Remove tag wrapping around prev and next pagination
How can I completely remove tag wrapping around prev and next pagination links? According to Cake's manual: tag The tag wrapping tag you want to use, defaults to 'span' I have tried to set the tag attribute to false and all I got was some bizarre behavior as below: class=next -- You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en-US.
Re: Se Ya Cake..bake a dick cake frosting on your face...............
Why are you comparing Cake to Drupal? Shouldn't you be comparing Cake to Django? Or Ruby on Rails? I don't see the point in your troll at all. Maybe you should had posted your message in the Joomla group. -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php
Re: Facts
The reason that Drupal/WP/etc... has more job posts is because most employers want to hire offshore people to make shitty sites in a short time for cheap. Like I said before, you comparison of a PHP framework with a CMS is irrelevant... they serve for different purposes. -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php
Re: $_POST is populated with the form data, but $this-data is always empty
Did you try to check for the value of the data attribute from a method
invoked after the beforeFilter method? I would guess that the data
attribute is not set when beforeFilter is being called. Also, are you
calling the parent method on your method before reading the data?
parent::beforeFilter();
On Nov 29, 10:56 am, amfriedman amfried...@gmail.com wrote:
Hey folks
This is a very strange issue indeed, and at its root it is NOT related
to this post that declares a similar
symptom:http://groups.google.com/group/cake-php/browse_thread/thread/840eaa08...
I have a form in /users/view/. When I submit it and check $_POST and
$this-data at the very beginning of AppController-beforeFilter(),
the form data appears in the $_POST array but $this-data does not
have any data. In fact, $this-data is not even set by Cake!
The Auth component is removed from the $components list, so I know
that Auth is not the culprit. I've also tried to test this form in
different controllers/views, and I get the same problem. Pretty
scary, huh?
---
Here is the view code (I've also tried setting the form-create()
first argument with a model of 'User' and used full Model.field dot
notation for my inputs):
---
?php echo $form-create(NULL,
array(
'default' = true,
'inputDefaults' = array(
'label' = false,
'div' = false
)
)
); // default = onsubmit true/false ?
?php echo $form-input('username', array('size'=
20, 'maxlength'
= 50)); ?
?php echo $form-input('pw', array('type' =
'password',
'size'= 20, 'maxlength' = 50)); ?
?php echo $form-submit('Log In raquo;',
array('class' =
'submit', 'name' = 'submit', 'title' = 'Enter your username and
password for access.', 'class' = 'button', 'escape' = false)); ?
?php echo $form-end(); ?
---
Here is the app_controller:
---
function beforeFilter() {
pr(__CLASS__.'::'.__FUNCTION__.'()...');
pr('POST data: ');
pr($_POST);
if(isset($this-data)) {
pr('this-data: ');
pr($this-data);
} else { pr('this-data not set!'); }
// ...
}
---
Here is the browser output:
---
AppController::beforeFilter()...
POST data:
Array
(
[_method] = POST
[data] = Array
(
[User] = Array
(
[username] = testuser
[pw] = 12345
)
)
[submit] = Log In »
)
this-data not set!
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Re: Phone Number Validation
You can try to use a virtual field: http://book.cakephp.org/view/1608/Virtual-fields Or you can validate those fields before you save and errors are found, use the session flash variable to show the error message. On Nov 29, 9:18 am, Dave Maharaj m...@davemaharaj.com wrote: I am taking a single Model.phone and breaking the input up into 3 inputs (area_code) - (prefix) - (suffix) so my question is how do I validate that? I can merge the data to get my Model.phone and run standard validation on that but how to get the message on error back to the view since Model.phone is not on the page? My guess is validate each 3 if valid merge the data to get my Model.phone, but if any of the 3 are not valid (area_code) - (prefix) - (suffix) I only want 1 error message. I do not want individual error messages for the 3 inputs since everyone knows a phone number is NUMBER if they want to waste their time putting in letters and junk well then go ahead, I only want to return 1 error message for the full Model.phone (wrong length, not empty stuff like that Any ideas how to do this? Standard submit no js checking. Thanks, Dave Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Session not saved before redirect
I googled about this problem and found some people with the same
issues, but I could not find a resolution. This simple code doesn't
work:
$user_id = $this-User-getLastInsertID();
$this-Session-write('user_id', $user_id);
$this-redirect('/profiles');
$user_id is being correctly set, but I am trying to grab the user_id
session inside the profiles method with no success - it returns 0.
