Re: Why CakePHP ?
If all you need is a CMS I would suggest using an existing CMS rather than trying to build one yourself in any language. There are many good CMS packages available and some of them are based on CakePHP. CakePHP, or another framework regardless of the language it is based on, is appropriate for developing custom web applications that cannot be addressed by existing software packages. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/d/optout.
Does CakePHP 2.5 support the HSTORE and ARRAY data types from PostgreSQL?
We are looking into what framework to use for a new project. One of the requirements of the project is to use PostgreSQL and take advantage of the Postgres specific data types like HSTORE. Is that something that CakePHP supports? Thanks. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/d/optout.
Re: Form field which is displayed only
Why are you using a form field at all? If you just want to display the data
then just output the data as text.
On Tuesday, June 3, 2014 2:13:58 PM UTC+3, th...@gmx.at wrote:
>
> I'm using CakePHP 2.4.9
> In my application I want to have a readonly field where I display data
> which cannot be changed. E.g., a persons country: there is a hidden field
> with the country ID and a readonly text field with the countries name. The
> user can see the persons country but is not able to change it. So I do in
> the edit.ctp
>
>
> $this->Form->input('Person.country_id', array('type' => 'hidden', ...));
>
> $this->Form->input(null, array('type' => text, 'value' => 'Country',
> 'readonly' => 'readonly', ...)
>
> The expected outcome is that only the data of the hidden field are posted
> on submit but not the data of the readonly field.
> But what I have is that both fields have the name '[Person][country_id]'
> and both fields are part of the submit data.
>
> Is there a way to format such informative readonly fields like any other
> form data, but not include them in the form data on submit?
>
> In the FormHelper I see that the setEntity does not change _entityPath if
> the $fieldName parameter is null, it just remains what it was before. Is
> that intended?
>
> I can, of course, use an invalid model. e.g.
>
> $this->Form->input('Invalid.country', ...)
> But that looks like an ugly hack to me.
>
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Using PHPUnit for code that requires basic authentication
How do I write test cases in PHPUnit for code that is using the Auth module with basic authentication? I have found bits and pieces of information about it but does anyone know of a step by step howto or detailed documentation? My code limits certain actions to certain user types so it calls the Auth->login method and then gets the user object from Auth ($User = $this->Auth->user()) and then checks the group_id ($User['group_id']). There seem to be two approaches to this: 1. Mock the User object and the Auth component 2. Read the User information from the database and call Auth->login explicitly in the test setup Which approach is "best practice"? Are there some cases where it is better to use one over the other? Unfortunately, I have no real experience using PHPUnit or other unit testing frameworks. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/groups/opt_out.
Re: Putting custom code in a separate repository
On Monday, September 9, 2013 5:05:04 PM UTC+3, Jeremy Burns : class...@classoutfit.com wrote: > > You add submodules in a path relative to the root of the git repository. I > am a Git command line coward so use SourceTree (http://sourcetreeapp.com) > which does it all for me. I have all (most) of my plugins as submodules. > > Yes - this approach would work well for plugins as they have their own directory structure and everything for a plugin is contained below one parent directory. However, for general Cake code (i.e. models, views and controllers) there is no isolated directory point under which all of these would be done. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/groups/opt_out.
Re: Putting custom code in a separate repository
On Monday, September 9, 2013 4:58:06 PM UTC+3, Simon Males wrote: > > Some people have made lib/Cake a submodule > > https://github.com/nodesagency/cakephp-lib > This sounds like it would work although it is somewhat of a shame to leave out all the code under app. My question would be how to get started. If I just clone the cakephp-lib where do I get the code under app from? Take it from a zip file? Another suggestion is too have cakephp/cakephp as an remote named > 'upstream'. Then you could suck in changes via `git fetch upstream`, but it > could get messy in the app directory. > As the app directory is what I am most interested in I don't think I want to go for messy. -- > Simon Males > -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/groups/opt_out.
Re: Putting custom code in a separate repository
Thanks for the suggestion. >From a quick look at git submodules it seems that they are geared to using them in a single directory. The changes to a clean CakePHP installation end up being across multiple directories as well as include changes to some of the files in the original CakePHP repository. I didn't see how submodules would handle that situation. Do you have a reference that would explain this more? -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/groups/opt_out.
