Re: [CentOS] parsing out adjacent text

2014-06-05 Thread lee 
Tim Dunphy bluethu...@gmail.com writes:

 I'm very grateful. Ok so here is what I have so far of my script to get the
 number of apache requests to a given host:
 [...]
 So now my question is, is there any way to limit the size of the output log
 from within the script without having to use logrotate?

You could add a counter to the script and send the log off by email
after polling so many times, or on each poll, tail the file, omitting so
many lines as to remove the first entry.


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Re: [CentOS] parsing out adjacent text

2014-06-03 Thread Patrick Bervoets 


op 03-06-14 15:18, schreef Tim Dunphy:

  [root@uszmpwslp014lc ~]# GET http://$(hostname -i)/server-status  | grep
-i  requests/sec
dt4.08 requests/sec - 80.9 kB/second - 19.8 kB/request/dt


That works ok. And next I'm grepping it back down and awking it to just the
part I'm interested in:

[root@uszmpwslp014lc ~]# GET http://$(hostname -i)/server-status  | grep -i
-e request -e requests/sec | grep -i -v -e currently  -e code  -e ss | awk
'{print $1}'
dt4.08

But now I need to get rid of just the dt in front of the 4.08?

cut --delimiter= --field=2

you could even get rid of the awk and pipe your grep to cut --delimiter= --field=2 | 
cut --delimiter=  --field=1

But there are many different ways to solve this.

greetings
Patrick

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Re: [CentOS] parsing out adjacent text

2014-06-03 Thread Tim Dunphy 
Guys,

 Thank you all for your input. I can't believe how helpful this list is and
I'm very grateful. Ok so here is what I have so far of my script to get the
number of apache requests to a given host:

#!/bin/bash

# this script parses mod_status to see which hosts are getting the most
requests


echo “Time:”   /tmp/apache_request_log

/usr/bin/ts  /tmp/apache_request_log

echo -e “\n”  /tmp/apache_request_log

echo “hostname”/tmp/apache_request_log

/bin/hostname -f   /tmp/apache_request_log

echo -e “\n”  /tmp/apache_request_log

echo “hostname ip”/tmp/apache_request_log

/bin/hostname -i   /tmp/apache_request_log

echo -e “\n”  /tmp/apache_request_log

echo “Requests per second:”   /tmp/apache_request_log

/usr/bin/GET  http://$(/bin/hostname -i)/server-status  | /bin/grep  -i -e
request -e requests/sec | grep -i -v -e currently  -e code  -e ss | awk
'{print $1}' | cut -d'' -f2   /tmp/apache_request_log

echo “Requests processed / Idle workers:”   /tmp/apache_request_log

/usr/bin/GET http://$(hostname -i)/server-status | /bin/grep  -i -e
requests -e currently | grep -v -e requests/sec | cut -d'' -f2 | cut -d''
-f1   /tmp/apache_request_log

echo -e “\n\n”   /tmp/apache_request_log

/bin/sleep 60



So now my question is, is there any way to limit the size of the output log
from within the script without having to use logrotate? I can use that, but
I would prefer to do that from within the script if that's possib.e


Thanks

Tim


On Tue, Jun 3, 2014 at 9:29 AM, Patrick Bervoets 
patrick.bervo...@psc-elsene.be wrote:


 op 03-06-14 15:18, schreef Tim Dunphy:

[root@uszmpwslp014lc ~]# GET http://$(hostname -i)/server-status  |
 grep
 -i  requests/sec
 dt4.08 requests/sec - 80.9 kB/second - 19.8 kB/request/dt


 That works ok. And next I'm grepping it back down and awking it to just
 the
 part I'm interested in:

 [root@uszmpwslp014lc ~]# GET http://$(hostname -i)/server-status  | grep
 -i
 -e request -e requests/sec | grep -i -v -e currently  -e code  -e ss | awk
 '{print $1}'
 dt4.08

 But now I need to get rid of just the dt in front of the 4.08?

 cut --delimiter= --field=2

 you could even get rid of the awk and pipe your grep to cut
 --delimiter= --field=2 | cut --delimiter=  --field=1

