Re: [algogeeks] Re: Printing a Number triangle
I was asked to find out the no of rows given n . i.e. how we say 4 rows for
10 ???
On 14 Aug 2011 10:54, sagar pareek sagarpar...@gmail.com wrote:
here is sudo code
take two variables
int max=1;
int count=1;
int i,total_no_of_rows;
while(total_no_of_rows--)
{
for(i=0;icount;i++)
{
printf(%d ,max-i);
}
printf(\n);
count++;
max+=count;
}
On Sun, Aug 14, 2011 at 10:25 AM, Rahul raikra...@gmail.com wrote:
@Beginner
If You Know How to implement a series whose difference in terms form An
Arithmetic Progression
Then Is quite easy
to print the (n)TH Line
Add n to the highest number seen so far and then subtract the 1 for n
times (p = n-- , check for p )
@Everyone Else
Can anyone one think of a more elegant method , to find #rows
Rahul
On Sun, Aug 14, 2011 at 10:09 AM, Ankur Khurana ankur.kkhur...@gmail.com
wrote:
to print from 10 to 7 in the row number 4. here prev will be 6.
On Sun, Aug 14, 2011 at 10:05 AM, AASHISH SUMAN
aashish.barn...@gmail.com wrote:
@ankur
what is the need of
prev=((i-)*i)/2;
On Sun, Aug 14, 2011 at 9:51 AM, Ankur Khurana
ankur.kkhur...@gmail.com
wrote:
see , we can see that
first lline have 1 number, second have 2 and third have 3 .and so
on. we can observe that first number of every row is sum of first k
narutal
number, where k is the row number. so for k=4, n=((4+1)*4)/2=10;
so run a for loop,
for(int i=1;inum_rows;i++)
{
prev=((i-)*i)/2;
k=((i+1)*i)/2;
for(int j=k;i;kprev;j--)
{
coutprev ;
}
coutendl;
}
On Sun, Aug 14, 2011 at 9:43 AM, Dave dave_and_da...@juno.com wrote:
@Beginner: The largest number n in row r satisfies n = (r^2 + r) / 2.
So using the Quadratic Formula gives
r = ( sqrt( 8*n + 1 ) - 1 ) / 2.
For the row number r for any n (not necessarily the largest one in a
row),
r = ceil( sqrt( 8*n + 1 ) - 1 ) / 2 )
where ceil( x ) is the smallest integer not exceeding x.
Dave
On Aug 13, 10:22 pm, Beginner murugavidya1...@gmail.com wrote:
How to print this triangle?
1
3 2
6 5 4
10 9 8 7
and how to find the number of rows if n is given?
For ex if n=10 how to find num of rows=4??
Is it Log 10 to the base of 2!!
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Computer Science
Netaji Subhas Institute Of Technology
Delhi.
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MCA FINAL YEAR
*
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Computer Science
Netaji Subhas Institute Of Technology
Delhi.
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Re: [algogeeks] Re: Printing a Number triangle
Dave has given you the formula
Rahul
On Sun, Aug 14, 2011 at 7:49 PM, muruga vel murugavidya1...@gmail.comwrote:
I was asked to find out the no of rows given n . i.e. how we say 4 rows
for 10 ???
On 14 Aug 2011 10:54, sagar pareek sagarpar...@gmail.com wrote:
here is sudo code
take two variables
int max=1;
int count=1;
int i,total_no_of_rows;
while(total_no_of_rows--)
{
for(i=0;icount;i++)
{
printf(%d ,max-i);
}
printf(\n);
count++;
max+=count;
}
On Sun, Aug 14, 2011 at 10:25 AM, Rahul raikra...@gmail.com wrote:
@Beginner
If You Know How to implement a series whose difference in terms form An
Arithmetic Progression
Then Is quite easy
to print the (n)TH Line
Add n to the highest number seen so far and then subtract the 1 for n
times (p = n-- , check for p )
@Everyone Else
Can anyone one think of a more elegant method , to find #rows
Rahul
On Sun, Aug 14, 2011 at 10:09 AM, Ankur Khurana
ankur.kkhur...@gmail.comwrote:
to print from 10 to 7 in the row number 4. here prev will be 6.
