Events don't work when lazy load model class

2014-11-21 Thread gonzela2006
Hi,

I created an event 'Model.User.created' and attached the listener to my 
model as you can see below and it is working well

App::uses('AppModel', 'Model');
App::uses('CakeEvent', 'Event');

class User extends AppModel {
public function afterSave($created, $options = array()) {
$event = new CakeEvent('Model.User.created', $this, array(
'id' = $this-id,
'data' = $this-data[$this-alias]
));
$this-getEventManager()-dispatch($event);
}
}

/*/
// Attach to model
App::uses('UserListener', 'Event');
App::uses('ClassRegistry', 'Utility');
$user = ClassRegistry::init('User');
$user-getEventManager()-attach(new UserListener());

When I lazy load the model class User, the event doesn't work. so *How can 
I allow the event to work on lazy load?*
Please advise

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Migrate Passwords

2014-10-30 Thread gonzela2006
Hi,

How can I migrate my users passwords from SimplePasswordHasher to 
BlowfishPasswordHasher *without interrupt my users to change their 
passwords*?

Thanks

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Load model in bootstrap

2014-02-02 Thread gonzela2006
Hello,

I want to load model in bootstrap.php so I made it with two techniques as 
the following:

App::uses('ClassRegistry', 'Utility');
ClassRegistry::init('Option')-load();

and

App::import('Model', 'Option');
$option = new Option();
$option-load();

Both of them worked for me but I don't know the deference between 
ClassRegistry::init and App::import ? And what is the best choice for my 
case?

Thanks

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Re: Load model in bootstrap

2014-02-02 Thread gonzela2006
Hi euromark,

Thanks for your reply.
So you recommend to use ClassRegistry::init


On Monday, February 3, 2014 1:03:21 AM UTC+2, euromark wrote:

 The second example uses App::import() which in 2.x is only used for 
 importing vendor classes (as it does not support lazyloading of classes)
 You would have to use App::uses('Option', 'Model').
 Even if in this case it would not really make a difference.

 But stick to the first one as it is the recommended approach.


 Am Sonntag, 2. Februar 2014 23:53:11 UTC+1 schrieb gonzela2006:

 Hello,

 I want to load model in bootstrap.php so I made it with two techniques as 
 the following:

 App::uses('ClassRegistry', 'Utility');
 ClassRegistry::init('Option')-load();

 and

 App::import('Model', 'Option');
 $option = new Option();
 $option-load();

 Both of them worked for me but I don't know the deference between 
 ClassRegistry::init and App::import ? And what is the best choice for my 
 case?

 Thanks



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Router redirect pass all parameters to another domian

2014-01-20 Thread gonzela2006
Hello,

I want to use *Router::redirect* to redirect to another domain and pass all 
parameters to this domain

Example:
Redirect this url
http://domain-*one*.com/posts/view/1
to
http://domain-*two*.com/posts/view/1

I tried the following
Router::redirect( '/*', 'http://domain-*two*.com/', array('persist' = 
true) );
but it redirect to  http://domain-*two*.com/ without parameters.
Please advise

Thanks

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Routing problem with /* url

2014-01-03 Thread gonzela2006
Hi,

I want my posts url to be like this:
example.com/post-slug
so I added the routing rule on routes.php like this

Router::connect('/*', array('controller' = 'posts', 'action' = 'view'));

It works well but other links give 404 error like this one

Error: The requested address '/members/users/login' was not found on this 
server.

Please advise

Thanks

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Re: Routing problem with /* url

2014-01-03 Thread gonzela2006
Hi Stephen,

s members a prefix, or do you have a users method with login parameter, or 
 do you have that as a custom route?

Yes, members is a prefix but the problem also exists with urls without 
prefix like /pages/display/about

I found a post on Mark Story's blog that is talking about my problem but it 
was for CakePHP 1.3 how can I use it with CakePHP 2?

http://mark-story.com/posts/view/using-custom-route-classes-in-cakephp

Thanks

On Friday, January 3, 2014 9:16:58 PM UTC+2, Stephen S wrote:

 A few things come to my mind off the top off my head.

 You could route your controller-action url's first, to catch the actual 
 links such as /members/users/login (is members a prefix, or do you have a 
 users method with login parameter, or do you have that as a custom route?)

 Then providing you did those routes correctly, the bottom route would 
 catch anything that didn't match the earlier ones, hopefully your post slug.

