Re: How to get user's country and language with cakePHP
As an alternative to the webservice you can also use the apache api version. The geoip_country version works quite well. On 14 nov, 22:15, euromark dereurom...@googlemail.com wrote: for the country you can use RequestHandlerComponent::getClientIP() in combination with sth likehttp://planetcakephp.org/aggregator/items/3841-cakephp-requesthandler... for the language simply use the $_SERVER['HTTP_ACCEPT_LANGUAGE'] string in my case for example: [HTTP_ACCEPT_LANGUAGE] = de-DE,de;q=0.8,en-US;q=0.6,en;q=0.4 the first one is usually the language the user expects (0.8 is the closest to 1) On 14 Nov., 21:31, Mariano C. mariano.calan...@gmail.com wrote: Is there a way (helpers, components) to obtain with Cake PHP the user's country and associated language for that country? Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
prefix for join tables
hello, i use for plugins different table prefixes. when i want to work with habtm relationship and a join table i can't use the plugin prefix for this table. Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: Paginate Multiple Models in the same view
On a certain project I ran into the same problem with Cake and
couldn't find an elegant solution in the time I had..so what I did was
paginate the different models on the same page using ajax. Probably
not the answer you are looking for but it keeps things real simple!
On Nov 13, 10:46 pm, Arak Tai'Roth nielsen.dus...@gmail.com wrote:
This can't be the first time this has been tried?
On Nov 12, 5:12 pm, Arak Tai'Roth nielsen.dus...@gmail.com wrote:
Anyone have any other ideas?
On Nov 12, 12:56 am, Arak Tai'Roth nielsen.dus...@gmail.com wrote:
That doesn't work, it actually disabled the working pagination on the
Image model.
I know there is a model option that can be set in the Paginator
options, I'm wondering if it can be used for this purpose. But I have
been unable to find anything that lists how it's used and what exactly
it does or is used for.
On Nov 11, 9:39 pm, Amit Badkas amitrb...@gmail.com wrote:
Hi,
Just like you set different options for $paginate in controller's
action, I
think you need to do it for helper too, something like
$this-Paginator-options(array(
'Image' = array('update' = .),
'Floorplan' = array('update' = .)
));
should work.
Amit
PHP Applications for E-Biz:http://www.sanisoft.com
On Fri, Nov 12, 2010 at 8:00 AM, Arak Tai'Roth
nielsen.dus...@gmail.comwrote:
Hey everyone,
I have what I thought was a simple problem, but haven't been able to
find anything regarding it. Everything I can find is based off of
paginating different sets of data but all from the same model.
I have two models that are related to the model that the view is based
off of. So I have a view that shows a single product, in that
controller each product can have multiple images and multiple
floorplans, as such:
var $hasMany = array(
'Image' = array(
'className' = 'Image',
'dependant' = true,
'exclusive' = true
),
'Floorplan' = array(
'className' = 'Floorplan',
'dependant' = true,
'exclusive' = true
)
);
Now I am getting the data alright with the following code in my
Products controller:
var $paginate = array(
'Image' = array(
'fields' = array(
'Image.filename', 'Image.caption'
),
'limit' = 3,
'order' = array(
'Image.id' = 'asc'
)
),
'Floorplan' = array(
'fields' = array(
'Floorplan.filename',
'Floorplan.floorplan_name',
'Floorplan.floorplan_price'
),
'limit' = 1,
'order' = array(
'Floorplan.id' = 'asc'
)
)
);
$dbImages = $this-paginate('Image', array('product_id' =
$dbProduct['Product']['id']));
$dbFloorplans = $this-paginate('Floorplan', array('product_id' =
$dbProduct['Product']['id']));
However the problem becomes apparent when I go to implement the
pagination in the view, I have to set the options for the paginator,
so it knows what div to update and what to do on before and complete
callbacks.
?php
$this-Paginator-options(array(
'update' = '#showProducts',
'evalScripts' = true,
'before' =
$this-Js-get('#image_box')-effect('fadeOut'),
'complete' =
$this-Js-get('#image_box')-effect('fadeIn',
array('speed' = 'slow'))
));
?
However, this only works for the Image model, because I need to update
a different div for the Floorplans model and use different before and
complete callbacks.
Is there anyway to do this?
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Re: Cahe Helper: Cached Render Time
Thanks. Since i'm using jquery to get the json data, solved the
problem using the dataFilter callback to remove that info before
parsing the json.
On 12 nov, 01:25, Amit Badkas amitrb...@gmail.com wrote:
Hi,
If you look at renderCache() method of class View, in file
cake/libs/view/view.php, it uses following code to append the cache render
time in HTML comment
if (Configure::read() 0 $this-layout != 'xml') {
echo !-- Cached Render Time: . round(getMicrotime() - $timeStart, 4)
. s --;
}
So, either you need to set the debug level to 0 or need to use your own View
class by extending CakePHP's built-in and to override the renderCache()
method to add the code as needed. The non-recommended way is to modify
CakePHP's built-in View::renderCache() method.
Amit
PHP Applications for E-Biz:http://www.sanisoft.com
On Fri, Nov 12, 2010 at 12:57 AM, Gabriel gbrl...@gmail.com wrote:
Hi, i'm having some problems with the Cache Helper, i have some cached
json responses, and the cache helper adds at the end of the json data
stats like this: !-- Cached Render Time: 0.0467s --, that screwup
the javascript json parser. How i could remove that info?
Thanks
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Re: CakePHP Stores the user login information to Cookies automatically
Read the CakePHP book at: http://book.cakephp.org/view/1310/Sessions so that you may know how to set the timeout of the session. Enjoy, John On 14 Nov., 20:34, Muhaimen Ezabbad mezab...@gmail.com wrote: Team, Maybe I didn't explain the issue, In CakePHP 1.2.8, the cookie expires when I exit the browser, even if I didn't logout. in CakePHP 1.2.8, if I want to store the user information, then I need to store them manually, then I need to load them, of course after encrypting the username and password. in CakePHP 1.3.5 the Cookies will be valid for few days, unless the user logout by him self. Now 1.3.5, if the user used a public computer, then he closed the browser without logging in, then the website will log him in automatically. Is there anywhere I need to tell the session to make the cookies expires when I exit the browser? I really don't want the browser to remember the login data, unless the user choose that from the remember me checkbox. Thanks Team, and I really appreciate your help. Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Media View: Dowload works on local machine from external server, but production server gets 0 byte files...