On Sun, Aug 14, 2011 at 10:05 AM, AASHISH SUMAN
aashish.barn...@gmail.com wrote:
@ankur
what is the need of
prev=((i-)*i)/2;
On Sun, Aug 14, 2011 at 9:51 AM, Ankur Khurana
ankur.kkhur...@gmail.com
wrote:
see , we can see that
first lline have 1 number, second have 2 and third have 3 .and so
on. we can observe that first number of every row is sum of first k
narutal
number, where k is the row number. so for k=4, n=((4+1)*4)/2=10;
so run a for loop,
for(int i=1;inum_rows;i++)
{
prev=((i-)*i)/2;
k=((i+1)*i)/2;
for(int j=k;i;kprev;j--)
{
coutprev ;
}
coutendl;
}
On Sun, Aug 14, 2011 at 9:43 AM, Dave dave_and_da...@juno.com
wrote:
@Beginner: The largest number n in row r satisfies n = (r^2 + r) /
2.
So using the Quadratic Formula gives
r = ( sqrt( 8*n + 1 ) - 1 ) / 2.
For the row number r for any n (not necessarily the largest one in a
row),
r = ceil( sqrt( 8*n + 1 ) - 1 ) / 2 )
where ceil( x ) is the smallest integer not exceeding x.
Dave
On Aug 13, 10:22 pm, Beginner murugavidya1...@gmail.com wrote:
How to print this triangle?
1
3 2
6 5 4
10 9 8 7
and how to find the number of rows if n is given?
For ex if n=10 how to find num of rows=4??
Is it Log 10 to the base of 2!!
--
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--
Ankur Khurana
Computer Science
Netaji Subhas Institute Of Technology
Delhi.
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AASHISH SUMAN
MCA FINAL YEAR
*
*NIT DURGAPUR*
*+91-9547969906*
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Computer Science
Netaji Subhas Institute Of Technology
Delhi.
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COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD
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You received this message because you are
Re: [algogeeks] Re: Printing a Number triangle
plz tell me that for this triangle.. if 12 is given then what to do?
On Sun, Aug 14, 2011 at 7:49 PM, muruga vel murugavidya1...@gmail.comwrote:
I was asked to find out the no of rows given n . i.e. how we say 4 rows
for 10 ???
On 14 Aug 2011 10:54, sagar pareek sagarpar...@gmail.com wrote:
here is sudo code
take two variables
int max=1;
int count=1;
int i,total_no_of_rows;
while(total_no_of_rows--)
{
for(i=0;icount;i++)
{
printf(%d ,max-i);
}
printf(\n);
count++;
max+=count;
}
On Sun, Aug 14, 2011 at 10:25 AM, Rahul raikra...@gmail.com wrote:
@Beginner
If You Know How to implement a series whose difference in terms form An
Arithmetic Progression
Then Is quite easy
to print the (n)TH Line
Add n to the highest number seen so far and then subtract the 1 for n
times (p = n-- , check for p )
@Everyone Else
Can anyone one think of a more elegant method , to find #rows
Rahul
On Sun, Aug 14, 2011 at 10:09 AM, Ankur Khurana
ankur.kkhur...@gmail.comwrote:
to print from 10 to 7 in the row number 4. here prev will be 6.
On Sun, Aug 14, 2011 at 10:05 AM, AASHISH SUMAN
aashish.barn...@gmail.com wrote:
@ankur
what is the need of
prev=((i-)*i)/2;
On Sun, Aug 14, 2011 at 9:51 AM, Ankur Khurana
ankur.kkhur...@gmail.com
wrote:
see , we can see that
first lline have 1 number, second have 2 and third have 3 .and so
on. we can observe that first number of every row is sum of first k
narutal
number, where k is the row number. so for k=4, n=((4+1)*4)/2=10;
so run a for loop,
for(int i=1;inum_rows;i++)
{
prev=((i-)*i)/2;
k=((i+1)*i)/2;
for(int j=k;i;kprev;j--)
{
coutprev ;
}
coutendl;
}
On Sun, Aug 14, 2011 at 9:43 AM, Dave dave_and_da...@juno.com
wrote:
@Beginner: The largest number n in row r satisfies n = (r^2 + r) /
2.
