Changing /webroot and /views directories
I need to have 5 different views directories which use the same controllers.
I want all front end views to be different but i want them to use the same
controllers. I see there is a way to define the constants but i would like
to use the bootstrap to define the different View paths
/**
* The settings below can be used to set additional paths to models, views
and controllers.
* This is related to Ticket #470 (https://trac.cakephp.org/ticket/470)
*
* App::build(array(
* 'plugins' = array('/full/path/to/plugins/',
'/next/full/path/to/plugins/'),
* 'models' = array('/full/path/to/models/',
'/next/full/path/to/models/'),
* 'views' = array('/full/path/to/views/',
'/next/full/path/to/views/'),
* 'controllers' = array('/full/path/to/controllers/',
'/next/full/path/to/controllers/'),
* 'datasources' = array('/full/path/to/datasources/',
'/next/full/path/to/datasources/'),
* 'behaviors' = array('/full/path/to/behaviors/',
'/next/full/path/to/behaviors/'),
* 'components' = array('/full/path/to/components/',
'/next/full/path/to/components/'),
* 'helpers' = array('/full/path/to/helpers/',
'/next/full/path/to/helpers/'),
* 'vendors' = array('/full/path/to/vendors/',
'/next/full/path/to/vendors/'),
* 'shells' = array('/full/path/to/shells/',
'/next/full/path/to/shells/'),
* 'locales' = array('/full/path/to/locale/',
'/next/full/path/to/locale/')
* ));
*
*/
considering these are 2 different view paths:
'views' = array('/full/path/to/views/', '/next/full/path/to/views/'),
How do i specify the full paths? Should it be like this:
'views' = array(APP.'views'.DS , APP.'mobile'.DS)
and where do i specify which path to use?
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How to turn off php safe mode in .htaccess
I get this error message when uploading images: Warning (2): copy() [function.copy]: SAFE MODE Restriction in effect. The script whose uid is 10214 is not allowed to access /usr/local/psa/ home/vhosts/testsite.com/httpdocs/app/webroot/img/Practitioner/338 owned by uid 80 [APP/models/behaviors/image.php, line 307] This is because safe mode is on. how can I set it off using a .htaccess file? Folder permissions are set to 0777 PLEASE HELP, THANKS IN ADVANCE! -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php
Re: cakephp Paginator-sort()
Thanks SCS, it works!
On Sep 1, 2:59 pm, scs scs2...@gmail.com wrote:
Change:
th?php echo $this-Paginator-sort('country_id',
'Country.name');?/th
To:
th?php echo $this-Paginator-sort('Country', 'Country.name');?
/th
http://book.cakephp.org/view/1233/Pagination-in-Views
On Sep 1, 5:06 am, mthabisi mlunjwa mmlun...@gmail.com wrote: In my view I
have the following:
th?php echo $this-Paginator-sort('country_id', 'Country.name');?
/th
The above code will display country_id as the heading of a list of
counties. I'm looking for a way to rename country_id such that it
displays as Country.
Please note country_id is a foreign key for table Country
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cakephp Paginator-sort()
In my view I have the following:
th?php echo $this-Paginator-sort('country_id', 'Country.name');?
/th
The above code will display country_id as the heading of a list of
counties. I'm looking for a way to rename country_id such that it
displays as Country.
Please note country_id is a foreign key for table Country
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Re: How to display hasMany association in the view
@gremlin I'm sending $Practicioner to the view and I'm looping over
$Practicioner like this:
foreach ($Practitioner as $Practitioners){
..
.
}
so that should explain why one is singular and the other is plural.
But its now working thanks to Jeremy.
On Jul 22, 6:27 am, gremlin abba.bry...@gmail.com wrote:
It also looks like in at least your sample code you were sending
$Practicioner to the view and trying to loop over $Practicioners
(notice one is plural - one is singular)
On Jul 21, 10:46 am, mthabisi mlunjwa mmlun...@gmail.com wrote:
Thanks Jeremy!
I used $practitioner['Practice'][0]['town'] and its now working.
Thanks a lot man!
On Jul 21, 4:17 pm, Jeremy Burns | Class Outfit
jeremybu...@classoutfit.com wrote:
I apologise;
$practitioner['Practice'][0]['town']
Not sure how you are generating that array...
Jeremy Burns
Class Outfit
http://www.classoutfit.com
On 21 Jul 2011, at 15:14, Jeremy Burns | Class Outfit wrote:
So (assuming this array is called $practitioner) you can display the
town by $practitioner['Practice']['town'].