 But there are many different ways to solve this.

 greetings
 Patrick


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Re: [CentOS] parsing out adjacent text

2014-06-03 Thread Marios Zindilis 
On Tue, Jun 3, 2014 at 4:56 PM, Tim Dunphy bluethu...@gmail.com wrote:

 Guys,

  Thank you all for your input. I can't believe how helpful this list is and
 I'm very grateful. Ok so here is what I have so far of my script to get the
 number of apache requests to a given host:

 #!/bin/bash

 # this script parses mod_status to see which hosts are getting the most
 requests


 echo “Time:”   /tmp/apache_request_log

 /usr/bin/ts  /tmp/apache_request_log

 echo -e “\n”  /tmp/apache_request_log

 echo “hostname”/tmp/apache_request_log

 /bin/hostname -f   /tmp/apache_request_log

 echo -e “\n”  /tmp/apache_request_log

 echo “hostname ip”/tmp/apache_request_log

 /bin/hostname -i   /tmp/apache_request_log

 echo -e “\n”  /tmp/apache_request_log

 echo “Requests per second:”   /tmp/apache_request_log

 /usr/bin/GET  http://$(/bin/hostname -i)/server-status  | /bin/grep  -i -e
 request -e requests/sec | grep -i -v -e currently  -e code  -e ss | awk
 '{print $1}' | cut -d'' -f2   /tmp/apache_request_log

 echo “Requests processed / Idle workers:”   /tmp/apache_request_log

 /usr/bin/GET http://$(hostname -i)/server-status | /bin/grep  -i -e
 requests -e currently | grep -v -e requests/sec | cut -d'' -f2 | cut -d''
 -f1   /tmp/apache_request_log

 echo -e “\n\n”   /tmp/apache_request_log

 /bin/sleep 60



 So now my question is, is there any way to limit the size of the output log
 from within the script without having to use logrotate? I can use that, but
 I would prefer to do that from within the script if that's possib.e


 Thanks

 Tim


 On Tue, Jun 3, 2014 at 9:29 AM, Patrick Bervoets 
 patrick.bervo...@psc-elsene.be wrote:

 
  op 03-06-14 15:18, schreef Tim Dunphy:
 
 [root@uszmpwslp014lc ~]# GET http://$(hostname -i)/server-status  |
  grep
  -i  requests/sec
  dt4.08 requests/sec - 80.9 kB/second - 19.8 kB/request/dt
 
 
  That works ok. And next I'm grepping it back down and awking it to just
  the
  part I'm interested in:
 
  [root@uszmpwslp014lc ~]# GET http://$(hostname -i)/server-status  |
 grep
  -i
  -e request -e requests/sec | grep -i -v -e currently  -e code  -e ss |
 awk
  '{print $1}'
  dt4.08
 
  But now I need to get rid of just the dt in front of the 4.08?
 
  cut --delimiter= --field=2
 
  you could even get rid of the awk and pipe your grep to cut
  --delimiter= --field=2 | cut --delimiter=  --field=1
 
  But there are many different ways to solve this.
 
  greetings
  Patrick
 
 
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  http://lists.centos.org/mailman/listinfo/centos
 
 


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Try accessing the stats with the additional ?auto suffix, it is meant to
be machine-readable, and is much shorter, e.g:

http://$(hostname -i)/server-status/?auto



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Re: [CentOS] parsing out adjacent text

2014-06-03 Thread Tim Dunphy 

 Try accessing the stats with the additional ?auto suffix, it is meant to
 be machine-readable, and is much shorter, e.g:

 http://$(hostname -i)/server-status/?auto



Awesome tip! This is some of the output I get when I run this command:

[root@uszmpwslp014lc script]# GET $(hostname -f)/server-status/?auto
Total Accesses: 1371927
Total kBytes: 27060974
CPULoad: 2.70778
Uptime: 70
ReqPerSec: 4.11533
BytesPerSec: 83122.2
BytesPerReq: 20198.2
BusyWorkers: 7
IdleWorkers: 44

This will be way easier to parse!