Any idea on how to solve this without any crazy hacking? :)
Thanks
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Re: Loading a cookie inside a model's constructor
But I need to access the cookie in the model because that model uses a
dbconfig that relies in what the cookie is set to.
On Oct 14, 4:15 pm, cricket zijn.digi...@gmail.com wrote:
On Thu, Oct 14, 2010 at 4:38 PM, Raisen weys...@gmail.com wrote:
So I want to read a cookie using the Cakephp's Cookie class. First, I
tried to import only the cookie class and read the cookie, but I was
getting an error stating that the cipher key cannot be null. So I
imported the Configure class, set the key property of the cookie
instance to the respective cipher key, but the cookie is returning a
different result from what it's set to. Any ideas?\
The override constructor class looks like:
class Member extends AppModel {
function __construct( $id = false, $table = NULL, $ds = NULL ) {
App::import('Component','Cookie');
App::import('Core','Configure');
$conf = new Configure();
$cookie = new CookieComponent();
$cookie-key = $conf-read(Security.cipherSeed);
var_dump($cookie-read('sel_app'));
...
parent::__construct($id,$table,$ds);
You should read write to cookies in the controller (or component)
not the model.
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Re: Loading a cookie inside a model's constructor
Thank you!! I was missing the initialize method. Also, I don't think I
can pass from the controller because it needs to be set at the
constructor method otherwise cake will thrown an exception saying that
it cannot find the table.
On Oct 14, 6:22 pm, Miles J mileswjohn...@gmail.com wrote:
You should be passing the cookie from the controller to the model.
$this-Model-cookie = $this-Cookie-read('cookieName');
But to answer your question, you need to initialize the cookie
component.
$cookie = new CookieComponent();
$cookie-initialize($this, array());
On Oct 14, 4:15 pm, cricket zijn.digi...@gmail.com wrote:
On Thu, Oct 14, 2010 at 4:38 PM, Raisen weys...@gmail.com wrote:
So I want to read a cookie using the Cakephp's Cookie class. First, I
tried to import only the cookie class and read the cookie, but I was
getting an error stating that the cipher key cannot be null. So I
imported the Configure class, set the key property of the cookie
instance to the respective cipher key, but the cookie is returning a
different result from what it's set to. Any ideas?\
The override constructor class looks like:
class Member extends AppModel {
function __construct( $id = false, $table = NULL, $ds = NULL ) {
App::import('Component','Cookie');
App::import('Core','Configure');
$conf = new Configure();
$cookie = new CookieComponent();
$cookie-key = $conf-read(Security.cipherSeed);
var_dump($cookie-read('sel_app'));
...
parent::__construct($id,$table,$ds);
You should read write to cookies in the controller (or component)
not the model.
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their CakePHP related questions.
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Re: Loading a cookie inside a model's constructor
Maybe... :) This model is a plugin model though, so it relies on the cookie set by the main application's controller to find out which database configuration to connect to. Thanks all for the replies, the code is working now. On Oct 15, 10:08 am, Dr. Tarique Sani tariques...@gmail.com wrote: On Fri, Oct 15, 2010 at 9:56 PM, Raisen weys...@gmail.com wrote: But I need to access the cookie in the model because that model uses a dbconfig that relies in what the cookie is set to. Like said above pass the cookie from the controller to the model, in fact just pass the needed value from within the cookie to the model. If your model is dependent on a cookie then it is time to refactor :-) Cheers Tarique -- = Cheesecake-Photoblog:http://cheesecake-photoblog.org PHP for E-Biz:http://sanisoft.com = Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: Possible to create a gzip xml file?