Jeremy Burns
Class Outfit
http://www.classoutfit.com
On 21 Jul 2011, at 15:02, mthabisi mlunjwa wrote:
Sorry its a typo. All field names are in lower case.
I'm failing to display the town. But when I use debug($Practitioner)
the practitioner fields and practice towns are all displayed as shown
below:
array
(
[0] = Array
(
[Practitioner] = Array
(
[id] = 233
[region_id] = 2
[country_id] = 5
[status_id] = 1
[role_id] = 2
[bsrno] = 241
[surname] = Bossley
[name] = Bronwyn
[cell] = 0215656765
[password] =
dd4e8d1e0dfeb4ace2dda0fdfc8db83948109151
[created] = -00-00 00:00:00
[modified] = 2011-05-05 11:11:45
)
[Practice] = Array
(
[0] = Array
(
[id] = 233
[practitioner_id] = 233
[region_id] = 2
[country_id] = 5
[name] = Main
[Telephone] = +61 411673912
[Address] = 15 Edna Street, Carrimundi,
Queensland, 4551, Australia
[town] = Carrimundi
)
)
)
From my own understanding I thought the containable behaviour helps to
filter out unwanted results so as to improve the overall response
time. At the moment I'm interested in displaying the practise town.
On Jul 21, 3:13 pm, Jeremy Burns | Class Outfit
jeremybu...@classoutfit.com wrote:
Not sure if it's a typo, but your field names should be lower case.
Look at the Containable behaviour
(http://book.cakephp.org/view/1323/Containable).
Jeremy Burns
Class Outfit
http://www.classoutfit.com
On 21 Jul 2011, at 14:10, mthabisi mlunjwa wrote:
I have two models: Practitioner and Practice
Practitioner hasMany Practice and
Practise Belongs to Practitioner
The practise model has the following fields id,Practitioner_id, Name,
Town etc.
The Practitioner model has the following fields id,Surname, Name,
Cell
etc.
In my controller I used a find function:
$Practitioner = $this-Practitioner-find('all');
$this-set(compact('Practitioner'));
In my view I want to display the practitioner name, Surname, cell,
practice name and practice town.
I can display practitioner name, Surname and cell using code like
this
$Practitioners['Practitioner']['cell']
But I'm failing to display the corresponding practitioner's practice
name and practice town. I've tried using: $Practitioners['Practice']
['town']; to display town but it looks like nothing gets displayed.
How can I display town? Please help thanks in advance
--
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How to display hasMany association in the view
I have two modes: Practitioner and Practice
Practitioner hasMany Practice and
Practise Belongs to Practitioner
The practise model has the following fields id,Practitioner_id, Name,
Town etc.
The Practitioner model has the following fields id,Surname, Name, Cell
etc.
In my controller I used a find function:
$Practitioner = $this-Practitioner-find('all');
$this-set(compact('Practitioner'));
In my view I want to display the practitioner name, Surname, cell,
practice name and practice town.
I can display practitioner name, Surname and cell using code like this
$Practitioners['Practitioner']['cell']
But I'm failing to display the corresponding practitioner's practice
name and practice town. I've tried using: $Practitioners['Practice']
['town']; to display town but it looks like nothing gets displayed.
How can I display town? Please help thanks in advance
--
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Re: How to display hasMany association in the view
Sorry its a typo. All field names are in lower case.
I'm failing to display the town. But when I use debug($Practitioner)
the practitioner fields and practice towns are all displayed as shown
below:
array
(
[0] = Array
(
[Practitioner] = Array
(
[id] = 233
[region_id] = 2
[country_id] = 5
[status_id] = 1
[role_id] = 2
[bsrno] = 241
[surname] = Bossley
[name] = Bronwyn
[cell] = 0215656765
[password] =
dd4e8d1e0dfeb4ace2dda0fdfc8db83948109151
[created] = -00-00 00:00:00
[modified] = 2011-05-05 11:11:45
)
[Practice] = Array
(
[0] = Array
(
[id] = 233
[practitioner_id] = 233
[region_id] = 2
[country_id] = 5
[name] = Main
[Telephone] = +61 411673912
[Address] = 15 Edna Street, Carrimundi,
Queensland, 4551, Australia
[town] = Carrimundi
)
)
)
From my own understanding I thought the containable behaviour helps to
filter out unwanted results so as to improve the overall response
time. At the moment I'm interested in displaying the practise town.
On Jul 21, 3:13 pm, Jeremy Burns | Class Outfit
jeremybu...@classoutfit.com wrote:
Not sure if it's a typo, but your field names should be lower case.