 Another idea would be to use a regular expression to match the pattern of 
 a post-slug, if there are any distinguishing features this would be much 
 more effective. If not I would recommend doing something like this:

 /posts/post-slug
 /blog/post-slug
 /keyword/post-slug (i.e. if I was writing on a health care blog, I would 
 use /health/post-slug. This could produce something like 
 /health/top-10-diet-tips which holds the keyword health as well as the 
 slug.)

 It would be easier to avoid issues if you did it this way.

 HTH

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 Kind Regards
  Stephen Speakman
  

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Re: Routing problem with /* url

2014-01-03 Thread gonzela2006
But other links like /pages/display/about gave me 404 error as it routes to 
posts controller not pages controller.

Thanks


On Friday, January 3, 2014 10:07:23 PM UTC+2, Stephen S wrote:

 The link you gave me is done a little differently to how you are doing it 
 now, all the post is introducing is a new method to parse the route itself.

 Normally you may have something like /posts/view/slug which may be public 
 function view($slug = null), then you may execute a query to find the first 
 post record which contained that exact slug and load the results into an 
 array. Mark is doing a similar search in his actual custom route file, 
 caching it, then passing that information to the controller so it doesn't 
 have to do that. He doesn't appear to mention the issue you are having, 
 unless I missed it, I'm afraid.

 Try this for me and see if it helps

 Router::connect(
 /members/:plugin/:controller,
 array('action' = 'index', 'prefix' = members, members = true)
 );
 Router::connect(
 /members/:plugin/:controller/:action/*,
 array('prefix' = members, members = true)
 );
 Router::connect(
 /members/:controller,
 array('action' = 'index', 'prefix' = members, members = true)
 );
 Router::connect(
 /members/:controller/:action/*,
 array('prefix' = members, members = true)
 );
 Router::connect('/*', array('controller' = 'posts', 'action' = 'view'));

 Then try to access /post-slug and /members/users/login and see what 
 happens.


 On 3 January 2014 19:31, gonzela2006 gonze...@gmail.com javascript:wrote:

 Hi Stephen,

 s members a prefix, or do you have a users method with login parameter, 
 or do you have that as a custom route?

 Yes, members is a prefix but the problem also exists with urls without 
 prefix like /pages/display/about

 I found a post on Mark Story's blog that is talking about my problem but 
 it was for CakePHP 1.3 how can I use it with CakePHP 2?

 http://mark-story.com/posts/view/using-custom-route-classes-in-cakephp

 Thanks


 On Friday, January 3, 2014 9:16:58 PM UTC+2, Stephen S wrote:

  A few things come to my mind off the top off my head.

 You could route your controller-action url's first, to catch the actual 
 links such as /members/users/login (is members a prefix, or do you have a 
 users method with login parameter, or do you have that as a custom route?)

 Then providing you did those routes correctly, the bottom route would 
 catch anything that didn't match the earlier ones, hopefully your post slug.

 Another idea would be to use a regular expression to match the pattern 
 of a post-slug, if there are any distinguishing features this would be 
 much more effective. If not I would recommend doing something like this:

 /posts/post-slug
 /blog/post-slug
 /keyword/post-slug (i.e. if I was writing on a health care blog, I would 
 use /health/post-slug. This could produce something like 
 /health/top-10-diet-tips which holds the keyword health as well as the 
 slug.)

 It would be easier to avoid issues if you did it this way.

 HTH

 -- 
 Kind Regards
  Stephen Speakman
  
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Re: Help in simple query!

2013-05-31 Thread gonzela2006
@Dr. Drijk @resting
Model names must be singular.

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Re: Help in simple query!

2013-05-31 Thread gonzela2006
@Dakota
I'm already setting the relation as below

class Student extends AppModel {
var $name = 'Student';
var $hasMany = array('StudentAttendance');

AND

class StudentAttendance extends AppModel {
var $name = 'StudentAttendance';
var $belongsTo = 'Student';


On Thursday, May 30, 2013 8:26:28 AM UTC+2, Dakota wrote:

 That would be the expected result for that query. You aren't including the 
 'SudentAttendance' model in your query. Looking how to use Containable, or 
 custom join. You don't say what kind of relation there is between 
 StudentAttendance and Student. CakePHP can't guess what you are trying to 
 do, you need to tell it (The guessing part is coming up in version 4 as 
 part of the MRD featureset)



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Re: Help in simple query!

