Variables
Kann mit jemand erklären, warum
?php echo $current_user['username']; ?
im default.ctp funktioniert und im add.ctp nicht?
Version 2.1
current_user gesetzt in AppController.php
...
public function beforeFilter() {
...
$this-set('current_user', $this-Auth-user());
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Re: Variables
Il 02/05/2012 09:18, Historiker ha scritto:
Kann mit jemand erklären, warum
?php echo $current_user['username']; ?
im default.ctp funktioniert und im add.ctp nicht?
Version 2.1
current_user gesetzt in AppController.php
...
public function beforeFilter() {
...
$this-set('current_user', $this-Auth-user());
Maybe you implement beforeFilter in the add.ctp related controller
without parent::beforeFilter ?
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to realize a join query !
Hi all,
i trying to realize a join query but its not work and i can not see my
problem/issue?!? I implement my code according to:
http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html
//Models:
class Category extends AppModel {
public $hasMany = array(
'Url' = array(
'className' = 'Url',
'foreignKey' = 'category_id'
)
);}
class Url extends AppModel {
public $hasMany = array(
'ATag' = array(
'className' = 'ATag',
'foreignKey' = 'url_id'
),
'HTag' = array(
'className' = 'HTag',
'foreignKey' = 'url_id'
),
'HeadTag' = array(
'className' = 'HeadTag',
'foreignKey' = 'url_id'
),
'PTag' = array(
'className' = 'PTag',
'foreignKey' = 'url_id'
),
);
}
//Controller:
class FrontendController extends AppController {
public function index(){
$this-loadModel('Category');
$keyword = 'some key';
$domain = 'www.some-domain.com'
/*
How can i realize this with joins:
SELECT * FROM categories, urls, a_tags, head_tags
WHERE categories.id = urls.category_id AND
urls.id = a_tags.url_id AND
urls.id = head_tags.url_id AND
categories.name = 'some key' AND
urls.name LIKE '%www.some-domain.com%'
**/
//it does not work(join)!
$options['joins'] = array(
array('table' = 'urls',
'alias' = 'Url',
'type' = 'LEFT',
'conditions' = array(
'Url.id = ATag.url_id',
'Url.id = HTag.url_id',
'Url.id = HeadTag.url_id',
'Url.id = PTag.url_id',
)
)
);
$options['conditions'] = array(
'AND' =
array('Category.name' = $keyword),
array(Url.name LIKE = %$domain%),
);
$this-Category-recursive = -1;
$res = $this-Category-find('all', $options);
pr($res)
//Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column
'ATag.url_id' in 'on clause'
/* SQL Query:
SELECT `Category`.`id`, `Category`.`parent_id`, `Category`.`lft`,
`Category`.`rght`, `Category`.`name`,
`Category`.`created`,`Category`.`modified`,`Category`.`blacklist`,
`Category`.`is_searched_by_user`
FROM `ssx`.`categories` AS
`Category`
LEFT JOIN `ssx`.`urls` AS `Url` ON (
`Url`.`id` =`ATag`.`url_id` AND
`Url`.`id` = `HTag`.`url_id` AND
`Url`.`id` =
`HeadTag`.`url_id` AND
`Url`.`id` = `PTag`.`url_id`)
WHERE
`Category`.`name` = 'some kategory' AND
`Url`.`name` LIKE
'%www.some-domain.com%'
*/
}
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$this-Params['controller'] doesn't work in cakephp component
hi guys...i need to know how to get current controller from cakephp component i tried to use $this-Params['controller'] on my component but it keeping me get error message like this : Notice (8): Undefined property: DynRubrikComponent::$params [APP \controllers\components\dyn_rubrik.php, line 17] do u guys know how to deal with this matter ? need ur help very soon...thank u.. -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php
Re: $this-Params['controller'] doesn't work in cakephp component
in your __construct() method for component, first parameter is ComponentCollection $collection object. From here you can store controller to component like $this-Controller = $collection-getController(); then params you have in $this-Controller-params -- Lep pozdrav, Tilen Majerle http://majerle.eu 2012/5/2 Cruisine cruisin...@yahoo.co.id hi guys...i need to know how to get current controller from cakephp component i tried to use $this-Params['controller'] on my component but it keeping me get error message like this : Notice (8): Undefined property: DynRubrikComponent::$params [APP \controllers\components\dyn_rubrik.php, line 17] do u guys know how to deal with this matter ? need ur help very soon...thank u.. -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php
Re: get output controller from another controller
Hello,
Unfortunately the output format (in my variable) is still not the REST XML.