On Tue, Jun 3, 2014 at 10:02 AM, Marios Zindilis mar...@zindilis.com
wrote:

 On Tue, Jun 3, 2014 at 4:56 PM, Tim Dunphy bluethu...@gmail.com wrote:

  Guys,
 
   Thank you all for your input. I can't believe how helpful this list is
 and
  I'm very grateful. Ok so here is what I have so far of my script to get
 the
  number of apache requests to a given host:
 
  #!/bin/bash
 
  # this script parses mod_status to see which hosts are getting the most
  requests
 
 
  echo “Time:”   /tmp/apache_request_log
 
  /usr/bin/ts  /tmp/apache_request_log
 
  echo -e “\n”  /tmp/apache_request_log
 
  echo “hostname”/tmp/apache_request_log
 
  /bin/hostname -f   /tmp/apache_request_log
 
  echo -e “\n”  /tmp/apache_request_log
 
  echo “hostname ip”/tmp/apache_request_log
 
  /bin/hostname -i   /tmp/apache_request_log
 
  echo -e “\n”  /tmp/apache_request_log
 
  echo “Requests per second:”   /tmp/apache_request_log
 
  /usr/bin/GET  http://$(/bin/hostname -i)/server-status  | /bin/grep  -i
 -e
  request -e requests/sec | grep -i -v -e currently  -e code  -e ss | awk
  '{print $1}' | cut -d'' -f2   /tmp/apache_request_log
 
  echo “Requests processed / Idle workers:”   /tmp/apache_request_log
 
  /usr/bin/GET http://$(hostname -i)/server-status | /bin/grep  -i -e
  requests -e currently | grep -v -e requests/sec | cut -d'' -f2 | cut
 -d''
  -f1   /tmp/apache_request_log
 
  echo -e “\n\n”   /tmp/apache_request_log
 
  /bin/sleep 60
 
 
 
  So now my question is, is there any way to limit the size of the output
 log
  from within the script without having to use logrotate? I can use that,
 but
  I would prefer to do that from within the script if that's possib.e
 
 
  Thanks
 
  Tim
 
 
  On Tue, Jun 3, 2014 at 9:29 AM, Patrick Bervoets 
  patrick.bervo...@psc-elsene.be wrote:
 
  
   op 03-06-14 15:18, schreef Tim Dunphy:
  
  [root@uszmpwslp014lc ~]# GET http://$(hostname -i)/server-status  |
   grep
   -i  requests/sec
   dt4.08 requests/sec - 80.9 kB/second - 19.8 kB/request/dt
  
  
   That works ok. And next I'm grepping it back down and awking it to
 just
   the
   part I'm interested in:
  
   [root@uszmpwslp014lc ~]# GET http://$(hostname -i)/server-status  |
  grep
   -i
   -e request -e requests/sec | grep -i -v -e currently  -e code  -e ss |
  awk
   '{print $1}'
   dt4.08
  
   But now I need to get rid of just the dt in front of the 4.08?
  
   cut --delimiter= --field=2
  
   you could even get rid of the awk and pipe your grep to cut
   --delimiter= --field=2 | cut --delimiter=  --field=1
  
   But there are many different ways to solve this.
  
   greetings
   Patrick
  
  
   ___
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   http://lists.centos.org/mailman/listinfo/centos
  
  
 
 
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 Try accessing the stats with the additional ?auto suffix, it is meant to
 be machine-readable, and is much shorter, e.g:

 http://$(hostname -i)/server-status/?auto



 --
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Re: [CentOS] parsing out adjacent text

2014-06-03 Thread Tim Dunphy 
Ok! So this is where my script is at this point:

#!/bin/bash
# this script parses mod_status to see which hosts are getting the most
requests

while true
do
echo Time and date:  /tmp/apache_request_log
/bin/date +%D %H:%M:%S  /tmp/apache_request_log
echo -e \n
echo “hostname:”/tmp/apache_request_log
/bin/hostname -f   /tmp/apache_request_log
echo -e “\n”  /tmp/apache_request_log
echo “host ip”/tmp/apache_request_log
/bin/hostname -i   /tmp/apache_request_log
echo -e “\n”  /tmp/apache_request_log
echo Server Stats:  /tmp/apache_request_log
GET $(hostname -f)/server-status/?auto | egrep -i (accesses|kbytes) 
/tmp/apache_request_log
echo -e “\n”   /tmp/apache_request_log
/bin/sleep 60
done