2013-05-29 Thread gonzela2006
Hello,

I used the following code in StudentAttendances controller:

$students = $this -StudentAttendance-Student- find('all', array(
'conditions' = array(
'NOT' = array('StudentAttendance.date' = array($year.'-'.$month.'-'.$day))
),
'fields' = array('Student.id', 'Student.name'),
'order' = 'Student.name ASC'
));


On Wednesday, May 29, 2013 8:02:29 AM UTC+2, resting wrote:

 It will be helpful if you show us what you had done to produce that error.



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Help in simple query!

2013-05-28 Thread gonzela2006
Hello,
As you can see on the below image

https://lh3.googleusercontent.com/-_Q29P1DXHlQ/UaUWfBmdtYI/AX8/CbEsouqCcCg/s1600/Presentation1.jpg
I want to display students that didn't attendance on date 2013-03-01 so the 
result should be as the following:
*id name*
2 Marta Simon
4 Rex Maxwell
6 Vivian Ellis

I know this is simple query but I got this error
Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column 
'StudentAttendance.date' in 'where clause'

Thanks,

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Can't validate URL

2013-01-24 Thread gonzela2006
Hello,

can't validate the below url using 'rule' = 'url' on my model

https://www.google.com/search?sugexp=les;gs_rn=1gs_ri=serptok=ryp3YY4UdU39xLhgeQ6ElQpq=cakephp
 
cakephp cakephp cakephp cakephp cakephp cakephp cakephp cakephp cakephp 
cakephp cakephp cakephp cakephp cakephp cakephp 
cakephpcp=5gs_id=1a6xhr=tq=lorem 
ipsumpf=pclient=firefox-atbo=drls=org.mozilla:en-US:officialsclient=psy-aboq=loremgs_l=pbx=1bav=on.2,or.r_gc.r_pw.r_qf.bvm=bv.41248874,d.ZG4biw=1366bih=650#hl=enclient=firefox-atbo=drls=org.mozilla:en-US:officialsclient=psy-abq=Lorem
 
ipsum dolor sit amet, consectetur adipiscing elitoq=Lorem ipsum dolor sit 
amet, consectetur adipiscing 
elitgs_l=serp.12..0l4.23366.23366.2.24779.1.1.0.0.0.0.289.289.2-1.1.0.les;..0.0...1c.1.9MZ2Kf0IJq0pbx=1bav=on.2,or.r_gc.r_pw.r_qf.bvm=bv.41248874,d.ZG4fp=4d3ec0306f8423d6biw=1366bih=650

Please advise

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Re: Can't validate URL

2013-01-24 Thread gonzela2006
Hello euromark,

No spam, I'm just trying to find a solution to my problem in different 
places.

On Thursday, January 24, 2013 6:59:20 PM UTC+2, euromark wrote:

 the same spam as  
 http://stackoverflow.com/questions/14505837/cakephp-cant-validate-url ?

 Am Donnerstag, 24. Januar 2013 17:16:49 UTC+1 schrieb gonzela2006:

 Hello,

 can't validate the below url using 'rule' = 'url' on my model


 https://www.google.com/search?sugexp=les;gs_rn=1gs_ri=serptok=ryp3YY4UdU39xLhgeQ6ElQpq=cakephpcakephp
  cakephp cakephp cakephp cakephp cakephp cakephp cakephp cakephp 
 cakephp cakephp cakephp cakephp cakephp cakephp 
 cakephpcp=5gs_id=1a6xhr=tq=lorem 
 ipsumpf=pclient=firefox-atbo=drls=org.mozilla:en-US:officialsclient=psy-aboq=loremgs_l=pbx=1bav=on.2,or.r_gc.r_pw.r_qf.bvm=bv.41248874,d.ZG4biw=1366bih=650#hl=enclient=firefox-atbo=drls=org.mozilla:en-US:officialsclient=psy-abq=Lorem
  
 ipsum dolor sit amet, consectetur adipiscing elitoq=Lorem ipsum dolor sit 
 amet, consectetur adipiscing 
 elitgs_l=serp.12..0l4.23366.23366.2.24779.1.1.0.0.0.0.289.289.2-1.1.0.les;..0.0...1c.1.9MZ2Kf0IJq0pbx=1bav=on.2,or.r_gc.r_pw.r_qf.bvm=bv.41248874,d.ZG4fp=4d3ec0306f8423d6biw=1366bih=650

 Please advise



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Re: Can't validate URL

2013-01-24 Thread gonzela2006
Hello euromark,

Thanks for your reply
I'm trying to make my own short link service for my blog and I wish to make 
it using CakePHP
I think I can't validate this URL because it is too long
*Note*:
I have tried to encode this URL before validate it and still getting false 
URL.

