadecimal string say 02F9A to its decimal representation in C++?
thanks,
Sarvesh
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 3:41 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do. Given the number is with in the range of
integer.
On Sun, Aug 21, 2011 at 3:40 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do.
On Sun, Aug 21, 2011 at 2:25 PM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi,
I have a vectorint A or an array (for C guys) that contains the
octal representation of a number.
So the array can be something like: [1,5,7] or [7,7,5,6,3,4,2] etc
i.e no number in the array can be = 8.
Now given this array, I need to convert it its decimal
representation.
The naive way to do it would be to scan array from left to right,
take each digit, multiply by 8 pow (x) where x is from 0 to ...n and
compute
sum.
i.e something like:
int oct = 1;
int num = 0;
for(array length){
num+= oct * A[i];
oct = oct * 8;
}
is there a faster way to do this? maybe using some STL container or
algorithm. ?
thanks,
sarvesh
--
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Re: [algogeeks] convert a vector containing octal representation of a number to decimal number
Hi Anantha,
No. that makes sense. thanks!
I am now trying to solve a really tricky problem. It can be found here:
http://stackoverflow.com/questions/5370134/interesting-programming-interview-question
A user called Xanatos has given a solution but i cannot make any sense of
it.
-sarvesh
On Sun, Aug 21, 2011 at 11:48 PM, Anantha Krishnan
ananthakrishnan@gmail.com wrote:
Hi Sarvesh,
For this problem this is my solution.
A=[1,5,6]
n=len(A)
Ans=[0,1,1,2,1,2,2,3]
count=0
for i in range(0,n):
count=count+Ans[A[i]]
print count
Is there any flaw?
Thanks Regards,
Anantha Krishnan
On Sun, Aug 21, 2011 at 4:25 PM, sarvesh saran aquarian.thun...@gmail.com
wrote:
Hi Prakash,
I'll paste the exact description of the problem:
A non-empty array A of N elements contains octal representation of a
non-negative integer K, i.e. each element of A belongs to the interval [0;
7] (both ends included).
Write a function that returns the number of bits set to 1 in the binary
representation of K.
thanks,
Sarvesh
i.e take any decimal number, convert to base 8 and then store each digit
of base 8 representation in an array.
So the question is, given such an array get back the original number.
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 4:13 PM, Prakash D cegprak...@gmail.com wrote:
A[i]3*i
why is it needed to convert from base 8 to base 10??
On Sun, Aug 21, 2011 at 4:07 PM, Sanjay Rajpal srn...@gmail.com wrote:
Hi your intention was logical OR or BITWISE OR ?
u did Logical.
Sanju
:)
On Sun, Aug 21, 2011 at 3:30 AM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi Nitin,
thanks that makes sense. I will try that out.
I have another question. Is there a really fast way of converting a
hexadecimal string say 02F9A to its decimal representation in C++?
thanks,
Sarvesh
thanks,
Sarvesh
On Sun, Aug 21, 2011 at 3:41 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do. Given the number is with in the range of
integer.
On Sun, Aug 21, 2011 at 3:40 PM, Nitin Nizhawan
nitin.nizha...@gmail.com wrote:
int num = 0;
for(int i=0;iA.size();i++){
num=num||(A[i]3*i);
}
printf(%d,num);
I think this will do.
On Sun, Aug 21, 2011 at 2:25 PM, sarvesh saran
aquarian.thun...@gmail.com wrote:
Hi,
I have a vectorint A or an array (for C guys) that contains the
octal representation of a number.
So the array can be something like: [1,5,7] or [7,7,5,6,3,4,2] etc
i.e no number in the array can be = 8.
Now given this array, I need to convert it its decimal
representation.
The naive way to do it would be to scan array from left to right,
take each digit, multiply by 8 pow (x) where x is from 0 to ...n and
compute
sum.
i.e something like:
int oct = 1;
int num = 0;
for(array length){
num+= oct * A[i];
oct = oct * 8;
}
is there a faster way to do this? maybe using some STL container or
algorithm. ?
thanks,
sarvesh
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