Now the only problems I am having are some output issues. This is the
output I've gotten from this:

[root@webhost014lc ~]# tail -f /tmp/apache_request_log
Time and date:
06/03/14 10:24:09
“hostname:”
webhost014lc.west.dmz-nbcuni.com
“n”
“host ip”
10.10.1.98
“n”
Server Stats:
Total Accesses: 1383898
Total kBytes: 27198225
“n”
Time and date:
06/03/14 10:25:09
“hostname:”
webhost014lc.west.dmz-nbcuni.com
“n”
“host ip”
10.10.1.98
“n”
Server Stats:
Total Accesses: 1384666
Total kBytes: 27206570
“n”

What I need to figure out at this point is how to get the time and date
info on the same line as it's category. ie get

Time and date: 06/03/14 10:24:09

instead of

Time and date:
06/03/14 10:24:09

As it is now.

Also I'm trying to print out newlines with  echo -e \n but somehow that
isn't working. Tho I think I've gotten that to work in the past.

If someone could please help me fix these minor formatting issues that
would be great and appreciated.

Thanks
Tim


On Tue, Jun 3, 2014 at 10:09 AM, Tim Dunphy bluethu...@gmail.com wrote:

 Try accessing the stats with the additional ?auto suffix, it is meant to
 be machine-readable, and is much shorter, e.g:

 http://$(hostname -i)/server-status/?auto



 Awesome tip! This is some of the output I get when I run this command:

 [root@uszmpwslp014lc script]# GET $(hostname -f)/server-status/?auto
 Total Accesses: 1371927
 Total kBytes: 27060974
 CPULoad: 2.70778
 Uptime: 70
 ReqPerSec: 4.11533
 BytesPerSec: 83122.2
 BytesPerReq: 20198.2
 BusyWorkers: 7
 IdleWorkers: 44

 This will be way easier to parse!




 On Tue, Jun 3, 2014 at 10:02 AM, Marios Zindilis mar...@zindilis.com
 wrote:

 On Tue, Jun 3, 2014 at 4:56 PM, Tim Dunphy bluethu...@gmail.com wrote:

  Guys,
 
   Thank you all for your input. I can't believe how helpful this list is
 and
  I'm very grateful. Ok so here is what I have so far of my script to get
 the
  number of apache requests to a given host:
 
  #!/bin/bash
 
  # this script parses mod_status to see which hosts are getting the most
  requests
 
 
  echo “Time:”   /tmp/apache_request_log
 
  /usr/bin/ts  /tmp/apache_request_log
 
  echo -e “\n”  /tmp/apache_request_log
 
  echo “hostname”/tmp/apache_request_log
 
  /bin/hostname -f   /tmp/apache_request_log
 
  echo -e “\n”  /tmp/apache_request_log
 
  echo “hostname ip”/tmp/apache_request_log
 
  /bin/hostname -i   /tmp/apache_request_log
 
  echo -e “\n”  /tmp/apache_request_log
 
  echo “Requests per second:”   /tmp/apache_request_log
 
  /usr/bin/GET  http://$(/bin/hostname -i)/server-status  | /bin/grep
  -i -e
  request -e requests/sec | grep -i -v -e currently  -e code  -e ss | awk
  '{print $1}' | cut -d'' -f2   /tmp/apache_request_log
 
  echo “Requests processed / Idle workers:”   /tmp/apache_request_log
 
  /usr/bin/GET http://$(hostname -i)/server-status | /bin/grep  -i -e
  requests -e currently | grep -v -e requests/sec | cut -d'' -f2 | cut
 -d''
  -f1   /tmp/apache_request_log
 
  echo -e “\n\n”   /tmp/apache_request_log
 
  /bin/sleep 60
 
 
 
  So now my question is, is there any way to limit the size of the output
 log
  from within the script without having to use logrotate? I can use that,
 but
  I would prefer to do that from within the script if that's possib.e
 