Look at the Containable behaviour
(http://book.cakephp.org/view/1323/Containable).
Jeremy Burns
Class Outfit
http://www.classoutfit.com
On 21 Jul 2011, at 14:10, mthabisi mlunjwa wrote:
I have two models: Practitioner and Practice
Practitioner hasMany Practice and
Practise Belongs to Practitioner
The practise model has the following fields id,Practitioner_id, Name,
Town etc.
The Practitioner model has the following fields id,Surname, Name, Cell
etc.
In my controller I used a find function:
$Practitioner = $this-Practitioner-find('all');
$this-set(compact('Practitioner'));
In my view I want to display the practitioner name, Surname, cell,
practice name and practice town.
I can display practitioner name, Surname and cell using code like this
$Practitioners['Practitioner']['cell']
But I'm failing to display the corresponding practitioner's practice
name and practice town. I've tried using: $Practitioners['Practice']
['town']; to display town but it looks like nothing gets displayed.
How can I display town? Please help thanks in advance
--
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Re: How to display hasMany association in the view
Thanks Jeremy!
I used $practitioner['Practice'][0]['town'] and its now working.
Thanks a lot man!
On Jul 21, 4:17 pm, Jeremy Burns | Class Outfit
jeremybu...@classoutfit.com wrote:
I apologise;
$practitioner['Practice'][0]['town']
Not sure how you are generating that array...
Jeremy Burns
Class Outfit
http://www.classoutfit.com
On 21 Jul 2011, at 15:14, Jeremy Burns | Class Outfit wrote:
So (assuming this array is called $practitioner) you can display the town
by $practitioner['Practice']['town'].
Jeremy Burns
Class Outfit
http://www.classoutfit.com
On 21 Jul 2011, at 15:02, mthabisi mlunjwa wrote:
Sorry its a typo. All field names are in lower case.
I'm failing to display the town. But when I use debug($Practitioner)
the practitioner fields and practice towns are all displayed as shown
below:
array
(
[0] = Array
(
[Practitioner] = Array
(
[id] = 233
[region_id] = 2
[country_id] = 5
[status_id] = 1
[role_id] = 2
[bsrno] = 241
[surname] = Bossley
[name] = Bronwyn
[cell] = 0215656765
[password] =
dd4e8d1e0dfeb4ace2dda0fdfc8db83948109151
[created] = -00-00 00:00:00
[modified] = 2011-05-05 11:11:45
)
[Practice] = Array
(
[0] = Array
(
[id] = 233
[practitioner_id] = 233
[region_id] = 2
[country_id] = 5
[name] = Main
[Telephone] = +61 411673912
[Address] = 15 Edna Street, Carrimundi,
Queensland, 4551, Australia
[town] = Carrimundi
)
)
)
From my own understanding I thought the containable behaviour helps to
filter out unwanted results so as to improve the overall response
time. At the moment I'm interested in displaying the practise town.
On Jul 21, 3:13 pm, Jeremy Burns | Class Outfit
jeremybu...@classoutfit.com wrote:
Not sure if it's a typo, but your field names should be lower case.
Look at the Containable behaviour
(http://book.cakephp.org/view/1323/Containable).
Jeremy Burns
Class Outfit
http://www.classoutfit.com
On 21 Jul 2011, at 14:10, mthabisi mlunjwa wrote:
I have two models: Practitioner and Practice
Practitioner hasMany Practice and
Practise Belongs to Practitioner
The practise model has the following fields id,Practitioner_id, Name,
Town etc.
The Practitioner model has the following fields id,Surname, Name, Cell
etc.
In my controller I used a find function:
$Practitioner = $this-Practitioner-find('all');
$this-set(compact('Practitioner'));
In my view I want to display the practitioner name, Surname, cell,
practice name and practice town.
I can display practitioner name, Surname and cell using code like this
$Practitioners['Practitioner']['cell']
But I'm failing to display the corresponding practitioner's practice
name and practice town. I've tried using: $Practitioners['Practice']
['town']; to display town but it looks like nothing gets displayed.
How can I display town? Please help thanks in advance
--
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using sql LIKE in find()
I'm not sure if I'm missing something here. I'm trying to come up with
this sql statement the Cakephp way:
select * from practitioners where name like 'Vermeulen' or surname
like 'Vermeulen';
This is what I've come up with:
find( 'all', $conditions = array(OR=array('Practitioner.surname
LIKE' = %Vermeulen%,'Practitioner.name LIKE' =
%Vermeulen%)));
This works but it only outputs the whole database. I just want it to
output practitioners with surnames or names like Vermeulen.
Please help, thanks in advance.