Any other idea?
Thanks
Christophe
On Sat, Apr 28, 2012 at 6:31 AM, lowpass zijn.digi...@gmail.com wrote:
I don't know if this is all you need but these might help:
$this-response-type('xml');
$this-viewPath = 'events';
$this-view = 'view'; // assuming app/views/events/view.ctp
On Fri, Apr 27, 2012 at 2:45 AM, Christophe Vandeplas
christo...@vandeplas.com wrote:
Hello,
( using CakePHP 2.1 )
I'm building an application that synchronizes data between different
instances of my application. (download and upload)
My application is REST enabled and thus I can call controller actions
from external applications and get the result in clean xml. However it
is not only a REST server, but also a REST client.
Downloading data from the other instance is easy. I do a $xml =
Xml::build($xmlurl); and process the $xml variable to import
everything into my database. Perfect.
However I am stuck in the other direction: Uploading data.
I could simply do a $xmldata = Xml::fromArray($event)-asXML() however
there is some cleaning to be done. This cleaning is what I do in my
REST view as my REST clients should see the same xml as what I'm
uploading to the other instance.
So if I already do all the work in my rest view, why recoding exactly
the same filtering?
The url /events/view/5.xml calls EventsController-view(5) with XML
layout and outputs everything in XML, exactly as I want it.
I have a ServersController-push() function.
This function needs to do get the same output as /events/view/5.xml ,
and upload it using a REST POST request to the other instance.
You could say I could simply call the /events/view/5.xml page using an
HTTP request from the application.
However it seems absurd as i) it seems absurd (and inefficient/slow)
to do HTTP requests to yourself to extract data and ii) I have
authentication on my REST calls which makes it a lot more difficult.
I tried with :
$eventsController = new EventsController();
$eventsController-set('event', $event);
$view = new View($eventsController);
$viewdata = $view-render('view');
But this only outputs the data in HTML, and not XML.
I tried to play with the CakeResponse object in that newly created
$eventsController, but that doesn't work. (there are no request or
response instances created, and creating them myself doesn't work)
So my question is:
What is the best way to get the output of /events/view/5.xml
(EventsController-view(5) ) inside another controller ?
Thanks for your expertise.
Christophe
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Re: get output controller from another controller
Ok, great.
I managed to get what I want using lowpass advice.
$this-RequestHandler-renderAs($this, 'xml');
$this-viewPath = 'Events';
$this-set('event', $event);
$viewdata = $this-render('view');
print $viewdata;
But resetting the $this Controller to normal variables is rather
annoying and another problem right now.
So I tried to use the same code, but by using a separate
$eventsController = new EventsController();
This also doesn't work. (I don't get the XML output, but the html one)
$eventsController = new EventsController();
$this-RequestHandler-renderAs($eventsController, 'xml');
debug($eventsController);
$eventsController-set('event', $event);
$eventsController-set('isAdmin', $this-_isAdmin());
$view = new View($eventsController);
$viewdata = $view-render('view');
print $viewdata;
Any idea why the separate controller option doesn't work?
Thanks
Christophe
On Wed, May 2, 2012 at 3:16 PM, Christophe Vandeplas
christo...@vandeplas.com wrote:
Hello,
Unfortunately the output format (in my variable) is still not the REST XML.
Any other idea?
Thanks
Christophe
On Sat, Apr 28, 2012 at 6:31 AM, lowpass zijn.digi...@gmail.com wrote:
I don't know if this is all you need but these might help:
$this-response-type('xml');
$this-viewPath = 'events';
$this-view = 'view'; // assuming app/views/events/view.ctp
On Fri, Apr 27, 2012 at 2:45 AM, Christophe Vandeplas
christo...@vandeplas.com wrote:
Hello,
( using CakePHP 2.1 )
I'm building an application that synchronizes data between different
instances of my application. (download and upload)
My application is REST enabled and thus I can call controller actions
from external applications and get the result in clean xml. However it
is not only a REST server, but also a REST client.