 
  Thanks
 
  Tim
 
 
  On Tue, Jun 3, 2014 at 9:29 AM, Patrick Bervoets 
  patrick.bervo...@psc-elsene.be wrote:
 
  
   op 03-06-14 15:18, schreef Tim Dunphy:
  
  [root@uszmpwslp014lc ~]# GET http://$(hostname -i)/server-status
  |
   grep
   -i  requests/sec
   dt4.08 requests/sec - 80.9 kB/second - 19.8 kB/request/dt
  
  
   That works ok. And next I'm grepping it back down and awking it to
 just
   the
   part I'm interested in:
  
   [root@uszmpwslp014lc ~]# GET http://$(hostname -i)/server-status  |
  grep
   -i
   -e request -e requests/sec | grep -i -v -e currently  -e code  -e ss
 |
  awk
   '{print $1}'
   dt4.08
  
   But now I need to get rid of just the dt in front of the 4.08?
  
   cut --delimiter= --field=2
  
   you could even get rid of the awk and pipe your grep to cut
   --delimiter= --field=2 | cut --delimiter=  --field=1
  
   But there are many different ways to solve this.
  
   greetings
   Patrick
  
  
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Re: [CentOS] parsing out adjacent text

2014-06-03 Thread Keith Keller 
On 2014-06-03, Tim Dunphy bluethu...@gmail.com wrote:
 Ok! So this is where my script is at this point:

I strongly suggest that if you are writing a program to use a better
language.  bash is really painful for this sort of task.  Here's a
Perl script that queries /server-status:

http://www.perlmonks.org/?node_id=465848

And modify to taste.

--keith

-- 
kkel...@wombat.san-francisco.ca.us


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Re: [CentOS] parsing out adjacent text

2014-06-03 Thread Patrick Bervoets 


op 03-06-14 16:32, schreef Tim Dunphy:

What I need to figure out at this point is how to get the time and date
info on the same line as it's category. ie get

Time and date: 06/03/14 10:24:09

instead of

Time and date:
06/03/14 10:24:09

printf Time and date: $(/bin/date +%D %H:%M:%S)\n solves both problems here

As it is now.

Also I'm trying to print out newlines with  echo -e \n but somehow that
isn't working. Tho I think I've gotten that to work in the past.

If someone could please help me fix these minor formatting issues that
would be great and appreciated.

Thanks
Tim






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Re: [CentOS] parsing out adjacent text

2014-06-03 Thread Tim Dunphy 
Ok this is what I came up with:

#!/bin/bash
# this script parses mod_status to see which hosts are getting the most
requests

while true
do
echo Time and date: $(/bin/date +%D %H:%M:%S) 
/tmp/apache_request_log  /tmp/apache_request_log
echo “hostname: $(/bin/hostname -f)\n”/tmp/apache_request_log
echo “host ip: $(/bin/hostname -i)”/tmp/apache_request_log
echo Server Stats: $(/usr/bin/GET `hostname -f`/server-status/?auto |
/bin/egrep  -i 'kbytes')  /tmp/apache_request_log
echo Server Stats: $(/usr/bin/GET `hostname -f`/server-status/?auto |
/bin/egrep  -i 'ReqPerSec')  /tmp/apache_request_log
echo -e \n
sleep 60
done

Still can't get the echo -e \n statement to print a new line for some
reason. Other than that I'm good. And thanks for everyone's help!

Tim


On Tue, Jun 3, 2014 at 10:43 AM, Patrick Bervoets 
patrick.bervo...@psc-elsene.be wrote:


 op 03-06-14 16:32, schreef Tim Dunphy:

  What I need to figure out at this point is how to get the time and date
 info on the same line as it's category. ie get

 Time and date: 06/03/14 10:24:09

 instead of

 Time and date:
 06/03/14 10:24:09

 printf Time and date: $(/bin/date +%D %H:%M:%S)\n solves both problems
 here

  As it is now.

 Also I'm trying to print out newlines with  echo -e \n but somehow that
 isn't working. Tho I think I've gotten that to work in the past.

 If someone could please help me fix these minor formatting issues that
 would be great and appreciated.