So using the Quadratic Formula gives
r = ( sqrt( 8*n + 1 ) - 1 ) / 2.
For the row number r for any n (not necessarily the largest one in a
row),
r = ceil( sqrt( 8*n + 1 ) - 1 ) / 2 )
where ceil( x ) is the smallest integer not exceeding x.
Dave
On Aug 13, 10:22 pm, Beginner murugavidya1...@gmail.com wrote:
How to print this triangle?
1
3 2
6 5 4
10 9 8 7
and how to find the number of rows if n is given?
For ex if n=10 how to find num of rows=4??
Is it Log 10 to the base of 2!!
--
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--
Ankur Khurana
Computer Science
Netaji Subhas Institute Of Technology
Delhi.
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AASHISH SUMAN
MCA FINAL YEAR
*
*NIT DURGAPUR*
*+91-9547969906*
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Computer Science
Netaji Subhas Institute Of Technology
Delhi.
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COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD
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You received this
Re: [algogeeks] Re: Printing a Number triangle
8 times 12 is 96
96 + 1
is
97
take sqrt(97)
9.8488578017961047217462114149176
now 9.8488578017961047217462114149176 minus 1
EQUALS
8.8488578017961047217462114149176
Half IT
And Take The Ceiling of it = 5
On Sun, Aug 14, 2011 at 8:05 PM, Anika Jain anika.jai...@gmail.com wrote:
plz tell me that for this triangle.. if 12 is given then what to do?
On Sun, Aug 14, 2011 at 7:49 PM, muruga vel murugavidya1...@gmail.comwrote:
I was asked to find out the no of rows given n . i.e. how we say 4 rows
for 10 ???
On 14 Aug 2011 10:54, sagar pareek sagarpar...@gmail.com wrote:
here is sudo code
take two variables
int max=1;
int count=1;
int i,total_no_of_rows;
while(total_no_of_rows--)
{
for(i=0;icount;i++)
{
printf(%d ,max-i);
}
printf(\n);
count++;
max+=count;
}
On Sun, Aug 14, 2011 at 10:25 AM, Rahul raikra...@gmail.com wrote:
@Beginner
If You Know How to implement a series whose difference in terms form An
Arithmetic Progression
Then Is quite easy
to print the (n)TH Line
Add n to the highest number seen so far and then subtract the 1 for n
times (p = n-- , check for p )
@Everyone Else
Can anyone one think of a more elegant method , to find #rows
Rahul
On Sun, Aug 14, 2011 at 10:09 AM, Ankur Khurana
ankur.kkhur...@gmail.comwrote:
to print from 10 to 7 in the row number 4. here prev will be 6.
On Sun, Aug 14, 2011 at 10:05 AM, AASHISH SUMAN
aashish.barn...@gmail.com wrote:
@ankur
what is the need of
prev=((i-)*i)/2;
On Sun, Aug 14, 2011 at 9:51 AM, Ankur Khurana
ankur.kkhur...@gmail.com
wrote:
see , we can see that
first lline have 1 number, second have 2 and third have 3 .and
so
on. we can observe that first number of every row is sum of first k
narutal
number, where k is the row number. so for k=4, n=((4+1)*4)/2=10;
so run a for loop,
for(int i=1;inum_rows;i++)
{
prev=((i-)*i)/2;
k=((i+1)*i)/2;
for(int j=k;i;kprev;j--)
{
coutprev ;
}
coutendl;
}
On Sun, Aug 14, 2011 at 9:43 AM, Dave dave_and_da...@juno.com
wrote:
@Beginner: The largest number n in row r satisfies n = (r^2 + r) /
2.
So using the Quadratic Formula gives
r = ( sqrt( 8*n + 1 ) - 1 ) / 2.
