Re: How to define a checkbox variable in Cakephp
You already got your answer at SO.
Am Mittwoch, 6. März 2013 08:50:35 UTC+1 schrieb Victor Musvibe:
I have a form in my Plugin elements and what i would like to insert the
checkbox value into a table named it_queries and field status_type and its
giving me an error Undefined variable: variableValue
[APP\Plugin\Feedback\View\Elements\comment_add.ctp, line 37] .I have
declared the variable in my controller like this
$this-set('variableValueStatus', 'Pending');
and this is line 37 thats giving me the error
Below is the Controller code
class CommentsController extends FeedbackAppController
{
public $components = array('Feedback.Comments');
public function add($foreign_model = null, $foreign_id = null)
{
if (empty($foreign_model) ||
empty($foreign_id) ||
!$this-request-is('post')
)
{
$this-set('variableValueStatus', 'Pending');
return $this-redirect('/');
}
//Other code
}
and in the add view in my element here is how i am trying to accessing the
variable value
echo $this-Form-checkbox('ItQuery.status_type', array('type' =
'hidden', 'value'=$variableValueStatus));
If someone can show me how to fix this, that would be awesome
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Re: How to define a checkbox variable in Cakephp
Thanks euromark. I am on it
On Wed, Mar 6, 2013 at 10:34 AM, euromark dereurom...@gmail.com wrote:
You already got your answer at SO.
Am Mittwoch, 6. März 2013 08:50:35 UTC+1 schrieb Victor Musvibe:
I have a form in my Plugin elements and what i would like to insert the
checkbox value into a table named it_queries and field status_type and its
giving me an error Undefined variable: variableValue
[APP\Plugin\Feedback\View\**Elements\comment_add.ctp, line 37] .I have
declared the variable in my controller like this
$this-set('**variableValueStatus', 'Pending');
and this is line 37 thats giving me the error
Below is the Controller code
class CommentsController extends FeedbackAppController
{
public $components = array('Feedback.Comments');
public function add($foreign_model = null, $foreign_id = null)
{
if (empty($foreign_model) ||
empty($foreign_id) ||
!$this-request-is('post')
)
{
$this-set('**variableValueStatus', 'Pending');
return $this-redirect('/');
}
//Other code
}
and in the add view in my element here is how i am trying to accessing
the variable value
echo $this-Form-checkbox('**ItQuery.status_type', array('type' =
'hidden', 'value'=$variableValueStatus)**);
If someone can show me how to fix this, that would be awesome
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Re: Cake 2.1 admin layout is not working
Hi majna, I will follow your suggestion.
Thanks
On Sunday, March 3, 2013 10:27:24 PM UTC+2, majna wrote:
Hi, here's my suggestions,
- change admin route to
Router::connect(‘/admin’, array(‘controller’ = ‘users’, ‘action’ =
‘index’, ‘admin’ = true));
- replace your beforeRender() callback with:
public function beforeRender() {
if (isset($this-request-params['prefix'])
$this-request-params['prefix'] === 'admin') {
if (!$this-request-is('ajax') $this-name !== 'CakeError'
$this-viewPath !== 'Errors') {
$this-layout = 'admin';
}
}
}
- change isAuthorized() callback like in this example:
http://book.cakephp.org/2.0/en/core-libraries/components/authentication.html#using-controllerauthorize
- remove completely beforeFilter() callback (containing
$this-Auth-allow(‘*’))
- in each controller list only publicly accessible actions, i.e in Users
controller add:
public function beforeFilter() {
$this-Auth-allow('login', 'logout', 'register');
parent::beforeFilter();
}
I hope it'll work then...