 Thanks
 Tim






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Re: [CentOS] parsing out adjacent text

2014-06-03 Thread Stephen Harris 
On Tue, Jun 03, 2014 at 11:55:55AM -0400, Tim Dunphy wrote:
 while true
 do
 echo Time and date: $(/bin/date +%D %H:%M:%S) 
 /tmp/apache_request_log  /tmp/apache_request_log
 echo ???hostname: $(/bin/hostname -f)\n???/tmp/apache_request_log
 echo ???host ip: $(/bin/hostname -i)???/tmp/apache_request_log
 echo Server Stats: $(/usr/bin/GET `hostname -f`/server-status/?auto |
 /bin/egrep  -i 'kbytes')  /tmp/apache_request_log
 echo Server Stats: $(/usr/bin/GET `hostname -f`/server-status/?auto |
 /bin/egrep  -i 'ReqPerSec')  /tmp/apache_request_log
 echo -e \n
 sleep 60
 done

Look at this code structure:

  while true
  do
{
  echo Time and date: $(date +%D %H:%M:%S)
  echo Hostname: $(hostname -f)
  echo Hostname IP: $(hostname -i)
  ...
  ...
  # Leave two blank lines
  echo
  echo
}  /tmp/apache_request_log
sleep 60
  done

Note how we're only doing one redirect; this makes the code easier
to read and less likely to make a mistake (and more efficient).

 Still can't get the echo -e \n statement to print a new line for some
 reason. Other than that I'm good. And thanks for everyone's help!

That's one of the mistakes; you forgot the  /tmp/apache_request_log
on the echo line.  But echo on its own without anything else leaves
a blank line.

The next clever bit is to not call GET twice; why make apache do
twice the work?  Call it once and store the results in a variable

  stat=$(GET $(hostname -f)/server-status/?auto)
  echo Server Stats: $(echo $stat | grep -i kbytes)
  echo Server Stats: $(echo $stat | grep -i ReqPerSec)

(You can get even more clever, but that's a little more involved; we'll
start with some basics :-))

So we end up with something like:

  #!/bin/bash

  # These never change...
  name=$(hostname -f)
  ip=$(hostname -i)

  # Once a minute, record some stats
  while true
  do
{
  echo Time and date: $(date +%D %H:%M:%S)
  echo Hostname: $name
  echo Hostname IP: $ip
  stat=$(GET $name/server-status/?auto)
  echo Server Stats: $(echo $stat | grep -i kbytes)
  echo Server Stats: $(echo $stat | grep -i ReqPerSec)
  echo
  echo
}  /tmp/apache_request_log
sleep 60
  done

-- 

rgds
Stephen
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Re: [CentOS] parsing out adjacent text

2014-06-03 Thread Bowie Bailey 
On 6/3/2014 11:55 AM, Tim Dunphy wrote:
 Ok this is what I came up with:

 #!/bin/bash
 # this script parses mod_status to see which hosts are getting the most
 requests

 while true
 do
 echo Time and date: $(/bin/date +%D %H:%M:%S) 
 /tmp/apache_request_log  /tmp/apache_request_log
 echo “hostname: $(/bin/hostname -f)\n”/tmp/apache_request_log
 echo “host ip: $(/bin/hostname -i)”/tmp/apache_request_log
 echo Server Stats: $(/usr/bin/GET `hostname -f`/server-status/?auto |
 /bin/egrep  -i 'kbytes')  /tmp/apache_request_log
 echo Server Stats: $(/usr/bin/GET `hostname -f`/server-status/?auto |
 /bin/egrep  -i 'ReqPerSec')  /tmp/apache_request_log
 echo -e \n
 sleep 60
 done

 Still can't get the echo -e \n statement to print a new line for some
 reason. Other than that I'm good. And thanks for everyone's help!

'echo' on it's own should print a new line.  If you want two, why not 
just use two echo lines?

Also, you are piping everything else to the apache_request_log except 
for the last echo line.  Is the problem simply that you forgot to pipe 
that to the log file?

echo -e \n  /tmp/apache_request_log

-- 
Bowie
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