Putting custom code in a separate repository
I started a project locally by cloning the git repository for CakePHP (branch 2.4). I would like to maintain the ability to do a pull on the git repository to get any updates as new releases are put out. I assume I should be on branch 2.4 rather than on master. I would also like to have my code in a separate repository. That includes any changes I made to files that come as part of the CakePHP repository (so far this includes app/Config/bootstrap.php, app/Config/core.php, app/Config/routes.php and app/Controller/AppController.php) as well as files that I have added (i.e. everything under Config, Controller, Model, Test, View and webroot). There are also Plugins that have been retrieved from other repositories but since those are contained under a single directory that isn't a problem to maintain. Does anyone have a recommendation as to how to go about doing this? Thanks. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/groups/opt_out.
Re: User Defined Dashboard?
If I understand the problem correctly I would restate it as: There are dashboard items (DashboardItem) that can be displayed on a dashboard. There is a relationship between user groups (Group) and a subset of dashboard items defining which dashboard items can be displayed for that group. You want to add a relationship between the user (User) and the subset of dashboard items that are available to the group and allow them to choose which of those items will be displayed on their personal dashboard. If that problem statement is correct then you would want to do something with a HABTM relationship between DashboardItem and Group as well as a HABTM relationship between DashboardItem and User with the limitation that only items that satisfy the constraint of being in the list of DashboardItems associated with a particular group are available to be included in the DashboardItems that can be associated with a User. You will probably need custom code in the afterDelete and afterSave callbacks of the group_dashboard_items model that will update the user_dashboard_items model to remove or insert additional relationships. This does not address the actual content of your DashboardItems which would presumably be generated on the fly from other models (as others have already pointed out in their responses). -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/groups/opt_out.
parseExtensions and ssl
I am developing a REST API. I have it working using paresExtensions and mapResources. However, if I try to access the API using ssl (https instead of http) the routing does not seem to work and I get an error Missing Method in TenantsController > > *Error: * The action *30.json* is not defined in controller * > TenantsController* > What do I have to do to get this to work together with SSL? I want to enable the Security component and requireSecure for the entire API as well. That seems to work but also has the same problem of the broken routing. Thanks. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/groups/opt_out.
Re: Throwing error should output JSON
Replying to myself - this is what I found.
The presentation that I saw that said that putting error400.ctp in a json
folder under /app/View/Errors would work automatically seems to be
incorrect.
The solution I came up with included the following steps:
1. Set a flag in app/Controller/AppController indicating that this is a
REST call. As there does not seem to be an is("rest") or isRest call I did
this based on the extension.
In AppController.php within the AppController class add:
public $REST = FALSE;
function beforeFilter()
{
// Add additional checks here to support other formats
if (isset($this->request->params['ext']) &&
($this->request->params['ext'] == 'json'))
{
$this->REST = 'json';
}
$this->set('REST', $this->REST);
}
2. Using the comments from COTP that I found
heresays
to set the layout in the view files but it seems
// more efficient to put it here once then in all of the view files
// Use a different layout if you want something special. ajax layout
just
// outputs the view content with nothing else
$this->layout = 'ajax';
}
}
3. Now I can create View/Errors/json/error400.ctp:
{"Error":
{
"code": getCode(); echo $Code; ?>,
"description": "response->httpCodes($Code); echo
$Status[$Code] . ": " . $error->getMessage(); ?>"
}
}
Hope this helps someone
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Throwing error should output JSON
I am developing a REST API using the latest CakePHP. I was under the impression (from a presentation I watched on YouTube from CakeFest 2010) that I could throw an error and have it return the error as JSON to the client by adding a json direction below /app/View/Errors and adding the appropriate error file (i.e. error400.ctp) in that directory. The API itself is working (i.e. if I call /tenants/30.json it returns the tenant with id 30 as json). However, when I throw a NotFoundException it is outputting the HTML template under /app/View/Errors/error400.ctp instead of the json template under /app/View/Errors/json/error400.ctp. What do I have to do to get it to output the json template? -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/groups/opt_out.