Please advise

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Re: Routing help

2013-01-17 Thread gonzela2006
Any help please

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Re: Routing help

2013-01-17 Thread gonzela2006
Hello Mathew,

Thanks for your reply.
Regarding to my question,I have wrote wrong controller the right one must 
be *posts *not *users*.
Really I need to make it as a subdomian and I have found an article on 
Bakery
http://bakery.cakephp.org/articles/Mum_Chamber/2008/02/04/subdomaining-with-cake
I'll give a try

On Thursday, January 17, 2013 10:03:14 PM UTC+2, Mathew wrote:

 I don't think cakes routing can handle subdomain changes. For that you 
 would have to write your own customer router in CakePHP 2.

 I don't recommend using subdomains to view user profiles. It introduces a 
 lot of issues for SEO, SSL, cookies and sessions.



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Re: Routing help

2013-01-17 Thread gonzela2006
I have tried the following 
Router::connect('/*', array('controller' = 'posts', 'action' = 'view', 
'members'=1));
and the result is
http://domain.com/username/post-alias
and it works but the all other links give me 404 not found

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Re: Routing help

2013-01-17 Thread gonzela2006
Hello ibejohn818,

How can I make conditional statement in routes.php file?


On Thursday, January 17, 2013 10:43:17 PM UTC+2, ibejohn818 wrote:

 You would be best served by triggering your route using a conditional 
 statement in your routes file then using a custom route class to verify the 
 username passed in and returning the correct controller/action to dispatch.



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Re: Routing help

2013-01-17 Thread gonzela2006
I got it :)
Could you please help me to make this routing
http://domain.com/members/posts/view/username/posttitle
to be
http://username.domain.com/posttitle


On Thursday, January 17, 2013 11:05:49 PM UTC+2, ibejohn818 wrote:

 if(preg_match('/*FILTER*/',$_SERVER['HTTP_HOST'])) {

 Router::connect()…...

 }



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Routing help

2013-01-16 Thread gonzela2006
Hello,

I need your help to make this routing
http://domain.com/members/users/view/username/posttitle
to be
http://username.domain.com/posttitle
Where
domain.com - My domain
members - Routing prefix
users - Controller
view - Action
username - Member username(First variable for view() action)
posttitle- Member post title(Second variable for view() action)

Please help me

Thanks

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Re: Routing help

2013-01-16 Thread gonzela2006
Hello,

I have already created the wildcard subdomain *.domian.com. I just need to 
know how to make the routing process.

Thanks,

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Re: Conditional validation rule1 OR rule2

2013-01-13 Thread gonzela2006
Thanks cricket  AD7six.
I have used the following code to validate variable if it url or email.


public $validate = array(
'variable' = array(
  'url' = array(
'rule' = array('urlOrEmail'),
'message' = 'Please supply a valid URL/email address.'
)
)
);

public function urlOrEmail($field = array()) {
$key = key($field);
if(Validation::url($field[$key], true)) {
return TRUE;
} elseif (Validation::email($field[$key] ,true)) {
return TRUE;
} else {
return FALSE;
}
}

Thanks

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Re: Conditional validation rule1 OR rule2

2013-01-12 Thread gonzela2006
Hello Cricket,

I got this error message:

 *Error: * Call to undefined method ModelValidator::url() 


Please advise

On Saturday, January 12, 2013 3:11:26 AM UTC+2, cricket wrote:

 You'll need to create your own validation method. 

 http://book.cakephp.org/2.0/en/models/data-validation.html#custom-validation-rules
  

 Personally, I'd create columns for both url and email in the table, 
 then set up a custom rule to check that either one is there, and that 
 whichever one is there is correct. Something like this: 

 public $validate = array( 
 'email' = array( 
 'rule' = array('emailOrUrl', 'url'), 
 'message' = 'Please supply a valid URL or email address' 
 ), 
 'url' = array( 
 'rule' = array('emailOrUrl', 'email'), 
 'message' = 'Please supply a valid URL or email address' 
 ) 
 ); 


 function emailOrUrl($field = array(), $other_field = null) 
 { 
 $key = key($field); 
  