On Friday, March 1, 2013 8:52:29 PM UTC+1, di wrote:
I have this:
In routes.php: Router::connect(‘/admin’, array(‘controller’ = ‘users’,
‘action’ = ‘index’,'add’, ‘admin’ = true,’prefix’ = ‘admin’,'layout’ =
‘admin’));
In core.php: (debug, 0)
In appController:
class AppController extends Controller {
public $components = array(
‘Session’,
‘Auth’=array(
‘loginRedirect’=array(‘controller’=’pagina_inicial’,
‘action’=’index’,'admin’=false),
‘logoutRedirect’=array(‘controller’=’users’, ‘action’=’login’),
‘authError’= ”,
‘authorize’=array(‘Controller’)
)
);
public $helpers = array(‘Session’,'form’,'Html’,'PhpExcel’);
public $pdfConfig = array(
‘engine’ = ‘CakePdf.Tcpdf’,
);
public $cacheAction = ’1 hour’;
public function isAuthorized($user) {
$role=$this-Session-read(‘Auth.User.role’);
//die(debug($role));
if(isset($this-request-prefix) $role!=’admin’){
return FALSE;
}
return true;
}
public function beforeFilter() {
$this-Auth-allow(‘*’);
//$this-set(‘logged_in’, $this-Auth-loggedIn());
//$this-set(‘current_user’, $this-Auth-user());
// if its the administrator/manager – change the layout
/**if (isset($this-params['prefix']) $this-params['prefix'] ==
‘admin’) {
$this-layout = ‘admin’;
} else {
$this-layout = ‘user’;
}**/
}
public function beforeRender() {
$this-_configureErrorLayout();
}
public function _configureErrorLayout() {
if ($this-name == ‘CakeError’) {
if ($this-_isAdminMode()) {
$this-layout = ‘admin’;
} else {
$this-layout = ‘default’;
}
}
}
public function _isAdminMode() {
$adminRoute = Configure::read(‘Routing.prefixes’);
if (isset($this-params['prefix']) in_array($this-params['prefix'],
$adminRoute)) {
return true;
}
return false;
}
also have:
app/view/layout/default.ctp and app/view/layout/admin.ctp
app/view/Homepage/index.ctp and app/view/HomePage/admin_index.ctp
But not working, what am I doing wrong, any help please.
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debug disabled in Custom Authentication object?
Hi there, I'm trying to write my own authentication Custom Authentication object and doing the usual thing of debugging everywhere to check stuff and I have noticed that debug seems to be suppressed even tho it's set to 2 in the core? I have a results array that I can echo out serialized but cannot display with the normal debug() function... Is this by design or am I missing something? Obviously I can see why it would be by design in the core - leaving debug calls in authentication methods is mega stupid, but it's just confusing me so I'd like to know for certain! TIA d//t -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups CakePHP group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: Setting the Value of Options in a drop down...
Thanks! ...Unfortunately, sometimes you inherit a database schema and just
have to make do with what you have.
I have, however, located a solution in case anyone else comes across this
issue:
echo $this-Form-input('Sold', array('options' =
array(*'SOLD'='Sold'*),'empty'
= $biddetail['Biddetail']['Sold']));
The first element ('SOLD' in this case) is the value of the option
The second element ('Sold' in this case) is the selection option
Hope this helps!
On Tuesday, March 5, 2013 5:17:36 PM UTC-6, April DeRossett wrote:
Hello!
Here is what I have in my view:
if($biddetail['Biddetail']['Sold'] == 'SOLD'){$otherstate = 'OPEN';} else
{$otherstate = 'SOLD';}
echo $this-Form-input('Sold', array('options' =
array($otherstate),'empty' = $biddetail['Biddetail']['Sold']));
Is there no way to set the value to equal to the option? ie value =
'SOLD' rather than value = '0'. As you can see above the values change
based on the current value populated in the data base...
I don't want to have to go back and add a table to hold two values that
will never change. Any solutions? I have already read the documentation
at:
http://book.cakephp.org/2.0/en/core-libraries/helpers/form.html which
does not provide a solution for this question.
Thanks!!
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Re: Date picker for CakePHP 2.0.3
@Florin Trifu Thanks for the instruction...Works perfectly!