Best practice for Helpers
As a best practice, should a helper output content or return the content to the View? In other words, should the call to the helper be: $this->MyHelper->someMethod($DataForHelper); or echo $this->MyHelper->someMethod($DataForHelper); Most of the built in helpers seem to prefer the latter form. Is this just a style issue or is there a preferred way? -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/groups/opt_out.
Re: Generating multiple 'requests' based on form selections
I think your use of the term "request" is confusing. Do you need the client to issue six requests to the server with the various combinations? Or can the client issue a single request with all of the information and have the server process that as a request for six new records to be created? If you need to actually issue six separate requests then the way I could think of doing it would be using JavaScript. Capture the submit button event and then use AJAX calls to issue the separate requests. This is a very messy way to do it as you would need to build into the client error handling and roll back for partially executed requests. If you can have the single request then basically all of the work happens on the server. I haven't used CakePHP 1.1 but in 1.3 you could generate an array of the model you want to save and call saveAll. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/groups/opt_out.
Re: Saving session data from a view
Thanks for your response. As I had no choice that is what I ended up doing. However, the information I was interested in storing was only relevant to the view (i.e. which menu was opened when the user clicked on a link) and only meant for use in the view (reopen the menu that was opened at the time the user clicked). It seems that I have now pushed knowledge of the view into the controller for an entirely arbitrary purpose. On Friday, June 14, 2013 11:08:57 PM UTC+3, John wrote: > > Your view is there to produce HTML not manipulate data (other than to > display them). The proper MVC way is to do it in the controller and just > pass the required data to the view to render it. > -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/groups/opt_out.
Saving session data from a view
I am using CakePHP 1.3. I have a helper which prints out the navigation menus. Depending on which top level menu is selected the appropriate sub menu is displayed. I want to be able to know on the next page view which menu / sub menu was previously displayed. I thought to accomplish this by writing a session variable from my helper. However, I am getting the error that session data cannot be written from a view. Can anyone suggest an alternative way of accomplishing this? I don't really understand why, if I can read Session information in the view, am I not able to write Session information in a view. Pointers to appropriate resources or hints and tricks would also be appreciated. Thanks. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: How to delete an ACL node
try cake acl help You can delete either and aro or an aco using cake acl delete aco or cake acl delete aro I am using CakePHP 1.3 so I don't know if this has changed in the 2.x series -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: Checking Consistency Before Saving
I think a more basic question has to do with the data model. Why are you duplicating information in two places? If the Student has a reference to a Province and a Province has a reference to a Country then you do not need a reference to a Country in Student. >From a UI standpoint I would allow the user to select a Country. When the country is selected I would display only the Provinces that are defined for that Country. When the Student is saved it would only save the province_id. If you need the country for the Student later on you can access it by doing a find with recursive set to 2 or by doing an explicit join of the Country table. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: changing table fields value for all found in the list
Yes you have to have "&" in front of $photo. This makes $photo a reference to the element in $photos instead of a copy. If you don't have it then you will be modifying a copy of the array element and not the element itself. See http://www.php.net/manual/en/language.references.php for a discussion of references in PHP. On Wednesday, April 17, 2013 12:28:58 PM UTC+3, Chris wrote: > > hi david,... > a quick question,... > > do I have to have "&" upfront of $photo > in foreach ($photos as &$photo) > and what is it stand for..? > > thanks > chris > > -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: changing table fields value for all found in the list
You are doing a redirect inside of your loop which is kicking you out of
your loop. That is why only the first update works.
Also, there is no need to use the query method. You would be better off
looping through the returned items and setting the privacy field and then
calling saveAll
i.e.
foreach ($photos as &$photo)
{
$photo['Photo']['privacy'] = 2;
}
$this->Photo->saveAll($photos);
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Re: find all users from another table
Since you are calling find the first time with 'list' it is returning the
array as you state. However, you are trying to index into that array with
an index of 'PhotoLike' which doesn't exist in that array. So the error
message is correct.
I believe that the second find should be
find('all', array('conditions' => array('User.id' => $photo_likes)))
This should generate a WHERE clause of WHERE 'User.id' in (59, 48) which is
what you want.
