Re: RegEx Substitution + Arrays
From: Seanie [EMAIL PROTECTED] Rob Dixon wrote: map(s/$find/$replace/, @arr); Haha yes you can, but if you want to write nasty code go for grep s/$find/$replace/, @arr; which also works. True, but grep implies find stuff, while map implies do stuff, so your nasty code is way, way, nastier than mine - it masks the intention. Maybe using map in void context is deep-level wrongness, but it'd be nice if somebody would explain WHY, instead of posting don't do it one-liners. Well, because it's for that implies do stuff. map means transform stuff and give me the results. With a for I expect that the work will be done as a side-effect, with map I expect that the code block will be side-effect free. That it will get a value and produce a value (or values). Sure, it may make sense to produce a value and do something more at the same time, but the produced value should be the main result. Jenda = [EMAIL PROTECTED] === http://Jenda.Krynicky.cz = When it comes to wine, women and song, wizards are allowed to get drunk and croon as much as they like. -- Terry Pratchett in Sourcery -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
Re: RegEx Substitution + Arrays
yitzle schreef: What's the best way to apply a RegEx to an array? For loop? @arr = qw/dc2ds reew12dsfa df2fdw/; s/$find/$replace/ for(@arr); Consider: s/\Q$find/$replace/ for(@arr); -- Affijn, Ruud Gewoon is een tijger. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
RegEx Substitution + Arrays
What's the best way to apply a RegEx to an array? For loop? @arr = qw/dc2ds reew12dsfa df2fdw/; s/$find/$replace/ for(@arr); Thanks -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
Re: RegEx Substitution + Arrays
yitzle wrote: What's the best way to apply a RegEx to an array? For loop? @arr = qw/dc2ds reew12dsfa df2fdw/; s/$find/$replace/ for(@arr); Yes. Exactly that. Rob -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
Re: RegEx Substitution + Arrays
yitzle wrote: What's the best way to apply a RegEx to an array? For loop? @arr = qw/dc2ds reew12dsfa df2fdw/; s/$find/$replace/ for(@arr); Yes, although the parentheses are redundant. John -- Perl isn't a toolbox, but a small machine shop where you can special-order certain sorts of tools at low cost and in short order. -- Larry Wall -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
Re: RegEx Substitution + Arrays
yitzle wrote: What's the best way to apply a RegEx to an array? For loop? @arr = qw/dc2ds reew12dsfa df2fdw/; s/$find/$replace/ for(@arr); Yep, you can do that. Or use map() map(s/$find/$replace/, @arr); -- [EMAIL PROTECTED] [pgp: 8A8FA6DE] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
Re: RegEx Substitution + Arrays
On 4/25/07, Seanie [EMAIL PROTECTED] wrote: yitzle wrote: What's the best way to apply a RegEx to an array? For loop? @arr = qw/dc2ds reew12dsfa df2fdw/; s/$find/$replace/ for(@arr); Yep, you can do that. Or use map() map(s/$find/$replace/, @arr); You should not use map in a void context, it is bad form. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
Re: RegEx Substitution + Arrays
Chas Owens wrote: map(s/$find/$replace/, @arr); You should not use map in a void context, it is bad form. Care to explain? Neither 'strict' nor 'warnings' complains, and it does what it says on the tin, but if I've missed something fundamental here I'd be grateful to know about it. -- [EMAIL PROTECTED] [pgp: 8A8FA6DE] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
Re: RegEx Substitution + Arrays
Seanie wrote: yitzle wrote: What's the best way to apply a RegEx to an array? For loop? @arr = qw/dc2ds reew12dsfa df2fdw/; s/$find/$replace/ for(@arr); Yep, you can do that. Or use map() map(s/$find/$replace/, @arr); Haha yes you can, but if you want to write nasty code go for grep s/$find/$replace/, @arr; which also works. Rob -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
Re: RegEx Substitution + Arrays
Sean King wrote: Chas Owens wrote: map(s/$find/$replace/, @arr); You should not use map in a void context, it is bad form. Care to explain? Neither 'strict' nor 'warnings' complains, and it does what it says on the tin, but if I've missed something fundamental here I'd be grateful to know about it. map() implements a mapping - a translation of one list into another by applying a function to each element. Just because it has to apply this function to every element in the target list isn't a good reason to use it as a for loop. Rob -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
Re: RegEx Substitution + Arrays
Rob Dixon wrote: map(s/$find/$replace/, @arr); Haha yes you can, but if you want to write nasty code go for grep s/$find/$replace/, @arr; which also works. True, but grep implies find stuff, while map implies do stuff, so your nasty code is way, way, nastier than mine - it masks the intention. Maybe using map in void context is deep-level wrongness, but it'd be nice if somebody would explain WHY, instead of posting don't do it one-liners. -- [EMAIL PROTECTED] [pgp: 8A8FA6DE] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
Re: RegEx Substitution + Arrays
Seanie wrote: Rob Dixon wrote: map(s/$find/$replace/, @arr); Haha yes you can, but if you want to write nasty code go for grep s/$find/$replace/, @arr; which also works. True, but grep implies find stuff, while map implies do stuff, so your nasty code is way, way, nastier than mine - it masks the intention. Maybe using map in void context is deep-level wrongness, but it'd be nice if somebody would explain WHY, instead of posting don't do it one-liners. perldoc perl581delta [ snip ] Miscellaneous Enhancements map in void context is no longer expensive. map is now context aware, and will not construct a list if called in void context. So it is not really wrong anymore (for certain values of wrongness.) John -- Perl isn't a toolbox, but a small machine shop where you can special-order certain sorts of tools at low cost and in short order. -- Larry Wall -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
Re: RegEx Substitution + Arrays
On 4/25/07, John W. Krahn [EMAIL PROTECTED] wrote: Seanie wrote: Rob Dixon wrote: map(s/$find/$replace/, @arr); Haha yes you can, but if you want to write nasty code go for grep s/$find/$replace/, @arr; which also works. True, but grep implies find stuff, while map implies do stuff, so your nasty code is way, way, nastier than mine - it masks the intention. Maybe using map in void context is deep-level wrongness, but it'd be nice if somebody would explain WHY, instead of posting don't do it one-liners. perldoc perl581delta [ snip ] Miscellaneous Enhancements map in void context is no longer expensive. map is now context aware, and will not construct a list if called in void context. So it is not really wrong anymore (for certain values of wrongness.) John -- Perl isn't a toolbox, but a small machine shop where you can special-order certain sorts of tools at low cost and in short order. -- Larry Wall It is no longer inefficient; however, it is still an abuse of map and longer than the for loop version. It is hard to defend the use of map in a void context. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/