Downloading data from the other instance is easy. I do a $xml =
Xml::build($xmlurl); and process the $xml variable to import
everything into my database. Perfect.
However I am stuck in the other direction: Uploading data.
I could simply do a $xmldata = Xml::fromArray($event)-asXML() however
there is some cleaning to be done. This cleaning is what I do in my
REST view as my REST clients should see the same xml as what I'm
uploading to the other instance.
So if I already do all the work in my rest view, why recoding exactly
the same filtering?
The url /events/view/5.xml calls EventsController-view(5) with XML
layout and outputs everything in XML, exactly as I want it.
I have a ServersController-push() function.
This function needs to do get the same output as /events/view/5.xml ,
and upload it using a REST POST request to the other instance.
You could say I could simply call the /events/view/5.xml page using an
HTTP request from the application.
However it seems absurd as i) it seems absurd (and inefficient/slow)
to do HTTP requests to yourself to extract data and ii) I have
authentication on my REST calls which makes it a lot more difficult.
I tried with :
$eventsController = new EventsController();
$eventsController-set('event', $event);
$view = new View($eventsController);
$viewdata = $view-render('view');
But this only outputs the data in HTML, and not XML.
I tried to play with the CakeResponse object in that newly created
$eventsController, but that doesn't work. (there are no request or
response instances created, and creating them myself doesn't work)
So my question is:
What is the best way to get the output of /events/view/5.xml
(EventsController-view(5) ) inside another controller ?
Thanks for your expertise.
Christophe
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Re: Sort assoc data
Yep, thats what I was looking for. Thanks. On Tue, May 1, 2012 at 3:40 PM, lowpass zijn.digi...@gmail.com wrote: Do you mean using Containable? If so, just add an 'order' array under the associated model. 'contain' = array( 'OtherModel' = array( 'fields' = array(...), 'order' = array( 'OtherModel.column' = 'ASC' ) ) ) On Tue, May 1, 2012 at 5:55 PM, Michael Gaiser mjgai...@gmail.com wrote: So, I have been able to sort queries of the basic model, but how do you specify sorting paramaters for the associated models? -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php
Re: Send email Shell Application
I recently upgraded from cakephp 2.0.6 to 2.1.1 and started having problem sending out nightly emails. I'm getting smtp connection time out errors. Nothing has changed on the email server, and emails generated from website forms are still working ... Is it possible that the connection is being dropped because of the malformed message id? http://cakephp.lighthouseapp.com/projects/42648/tickets/2698-cakeemail-messageid-in-cli-environment If so, how do I go about fixing this issue? -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php
Giving context to a select field?
So, I have a Location Model that is using the tree behavior. Level 1
is Countries, their children are Regions. The Regions children are
cities... So I need to give some context to the results in the select
menu since there are several cities with the name Portland for
example. Is it Portland, Oregon or Portland, Maine? I know you can
give context to select fields by giving it an array with sub arrays.
As such, this is what I want to get from my database when I ask for
all the cities:
array('Oregon'=array(42='Salem',33='Portland', 50='Ashland'),
'Maine'=array(86='Portland', 103='Agusta'));
I can make that with a bit of post processing after the data is
retrieved from the DB, but is there a way to get that kind of format
straight from the query? Thanks.
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Re: Cakephp SSN Encryption
Can you give me a specific example of how to use saveMany? I have 4000
clients in my database. Can I create another encrypted field in the
database (say ssn_temp) then do something like this:
$this-User-saveMany(array(array('ssn_temp' = array('User' = 'ssn';
Would something like that work? I'm really confused by the documentation on
saveMany
On Tuesday, May 1, 2012 2:51:50 PM UTC-5, Justin Edwards wrote:
Sorry temp table* not temp folder
On Tue, May 1, 2012 at 7:51 PM, Justin Edwards
justinledwa...@gmail.comwrote:
Steven,
Create a controller method.
Find the data from the temp folder set it to a variable, and then
saveMany from the variable to the encrypted table.
http://book.cakephp.org/2.0/en/models/saving-your-data.html#model-savemany-array-data-null-array-options-array
On Tue, May 1, 2012 at 7:18 PM, Steven Scaffidi ssca...@gmail.comwrote:
Ok I have the data migrated already (I probably should have used
something like pentaho instead of writing my own queries but oh well). How
do I use cake's encryption function on the data?