Hey,
I ran into a strange problem today and need help...
I added cake's media view as download action to my app, which works
fine when I download files from my virtual hosts on my dev laptop. The
files are being downloaded from a central fileserver, and all files
are downloaded complete and working from there.
The interesting part is when I try to download the files via my
production server where the app is running, I get 0 byte files! How
can this be?
The folder and files can be accessed by the webserver (I also tried
777 on the files...) and as I said everything works fine from my local
dev machine.
Here's the code by the way:
function download($filename = null) {
$file = $this-Upload-findByFilename($filename);
if(empty($file)) {
$this-Session-setFlash(__('Sorry, could not find
requested file!', true), 'default', array('class' = 'negative'));
$this-redirect($this-referer());
}
$this-view = 'media';
$params = array(
'id' = $file['Upload']['filename'],
'name' = $file['Upload']['original_name'],
'download' = true,
'extension' = 'pdf',
'path' = 'http://my.fileserver.com/pdf/'
);
$this-set($params);
}
Could this be an apache problem or something with the mimetype? I just
do not understand why I can download the files from my local computer
when the app runs under XAMPP, but not from the production server...?
If there is an access restriction, why can I get the files from here
but not from a real server?!
Please help...
Regards,
DD
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Re: Paginate Multiple Models in the same view
Hey,
that's because you need a different approach on pagination...
Try this instead:
$this-paginate['Model1'] = array(
'limit' = 20,
'conditions' = $conditions,
);
$models1 = $this-paginate('Model1');
$this-paginate['Model2'] = array(
'limit' = 20,
'conditions' = $conditions,
);
$models2 = $this-paginate('Model2');
$this-paginate['Model3'] = array(
'limit' = 20,
'conditions' = $conditions,
);
$models3 = $this-paginate('Model3');
$this-set(compact('models1', 'models2', 'models3'));
With the update option within the paginator-helper like Amit said
before this should work.
If it does not work, use AJAX pagination instead and update the
desired element within the RequestHandler-isAjax() part.
On 15 Nov., 12:59, parallel32 paralle...@gmail.com wrote:
On a certain project I ran into the same problem with Cake and
couldn't find an elegant solution in the time I had..so what I did was
paginate the different models on the same page using ajax. Probably
not the answer you are looking for but it keeps things real simple!
On Nov 13, 10:46 pm, Arak Tai'Roth nielsen.dus...@gmail.com wrote:
This can't be the first time this has been tried?
On Nov 12, 5:12 pm, Arak Tai'Roth nielsen.dus...@gmail.com wrote:
Anyone have any other ideas?
On Nov 12, 12:56 am, Arak Tai'Roth nielsen.dus...@gmail.com wrote:
That doesn't work, it actually disabled the working pagination on the
Image model.
I know there is a model option that can be set in the Paginator
options, I'm wondering if it can be used for this purpose. But I have
been unable to find anything that lists how it's used and what exactly
it does or is used for.
On Nov 11, 9:39 pm, Amit Badkas amitrb...@gmail.com wrote:
Hi,
Just like you set different options for $paginate in controller's
action, I
think you need to do it for helper too, something like
$this-Paginator-options(array(
'Image' = array('update' = .),
'Floorplan' = array('update' = .)
));
should work.
Amit
PHP Applications for E-Biz:http://www.sanisoft.com
On Fri, Nov 12, 2010 at 8:00 AM, Arak Tai'Roth
nielsen.dus...@gmail.comwrote:
Hey everyone,
I have what I thought was a simple problem, but haven't been able to
find anything regarding it. Everything I can find is based off of
paginating different sets of data but all from the same model.
I have two models that are related to the model that the view is
based
off of. So I have a view that shows a single product, in that
controller each product can have multiple images and multiple
floorplans, as such:
var $hasMany = array(
'Image' = array(
'className' = 'Image',
'dependant' = true,
'exclusive' = true
),
'Floorplan' = array(
'className' = 'Floorplan',
'dependant' = true,
'exclusive' = true
)
);
Now I am getting the data alright with the following code in my
Products controller:
var $paginate = array(
'Image' = array(
'fields' = array(
'Image.filename', 'Image.caption'
),
'limit' = 3,
'order' = array(
'Image.id' = 'asc'
)
),
'Floorplan' = array(
'fields' = array(
'Floorplan.filename',
'Floorplan.floorplan_name',
'Floorplan.floorplan_price'
),
'limit' = 1,
'order' = array(
'Floorplan.id' = 'asc'
)
)
);
$dbImages = $this-paginate('Image', array('product_id' =
$dbProduct['Product']['id']));
$dbFloorplans = $this-paginate('Floorplan', array('product_id' =
$dbProduct['Product']['id']));
However the problem becomes apparent when I go to implement the
pagination in the view, I have to set the options for the paginator,
so it knows what div to update and what to do on before and complete
callbacks.
?php
$this-Paginator-options(array(
'update' = '#showProducts',
'evalScripts' = true,
'before' =
$this-Js-get('#image_box')-effect('fadeOut'),
'complete' =
$this-Js-get('#image_box')-effect('fadeIn',
array('speed' = 'slow'))
));
?
However, this only works for the Image model,
CakePHP Two Step View Pattern
Hi guys I'm new here in CakePHP. How can I implement a two step view
pattern in CakePHP? Example I have a layout there are two content divs
namely content1 and content2. The code is like this
html
head
titleMy Cake Blog Application/title
?=$html-css('styles');?
/head
body
div id=container
div id=content
?=$content_for_layout;?
/div
/div
div id=container2
div id=content2
?=$content_for_layout2;?
/div
/div
/body
/html
Can I do this in CakePHP? Cause in CodeIgniter we setup a layout and
then in the layout we could display many views. How can I do that here
in CakePHP?
Thanks in advance..
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Re: CakePHP Two Step View Pattern
This isn't possible in Cake. You can only have 1 content, which is the
HTML rendered based on the action/controller.