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Re: retrieving data in a view cake 1.3
The easiest way to debug a problem like this is to set up a debugging environment (like NetBeans and XDebug see https://netbeans.org/kb/docs/php/debugging.html). You can then set a break point at the point in the code and walk through and look at your data structures to see what is going on. If you cannot set that up then you will need to do it the old fashioned way of printing out interim results and working from there. Some questions to figure out are: 1. Is $notes actually set in the view with the relevant data? You can do a print_r of $notes before the foreach and see what comes out. If the page is live you can do the print_r within a comment block in the HTML and view source to see the results. 2. Does $notes actually have an array which contains 'User' as an associative element? 3. Does the 'User' associative array have elements 'firstname', 'lastname' and 'username' 4. Is there some control flow above the foreach which causes the entire block of code to be skipped altogether? Once you know the answers to these questions you can have a better idea as to what is causing the problem and potentially how to solve it. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: Multiple Forms on the same form
I have done this using AJAX. Have the button fire an AJAX event which calls an action on your controller which returns an empty workcenter section of the field. Pass in to the AJAX call an index and have the form fields specified using the index. When the form is submitted you would then have an array of workcenters as part of your data and you can use saveAll to save the factory model and all related models (assuming you have set up a hasMany / belongsTo relationship between factory and workcenter). Just remember that when editing a factory you will need to present all of the existing workcenters associated with it as well. On Sunday, March 24, 2013 7:54:37 PM UTC+2, Steven Scaffidi wrote: > > Let's say I had a model called factory, and I wanted to add multiple > workcenters to the factory. When I go to add a new factory, I want a button > on the bottom of my form that says add workcenter. I want that button to be > always there just in case they want to add multiple work centers. I don't > want the form for workcenter to appear until they click the button add > workcenter. How can I accomplish this? > > > -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: Calling functions in other controllers
On Wednesday, February 27, 2013 6:33:41 AM UTC+2, Yasir Arafat wrote:
>
> Hello,
> Before calling make sure you load the model of your cart model
> like
>
> $this->loadModel('Cart');
>
>
>
Since he is already including Cart in the $uses variable he does not need
to call loadModel.
Also, the notation $this->Checkout->Cart is only relevant if the two models
are related via an associate (i.e Checkout hasOne or hasMany Cart). If the
two models are not associated and the other model is loaded separately
(either through $uses or through loadModel) then $this->Cart is the correct
notation.
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Re: Calling functions in other controllers
Sorry - noticed a couple of typos
1. The $uses variable indicates which other models this controller will use
2. you may need to find the cart you are looking for and pass that
information into the total() call
On Wednesday, February 27, 2013 3:03:24 PM UTC+2, david...@gmail.com wrote:
>
>
> On Wednesday, February 27, 2013 2:55:53 AM UTC+2, lirc201 wrote:
>>
>> I'm in 2 different controllers. In the checkout controller, I'm trying
>> to call a function in the cart controller.
>>
>> Are you sure that the function is in the cart controller? The $uses
> variable indicates which other models this model will use (not which other
> controllers). If you want to call a method on another controller you will
> need to use either App::Import or RequestAction. If the error you are
> getting is an SQL error rather than a method not found error it would seem
> like the get() method is on the model.
>
> In general, many people will tell you that calling one controller from
> another is a bad idea and should only be done as a last resort.
>
> If it is true that you are managing to call a controller method then it
> may be simpler to move these methods into the Cart model which you would
> then be able to access from the $uses variable.
>
> If the methods are really on the model (or if you choose to move them
> there) you will need to be acting on a particular instance of Cart so you
> would do something like:
> $this->Cart->id = $CartID; // assumes you already have the id of the cart
> you want
> $Cart = $this->Cart->get(); // assumes that the only state information
> that get needs is the id and will read any additional information for itself
>
> Alternatively, you may need to find the cart you are looking for and pass
> that information into the get call. I.e.