You can use the Zlip functions: http://php.net/manual/en/book.zlib.php On Oct 15, 8:42 am, 5942marine jluken...@gmail.com wrote: I've been doing some reading and so far, haven't found a solid answer. My question lies around gzip and xml. Is it possible to create a xml file using cakephp that is compressed? like /sitemap.xml.gz I have it working just fine if you hit /sitemap.xml, but I'd really like that ability to take that dynamic file, compress it, and store it as sitemap.xml.gz Thanks for all your suggestions! Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: log function inside a component
Thanks On Oct 13, 11:22 am, cricket zijn.digi...@gmail.com wrote: On Wed, Oct 13, 2010 at 1:15 PM, Raisen weys...@gmail.com wrote: Is there a way to use the log function inside a component? log() is a method of Object, so: $this-log(...) as with controllers. http://api.cakephp.org/ Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: Custom router question
I created the report plugin using the cake command line: cake bake plugin report The folder structure for the plugin looks just like the main application's one - views, controllers, models, etc. So I created a view/controller for each report I want. It's very simple. Be sure to read http://book.cakephp.org/view/119/Plugin-Tips Once a plugin has been installed in /app/plugins, you can access it at the URL /pluginname/controllername/action. In our pizza ordering plugin example, we'd access our PizzaOrdersController at /pizza/ pizzaOrders. That's what triggered me to use plugins - the url format. On Oct 13, 1:49 pm, Michael Tokar michael.to...@gmail.com wrote: Interesting. Do you think you could post some sample code of your report plugin? On 14 October 2010 09:41, Raisen weys...@gmail.com wrote: I did find a way to make a reports section the way I want - plugins! Just create a reports plugin and then you can add the sales, customers, etc... controllers/views. The url will look like: http://url.com/reports/sales/ On Oct 13, 1:15 pm, Michael Tokar michael.to...@gmail.com wrote: On 14 October 2010 07:17, cricket zijn.digi...@gmail.com wrote: But let's back up a bit--do you have Sale Customer models? What I was getting at in my earlier suggestion was that you could declare options in each model for how its reporting would be conducted. For my situation at least, that doesn't seem like a great solution, as I don't have a one-to-one relationship with Models and Reports. Several of my reports use multiple models, and several models have different reports associated to them. Check out the new CakePHP Questions sitehttp://cakeqs.organd help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.comcake-php%2bunsubscr...@googlegroups.c omFor more options, visit this group at http://groups.google.com/group/cake-php?hl=en Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Loading a cookie inside a model's constructor
So I want to read a cookie using the Cakephp's Cookie class. First, I
tried to import only the cookie class and read the cookie, but I was
getting an error stating that the cipher key cannot be null. So I
imported the Configure class, set the key property of the cookie
instance to the respective cipher key, but the cookie is returning a
different result from what it's set to. Any ideas?\
The override constructor class looks like:
class Member extends AppModel {
function __construct( $id = false, $table = NULL, $ds = NULL ) {
App::import('Component','Cookie');
App::import('Core','Configure');
$conf = new Configure();
$cookie = new CookieComponent();
$cookie-key = $conf-read(Security.cipherSeed);
var_dump($cookie-read('sel_app'));
...
parent::__construct($id,$table,$ds);
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their CakePHP related questions.
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Re: Custom router question
I've looked at the profiles routing before, and the reason I didn't
like was because I couldn't use the reports name for the top folder
hierarchy. So basically I have to create a sales_controller.php
instead of reports_sales_controller.php
But it looks like it's the only viable solution so far. Thanks :)
On Oct 13, 7:23 am, gremlin abba.bry...@gmail.com wrote:
What about a custom routing prefix ( ie. admin routing ) - just add
'reports' to the prefix array and then in the sales controller do a
reports_index function and in the customers controller define a
reports_index function and cakes default routing will give you the 2
urls you used as an example.
On Oct 13, 2:22 am, Michael T michael.to...@gmail.com wrote:
I have to do a similar thing in my Cake app, so I'm very interested to
hear how you go about it in the end. For the time being I've taken
your first approach of having a report-per-action in the one
controller.
I was thinking about defining each report in the Model layer however
(similar to what cricket was saying) by parameterising each report
into the necessary fields and then defining them in the app itself or
in the database. Hadn't thought about the routing issues yet however.
On Oct 13, 12:44 pm, cricket zijn.digi...@gmail.com wrote:
Why not just use a single controller that $uses each of the models in
question?
Router::connect(
'/reports/:type',
array(
'controller' = 'reports',
'action' = 'view'
),
array(
'type' = '[a-z]+',
'pass' = array('type')
)
);
public function view($type = null)
{
if (!$type)
{
// ...
}
$model = Inflector::modelize($type);
// ...
}
On Tue, Oct 12, 2010 at 7:27 PM, Raisen weys...@gmail.com wrote:
Assume that I have a reports page where there would be multiple sub-
reports. I want the urls to look like:
/reports/sales/
/reports/customers/
One way I managed to do that was to create actions inside the reports
controller for each subreport, but I am trying to do something
different. I want each subreport to have its own controller,view.