If you want to display additional content, use an element include or
requestAction.
On Nov 15, 9:31 am, Rey Philip reyphilipre...@gmail.com wrote:
Hi guys I'm new here in CakePHP. How can I implement a two step view
pattern in CakePHP? Example I have a layout there are two content divs
namely content1 and content2. The code is like this
html
head
titleMy Cake Blog Application/title
?=$html-css('styles');?
/head
body
div id=container
div id=content
?=$content_for_layout;?
/div
/div
div id=container2
div id=content2
?=$content_for_layout2;?
/div
/div
/body
/html
Can I do this in CakePHP? Cause in CodeIgniter we setup a layout and
then in the layout we could display many views. How can I do that here
in CakePHP?
Thanks in advance..
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their CakePHP related questions.
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Phantom URL
So I have a site im building for myself so im just building it live on the server. Now no one can login or see anything other than the login screen.I am the only user and I deny everything with Auth (other than login / logout ). So that being said I was curious to google the site and sure enough site login page comes up yet other results show /password/error/script Click on that link and I get to a page which has my Opps! Error message in the site layout so its getting the view rendered from Cake. Yet I have no error/script function or page? I added a print_r $this-params['controller'] in app_controller to see what controller it was coming from but no clue. Searched for an script.ctp file, nothing. Another weird thing is I havecore.php debug set at 0 so the login page does not show the footer cake session / sql but on the password/error/script the full dump is there. So far I have check routes.php and nothing there. No script.ctp just not sure if there is a bug or simply over looked something. Any ideas would be great to help me track this down. Dave Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Problem with Cake session time out and security level
Hi,
My question is simple. Is it possible to have these 3 things set-up
for my project:
1) Security level to medium (and not high)
2) A given time-out of 90 seconds
3) An automatic log-out after browser closing
???
From what I understood, if I want 3, then I need to set the Security
level to high, which I don't want.
Now, I can set manually 3 by writing
ini_set('session.cookie_lifetime', 0); in a session config file, but
then how can I set a number of seconds for the session time-out???
So it seems like my request is impossible. Is it? That would be
completely incredible!
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One page not loading in IE
Hi All I have a very strange problem with IE, I have a My account page in my web site with Cake 1.2 and it is not showing in IE, the Security Level is set to Low and Sessions are controlling by Database. I used the Firebug and the only problem that I noticed was the cookies, Every time I tried to set a cookie, cake set it 3-4 times!!! Is it normal? because I was thinking maybe it may crash the IE Any Idea? Thanks in advanced Sherry http://cakephp.1045679.n5.nabble.com/file/n3266359/firebug.jpg -- View this message in context: http://cakephp.1045679.n5.nabble.com/One-page-not-loading-in-IE-tp3266359p3266359.html Sent from the CakePHP mailing list archive at Nabble.com. Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: Site Development from Start to Finish
Hi,
It seems that the controller is not Users controller but anything else. Am I
right?
Amit Badkas
PHP Applications for E-Biz: http://www.sanisoft.com
On Sat, Nov 13, 2010 at 12:54 AM, naidim nai...@gmail.com wrote:
I don't understand. Without the var $uses = array('User', 'Drug',
etc.) line, calls to $this-User-find() give this error: Fatal error:
Call to undefined method stdClass::find() With the uses line, it works
fine.
On Nov 12, 11:13 am, Shaz shazam...@gmail.com wrote:
It's better practice to use model relationships rather than $uses.
i.e. $this-User-Drug-find();
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Re: Submit button label in e.g. swedish
Hi,
You can also try
echo $form-end(array('label' = 'Lägg till', 'escape' = false));
Amit Badkas
PHP Applications for E-Biz: http://www.sanisoft.com
On Sun, Nov 14, 2010 at 1:46 AM, cricket zijn.digi...@gmail.com wrote:
On Sat, Nov 13, 2010 at 8:28 AM, Björn N edtb...@gmail.com wrote:
Hi!
I want to use a label Lägg till on a submit button, using the code:
?php echo $form-end('Lägg till'); ?, but that renders a button with
no text in it. If I change the 'ä' to an 'a' the label shows up fine,
but without the dots above the a. I've tried 'auml; to no avail.
I'm pretty sure that the problem exists for other european languages
too, but as I don't read these languages, it's hard to find a fix for
the problem.
Try:
echo $form-submit('Lägg till', array(escape' = false));
echo $form-end();
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Re: CakePHP Stores the user login information to Cookies automatically
Hi,
Have you checked the 'Security.level' configuration setting. It should be
'high' to set 'session.cookie_lifetime' to 0 so that session cookie will get
destroyed after closing the browser.
Hope this helps.
Amit Badkas
PHP Applications for E-Biz: http://www.sanisoft.com
On Mon, Nov 15, 2010 at 1:04 AM, Muhaimen Ezabbad mezab...@gmail.comwrote:
Team,
Maybe I didn't explain the issue,
In CakePHP 1.2.8, the cookie expires when I exit the browser, even
if I didn't logout.
in CakePHP 1.2.8, if I want to store the user information, then I
need to store them manually, then I need to load them, of course after
encrypting the username and password.
in CakePHP 1.3.5 the Cookies will be valid for few days, unless the
user logout by him self.
Now 1.3.5, if the user used a public computer, then he closed the
browser without logging in, then the website will log him in automatically.
Is there anywhere I need to tell the session to make the cookies
expires when I exit the browser?
I really don't want the browser to remember the login data, unless
the user choose that from the remember me checkbox.
Thanks Team, and I really appreciate your help.
On Nov 14, 2010, at 8:03 PM, John Andersen wrote:
What is actually the issue here?
Do you see the login information in the cookie or do you just see that
the cookie is there?
In order to know the session of the current user, a session-cookie is
stored on the users computer. Is this the one you are worried about?
Enjoy,
John
On 12 Nov., 15:15, Muhaimen Ezabbad mezab...@gmail.com wrote:
Amit,
Thanks for the reply,
Amit, Team,
I'm using 1.3.5 Stable version.