On Tuesday, May 1, 2012 2:07:56 PM UTC-5, Justin Edwards wrote:
I would migrate it using pentaho. Then you can run cake's encryption
function on the data. You could make a temporary table /model and then
append it to the production table.
On Tue, May 1, 2012 at 7:01 PM, Steven Scaffidi ssca...@gmail.comwrote:
Thanks for the plugin that worked great. I still don't understand how
to use pentaho though to encrypt social security numbers listed in the
access database.
On Apr 30, 5:28 pm, Justin Edwards justinledwa...@gmail.com wrote:
#1http://bakery.cakephp.org/**articles/jmillerdesign/2011/**
12/29/cipher_pl.http://bakery.cakephp.org/articles/jmillerdesign/2011/12/29/cipher_pl.
..
#2http://www.pentaho.com/**download/http://www.pentaho.com/download/
On Mon, Apr 30, 2012 at 4:46 PM, Steven Scaffidi ssca...@gmail.com
wrote:
Hi - I'm looking for information on how to encrypt data in
Cakephp. My
employer had a client management system built in Microsoft Access,
and
I recently took that application and put it on a web-based space
built
in cake. I need to now two things:
#1 How can I encrypt social security numbers from new clients
coming
into the system? I'm encrypting passwords right now, but I'm not
sure
how to do social security numbers.
#2 How do I take social security numbers that are currently listed
in
Microsoft Access with no encryption and put them into the MySQL
database encrypted?
Thanks for the help,
Steven
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Re: $this-Params['controller'] doesn't work in cakephp component
@romel
first error: he wants it in a component - not the view
second issue: the request object should be used for this. not the
controller itself (that used to be this way in 1.x)
http://book.cakephp.org/2.0/en/controllers/request-response.html#cakerequest
(as for right now it still works (readonly) but might be deprecated in
later versions anyway)
but - concerning the view - why passing it on to the view manually? the
view also has the request object and therefore this information
and last error: beforeFilter is only triggered on valid request. so it
might break. always use beforeRender() for passing stuff like that to the
view
but since its irrelevant to this thread..
Am Mittwoch, 2. Mai 2012 13:44:51 UTC+2 schrieb romel javier gomez herrera:
hi!
if the version of cakephp is 2.1
// in /app/Controller/AppController.php
public function beforeFilter(){
$this-set('controller',$this-params['controller']);
$this-set('action',$this-params['action']);
}
// in /app/View/Latyouts/default.ctp
echo 'Controller: '.$controller.'Controller.php'.'br /';
echo 'View: '.$action.'.ctp';
2012/5/2 Tilen Majerle tilen.maje...@gmail.com
in your __construct() method for component, first parameter is
ComponentCollection $collection object.
From here you can store controller to component like
$this-Controller = $collection-getController();
then params you have in $this-Controller-params
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http://majerle.eu
2012/5/2 Cruisine cruisin...@yahoo.co.id
hi guys...i need to know how to get current controller from cakephp
component
i tried to use $this-Params['controller'] on my component but it
keeping me get error message like this :
Notice (8): Undefined property: DynRubrikComponent::$params [APP
\controllers\components\dyn_rubrik.php, line 17]
do u guys know how to deal with this matter ? need ur help very
soon...thank u..
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Re: Cakephp SSN Encryption
I created SSN through using regular sql and just literally copying whats in
the ssn field to the ssn_temp field. And then, this would work if it didn't
time out on me. How can I change the timeout time? There has to be a better
way to do this though.
public function encryptssn() {
$ssns = $this-User-find('list', array('fields' = array('id',
'ssn_temp')));
$j = 1;
foreach ($ssns as $i) {
$this-User-id = $j;
$this-User-saveField('ssn', $i);
$j++;
}
$this-redirect(array('action' = 'index'));
}
On Wednesday, May 2, 2012 3:03:46 PM UTC-5, Steven Scaffidi wrote:
Can you give me a specific example of how to use saveMany? I have 4000
clients in my database. Can I create another encrypted field in the
database (say ssn_temp) then do something like this:
$this-User-saveMany(array(array('ssn_temp' = array('User' = 'ssn';
Would something like that work? I'm really confused by the documentation
on saveMany
On Tuesday, May 1, 2012 2:51:50 PM UTC-5, Justin Edwards wrote:
Sorry temp table* not temp folder
On Tue, May 1, 2012 at 7:51 PM, Justin Edwards
justinledwa...@gmail.comwrote:
Steven,
Create a controller method.
