Calling the same UDF twice..

2006-06-09 Thread Daniel Baughman
Anyone ever seen a situation like this:

You define a function (some arbitrary function)

cffunction name=fun1
HI
/cffunction


And then can't call it twice in a row?

cfset fun1()
cfset fun1()

The second time it says that fun1 is not defined, but if you comment out the
first call the second runs fine..


If anyone has seen this, or is interested in how to recreate, let me know.


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Re: Calling the same UDF twice..

2006-06-09 Thread Rob Wilkerson
Just out of curiousity, try assigning it to a variable in both cases...

cfset dummy = foo() /
cfset dummy2 = foo() /

I've never seen the case you're talking about, but function names are
set in the variables scope and that has caused me other hearburn on
occasion.  I wonder if something is going on with that?

On 6/9/06, Daniel Baughman [EMAIL PROTECTED] wrote:
 Anyone ever seen a situation like this:

 You define a function (some arbitrary function)

 cffunction name=fun1
 HI
 /cffunction


 And then can't call it twice in a row?

 cfset fun1()
 cfset fun1()

 The second time it says that fun1 is not defined, but if you comment out the
 first call the second runs fine..


 If anyone has seen this, or is interested in how to recreate, let me know.


 

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Re: Calling the same UDF twice..

2006-06-09 Thread Raymond Camden
Can you show us the real code?

On 6/9/06, Daniel Baughman [EMAIL PROTECTED] wrote:
 Anyone ever seen a situation like this:

 You define a function (some arbitrary function)

 cffunction name=fun1
 HI
 /cffunction


 And then can't call it twice in a row?

 cfset fun1()
 cfset fun1()

 The second time it says that fun1 is not defined, but if you comment out the
 first call the second runs fine..


 If anyone has seen this, or is interested in how to recreate, let me know.


 

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Re: Calling the same UDF twice..

2006-06-09 Thread Jerry Johnson
Just a guess:
Because you are setting the value of the function Fun1() to nothing?

Don't you want:

cfset temp=fun1()
cfset temp=fun1()

not

cfset fun1()
(which replaces the value of fun1() with null)?



On 6/9/06, Raymond Camden [EMAIL PROTECTED] wrote:
 Can you show us the real code?

 On 6/9/06, Daniel Baughman [EMAIL PROTECTED] wrote:
  Anyone ever seen a situation like this:
 
  You define a function (some arbitrary function)
 
  cffunction name=fun1
  HI
  /cffunction
 
 
  And then can't call it twice in a row?
 
  cfset fun1()
  cfset fun1()
 
  The second time it says that fun1 is not defined, but if you comment out the
  first call the second runs fine..
 
 
  If anyone has seen this, or is interested in how to recreate, let me know.
 
 
 

 

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RE: Calling the same UDF twice..

2006-06-09 Thread Ian Skinner
You define a function (some arbitrary function)

cffunction name=fun1
HI
/cffunction


And then can't call it twice in a row?

cfset fun1()
cfset fun1()

Do you do anything to the fun1 value?  The variable can be redefined at any 
time to be something other then a function.

Either of these would be a problem

cfunction name=fun1
cfset fun1 = HI
/cfunction

OR 
cfoutput#fun1()#/cfoutput
cfset fun1 = George
cfoutput#fun1()#/cfoutput

I suspect something closer to the former issue from what you have described.


--
Ian Skinner
Web Programmer
BloodSource
www.BloodSource.org
Sacramento, CA

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RE: Calling the same UDF twice..

2006-06-09 Thread Daniel Baughman
I have tried calling the functions like this:
cfscript
updateUser(valueUseList, fieldUseList,
form.u1id);
/cfscript
cfscript
updateUser(valueUseList, fieldUseList,
form.u1id);
/cfscript

The second time it will throw the error that the function is undefined, if I
comment out the first call, the second call works just fine.

Here is the actual function:
cffunction name=updateUser
cfargument name=valueUseList required=true type=string
cfargument name=fieldUseList required=true type=string  
cfargument name=userId required=true type=numeric
cfif listlen(fielduselist, |) gt 0
cfquery name=updateUser datasource=xxx
Update myTable set
cfloop from=1 to=#listLen(fieldUseList, |)#
index=i
cfoutput
#listgetat(fieldUseList,i, | )# =
cfqueryparam value=#listgetat(valueUseList,i, |)#
cfsqltype=cf_sql_varchar
cfif listLen(fieldUseList, |) gt
i,/cfif
/cfoutput
/cfloop
where tableId = cfoutput'#userid#'/cfoutput
/cfquery
cfelse
No data given to update user
cfoutput#userId#/cfoutput...
/cfif
cfreturn
/cffunction





Daniel Baughman

-Original Message-
From: Raymond Camden [mailto:[EMAIL PROTECTED] 
Sent: Friday, June 09, 2006 10:39 AM
To: CF-Talk
Subject: Re: Calling the same UDF twice..


Can you show us the real code?

On 6/9/06, Daniel Baughman [EMAIL PROTECTED] wrote:
 Anyone ever seen a situation like this:

 You define a function (some arbitrary function)

 cffunction name=fun1
 HI
 /cffunction


 And then can't call it twice in a row?

 cfset fun1()
 cfset fun1()

 The second time it says that fun1 is not defined, but if you comment out
the
 first call the second runs fine..


 If anyone has seen this, or is interested in how to recreate, let me know.


 



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RE: Calling the same UDF twice..

2006-06-09 Thread Daniel Baughman
Oh your exactly right, my previous post proved it.  In the function I have a
query named updateUser that is replacing the function.

Thanks for the help. 

-Original Message-
From: Ian Skinner [mailto:[EMAIL PROTECTED] 
Sent: Friday, June 09, 2006 11:07 AM
To: CF-Talk
Subject: RE: Calling the same UDF twice..


You define a function (some arbitrary function)

cffunction name=fun1
HI
/cffunction


And then can't call it twice in a row?

cfset fun1()
cfset fun1()

Do you do anything to the fun1 value?  The variable can be redefined at any
time to be something other then a function.

Either of these would be a problem

cfunction name=fun1
cfset fun1 = HI
/cfunction

OR 
cfoutput#fun1()#/cfoutput
cfset fun1 = George
cfoutput#fun1()#/cfoutput

I suspect something closer to the former issue from what you have described.


--
Ian Skinner
Web Programmer
BloodSource
www.BloodSource.org
Sacramento, CA

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RE: Calling the same UDF twice..

2006-06-09 Thread Ian Skinner
Here is the actual function:
cffunction name=updateUser

cfquery name=updateUser datasource=xxx

And here is your problem.  After the cfquery line the variable updateUser is 
a recordSet not a function.


--
Ian Skinner
Web Programmer
BloodSource
www.BloodSource.org
Sacramento, CA

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RE: Calling the same UDF twice..

2006-06-09 Thread Ian Skinner
cffunction name=updateUser
.
cfquery name=updateUser datasource=xxx

And here is your problem.  After the cfquery line the variable updateUser is 
a recordSet not a function.

And a solution, other then changing the query name is you can use local 
variable.

cffunction name=updateUser
cfargument 
cfargument ...

cfset var updateUser = 
.
cfquery name=updateUser datasource=xxx

This should create the existence of an updateUser local to the function that is 
different then the update use in the pages variables scope.  Not sure this is 
the best way to solve this problem, but it is a good idea to var scope any 
variables used inside of functions to prevent this kind of problem.

--
Ian Skinner
Web Programmer
BloodSource
www.BloodSource.org
Sacramento, CA

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