BTW, I also created a new empty project with two tables, items
and users
in the AppController I wrote:
var $components=array('Auth');
function beforeFilter() {
$this-Auth-loginRedirect =
array('controller'='items','action'='index');
$this-Auth-logoutRedirect =
array('controller'='users','action'='login');
$this-set('loggedIn',$this-Auth-user('id'));
//$this-Auth-allow('signup');
}
function isAuthorized() {
//parent::isAuthorized();
return true;
}
and I didn't write anything in the login function in the
UserController.
My problem again the login informations stored in the cookies
, I don't want to store these data without the user confirmation.
Thanks for your help
[snip]
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Re: Making a file downloadable
Hi, I am having a similar problem only my folder 'files' is already in the webroot directory. The files folder contains xml files which the site takes some of its contents from. Sometimes it works fine and reads the xml files but others it looks for files_controller Does anyone know why it's doing this? thanks Rachael -- View this message in context: http://cakephp.1045679.n5.nabble.com/Making-a-file-downloadable-tp3235245p3265360.html Sent from the CakePHP mailing list archive at Nabble.com. Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Book software like on book.cakephp.org
Hey guys, (Maybe a little off-topic) I was just browsing through http://book.cakephp.org/view/875/x1-3-Collection and marveling at the implementation of the book software. Is this open? And if not do you know of any similar web apps that allow a community of contributors to create a book together? I would like to be able to auto generate a nightly PDF from the book pages. Will I need to implement this from scratch? -sasa Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Auth / Acl redirect issue CakePHP 1.3.4
I have an application setup with admin prefix route, Auth, and ACL. everything seems to be working as expected, except when I am logged in as an admin user and I try to access a ACL restriced action by typing the url in the address bar of the browser. I get redirected to the home page of the site (view/pages/home.ctp) instead of the admin dashboard (users/admin_dashboard) i have created. If I click on a link to the exact same action in the admin dashboard that is restricted, I get redirected to the admin dashboard as expected with an auth error message telling me I am not authorized to access that location. What am I missing? Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Mail Distributor
Hello Everybody!
I like to write a mail distributor. It shall send an email to all
registered users with an valid email address. The distributor has no
table in a data base, thus I set var $useTable = false;. But I have
a user module including the email address of every registered user. I
thought I can work with the hasMany relation and a find('all') but it
does not work. Here are a view code snippets.
@Mail Distributor-Model:
var $hasMany = array(
'User' = array(
'className' = 'User',
'foreignKey' = 'id',
)
);
@Mail Distributor-Controller
$email_addresses = $this-Mailinglist-find('all');
Can anyone help me here?
Best Regards,
Tim
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Re: Phantom URL
Is this the error you'd expect to see if the login fails validation? If so, is your code in the login action checking for the presence of data before processing it further? If not, the error will fire. Another suggestion is to clear the cache. Jeremy Burns Class Outfit jeremybu...@classoutfit.com (t) +44 (0) 208 123 3822 (m) +44 (0) 7973 481949 Skype: jeremy_burns http://www.classoutfit.com On 15 Nov 2010, at 19:09, Dave Maharaj wrote: So I have a site im building for myself so im just building it live on the server. Now no one can login or see anything other than the login screen…I am the only user and I deny everything with Auth (other than login / logout ). So that being said I was curious to google the site and sure enough site login page comes up yet other results show /password/error/script Click on that link and I get to a page which has my Opps! Error message in the site layout so its getting the view rendered from Cake. Yet I have no error/script function or page? I added a print_r $this-params[‘controller’] in app_controller to see what controller it was coming from but no clue. Searched for an script.ctp file, nothing. Another weird thing is I havecore.php debug set at 0 so the login page does not show the footer cake session / sql but on the password/error/script the full dump is there. So far I have check routes.php and nothing there. No script.ctp just not sure if there is a bug or simply over looked something. Any ideas would be great to help me track this down. Dave Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: Mail Distributor
Why not run this out of the User model?
Jeremy Burns
Class Outfit
jeremybu...@classoutfit.com
http://www.classoutfit.com
On 15 Nov 2010, at 20:23, TimK wrote:
Hello Everybody!
I like to write a mail distributor. It shall send an email to all
registered users with an valid email address. The distributor has no
table in a data base, thus I set var $useTable = false;. But I have
a user module including the email address of every registered user. I
thought I can work with the hasMany relation and a find('all') but it
does not work. Here are a view code snippets.
@Mail Distributor-Model:
var $hasMany = array(
'User' = array(
'className' = 'User',
'foreignKey' = 'id',
)
);
@Mail Distributor-Controller
$email_addresses = $this-Mailinglist-find('all');
Can anyone help me here?
Best Regards,
Tim
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Re: Mail Distributor
Hi Jeremy!
Thank you for your idea. I'm sure it will work. I thought I separate
the mailing function for the user for structural reasons. But the
mailing module is extremely small and maybe my idea is only micro
management. Nevertheless I am still interested in a solution with two
models.
Best Regards,
Tim
On Nov 15, 9:27 pm, Jeremy Burns | Class Outfit
jeremybu...@classoutfit.com wrote:
Why not run this out of the User model?
Jeremy Burns
Class Outfit
jeremybu...@classoutfit.comhttp://www.classoutfit.com
On 15 Nov 2010, at 20:23, TimK wrote:
Hello Everybody!
I like to write a mail distributor. It shall send an email to all
registered users with an valid email address. The distributor has no
table in a data base, thus I set var $useTable = false;. But I have
a user module including the email address of every registered user. I
thought I can work with the hasMany relation and a find('all') but it
does not work. Here are a view code snippets.
@Mail Distributor-Model:
var $hasMany = array(
'User' = array(
'className' = 'User',
'foreignKey' = 'id',
)
);
@Mail Distributor-Controller
$email_addresses = $this-Mailinglist-find('all');
Can anyone help me here?
Best Regards,
Tim
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with their CakePHP related questions.