For the row number r for any n (not necessarily the largest one in
a
row),
r = ceil( sqrt( 8*n + 1 ) - 1 ) / 2 )
where ceil( x ) is the smallest integer not exceeding x.
Dave
On Aug 13, 10:22 pm, Beginner murugavidya1...@gmail.com wrote:
How to print this triangle?
1
3 2
6 5 4
10 9 8 7
and how to find the number of rows if n is given?
For ex if n=10 how to find num of rows=4??
Is it Log 10 to the base of 2!!
--
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--
Ankur Khurana
Computer Science
Netaji Subhas Institute Of Technology
Delhi.
--
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AASHISH SUMAN
MCA FINAL YEAR
*
*NIT DURGAPUR*
*+91-9547969906*
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Computer Science
Netaji Subhas Institute Of Technology
Delhi.
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COMPUTER SCIENCE AND ENGINEERING
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Re: [algogeeks] Re: Printing a Number triangle
see , we can see that
first lline have 1 number, second have 2 and third have 3 .and so on. we
can observe that first number of every row is sum of first k narutal number,
where k is the row number. so for k=4, n=((4+1)*4)/2=10;
so run a for loop,
for(int i=1;inum_rows;i++)
{
prev=((i-)*i)/2;
k=((i+1)*i)/2;
for(int j=k;i;kprev;j--)
{
coutprev ;
}
coutendl;
}
On Sun, Aug 14, 2011 at 9:43 AM, Dave dave_and_da...@juno.com wrote:
@Beginner: The largest number n in row r satisfies n = (r^2 + r) / 2.
So using the Quadratic Formula gives
r = ( sqrt( 8*n + 1 ) - 1 ) / 2.
For the row number r for any n (not necessarily the largest one in a
row),
r = ceil( sqrt( 8*n + 1 ) - 1 ) / 2 )
where ceil( x ) is the smallest integer not exceeding x.
Dave
On Aug 13, 10:22 pm, Beginner murugavidya1...@gmail.com wrote:
How to print this triangle?
1
3 2
6 5 4
10 9 8 7
and how to find the number of rows if n is given?
For ex if n=10 how to find num of rows=4??
Is it Log 10 to the base of 2!!
--
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Algorithm Geeks group.
To post to this group, send email to algogeeks@googlegroups.com.
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For more options, visit this group at
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--
Ankur Khurana
Computer Science
Netaji Subhas Institute Of Technology
Delhi.
--
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Re: [algogeeks] Re: Printing a Number triangle
@ankur
what is the need of
prev=((i-)*i)/2;
On Sun, Aug 14, 2011 at 9:51 AM, Ankur Khurana ankur.kkhur...@gmail.comwrote:
see , we can see that
first lline have 1 number, second have 2 and third have 3 .and so on.
we can observe that first number of every row is sum of first k narutal
number, where k is the row number. so for k=4, n=((4+1)*4)/2=10;
so run a for loop,
for(int i=1;inum_rows;i++)
{
prev=((i-)*i)/2;
k=((i+1)*i)/2;
for(int j=k;i;kprev;j--)
{
coutprev ;
}
coutendl;
}
On Sun, Aug 14, 2011 at 9:43 AM, Dave dave_and_da...@juno.com wrote:
@Beginner: The largest number n in row r satisfies n = (r^2 + r) / 2.
So using the Quadratic Formula gives
r = ( sqrt( 8*n + 1 ) - 1 ) / 2.
For the row number r for any n (not necessarily the largest one in a
row),
r = ceil( sqrt( 8*n + 1 ) - 1 ) / 2 )
where ceil( x ) is the smallest integer not exceeding x.
Dave
On Aug 13, 10:22 pm, Beginner murugavidya1...@gmail.com wrote:
How to print this triangle?
1
3 2
6 5 4
10 9 8 7
and how to find the number of rows if n is given?
For ex if n=10 how to find num of rows=4??
Is it Log 10 to the base of 2!!
--
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Ankur Khurana
Computer Science
Netaji Subhas Institute Of Technology
Delhi.