@Yen Hua Chuah You can set the date format here:
script
$(function() {
$(#datepicker).datepicker({ dateFormat: yy-mm-dd });
});
/script
Check out the API documentation...It is pretty nice.
http://api.jqueryui.com/datepicker/#option-dateFormat
On Thursday, February 21, 2013 1:25:13 AM UTC-6, Yen Hua Chuah wrote:
Hi
it does work but the default date format is mm/dd/. How can i change
it to /mm/dd
please advise
thanks
chris
On Wednesday, January 23, 2013 3:53:30 PM UTC+8, Gian Carlo Asuncion wrote:
Works like magic bro no more conflict on other components, keep sharing
God Bless!
On Tuesday, November 29, 2011 4:11:27 PM UTC-8, Florin Trifu wrote:
Thank you very much! Indeed it worked.
Just to let the other users know in case they will have the same problem:
1. Download jquery (http://docs.jquery.com/Downloading_jQuery) and put
the file in $project/app/webroot/js (e.q: *
$project/app/webroot/js/jquery.js*)
2. Download jquery-ui (http://jqueryui.com/download); I, for example,
downloaded a zip archive called: jquery-ui-1.8.16.custom.zip. From this
archive you will have to copy the followings:
a. *$archive_root/js/jquery-ui-*.js* in *$project/app/webroot/js* (give
it a shorter name e.q: jquery-ui.js)
b. *$archive_root/css/smothness/** to *$project/app/webroot/css*(including
the images; rename the css file to something shorter)
3. Include both js files in your layout. eq:
*
//$project/app/views/Layouts/default.ctp
-
echo $this-Html-script(array('jquery',
'jquery-ui'));
*4. Include the css file. Eq
*//$project/app/views/Layouts/default.ctp
-
echo $this-Html-css('jquery-ui.css');
*5. Put this lines of code before calling the date-picker:
*script
$(function() {
$(#datepicker).datepicker();
});
/script*
6. Call the date picker in your form:
*echo $this-Form-input('expire',
array(
'id'='datepicker',
'type'='text'
)*
This is it!
Best regards!
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Saving AJAX Checkboxes
Hi there,
i have following tables
Events
Cities
Locations
EventLocations
When i edit an Event i can select the city (city_id) where the event is.
But every City has more than one location which i get over AJAX.
That works Great.
But now i want to store the locations which i have checkboxed into the
table event_locations
How can i do that ?
Any ideas ?
Here is my Code:
*edit.ctp*
*?php*
*echo $this-Form-input('city_id');
*
*echo $this-Js-writeBuffer();*
*?*
*
*
*div id=target-div/div
*
*
*
*script typ=text/javascript*
* $(#EventCityId).click(function(){*
*var cityid = $(#EventCityId).val();*
*$.get(/events/fetch/+ cityid,*
* function(data) {*
* $('#target-div').fadeOut(fast, function() { *
* $('#target-div').html(data);*
* $('#target-div').fadeIn(fast);*
* });*
* });*
*return false;*
* });*
*/script*
*EventsController.php*
*public function fetch($city_id) {*
*$locations = $this-Event-Location-findAllByCityId($city_id);*
*$this-set('locations', $locations);*
*}*
*
*
*fetch.ctp*
*?php*
* $select_value = array(); *
* foreach($locations as $location) {*
* $key = $location['Location']['id'];*
* $value = $location['Location']['name'];*
* $select_value[$key]= $value;*
* }*
* *
* $mydata = $this-data;*
* echo $this-Form-select('Location', $select_value, array('label'=
false, 'multiple' = 'checkbox'));*
* echo $this-Html-link(__('Add another Location'), array('controller' =
'locations', 'action' = 'add'));*
*?*
Thanks for help
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Multirow form - add inputs with JS, but only the first ones gets submitted ...
I'm doing a CakePHP site, I have a form there, and the user should be able
to add multirow inputs dynamically, with JavaScript. Let me simplify it: I
generate the first input with this code:
echo $this-Form-input('Student.0.name');
So, when the user click on add more inputs - then I inject the HTML for
this input - which is:
div class=input required
label for=Student1NameWidth/labelinput name=data[Student][1][name]
id=Student1Name type=text/div
The HTML, generated from the CakePHP code is equal to the other one -
except the 0 and 1, we have sequent number here. But, when I submit - I
have only the first input data on the server ... as the other ones have
never been submitted.