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Re: Making a file downloadable
On Mon, Nov 15, 2010 at 4:59 AM, rlparker81 rlparke...@googlemail.com wrote: Hi, I am having a similar problem only my folder 'files' is already in the webroot directory. The files folder contains xml files which the site takes some of its contents from. Sometimes it works fine and reads the xml files but others it looks for files_controller Does anyone know why it's doing this? Look at the RewriteRules in your .htaccess (or apache conf). If the file cannot be found, the request is passed to Cake. Make sure that the requested file exists. Also, be aware that the request is case-sensitive. Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
RE: Phantom URL
I was not expecting anything to show since everything is denied with redirect to login. If I type in /anything/here it goes to login as expected it I type in /password/error it goes to login yet password/error/script sits there with the error message. From: Jeremy Burns | Class Outfit [mailto:jeremybu...@classoutfit.com] Sent: November-15-10 4:55 PM To: cake-php@googlegroups.com Subject: Re: Phantom URL Is this the error you'd expect to see if the login fails validation? If so, is your code in the login action checking for the presence of data before processing it further? If not, the error will fire. Another suggestion is to clear the cache. Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: Phantom URL
That's my point. Is it the code behind the login form that is triggering the error? So when the login page is opened the code tries to log the user in based on the values entered (which are of course empty) and therefore log in is failing, even though its the first visit to the page? Jeremy Burns Class Outfit jeremybu...@classoutfit.com http://www.classoutfit.com On 15 Nov 2010, at 20:50, Dave Maharaj wrote: I was not expecting anything to show since everything is denied with redirect to login. If I type in /anything/here it goes to login as expected it I type in /password/error it goes to login yet password/error/script sits there with the error message. From: Jeremy Burns | Class Outfit [mailto:jeremybu...@classoutfit.com] Sent: November-15-10 4:55 PM To: cake-php@googlegroups.com Subject: Re: Phantom URL Is this the error you'd expect to see if the login fails validation? If so, is your code in the login action checking for the presence of data before processing it further? If not, the error will fire. Another suggestion is to clear the cache. Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
RE: Phantom URL
Not sure I follow what you are saying.sorry. No login attempt is being made. Google has indexed this 1 page that shows up when I search for my site and its an error page that is coming from no where. There is no access to anything on the site except login. If you play with the url it all directs to login except the /password/error/script. It shows an error page with full debug dump yet the site is set at debug 0. That's where I am lost. Thanks, Dave From: Jeremy Burns | Class Outfit [mailto:jeremybu...@classoutfit.com] Sent: November-15-10 5:24 PM To: cake-php@googlegroups.com Subject: Re: Phantom URL That's my point. Is it the code behind the login form that is triggering the error? So when the login page is opened the code tries to log the user in based on the values entered (which are of course empty) and therefore log in is failing, even though its the first visit to the page? Jeremy Burns Class Outfit jeremybu...@classoutfit.com mailto:jeremybu...@mac.com http://www.classoutfit.com On 15 Nov 2010, at 20:50, Dave Maharaj wrote: I was not expecting anything to show since everything is denied with redirect to login. If I type in /anything/here it goes to login as expected it I type in /password/error it goes to login yet password/error/script sits there with the error message. From: Jeremy Burns | Class Outfit [mailto:jeremybu...@classoutfit.com] Sent: November-15-10 4:55 PM To: cake-php@googlegroups.com Subject: Re: Phantom URL Is this the error you'd expect to see if the login fails validation? If so, is your code in the login action checking for the presence of data before processing it further? If not, the error will fire. Another suggestion is to clear the cache. Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: Phantom URL
So you haven't programmed your Opps! Error message... in anywhere? Jeremy Burns Class Outfit jeremybu...@classoutfit.com http://www.classoutfit.com On 15 Nov 2010, at 21:34, Dave Maharaj wrote: Not sure I follow what you are saying…sorry. No login attempt is being made. Google has indexed this 1 page that shows up when I search for my site and its an error page that is coming from no where. There is no access to anything on the site except login. If you play with the url it all directs to login except the /password/error/script. It shows an error page with full debug dump yet the site is set at debug 0. That’s where I am lost. Thanks, Dave From: Jeremy Burns | Class Outfit [mailto:jeremybu...@classoutfit.com] Sent: November-15-10 5:24 PM To: cake-php@googlegroups.com Subject: Re: Phantom URL That's my point. Is it the code behind the login form that is triggering the error? So when the login page is opened the code tries to log the user in based on the values entered (which are of course empty) and therefore log in is failing, even though its the first visit to the page? Jeremy Burns Class Outfit jeremybu...@classoutfit.com http://www.classoutfit.com On 15 Nov 2010, at 20:50, Dave Maharaj wrote: I was not expecting anything to show since everything is denied with redirect to login. If I type in /anything/here it goes to login as expected it I type in /password/error it goes to login yet password/error/script sits there with the error message. From: Jeremy Burns | Class Outfit [mailto:jeremybu...@classoutfit.com] Sent: November-15-10 4:55 PM To: cake-php@googlegroups.com Subject: Re: Phantom URL Is this the error you'd expect to see if the login fails validation? If so, is your code in the login action checking for the presence of data before processing it further? If not, the error will fire. Another suggestion is to clear the cache. Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Paginator Question
Hello Bakers,
I am using cake's paginator to paginate my views, i am actually using the
folowing code to accomplish this task:
$paginator-numbers(array('tag' = 'td align=center', 'separator' = ''));
My question is, how do you guys put a dynamic ALT for the links being
generated by the paginator using [$paginator-numbers]?
Thanks a lot for any answer
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RE: Phantom URL
No that is me.I just tossed that into missing controller error page. . But why is an error showing when the only thing allowed is login. And the debug thing too. That's what puzzles me. Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: Media View: Dowload works on local machine from external server, but production server gets 0 byte files...
the path usually doesnt start with http://
its a file path - at least afaik
windows: c:/...
linux /var/www/...
but the constansts should be just about fine:
ROOT.DS.'files'.DS.'whatever'
thats why you need the media view in the first place
because usually you want to serve files that are below the webroot
folder (and need to be passed through in order to get accessable)
On 15 Nov., 16:42, DigitalDude e.blumsten...@googlemail.com wrote:
Hey,
I ran into a strange problem today and need help...
I added cake's media view as download action to my app, which works
fine when I download files from my virtual hosts on my dev laptop. The
files are being downloaded from a central fileserver, and all files
are downloaded complete and working from there.