Basically I would have a controller named:
reports_sales_controller
and views
/reports/sales/index.ctp
Is that possible?
I was trying to do something like:
Router::connect('/reports/(.*)/*', array('controller'='$1',
'action'='index'));
which probably it's way off what I want.
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with their CakePHP related questions.
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Re: Custom router question
Oh yes, another question. According to the manual:
You can configure the Router to use multiple prefixes too:
Plain Text View
Router::connect('/profiles/:controller/:action/*', array('prefix' =
'profiles', 'profiles' = true));
1. Router::connect('/profiles/:controller/:action/*',
array('prefix' = 'profiles', 'profiles' = true));
I don't understand what that boolean assignment is for.
On Oct 13, 7:23 am, gremlin abba.bry...@gmail.com wrote:
What about a custom routing prefix ( ie. admin routing ) - just add
'reports' to the prefix array and then in the sales controller do a
reports_index function and in the customers controller define a
reports_index function and cakes default routing will give you the 2
urls you used as an example.
On Oct 13, 2:22 am, Michael T michael.to...@gmail.com wrote:
I have to do a similar thing in my Cake app, so I'm very interested to
hear how you go about it in the end. For the time being I've taken
your first approach of having a report-per-action in the one
controller.
I was thinking about defining each report in the Model layer however
(similar to what cricket was saying) by parameterising each report
into the necessary fields and then defining them in the app itself or
in the database. Hadn't thought about the routing issues yet however.
On Oct 13, 12:44 pm, cricket zijn.digi...@gmail.com wrote:
Why not just use a single controller that $uses each of the models in
question?
Router::connect(
'/reports/:type',
array(
'controller' = 'reports',
'action' = 'view'
),
array(
'type' = '[a-z]+',
'pass' = array('type')
)
);
public function view($type = null)
{
if (!$type)
{
// ...
}
$model = Inflector::modelize($type);
// ...
}
On Tue, Oct 12, 2010 at 7:27 PM, Raisen weys...@gmail.com wrote:
Assume that I have a reports page where there would be multiple sub-
reports. I want the urls to look like:
/reports/sales/
/reports/customers/
One way I managed to do that was to create actions inside the reports
controller for each subreport, but I am trying to do something
different. I want each subreport to have its own controller,view.
Basically I would have a controller named:
reports_sales_controller
and views
/reports/sales/index.ctp
Is that possible?
I was trying to do something like:
Router::connect('/reports/(.*)/*', array('controller'='$1',
'action'='index'));
which probably it's way off what I want.
Check out the new CakePHP Questions sitehttp://cakeqs.organdhelpothers
with their CakePHP related questions.
You received this message because you are subscribed to the Google
Groups CakePHP group.
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group athttp://groups.google.com/group/cake-php?hl=en
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log function inside a component
Is there a way to use the log function inside a component? Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: Custom router question
I did find a way to make a reports section the way I want - plugins! Just create a reports plugin and then you can add the sales, customers, etc... controllers/views. The url will look like: http://url.com/reports/sales/ On Oct 13, 1:15 pm, Michael Tokar michael.to...@gmail.com wrote: On 14 October 2010 07:17, cricket zijn.digi...@gmail.com wrote: But let's back up a bit--do you have Sale Customer models? What I was getting at in my earlier suggestion was that you could declare options in each model for how its reporting would be conducted. For my situation at least, that doesn't seem like a great solution, as I don't have a one-to-one relationship with Models and Reports. Several of my reports use multiple models, and several models have different reports associated to them. Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Custom router question
Assume that I have a reports page where there would be multiple sub-
reports. I want the urls to look like:
/reports/sales/
/reports/customers/
One way I managed to do that was to create actions inside the reports
controller for each subreport, but I am trying to do something
different. I want each subreport to have its own controller,view.
Basically I would have a controller named:
reports_sales_controller
and views
/reports/sales/index.ctp
Is that possible?
I was trying to do something like:
Router::connect('/reports/(.*)/*', array('controller'='$1',
'action'='index'));
which probably it's way off what I want.
Check out the new CakePHP Questions site http://cakeqs.org and help others with
their CakePHP related questions.
You received this message because you are subscribed to the Google Groups
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to
cake-php+unsubscr...@googlegroups.com For more options, visit this group at
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