What am I doing wrong?
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about float numbers
What I did
my form having some of input boxes.one of them is about salary .iam entered
salary as 111 and submitted form
What happened
in the database the salary stored as 1.1e+006
What I expected to happen
how can i store salary as 111
and my input box code is
?php echo $this-Form-input(sales_transaction_avg, array('div'=false,
'label'=false, 'type'='text', 'class'='number','style'='width:34%
!important'))?
plz suggest solution and explain indetail what is the actul problem
thank Q
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Help With Classes and Objects
I am currently taking on a medium sized application and I need a few pointers as far as the design process goes. The project I am working on is going to be a new version of a website written with the ASP.NET 1.1 framework. The application I am working with is very straightforward ,but I want to know what should be considered a class. There is one class that I am sure that I will have and that is Users. Now with that said, the application will have three types of users, which are Agency, Individuals, and last but not least Admin. Now the only thing that my application will be really used for is to submit data via forms, and once submitted the users will have to the ability to view the data submitted and export the data to an excel spreadsheet. Now my question is by looking at the legacy website, how should I know what should be considered a class, and also what should be considered an object. With that said, this is my first real project and I just need a little guidance. Thanks in advance!! -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups CakePHP group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
missing controller exception
Hi all, Im trying to debug this error. when I look at the cakelogs I get this [MissingControllerException] Controller class Controller could not be found. where should I look to begin debugging this? I googled around and everyone with a similar issue was referencing an actual controller like img or jscontroller. Is there a way i can get a better idea of what exactly is bombing? I looked at the server access logs and there is a revolving 302 happening. I commented out my routes to check if it was happening there and the error persisted. Any ideas? -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups CakePHP group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: missing controller exception
FYI, it was saying this was coming from webroot/index.php...but the site itself works fine. On Wednesday, March 6, 2013 12:56:58 PM UTC-5, Devario Johnson wrote: Hi all, Im trying to debug this error. when I look at the cakelogs I get this [MissingControllerException] Controller class Controller could not be found. where should I look to begin debugging this? I googled around and everyone with a similar issue was referencing an actual controller like img or jscontroller. Is there a way i can get a better idea of what exactly is bombing? I looked at the server access logs and there is a revolving 302 happening. I commented out my routes to check if it was happening there and the error persisted. Any ideas? -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups CakePHP group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: Authentication issue
Thanks, that worked, much appreciated On Tuesday, 5 March 2013 11:29:02 UTC+10:30, David Camerotto wrote: My apologies in advance, i am still relatively new to CakePHP. I took over a site a number on months ago and have slowly worked out how thing operate. (http://www.musicformywedding.com.au/) One issue that has me stumped is access to a custom plugin for FAQs, you can only access this page if logged in. I cannot work out where the code is to control this, i have looked in the plugins controller but it seems to only affect the admin page for creating the FAQs. I even created a new plugin that was identical to the FAQ plugin apart from the naming conventions (called it questions) and it still asks you to login, does this mean that all plugins need authentication. Any help much appreciated Regards David -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups CakePHP group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: about float numbers
See the answer you already got here
https://cakephp.lighthouseapp.com/projects/42648/tickets/3676
The answer still is the same:
You got no problem, since `1.1e+006 === 111` (note the identical
here)
You should also ask yourself if float makes sense here. seems like you are
only interesting in the integer.
Why not using it as such then?
Am Mittwoch, 6. März 2013 16:24:02 UTC+1 schrieb kishore reddy:
What I did
my form having some of input boxes.one of them is about salary .iam
entered salary as 111 and submitted form
What happened
in the database the salary stored as 1.1e+006
What I expected to happen
how can i store salary as 111
and my input box code is
?php echo $this-Form-input(sales_transaction_avg, array('div'=false,
'label'=false, 'type'='text', 'class'='number','style'='width:34%
!important'))?
plz suggest solution and explain indetail what is the actul problem
thank Q
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