 /* If this is empty, the other shouldn't be 
  */ 
 if (empty($field[$key])  
 empty($this-data[$this-alias][$other_field])) 
 { 
 return false; 
 } 
  
 switch ($key) 
 { 
 case 'email': 
 return $this-validator()-email($field[[$key]); 
  
 case 'url': 
 return $this-validator()-url($field[[$key]); 
  
 default: 
 return false; 
 } 
 } 

 Check the API for other params you can pass to these two methods. 

 http://api20.cakephp.org/class/validation 


 On Fri, Jan 11, 2013 at 2:49 PM, gonzela2006 
 gonze...@gmail.comjavascript: 
 wrote: 
  Hello, 
  
  I want to perform conditional validation between two rules 
  
  public $validate = array( 
  'variable' = array( 
  'notEmpty' = array( 
  'rule' = 'notEmpty' 
  ), 
  
   'url' = array( 
  'rule' = array('url', true), 
  'message' = 'Please supply a valid URL address.' 
  ) 
  
   'email' = array( 
 'rule'= array('email', true), 
 'message' = 'Please supply a valid email address.' 
 ) 
  
  ) 
  ); 
  
  I want to check if the variable is url or email 
  
  Thanks, 
  gonzela2006 
  
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Re: Conditional validation rule1 OR rule2

2013-01-12 Thread gonzela2006
Hello,

Any help please

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Conditional validation rule1 OR rule2

2013-01-11 Thread gonzela2006
Hello,

I want to perform conditional validation between two rules

public $validate = array(
'variable' = array(
'notEmpty' = array(
'rule' = 'notEmpty'
),
  
 'url' = array(
'rule' = array('url', true),
'message' = 'Please supply a valid URL address.'
)

 'email' = array(
'rule'= array('email', true),
'message' = 'Please supply a valid email address.'
)

)
);

I want to check if the variable is url *or* email

Thanks,
gonzela2006

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Re: Autocomplete example for cakephp 2.2

2012-07-25 Thread gonzela2006
Hi Greg,
I want an example for cakephp 2.1.x or 2.2.x.
Thanks

On Wednesday, July 25, 2012 6:16:06 PM UTC+2, Greg wrote:

 I use a jQuery autocomplete control
 and write a method in the desired controller which returns JSON and must 
 be requested as XHR ($this-request-is('ajax');)

 pretty straight forward to implement this way. Json views make it 
 ridiculously straight forward (just a bit of config really)

 if you are still stuck i'll grab an example from work tomorrow and dump it 
 for you.



 On Wed, Jul 25, 2012 at 11:27 PM, euromark dereurom...@googlemail.comwrote:

 Although the description might be german, the example itself should be 
 understandable:

 http://www.cakephp-forum.de/tutorials-und-snippets/autocomplete-mit-jquery-t1211.html
  


 Am Mittwoch, 25. Juli 2012 14:48:37 UTC+2 schrieb Dr. Tarique Sani:

 Keep your js separate from the php and any solution will work. 

 Tell us what specifically is not working 

 Cheers 
 Tarique 

 On Wed, Jul 25, 2012 at 6:40 AM, Christopher von Hessert 
 cvhess...@gmail.com wrote: 
  Hi, I'm looking all over google for a way to implement a Autocomplete 
 input 
  field with no luck. All examples I have found are for cakephp  1.3 
  
  Does anyone have a working example for cakephp 2.2? 
  
  Thanks. 
  
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Re: Search form like google

2012-06-13 Thread gonzela2006
Hi,

Thanks Dr. Tarique and I'll try the above tutorial and feedback you with 
the result :)

On Tuesday, June 12, 2012 9:30:22 AM UTC+3, Dr. Tarique Sani wrote:

 A bit dated but should get you started 
 http://blogfreakz.com/cakephp/cakephp-jquery-autocomplete-tutorial/  

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Search form like google

2012-06-11 Thread gonzela2006
Hi,
I'm a* newbie* on CakePHP 2 and I'm looking for a way to have a search box 
with ajax auto complete just like google does as you can see on the below 
image

https://lh5.googleusercontent.com/-r2LP5SW66x0/T9aQnbdZ9YI/AXY/mADzCvXpkGk/s1600/search+form.png

Thanks,
gonzela2006

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