The interesting part is when I try to download the files via my
production server where the app is running, I get 0 byte files! How
can this be?
The folder and files can be accessed by the webserver (I also tried
777 on the files...) and as I said everything works fine from my local
dev machine.
Here's the code by the way:
function download($filename = null) {
$file = $this-Upload-findByFilename($filename);
if(empty($file)) {
$this-Session-setFlash(__('Sorry, could not find
requested file!', true), 'default', array('class' = 'negative'));
$this-redirect($this-referer());
}
$this-view = 'media';
$params = array(
'id' = $file['Upload']['filename'],
'name' = $file['Upload']['original_name'],
'download' = true,
'extension' = 'pdf',
'path' = 'http://my.fileserver.com/pdf/'
);
$this-set($params);
}
Could this be an apache problem or something with the mimetype? I just
do not understand why I can download the files from my local computer
when the app runs under XAMPP, but not from the production server...?
If there is an access restriction, why can I get the files from here
but not from a real server?!
Please help...
Regards,
DD
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Re: Phantom URL
On Mon, Nov 15, 2010 at 4:41 PM, Dave Maharaj m...@davemaharaj.com wrote: No that is me…I just tossed that into missing controller error page. . But why is an error showing when the only thing allowed is login. And the debug thing too. That’s what puzzles me. Seeing an error view has nothing to do with being logged in or not. And this is a bit confusing because you've said both that you did, and you did not create your own error page. That said, perhaps you should empty your cache. Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
RE: Phantom URL
Ok to clarify I put the Opps! Message in the standard missing
controller.ctp error folder.
I have not made a custom error handler or setup any cake error directs or
anything like that.
So this is what I did step by step,
I am not logged. Not even attempting to login, not even going to login page.
I just search my site on google and there are are 2 links there
1 = login
2 = password/error/script
So someone can click on that 2nd link to get an error page all fine and
dandy but if auth is denying every page except login how can anyone even see
this page or get indexed? And if debug is set to 0 (I did a find thru the
whole site and no places have Config::write('debug' , other value) why am I
seeing the full dump at the bottom.
I can type in the address bar /asdfasdf/asdfsf/asdfasf/asdfasf and presto
redirected to login, type in /password sent to login so no error Opps!
message just directed to login as Auth is set to do...but type in
password/error/script and error page display with Opps!. Everything
redirects to login if you play with the url and type in anything except
password/error/script that is the only page that does not send you the login
page.
-Original Message-
From: cricket [mailto:zijn.digi...@gmail.com]
Sent: November-15-10 7:43 PM
To: cake-php@googlegroups.com
Subject: Re: Phantom URL
On Mon, Nov 15, 2010 at 4:41 PM, Dave Maharaj m...@davemaharaj.com wrote:
No that is me.I just tossed that into missing controller error page.
. But why is an error showing when the only thing allowed is login. And
the
debug thing too. That's what puzzles me.
Seeing an error view has nothing to do with being logged in or not.
And this is a bit confusing because you've said both that you did, and
you did not create your own error page.
That said, perhaps you should empty your cache.
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Re: Paginator Question
On Mon, Nov 15, 2010 at 4:40 PM, Ma'moon phpir...@gmail.com wrote:
Hello Bakers,
I am using cake's paginator to paginate my views, i am actually using the
folowing code to accomplish this task:
$paginator-numbers(array('tag' = 'td align=center', 'separator' = ''));
My question is, how do you guys put a dynamic ALT for the links being
generated by the paginator using [$paginator-numbers]?
echo $paginator-numbers(array('title' = 'foo'));
Not very helpful, eh? I had a look into this a while back to see about
setting distinct titles but gave up as it didn't seem worth the
trouble of extending the helper (which appears to be the only
solution) just for that.
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Re: Site Development from Start to Finish
At the time of last testing it wasn't, now it IS User and I'm getting
all kids of errors.
Without a $uses var, I get Error: Database table homepages for model
Homepage was not found. which is to be expected since there is no
related MODEL for the homepages controller.
With an empty $uses ( var $uses = array(); ) I get: Notice (8):
Undefined property: HomepagesController::$User [APP/controllers/
homepages_controller.php, line 7]
With a full $uses ( var $uses = array('User'); ) it works fine, as I
stated previously.
So it is apparent to me that $uses is required first if there is no
related MODEL, and second if you want to access an unrelated MODEL.
On Nov 14, 11:17 pm, Amit Badkas amit.sanis...@gmail.com wrote:
Hi,
It seems that the controller is not Users controller but anything else. Am I
right?
Amit Badkas
PHP Applications for E-Biz:http://www.sanisoft.com
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Re: Paginator Question
Thanks for the answer cricket, i am already aware of
[$paginator-numbers(array('title' = 'foo')] but this is a static ALT for
the link, i am trying to dynamically fill the ALT with something like
Page Number X From Section Y where X is the page number for the link and Y
is a dynamic or static string, there must be a way to do it, if this is
not possible then i will open a ticket at CakePHP's lighthouse in order to
have such a feature in Cake's paginator.
On Mon, Nov 15, 2010 at 7:02 PM, cricket zijn.digi...@gmail.com wrote:
On Mon, Nov 15, 2010 at 4:40 PM, Ma'moon phpir...@gmail.com wrote:
Hello Bakers,
I am using cake's paginator to paginate my views, i am actually using the
folowing code to accomplish this task:
$paginator-numbers(array('tag' = 'td align=center', 'separator' =
''));
My question is, how do you guys put a dynamic ALT for the links being
generated by the paginator using [$paginator-numbers]?
echo $paginator-numbers(array('title' = 'foo'));
Not very helpful, eh? I had a look into this a while back to see about
setting distinct titles but gave up as it didn't seem worth the
trouble of extending the helper (which appears to be the only
solution) just for that.
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with their CakePHP related questions.