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*WITH BEST REGARDS :
AASHISH SUMAN
MCA FINAL YEAR
*
*NIT DURGAPUR*
*+91-9547969906*
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Re: [algogeeks] Re: Printing a Number triangle
to print from 10 to 7 in the row number 4. here prev will be 6.
On Sun, Aug 14, 2011 at 10:05 AM, AASHISH SUMAN
aashish.barn...@gmail.comwrote:
@ankur
what is the need of
prev=((i-)*i)/2;
On Sun, Aug 14, 2011 at 9:51 AM, Ankur Khurana
ankur.kkhur...@gmail.comwrote:
see , we can see that
first lline have 1 number, second have 2 and third have 3 .and so on.
we can observe that first number of every row is sum of first k narutal
number, where k is the row number. so for k=4, n=((4+1)*4)/2=10;
so run a for loop,
for(int i=1;inum_rows;i++)
{
prev=((i-)*i)/2;
k=((i+1)*i)/2;
for(int j=k;i;kprev;j--)
{
coutprev ;
}
coutendl;
}
On Sun, Aug 14, 2011 at 9:43 AM, Dave dave_and_da...@juno.com wrote:
@Beginner: The largest number n in row r satisfies n = (r^2 + r) / 2.
So using the Quadratic Formula gives
r = ( sqrt( 8*n + 1 ) - 1 ) / 2.
For the row number r for any n (not necessarily the largest one in a
row),
r = ceil( sqrt( 8*n + 1 ) - 1 ) / 2 )
where ceil( x ) is the smallest integer not exceeding x.
Dave
On Aug 13, 10:22 pm, Beginner murugavidya1...@gmail.com wrote:
How to print this triangle?
1
3 2
6 5 4
10 9 8 7
and how to find the number of rows if n is given?
For ex if n=10 how to find num of rows=4??
Is it Log 10 to the base of 2!!
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Ankur Khurana
Computer Science
Netaji Subhas Institute Of Technology
Delhi.
--
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*WITH BEST REGARDS :
AASHISH SUMAN
MCA FINAL YEAR
*
*NIT DURGAPUR*
*+91-9547969906*
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--
Ankur Khurana
Computer Science
Netaji Subhas Institute Of Technology
Delhi.
--
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Re: [algogeeks] Re: Printing a Number triangle
@Beginner
If You Know How to implement a series whose difference in terms form An
Arithmetic Progression
Then Is quite easy
to print the (n)TH Line
Add n to the highest number seen so far and then subtract the 1 for n times
(p = n-- , check for p )
@Everyone Else
Can anyone one think of a more elegant method , to find #rows
Rahul
On Sun, Aug 14, 2011 at 10:09 AM, Ankur Khurana ankur.kkhur...@gmail.comwrote:
to print from 10 to 7 in the row number 4. here prev will be 6.
On Sun, Aug 14, 2011 at 10:05 AM, AASHISH SUMAN aashish.barn...@gmail.com
wrote:
@ankur
what is the need of
prev=((i-)*i)/2;
On Sun, Aug 14, 2011 at 9:51 AM, Ankur Khurana
ankur.kkhur...@gmail.comwrote:
see , we can see that
first lline have 1 number, second have 2 and third have 3 .and so on.
we can observe that first number of every row is sum of first k narutal
number, where k is the row number. so for k=4, n=((4+1)*4)/2=10;
so run a for loop,
for(int i=1;inum_rows;i++)
{
prev=((i-)*i)/2;
k=((i+1)*i)/2;
for(int j=k;i;kprev;j--)
{
coutprev ;
}
coutendl;
}
On Sun, Aug 14, 2011 at 9:43 AM, Dave dave_and_da...@juno.com wrote:
@Beginner: The largest number n in row r satisfies n = (r^2 + r) / 2.
So using the Quadratic Formula gives
r = ( sqrt( 8*n + 1 ) - 1 ) / 2.
For the row number r for any n (not necessarily the largest one in a
row),
r = ceil( sqrt( 8*n + 1 ) - 1 ) / 2 )
where ceil( x ) is the smallest integer not exceeding x.