> $Cart = $this->Cart->find('first', array('conditions' =>
> array('Cart.customer_id' => $CustomerID)));
> $Total = $this->Cart->total($Cart);
>
> As a side note:
> One debugging method you could use when confronted with this type of
> situation is to copy and paste the query that generated the error directly
> into something like PhpMyAdmin and see what part of the query is causing
> the SQL error. My guess is that in your case the query has a where clause
> with 'WHERE Cart.id=' with no id specified or something like that.
>
>
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Re: Calling functions in other controllers
On Wednesday, February 27, 2013 2:55:53 AM UTC+2, lirc201 wrote:
>
> I'm in 2 different controllers. In the checkout controller, I'm trying to
> call a function in the cart controller.
>
> Are you sure that the function is in the cart controller? The $uses
variable indicates which other models this model will use (not which other
controllers). If you want to call a method on another controller you will
need to use either App::Import or RequestAction. If the error you are
getting is an SQL error rather than a method not found error it would seem
like the get() method is on the model.
In general, many people will tell you that calling one controller from
another is a bad idea and should only be done as a last resort.
If it is true that you are managing to call a controller method then it may
be simpler to move these methods into the Cart model which you would then
be able to access from the $uses variable.
If the methods are really on the model (or if you choose to move them
there) you will need to be acting on a particular instance of Cart so you
would do something like:
$this->Cart->id = $CartID; // assumes you already have the id of the cart
you want
$Cart = $this->Cart->get(); // assumes that the only state information that
get needs is the id and will read any additional information for itself
Alternatively, you may need to find the cart you are looking for and pass
that information into the get call. I.e.
$Cart = $this->Cart->find('first', array('conditions' =>
array('Cart.customer_id' => $CustomerID)));
$Total = $this->Cart->total($Cart);
As a side note:
One debugging method you could use when confronted with this type of
situation is to copy and paste the query that generated the error directly
into something like PhpMyAdmin and see what part of the query is causing
the SQL error. My guess is that in your case the query has a where clause
with 'WHERE Cart.id=' with no id specified or something like that.
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Re: Problem with using components when Importing a Controller
On Thursday, February 21, 2013 2:20:00 PM UTC+2, euromark wrote: > > Even with Cake1.3 you dont import and abuse controllers this way. > You need to refactor those controller methods into clean model methods and > only re-use those. > Since we are talking about sending e-mails which uses the Email component the only options are to abuse controllers or models (as models are not supposed to use components). I can try moving the code into the model and using App::Import to get the Email component and see if it is set up correctly that way. I have a work around as I showed in the code I included originally so I don't have a lot of incentive to reorganize the code now. The primary question is, if you have a facility like App::Import shouldn't the result be fully functional? -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Problem with using components when Importing a Controller
I have a controller EmailNotifications which I am accessing using
App::Import('Controller', 'EmailNotifications');
The EmailNotifications controller uses the Email component
var $components = array('Email', 'RequestHandler');
When I import the controller I use the following code:
// Load the Email Notification controller
App::Import('Controller', 'EmailNotifications');
$EmailNotification = new EmailNotificationsController();
$EmailNotification->constructClasses();
Inside of the notify method of the EmailNotificationsController I use the
Email component
$this->Email->reset();
$this->Email->to = $Notify['EmailNotification']['email_address'];
$this->Email->subject = ucwords("$Subject ($Activity)");
$this->Email->replyTo = $Notify['EmailNotification']['email_address'];
$this->Email->from = $Notify['EmailNotification']['email_address'];
$this->Email->template = $Template;
$this->Email->sendAs = 'text';
// Since this is being used via App::Import the Controller is not
properly set
// so we set it here
$this->Email->Controller = $this;
$Ret = $this->Email->send();
If I do not manually set $this->Email->Controller = $this before calling
send the variables I have set earlier in the code are not exported to the
email view.
>From reading the manual I understood that calling constructClasses would
initialize any models and components used by the controller. However, the
components do not seem to be initialized correctly.