Find the data from the temp folder set it to a variable, and then
saveMany from the variable to the encrypted table.
http://book.cakephp.org/2.0/en/models/saving-your-data.html#model-savemany-array-data-null-array-options-array
On Tue, May 1, 2012 at 7:18 PM, Steven Scaffidi ssca...@gmail.comwrote:
Ok I have the data migrated already (I probably should have used
something like pentaho instead of writing my own queries but oh well). How
do I use cake's encryption function on the data?
On Tuesday, May 1, 2012 2:07:56 PM UTC-5, Justin Edwards wrote:
I would migrate it using pentaho. Then you can run cake's encryption
function on the data. You could make a temporary table /model and then
append it to the production table.
On Tue, May 1, 2012 at 7:01 PM, Steven Scaffidi ssca...@gmail.comwrote:
Thanks for the plugin that worked great. I still don't understand how
to use pentaho though to encrypt social security numbers listed in the
access database.
On Apr 30, 5:28 pm, Justin Edwards justinledwa...@gmail.com wrote:
#1http://bakery.cakephp.org/**articles/jmillerdesign/2011/**
12/29/cipher_pl.http://bakery.cakephp.org/articles/jmillerdesign/2011/12/29/cipher_pl.
..
#2http://www.pentaho.com/**download/http://www.pentaho.com/download/
On Mon, Apr 30, 2012 at 4:46 PM, Steven Scaffidi ssca...@gmail.com
wrote:
Hi - I'm looking for information on how to encrypt data in
Cakephp. My
employer had a client management system built in Microsoft
Access, and
I recently took that application and put it on a web-based space
built
in cake. I need to now two things:
#1 How can I encrypt social security numbers from new clients
coming
into the system? I'm encrypting passwords right now, but I'm not
sure
how to do social security numbers.
#2 How do I take social security numbers that are currently
listed in
Microsoft Access with no encryption and put them into the MySQL
database encrypted?
Thanks for the help,
Steven
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On Wednesday, May 2, 2012 3:03:46 PM UTC-5, Steven Scaffidi wrote:
Can you give me a specific example of how to use saveMany? I have 4000
clients in my database. Can I create another encrypted field in the
database (say ssn_temp) then do something like this:
$this-User-saveMany(array(array('ssn_temp' = array('User' = 'ssn';
Would something like that work? I'm really confused by the documentation
on saveMany
On Tuesday, May 1, 2012 2:51:50 PM UTC-5,
Re: Cakephp SSN Encryption
You can do it in batches. You can also set the timeout.
http://php.net/manual/en/function.set-time-limit.php
'conditions' = array('User.id ' = '200')
On Wed, May 2, 2012 at 3:39 PM, Steven Scaffidi ssca...@gmail.com wrote:
I created SSN through using regular sql and just literally copying whats
in the ssn field to the ssn_temp field. And then, this would work if it
didn't time out on me. How can I change the timeout time? There has to be a
better way to do this though.
public function encryptssn() {
$ssns = $this-User-find('list', array('fields' = array('id',
'ssn_temp')));
$j = 1;
foreach ($ssns as $i) {
$this-User-id = $j;
$this-User-saveField('ssn', $i);
$j++;
}
$this-redirect(array('action' = 'index'));
}
On Wednesday, May 2, 2012 3:03:46 PM UTC-5, Steven Scaffidi wrote:
Can you give me a specific example of how to use saveMany? I have 4000
clients in my database. Can I create another encrypted field in the
database (say ssn_temp) then do something like this:
$this-User-saveMany(array(**array('ssn_temp' = array('User' =
'ssn';
Would something like that work? I'm really confused by the documentation
on saveMany
On Tuesday, May 1, 2012 2:51:50 PM UTC-5, Justin Edwards wrote:
Sorry temp table* not temp folder
On Tue, May 1, 2012 at 7:51 PM, Justin Edwards justinledwa...@gmail.com
wrote:
Steven,
Create a controller method.