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Re: mysql connection refused
This is a dev environment where the application server is a VBox host. The MySQL server is a VBox guest machine on the VBox host. phpmyadmin runs from a browser on the VBox host, so it *is* using tcp. Everything was working fine until I upgraded the guest OS from 9.10 to 10.04. I think I might have changed the skip-networking option during the initial MySQL install and it must have been reset to the default 127.0.0.1 setting during the upgrade. I changed the bind-address option to 0.0.0.0 in the my.cnf, and now it works fine. Thanks for your help. On Nov 12, 9:49 pm, Anatoliy Dimitrov tollo...@gmail.com wrote: I can't believe you are connecting to MySQL from PHPMYADMIN with absolutely the same details. The error means that the application cannot connect to the MySQL server on that port. By default on decent Ubuntu MySQL listens only on the local interface 127.0.0.1 and not on all IPs. You can check it with: netstat -ntap |grep 3306 tcp 0 0 127.0.0.1:3306 0.0.0.0:* LISTEN - Thus if you have been connecting to the external IP before you will not be able to do so any longer (unless you reconfigure MySQL of course). Thus try using 127.0.0.1 for MySQL hostname. Best regards, Anatoli On Nov 12, 11:56 pm, rogwei rog...@comcast.net wrote: The subject search phrase returns 0 items in this group which surprises me a little, and google isn't. Anyway, I upgraded my DB server Ubuntu 9.10 to 10.04 LTS, and now when I try to access my application I get the following warning and a missing database table error. One factoid, I CAN connect with phpmyadmin using the same host and credentials. The only my.cnf file on the server uses port 3306. Not sure what to do or whose issue this is. Any help? Warning (2): mysql_connect() [function.mysql-connect]: [2002] Connection refused (trying to connect via tcp://x.x.x.x:3306) [CORE/ cake/libs/model/datasources/dbo/dbo_mysql.php, line 552] Code | Context $config = array( persistent = false, host = x.x.x.x, login = x, password = , database = xx, port = 3306, driver = mysql, prefix = ) mysql_connect - [internal], line ?? DboMysql::connect() - CORE/cake/libs/model/datasources/dbo/ dbo_mysql.php, line 552 DboSource::__construct() - CORE/cake/libs/model/datasources/ dbo_source.php, line 143 ConnectionManager::getDataSource() - CORE/cake/libs/model/ connection_manager.php, line 114 Model::setDataSource() - CORE/cake/libs/model/model.php, line 2818 Model::__construct() - CORE/cake/libs/model/model.php, line 469 AclNode::__construct() - CORE/cake/libs/model/db_acl.php, line 62 ClassRegistry::init() - CORE/cake/libs/class_registry.php, line 141 DbAcl::__construct() - CORE/cake/libs/controller/components/acl.php, line 237 AclComponent::__construct() - CORE/cake/libs/controller/components/ acl.php, line 58 Component::_loadComponents() - CORE/cake/libs/controller/ component.php, line 249 Component::init() - CORE/cake/libs/controller/component.php, line 78 Controller::constructClasses() - CORE/cake/libs/controller/ controller.php, line 487 Dispatcher::_invoke() - CORE/cake/dispatcher.php, line 186 Dispatcher::dispatch() - CORE/cake/dispatcher.php, line 171 [main] - /Users/Roger/Sites/uypBarebones/index.php, line 84 Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: Paginator Question
On Mon, Nov 15, 2010 at 7:21 PM, Ma'moon phpir...@gmail.com wrote:
Thanks for the answer cricket, i am already aware of
[$paginator-numbers(array('title' = 'foo')] but this is a static ALT for
the link, i am trying to dynamically fill the ALT with something like
Page Number X From Section Y where X is the page number for the link and Y
is a dynamic or static string, there must be a way to do it, if this is
not possible then i will open a ticket at CakePHP's lighthouse in order to
have such a feature in Cake's paginator.
Sorry, I forgot to add that links don't have an alt attribute. I think
you're thinking of title.
As for the rest, yes, that's what I was getting at. It's a static
string, or you'll have to extend the helper.
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Saving data in many tables in CakePHP
I a newbie question. This is how can I save data in many tables. Heres a scenario, example I have a Profiles controller, then I have a register method/action. Lets say I have 2 tables involved the users table and emails table, this is only for the sake of the demonstration. In my view in the register method there are two input boxes name which resides in the users table and email textbox for the emails table. Now what I want to do is that, when I press the submit button I want the name to be saved in the names table and the email to the emails table.. Here is the schema: users table: id name emails table: id user_id email I wonder what the view for register method would look like, since the form-create() methods 1st paramter is the name of the model.. And also how do I saved the data on two different tables. Again, thanks in advance. Philip Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: Problem with Cake session time out and security level
Hi,
If you want custom session settings then change configuration to something
like
Configure::write('Session.save', 'my_session');
and after that create app/config/my_session.php where you can define your
own session settings, something like
ini_set('session.use_trans_sid', 0);
ini_set('session.name', Configure::read('Session.cookie'));
ini_set('session.cookie_lifetime', 0);
ini_set('session.cookie_path', $this-path);
Hope this helps.
Amit Badkas
PHP Applications for E-Biz: http://www.sanisoft.com
On Tue, Nov 16, 2010 at 12:41 AM, thomaus tho...@saimiris.com wrote:
Hi,
My question is simple. Is it possible to have these 3 things set-up
for my project:
1) Security level to medium (and not high)
2) A given time-out of 90 seconds
3) An automatic log-out after browser closing
???
From what I understood, if I want 3, then I need to set the Security
level to high, which I don't want.
Now, I can set manually 3 by writing
ini_set('session.cookie_lifetime', 0); in a session config file, but
then how can I set a number of seconds for the session time-out???
So it seems like my request is impossible. Is it? That would be
completely incredible!