Is there something else I am supposed to do in order for this to work
correctly? Is this a bug? I am using CakePHP 1.3.10
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Re: Implementing the Event Notifier Pattern in CakePHP
On Wednesday, February 20, 2013 2:05:49 AM UTC+2, cricket wrote:
>
>
> Better to implement this in a component ... as long as your events
> will always be triggered from within a controller. That is, you won't
> be calling it in an afterDelete() callback. From the controller:
>
> $this->Notifier->send('ModelName', ...);
>
> Or, maybe pass it a keyed array. In any case, better as a component, imho.
>
The manual says "To access/use a model in a component is not generally
recommended" and this will need to access several models (at least the
EmailNotification model to determine who to send to as well as other models
to map the specific instance of the updated model to a particular client).
What is the advantage of a component over the other alternatives I raised?
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Implementing the Event Notifier Pattern in CakePHP
Does anyone have any advice as to how to go about implementing the Event Notifier pattern in CakePHP 1.3? Basically, I want to have email notifications sent out when various events occur (adding or deleting instances of specific models). The notifications can be sent to different e-mail addresses depending on the model that the event occurred on and whether the notification is being sent to the system administrator or to a client specific administrator. To this end I implemented a model called EmailNotification which has the client id (0 for system admin), the model to be monitored and the email address for the notifications to be sent to. I would have the models being monitored make a common call with the necessary information for the notification email to be sent out. It would be the responsibility of this code to look up who the notification should be sent to and to send it out. My current thought is to have a method on the EmailNotificationsController->notify that would be called by the controllers of the models being monitored using requestAction. Alternatively, I could load the EmailNotificationsController using App::import and call the method directly from the monitored model's controller. Or is there a better way to implement this? Thanks. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: Only check beforeDelete if direct deletion
On Monday, February 18, 2013 12:27:46 AM UTC+2, cricket wrote: > > > Perhaps you need to re-think your schema. What is the purpose of Record? > > Also, why do you wish to cancel a Record delete if an Invoice exists? > I abstracted the specific problem domain in the hopes of not getting lost in the details. A Record represents a Tenant call with a bunch of associated data. If an Invoice references a Record then the requirements of the system are that the view on Invoice needs to be able to display the information from the Record. In addition, the business logic for handling an invoice needs to handle cases of Invoices with a Record (using some of the data from the Record) and Invoices without a record. If a Record is deleted that is referenced by an Invoice then the data integrity is broken. Rather than get into the specifics of the problem domain I am more interested in the CakePHP issues. >From reading through the CakePHP code it seems like calling delete on the top level model will call deleteAll on a hasMany related model if "exclusive" is set in the relationship. deleteAll has three parameters. The third is $callbacks which is set to false by default. Since deleteAll is called by the top level model with only one parameter that would mean that the call backs would not be called and the problem I described would not happen. I don't know if that is the intention of the "exclusive" attribute as the documentation just says that it means deleteAll is called. But it seems to address my issue. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: Only check beforeDelete if direct deletion
Unfortunately, that won't work since an Invoice does not always have a Record. I still need to be able to get all of the Invoices for a Tenant even if there is no Record associated with the Invoice. Similarly, there can be Records that are not referenced by an Invoice. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Only check beforeDelete if direct deletion
I have an application built with CakePHP 1.3 with a model structure as follows: Tenant hasMany Records (dependent => true) Tenant hasMany Invoices (dependent => true) An Invoice can have a reference to a Record which I represent as Invoices belongsTo Records so that fetching an Invoice will fetch the associated Record (if there is one) In the Records model I have a beforeDelete method which checks that no Invoice references this record before deleting it. This all works fine. The potential problem I am considering is if I delete a Tenant it will cascade to delete all Records and Invoices associated with it. Since I don't control the order in which the related models will be deleted it would be possible that the Records would be cascaded first and fail the beforeDelete method because of existing Invoices that reference the record ultimately failing the entire delete operation. However, since the entire tenant is being deleted I do not want to enforce the constraint of not deleting a record if an invoice references it allowing the delete to complete regardless of the order that the associated models are deleted. My questions are: 1. Do I have to worry about this? I have not been able to produce the problem but it seems theoretically possible. 2. If I do have to worry about this scenario, is there a way to distinguish in the beforeDelete call whether this deleting is a direct deletion or a cascade from the Tenant deletion? If I can do that then I would be able to add a condition to only enforce the constraint if this is a direct delete. 3. Is there a better way of representing this relationship that would not run into this problem? Thanks -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: Can not save two fields