Dave
On Aug 13, 10:22 pm, Beginner murugavidya1...@gmail.com wrote:
How to print this triangle?
1
3 2
6 5 4
10 9 8 7
and how to find the number of rows if n is given?
For ex if n=10 how to find num of rows=4??
Is it Log 10 to the base of 2!!
--
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--
Ankur Khurana
Computer Science
Netaji Subhas Institute Of Technology
Delhi.
--
You received this message because you are subscribed to the Google Groups
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--
*WITH BEST REGARDS :
AASHISH SUMAN
MCA FINAL YEAR
*
*NIT DURGAPUR*
*+91-9547969906*
--
You received this message because you are subscribed to the Google Groups
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--
Ankur Khurana
Computer Science
Netaji Subhas Institute Of Technology
Delhi.
--
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Re: [algogeeks] Re: Printing a Number triangle
here is sudo code
take two variables
int max=1;
int count=1;
int i,total_no_of_rows;
while(total_no_of_rows--)
{
for(i=0;icount;i++)
{
printf(%d ,max-i);
}
printf(\n);
count++;
max+=count;
}
On Sun, Aug 14, 2011 at 10:25 AM, Rahul raikra...@gmail.com wrote:
@Beginner
If You Know How to implement a series whose difference in terms form An
Arithmetic Progression
Then Is quite easy
to print the (n)TH Line
Add n to the highest number seen so far and then subtract the 1 for n
times (p = n-- , check for p )
@Everyone Else
Can anyone one think of a more elegant method , to find #rows
Rahul
On Sun, Aug 14, 2011 at 10:09 AM, Ankur Khurana
ankur.kkhur...@gmail.comwrote:
to print from 10 to 7 in the row number 4. here prev will be 6.
On Sun, Aug 14, 2011 at 10:05 AM, AASHISH SUMAN
aashish.barn...@gmail.com wrote:
@ankur
what is the need of
prev=((i-)*i)/2;
On Sun, Aug 14, 2011 at 9:51 AM, Ankur Khurana ankur.kkhur...@gmail.com
wrote:
see , we can see that
first lline have 1 number, second have 2 and third have 3 .and so
on. we can observe that first number of every row is sum of first k narutal
number, where k is the row number. so for k=4, n=((4+1)*4)/2=10;
so run a for loop,
for(int i=1;inum_rows;i++)
{
prev=((i-)*i)/2;
k=((i+1)*i)/2;
for(int j=k;i;kprev;j--)
{
coutprev ;
}
coutendl;
}
On Sun, Aug 14, 2011 at 9:43 AM, Dave dave_and_da...@juno.com wrote:
@Beginner: The largest number n in row r satisfies n = (r^2 + r) / 2.
So using the Quadratic Formula gives
r = ( sqrt( 8*n + 1 ) - 1 ) / 2.
For the row number r for any n (not necessarily the largest one in a
row),
r = ceil( sqrt( 8*n + 1 ) - 1 ) / 2 )
where ceil( x ) is the smallest integer not exceeding x.
Dave
On Aug 13, 10:22 pm, Beginner murugavidya1...@gmail.com wrote:
How to print this triangle?
1
3 2
6 5 4
10 9 8 7
and how to find the number of rows if n is given?
For ex if n=10 how to find num of rows=4??
Is it Log 10 to the base of 2!!
--
You received this message because you are subscribed to the Google
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--
Ankur Khurana
Computer Science
Netaji Subhas Institute Of Technology
Delhi.
--
You received this message because you are subscribed to the Google
Groups Algorithm Geeks group.
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For more options, visit this group at
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--
*WITH BEST REGARDS :
AASHISH SUMAN
MCA FINAL YEAR
*
*NIT DURGAPUR*
*+91-9547969906*
--
You received this message because you are subscribed to the Google Groups
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--
Ankur Khurana
Computer Science
Netaji Subhas Institute Of Technology
Delhi.
--
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**Regards
SAGAR PAREEK
COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD
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