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Re: using sql LIKE in find()
Thanks its now working. :-)
On Jun 17, 6:55 pm, scs scs2...@gmail.com wrote:
sorry forgot to add the vars
$conditions = 'Practitioner.name LIKE %'.$name.'%';
$conditions .= ' OR Practitioner.surname LIKE %'.$surname.'%';
$record = $this-Practitioner-find('all', array('conditions'=
$conditions ));
On Jun 17, 12:54 pm, scs scs2...@gmail.com wrote:
Try this
$conditions = 'Practitioner.name LIKE %'..'%';
$conditions .= ' OR Practitioner.surname LIKE %'..'%';
$record = $this-Practitioner-find('all', array('conditions'=
$conditions ));
On Jun 17, 10:35 am, mthabisi mlunjwa mmlun...@gmail.com wrote:
I'm not sure if I'm missing something here. I'm trying to come up with
this sql statement the Cakephp way:
select * from practitioners where name like 'Vermeulen' or surname
like 'Vermeulen';
This is what I've come up with:
find( 'all', $conditions = array(OR=array('Practitioner.surname
LIKE' = %Vermeulen%,'Practitioner.name LIKE' =
%Vermeulen%)));
This works but it only outputs the whole database. I just want it to
output practitioners with surnames or names like Vermeulen.
Please help, thanks in advance.
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How can I customise sorting order for dropdown field (menu) for foreign-key values
My add view looks like this:
?php
echo $form-create('Practice');
echo $form-input('region_id');
echo $form-input('name');
echo $form-end('save Practise');
?
region table has the following columns:
-id(primary key)
-region
practice table has the following columns:
-id
-region_id
-name
the region_id dropdown menu displays a menu list of all the regions in
the database. They are automatically sorted using the region
id(primary key) field.
How can I change it so that it sorts by region instead of id?
Please help. Thanks in advance.
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Re: How can I customise sorting order for dropdown field (menu) for foreign-key values
Thanks Jeremy, you've saved my time! I didn't know it was that simple.
On May 13, 4:05 pm, Jeremy Burns | Class Outfit
jeremybu...@classoutfit.com wrote:
In you Region model:
var $order = 'name';
Jeremy Burns
Class Outfit
jeremybu...@classoutfit.comhttp://www.classoutfit.com
On 13 May 2011, at 15:03, mthabisi mlunjwa wrote:
My add view looks like this:
?php
echo $form-create('Practice');
echo $form-input('region_id');
echo $form-input('name');
echo $form-end('save Practise');
?
region table has the following columns:
-id(primary key)
-region
practice table has the following columns:
-id
-region_id
-name
the region_id dropdown menu displays a menu list of all the regions in
the database. They are automatically sorted using the region
id(primary key) field.
How can I change it so that it sorts by region instead of id?
Please help. Thanks in advance.
--
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Re: isUnique validation on edit action of User model
I once had the same problem with the Isunique validation rule when
editing my email field. I tried to create my own method which did
seem to work. But along the way I quickly realized I was not doing
things properly.
My problem was in the database, I was using an old database and some
records where using the same email address. They were added using the
previous system which did not check to see if the email was unique.
And obviously these records where not added from my app, otherwise the
isunique error could have popped up. In my app I was able to view the
user details but I couldn't edit. When I removed one of the duplicate
record, everything worked perfectly.
Please run an sql query on your database to check if there are no
other records using the same email. I hope this helps.
rifat wrote:
Its already in CakePHP core, you didn't need nothing at all. If you just use
echo $form-input('id'); in your view. Sorry, that I didn't notice your
problem in time.
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Re: how can I set my home page
Yes I'm using the Auth component, and yes I've added the Auth
component in my AppController.
I'm new to CakePhp so this might sound like a stupid question
I added the home action on $this-Auth-
allow('index','view','recover','verify','home');
I thought this would solve the problem but its still asking me to log
in. Please advice.
this is my Appcontroller:
class AppController extends Controller {
var $components = array('Auth','Session','Email');
//var $helpers = array('Time');
function beforeFilter(){
$this-Auth-allow('index','view','recover','verify','home');
$this-Auth-userModel = 'Practitioner';
$this-Auth-fields = array('username' = 'email', 'password' =
'password');
$this-Auth-authError = 'To login please enter your email and
password!';
$this-Auth-loginError = 'Incorect Email or password
combination.';
$this-Session-write('Auth.redirect', null);
$this-Auth-loginRedirect = array('controller' =
'Practitioners',
'action' = 'index');
$this-Auth-logoutRedirect =
array(Configure::read('Routing.admin')
= false, 'controller' = 'Practitioners', 'action' = 'logout');
$this-Model-authUserId = $this-Auth-user('id');
}
}
Thanks in advance
On May 4, 10:56 am, Ryan Schmidt google-2...@ryandesign.com wrote:
On May 3, 2011, at 17:07, mthabisi mlunjwa wrote:
I'm trying to set home.ctp as my home page/landing page. But no matter
how I try I'm redirected to a different page(http://domain.com/
practitioners/login).