Find the data from the temp folder set it to a variable, and then
saveMany from the variable to the encrypted table.
http://book.cakephp.org/2.0/**en/models/saving-your-data.**
html#model-savemany-array-**data-null-array-options-arrayhttp://book.cakephp.org/2.0/en/models/saving-your-data.html#model-savemany-array-data-null-array-options-array
On Tue, May 1, 2012 at 7:18 PM, Steven Scaffidi ssca...@gmail.comwrote:
Ok I have the data migrated already (I probably should have used
something like pentaho instead of writing my own queries but oh well). How
do I use cake's encryption function on the data?
On Tuesday, May 1, 2012 2:07:56 PM UTC-5, Justin Edwards wrote:
I would migrate it using pentaho. Then you can run cake's encryption
function on the data. You could make a temporary table /model and then
append it to the production table.
On Tue, May 1, 2012 at 7:01 PM, Steven Scaffidi ssca...@gmail.comwrote:
Thanks for the plugin that worked great. I still don't understand how
to use pentaho though to encrypt social security numbers listed in
the
access database.
On Apr 30, 5:28 pm, Justin Edwards justinledwa...@gmail.com wrote:
#1http://bakery.cakephp.org/**ar**ticles/jmillerdesign/2011/**12/*
*29/cipher_pl.http://bakery.cakephp.org/articles/jmillerdesign/2011/12/29/cipher_pl.
..
#2http://www.pentaho.com/**downl**oad/http://www.pentaho.com/download/
On Mon, Apr 30, 2012 at 4:46 PM, Steven Scaffidi
ssca...@gmail.com wrote:
Hi - I'm looking for information on how to encrypt data in
Cakephp. My
employer had a client management system built in Microsoft
Access, and
I recently took that application and put it on a web-based space
built
in cake. I need to now two things:
#1 How can I encrypt social security numbers from new clients
coming
into the system? I'm encrypting passwords right now, but I'm not
sure
how to do social security numbers.
#2 How do I take social security numbers that are currently
listed in
Microsoft Access with no encryption and put them into the MySQL
database encrypted?
Thanks for the help,
Steven
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On Wednesday, May 2, 2012 3:03:46 PM UTC-5,
Pass data between models during same request
I'm new to CakePHP and still unfamiliar with the API. So, please bear
with me here.
I have 5 models - 2 for an external data store, 2 for a local data
store, and 1 for the controller. I have one controller that's
directing all the activity. In the controller, I fetch the remote data
and pass control to the model. I have functions in my controller model
that perform all the data manipulation. Once complete, it sends the
data back to the controller. Now comes the tricky part for me. I'll
tell you how I want the app to behave functionally, maybe I can get
help in creating the solution to implement it.
I want the data that was passed out of the Invoice model to be saved
to the local data store. The data came from the remote source
identified in the models, InvoiceHeader and InvoiceDetail. The model,
Invoice, contains the data transformation methods. Once modified, the
data is passed back to the InvoicesController. All that work is
complete. My data array is ready to be saved locally.
But how do I accomplish this? ExternalHeader and ExternalDetail model
the local data store. How do I move the data from the Invoice models
to the External models so that it can be saved? Here's my broken
function:
protected function _saveLocal($_mergedData) {
if (!isset($this-ExternalHeader)) {
$this-loadModel('ExternalHeader');
if (!isset($this-ExternalDetail)) {
$this-loadModel('ExternalDetail');
}
}
//This part is broken.
$data = array($this-ExternalHeader = $_mergedData);
pr($data); die;
$this-ExternalHeader-create();
$this-ExternalHeader-saveAll($data);
//debug($this-ExternalHeader-validationErrors);
}
Please feel free to ask questions if something is unclear. I'm also
open to rethinking my workflow if what I'm doing is un-Cake-like or
overly complex.
Any help is appreciated.
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Re: Problem with JsHelper
You need to switch these two around:
?php
class Controller extends AppController {
}
On Wednesday, February 15, 2012 7:47:50 AM UTC-5, Diablo Sinfuego wrote:
I have a problem with Js that I cannot resolve. I am basically trying
to write a Hello, world app to learn how to use this feature.