What is the SQL that is generated from the save function? Do you have a debugging environment set up so you can step through the code? -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: $useDbConfig being ignored in 1.3.10
I figured out what the problem was. I had misnamed the model file so the file was being ignored and the defaults were being used for the model instead. I renamed the model file correctly and now it is working. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
$useDbConfig being ignored in 1.3.10
I have an app that was developed using CakePHP 1.3.10. I am now trying to
add a controller for a model that is in a different database. The code for
the model is very simple:
class Cdrs extends AppModel
{
/**
*
* @var string The name of the model
*/
var $name = 'Cdrs';
/**
*
* @var string Alternate database connection information for this model
*/
var $useDbConfig = 'otherdb';
/**
*
* @var string The name of the table for this model
*/
var $useTable = 'cdrs';
}
In database.php I added in otherdb as follows:
class DATABASE_CONFIG {
var $default = array(
'driver' => 'mysql',
'persistent' => false,
'host' => 'localhost',
'login' => 'user1',
'password' => 'password1',
'database' => 'db1',
'prefix' => '',
);
var $otherdb = array(
'driver' => 'mysql',
'persistent' => false,
'host' => 'localhost',
'login' => 'user2',
'password' => 'password2',
'database' => 'db2',
'prefix' => '',
);
var $test = array(
'driver' => 'mysql',
'persistent' => false,
'host' => 'localhost',
'login' => 'user',
'password' => 'password',
'database' => 'test_database_name',
'prefix' => '',
);
}
However, the controller is giving me the error
*Error: * Database table *cdrs* for model *Cdr* was not found.
When I step through the code in the debugger I see the following stack trace
cake/libs/model/model.php.Model->setDataSource:2831
cake/libs/model/model.php.Model->__construct:469
cake/libs/class_registry.php.ClassRegistry->init:150
cake/libs/controller/controller.php.Controller->loadModel:637
cake/libs/controller/controller.php.Controller->constructClasses:502
cake/dispatcher.php.Dispatcher->_invoke:186
cake/dispatcher.php.Dispatcher->dispatch:171
app/webroot/index.php.{main}:83
The $dataSource being passed in to setDataSource is "default" instead of
"otherdb"
If I change the value in the debugger to "otherdb" then the error goes away.
Why is the $useDbConfig being ignored? What am I doing wrong?
Is it possible that this was a bug that was fixed in a later version of
1.3? I can probably upgrade within 1.3 if necessary but I cannot upgrade
to 2.x at this point in the development process.
Any help would be appreciated.
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Multiple domains sharing a single database with non-unique user names
I have a Cake 1.3 application that we have been developing for a while. The application will support multiple domains and sub domains on a single database. We are using the standard ACL for user login and permissions. The problem that we have run in to is that the user name space is not unique across domains and sub domains. For example, there could be a user jack on sub.domain1.com and another user jack on sub2.domain1.com or a user jack on sub1.domain2.com. There is another table that contains the relationship between users and sub domains / domains using the user_id field in a belongsTo relationship. Since the username column in the users table must be unique this is problematic. For now we have come up with two approaches. The first is to change the username to j...@sub.domain1.com. This makes the username unique. However, it is cumbersome for the user since they are going to a url which is sub.domain.com/login already. Also, it would be a problem if the sub domain name is ever changed since all of the usernames would contain the old sub domain name. The other alternative is to change the users table to a view that does a join on a shadow users table and the fully qualified domain name. The problem with this is that it needs to be an updatable view to allow for updating passwords and the requirements in MySQL for an updateable view seem rather restrictive. We wouldn't want a change to either of the underlying tables to break the login process inadvertently. The other wrinkle to add in to the mix is that there are some users (system administrators) that are not associated with a sub domain / domain so we need to support them logging in as well. For now we are going with the first approach under the assumption that the downsides of that approach are less severe. However, I wanted to know if anyone else has dealt with this type of configuration and found a better alternative. Thanks. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to cake-php@googlegroups.com. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en.