Sounds like you've added the Auth component (possibly to your AppController).
Is that possible? If so, that's what's asking you to log in here.
http://book.cakephp.org/view/1250/Authentication
If you don't want users to have to log in to see your home page, then you
need to tell the Auth component that, for example by allowing the display
action. (This will allow all URLs handled by the Pages controller (not just
the home page) to be displayed.)
http://book.cakephp.org/view/1656/allowedActions
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Re: how can I set my home page
I've allowed the display action and it now works.
Thanks for the help guys.
On May 5, 3:46 pm, mi...@brightstorm.co.uk wrote:
Yes I'm using the Auth component, and yes I've added the Auth
component in my AppController.
I'm new to CakePhp so this might sound like a stupid question
I added the home action on $this-Auth-
allow('index','view','recover','verify','home');
I thought this would solve the problem but its still asking me to log
in. Please advice.
if you are using the pages controller to display your home.ctp then you'll
need to allow the 'display' action rather than the page you are trying to
display.
this is my Appcontroller:
class AppController extends Controller {
var $components = array('Auth','Session','Email');
//var $helpers = array('Time');
function beforeFilter(){
$this-Auth-allow('index','view','recover','verify','home');
$this-Auth-userModel = 'Practitioner';
$this-Auth-fields = array('username' = 'email', 'password' =
'password');
$this-Auth-authError = 'To login please enter your email and
password!';
$this-Auth-loginError = 'Incorect Email or password
combination.';
$this-Session-write('Auth.redirect', null);
$this-Auth-loginRedirect = array('controller' =
'Practitioners',
'action' = 'index');
$this-Auth-logoutRedirect =
array(Configure::read('Routing.admin')
= false, 'controller' = 'Practitioners', 'action' = 'logout');
$this-Model-authUserId = $this-Auth-user('id');
}
}
Thanks in advance
On May 4, 10:56 am, Ryan Schmidt google-2...@ryandesign.com wrote:
On May 3, 2011, at 17:07, mthabisi mlunjwa wrote:
I'm trying to set home.ctp as my home page/landing page. But no matter
how I try I'm redirected to a different page(http://domain.com/
practitioners/login).
Sounds like you've added the Auth component (possibly to your
AppController). Is that possible? If so, that's what's asking you to log
in here.
http://book.cakephp.org/view/1250/Authentication
If you don't want users to have to log in to see your home page, then
you need to tell the Auth component that, for example by allowing the
display action. (This will allow all URLs handled by the Pages
controller (not just the home page) to be displayed.)
http://book.cakephp.org/view/1656/allowedActions
--
Our newest site for the community: CakePHP Video Tutorials
http://tv.cakephp.org
Check out the new CakePHP Questions sitehttp://ask.cakephp.organd help
others with their CakePHP related questions.
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cake-php+unsubscr...@googlegroups.com For more options, visit this group
athttp://groups.google.com/group/cake-php
--
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how can I set my home page
I'm trying to set home.ctp as my home page/landing page. But no matter
how I try I'm redirected to a different page(http://domain.com/
practitioners/login). I'm not sure if I'm following the correct
procedure. see below the pagesController and routes.php
class PagesController extends AppController {
var $name = 'Pages';
var $helpers = array('Html');
var $uses = array();
function display() {
$path = func_get_args();
$count = count($path);
if (!$count) {
$this-redirect('/');
}
$page = $subpage = $title_for_layout = null;
if (!empty($path[0])) {
$page = $path[0];
}
if (!empty($path[1])) {
$subpage = $path[1];
}
if (!empty($path[$count - 1])) {
$title_for_layout = Inflector::humanize($path[$count -
1]);
}
$this-set(compact('page', 'subpage', 'title_for_layout'));
$this-render(implode('/', $path));
}
public function home(){
$this-set('title_for_layout', 'Practitioner's');
$this-layout = 'home2';
}
}
?
Routes.php:
Router::connect('/', array('controller' = 'pages', 'action' =
'display', 'home'));
Router::connect('/pages/*', array('controller' = 'pages', 'action'
= 'display'));
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