When I click on my submit button the first time, everything works.
When I click on the same button the second time, it blows up trying to
go to what appears to be a null controller:
Missing Controller
Error: Controller could not be found.
Error: Create the class Controller below in file: app/Controller/
Controller.php
?php
class Controller extends AppController {
}
Here is my Controller:
public function check($id = false) {
if (!empty($this-request-data)) {
if ($this-RequestHandler-isAjax()) {
$this-set('result', 'Hello, world');
$this-render('result', 'ajax');
}
}
}
Here is my View:
?php echo $this-Html-script('jquery', array('inline' = false)); ?
?php
echo $this-Form-create();
echo $this-Js-submit('Check', array('update' =
'#success'));
echo $this-Form-end();
?
div id=success/div
div id=checking style=display: none;Checking.../div
?php echo $this-Js-writeBuffer(); ?
JsHelper is generating the following JavaScript:
script type=text/javascript
//![CDATA[
$(#submit-549405557).bind(click, function (event) {$.ajax({data:$
(#submit-549405557).closest(form).serialize(), dataType:html,
success:function (data, textStatus) {$(#success).html(data);},
type:post, url:\/hosts\/check});
return false;});
//]]
/script
I'm stumped why it works on the first click but not the second.
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Fatal Error: Class 'String' not found in Model
I have a web application that has been working fine until recently when I
switched operating systems. I migrated from Ubuntu to Arch Linux, backing
up my application online. In the process I lost some directories and my web
application no longer worked.
To solve this, I downloaded CakePHP again, copied the Controllers, Models
and Views from my old project into my new copy of Cake, and modified my
config to reflect my database.
I'm using Cake's AuthComponent and I'm getting this strange error message:
Fatal error: Class 'String' not found in /srv/http/bfm/app/Model/User.php on
line 39
I didn't know what to make of the line number because line 39 is the last
line in the file. I'm not particularly experienced with PHP outside of Cake
so perhaps somebody else will be able to tell me what that might mean.
Each User has many Podcasts, and each Podcast belongs to a User. It was in
accessing any page which used find to retrieve Podcasts and associated User
objects that the error occurred.
Stranger still, actions managed by the UsersController worked fine. I was
able to access my user login page with no problems, and I was redirected to
login when I tried to create a new user, which is consistent with my Auth
settings.
In any case, I decided to track down the cause of this error. I commented
out my validation code and my beforeSave method, which used
AuthComponent::password to hash and salt my users' passwords. Once I did
this, the error vanished. With some further clumsy debugging through
commenting, I figured out that it was specifically the beforeSave method
that was causing problems.
I tried following the trail of functions called from beforeSave, through
AuthComponent and Security. Both of those files had App::uses('String',
'Utility') in them. What's more, I tried adding that line to User.php, and
it didn't help solve the problem either.
My beforeSave method looks like this:
public beforeSave() {
if (isset($this-data[$this-alias]['password']) {
$password = $this-data[$this-alias]['password'];
$this-data[$this-alias]['password'] = AuthComponent::password($password);
}
return true;
}
When I replaced AuthComponent::password($password) with $password, the
error was still there, which confused me, because I was sure String was
needed for AuthComponent::password (via Security), and that was what was
causing the trouble.
Maybe this was too long, but I wanted to give all the information I had,
because I am well and truly stuck. I have no idea what's happening inside
my code.
I can provide more information or code if it's useful. I just don't know
where to begin.
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Re: JsHelper CakePHP 2.1
I can turn around and with this: http://www.cakephp.4uk.pl/ Em 03-05-2012 02:11, Charles Blackwell escreveu: Are there any tutorials available for the JsHelper for CakePHP 2.1 yet? -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php -- Jackson Bicalho jacksonbica...@gmail.com jacksonbicalho.com.br .. Luango - Sistemas e serviços para Internet www.luango.com.br Precisando de ajuda? Acesse: suporte.luango.com.br Acompanhe nosso Blog: blog.luango.com.br .. cont...@luango.com.br Horário de atendimento: - De segunda a sexta: - - das 8:00 as 12:00 - - das 13:30 as 18:00 -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php