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Re: Auth / Acl redirect issue CakePHP 1.3.4
Hi, The redirection after ACL fails depends on HTTP_REFERER environment variable. If you access the restricted URL directly then referrer doesn't get set, that's why '/' (by default, home page) is being used. Amit Badkas PHP Applications for E-Biz: http://www.sanisoft.com On Mon, Nov 15, 2010 at 10:06 PM, danielnolan danielano...@gmail.comwrote: I have an application setup with admin prefix route, Auth, and ACL. everything seems to be working as expected, except when I am logged in as an admin user and I try to access a ACL restriced action by typing the url in the address bar of the browser. I get redirected to the home page of the site (view/pages/home.ctp) instead of the admin dashboard (users/admin_dashboard) i have created. If I click on a link to the exact same action in the admin dashboard that is restricted, I get redirected to the admin dashboard as expected with an auth error message telling me I am not authorized to access that location. What am I missing? Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.comcake-php%2bunsubscr...@googlegroups.comFor more options, visit this group at http://groups.google.com/group/cake-php?hl=en Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
yahoo web hosting problem
hello everybody I had a problem about hosting at yahoo web hosting. i can't upload .htaccess files (i think They Used IIS becauce IIS do not support .htaccess, CMIIW) so I use the way in http://book.cakephp.org/view/1533/A-Note-on-mod_rewrite to fix the problem. it's works. but now, i have new problem. i can't upload image. (I use jqimagecrop component), and TinyMCE does not work too, I have tried the tutorial on http://blog.knightdna.net/2010/07/enabling-cakephp-pretty-urls-on-iis.htmland http://book.cakephp.org/view/1636/URL -Rewrites-on-IIS7-Windows-hosts but failed. Is there someone who knows how to solve this problem? please help me. thanks before :) Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: Saving data in many tables in CakePHP
Hi,
First of all you need to set User's relation with Email. From the DB schema
you provided, I think it should be User hasOne Email. The view should be
something like
echo $form-create('User');
echo $form-input('name');
echo $form-input('Email.email');
echo $form-end('Submit');
and the code in action method to save it will be like
$this-User-saveAll($this-data);
Hope this helps.
Amit Badkas
PHP Applications for E-Biz: http://www.sanisoft.com
On Tue, Nov 16, 2010 at 9:54 AM, Rey Philip reyphilipre...@gmail.comwrote:
I a newbie question. This is how can I save data in many tables. Heres
a scenario, example I have a Profiles controller, then I have a
register method/action. Lets say I have 2 tables involved the users
table and emails table, this is only for the sake of the
demonstration. In my view in the register method there are two input
boxes name which resides in the users table and email textbox for the
emails table. Now what I want to do is that, when I press the submit
button I want the name to be saved in the names table and the email to
the emails table..
Here is the schema:
users table:
id
name
emails table:
id
user_id
email
I wonder what the view for register method would look like, since the
form-create() methods 1st paramter is the name of the model.. And
also how do I saved the data on two different tables.
Again, thanks in advance.
Philip
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RE: yahoo web hosting problem
Please describe what is occurring vs. what you think should be. Stating it doesn't work doesn't help us help you. From: cake-php@googlegroups.com [mailto:cake-...@googlegroups.com] On Behalf Of fadhli Sent: Tuesday, November 16, 2010 12:16 AM To: cake-php@googlegroups.com Subject: yahoo web hosting problem hello everybody I had a problem about hosting at yahoo web hosting. i can't upload .htaccess files (i think They Used IIS becauce IIS do not support .htaccess, CMIIW) so I use the way in http://book.cakephp.org/view/1533/A-Note-on-mod_rewrite to fix the problem. it's works. but now, i have new problem. i can't upload image. (I use jqimagecrop component), and TinyMCE does not work too, I have tried the tutorial on http://blog.knightdna.net/2010/07/enabling-cakephp-pretty-urls-on-iis.html and http://book.cakephp.org/view/1636/URL -Rewrites-on-IIS7-Windows-hosts but failed. Is there someone who knows how to solve this problem? please help me. thanks before :) Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: yahoo web hosting problem
I think, it would be easier to just change web hosts. -- Louie Miranda - Email: lmira...@gmail.com - Web: http://www.louiemiranda.com On Tue, Nov 16, 2010 at 2:14 PM, whmeroe whme...@gmail.com wrote: Please describe what is occurring vs. what you think should be. Stating it doesn't work doesn't help us help you. *From:* cake-php@googlegroups.com [mailto:cake-...@googlegroups.com] *On Behalf Of *fadhli *Sent:* Tuesday, November 16, 2010 12:16 AM *To:* cake-php@googlegroups.com *Subject:* yahoo web hosting problem hello everybody I had a problem about hosting at yahoo web hosting. i can't upload .htaccess files (i think They Used IIS becauce IIS do not support .htaccess, CMIIW) so I use the way in http://book.cakephp.org/view/1533/A-Note-on-mod_rewrite to fix the problem. it's works. but now, i have new problem. i can't upload image. (I use jqimagecrop component), and TinyMCE does not work too, I have tried the tutorial on http://blog.knightdna.net/2010/07/enabling-cakephp-pretty-urls-on-iis.htmland http://book.cakephp.org/view/1636/URL -Rewrites-on-IIS7-Windows-hosts but failed. Is there someone who knows how to solve this problem? please help me. thanks before :) Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.comcake-php%2bunsubscr...@googlegroups.comFor more options, visit this group at http://groups.google.com/group/cake-php?hl=en Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.comcake-php%2bunsubscr...@googlegroups.comFor more options, visit this group at http://groups.google.com/group/cake-php?hl=en Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: Submit button label in e.g. swedish
Did you try to translate with gettext and not using the Swedish characters
in the code?
On Mon, Nov 15, 2010 at 8:34 AM, Amit Badkas amit.sanis...@gmail.comwrote:
Hi,
You can also try
echo $form-end(array('label' = 'Lägg till', 'escape' = false));
Amit Badkas
PHP Applications for E-Biz: http://www.sanisoft.com
On Sun, Nov 14, 2010 at 1:46 AM, cricket zijn.digi...@gmail.com wrote:
On Sat, Nov 13, 2010 at 8:28 AM, Björn N edtb...@gmail.com wrote:
Hi!
I want to use a label Lägg till on a submit button, using the code:
?php echo $form-end('Lägg till'); ?, but that renders a button with
no text in it. If I change the 'ä' to an 'a' the label shows up fine,
but without the dots above the a. I've tried 'auml; to no avail.
I'm pretty sure that the problem exists for other european languages
too, but as I don't read these languages, it's hard to find a fix for
the problem.
Try:
echo $form-submit('Lägg till', array(escape' = false));
echo $form-end();
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--
Regards,
Zaky Katalan-Ezra
QA Administrator
www.IGeneriX.com
Sites.IGeneriX.com
054-7762312
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