Re: (ot) jQuery Select

[Dakota Burns]

Tested a bit more this AM -- thanks Matt! Works as you specified.
Appreciate the help!

~ Dakota

On Wednesday, June 5, 2013, Matt Quackenbush wrote:

>
> First you're telling the window to move to the new URL before the submit
> line. This means that the submit is never reached in the processing cycle.
>
> Next, when you remove the location change, "nothing happens" because you're
> explicitly saying to do nothing. Remove the function from the submit() and
> watch the magic take place.
>
> HTH
>
> Sent from a mobile something
> On Jun 5, 2013 12:31 PM, "Dakota Burns" >
> wrote:
>
> >
> > I am trying to use an HTML Select form component to select & go to a URL.
> > I'm using the attached jQuery to accomplish this. The selection opens a
> new
> > window to the intended URL but the submit function doesn't post the
> hidden
> > name/value pairs. I suspect my syntax is a bit in conflict since the
> submit
> > function isn't working as expected. When I pull the window.location
> nothing
> > happens.
> >
> > After googling "jquery select post" and related combinations, I haven't
> > solved this one yet so thought I'd check here since CF programmers
> > frequently use jQuery.
> >
> > Thanks in advance.
> >
> >  
> >   $(function(){
> >$('##dynamic_select').bind('change', function(){
> > var url = $(this).val();
> > if(url){
> >  window.location = url;
> >  $("##myForm")
> >   .attr("action", url)
> >   .attr("target", "_blank")
> >   .submit(function(){return false;});
> > }
> > return false;
> >});
> >   });
> > 
> >
> > 
> > 
> >
> > 
> > Navigate too ...
> > Library
> > School
> > History
> > 
> >
> > 
> >
> >
> >
>
> 

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Re: (ot) jQuery Select

[Dakota Burns]

Thanks for the response ... doesn't work as I'd hoped.


On Wed, Jun 5, 2013 at 12:41 PM, Matt Quackenbush wrote:

>
> First you're telling the window to move to the new URL before the submit
> line. This means that the submit is never reached in the processing cycle.
>
> Next, when you remove the location change, "nothing happens" because you're
> explicitly saying to do nothing. Remove the function from the submit() and
> watch the magic take place.
>
> HTH
>
> Sent from a mobile something
> On Jun 5, 2013 12:31 PM, "Dakota Burns"  wrote:
>
> >
> > I am trying to use an HTML Select form component to select & go to a URL.
> > I'm using the attached jQuery to accomplish this. The selection opens a
> new
> > window to the intended URL but the submit function doesn't post the
> hidden
> > name/value pairs. I suspect my syntax is a bit in conflict since the
> submit
> > function isn't working as expected. When I pull the window.location
> nothing
> > happens.
> >
> > After googling "jquery select post" and related combinations, I haven't
> > solved this one yet so thought I'd check here since CF programmers
> > frequently use jQuery.
> >
> > Thanks in advance.
> >
> >  
> >   $(function(){
> >$('##dynamic_select').bind('change', function(){
> > var url = $(this).val();
> > if(url){
> >  window.location = url;
> >  $("##myForm")
> >   .attr("action", url)
> >   .attr("target", "_blank")
> >   .submit(function(){return false;});
> > }
> > return false;
> >});
> >   });
> > 
> >
> > 
> > 
> >
> > 
> > Navigate too ...
> > Library
> > School
> > History
> > 
> >
> > 
> >
> >
> >
>
> 

~|
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Re: (ot) jQuery Select

[Matt Quackenbush]

First you're telling the window to move to the new URL before the submit
line. This means that the submit is never reached in the processing cycle.

Next, when you remove the location change, "nothing happens" because you're
explicitly saying to do nothing. Remove the function from the submit() and
watch the magic take place.

HTH

Sent from a mobile something
On Jun 5, 2013 12:31 PM, "Dakota Burns"  wrote:

>
> I am trying to use an HTML Select form component to select & go to a URL.
> I'm using the attached jQuery to accomplish this. The selection opens a new
> window to the intended URL but the submit function doesn't post the hidden
> name/value pairs. I suspect my syntax is a bit in conflict since the submit
> function isn't working as expected. When I pull the window.location nothing
> happens.
>
> After googling "jquery select post" and related combinations, I haven't
> solved this one yet so thought I'd check here since CF programmers
> frequently use jQuery.
>
> Thanks in advance.
>
>  
>   $(function(){
>$('##dynamic_select').bind('change', function(){
> var url = $(this).val();
> if(url){
>  window.location = url;
>  $("##myForm")
>   .attr("action", url)
>   .attr("target", "_blank")
>   .submit(function(){return false;});
> }
> return false;
>});
>   });
> 
>
> 
> 
>
> 
> Navigate too ...
> Library
> School
> History
> 
>
> 
>
>
> 

~|
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RE: (ot) jQuery Facebook Wall Display

[Justin Scott]

> Are you looking for the "Recent Activity" as shown on this site:
> http://www.campuscircle.com/

Not exactly.  That plugin shows what other people are doing with the content
on the site (i.e. so-and-so shared such-and-such page) and would be
customized to the visitor if they were logged in to Facebook and one of
their friends had shared something on the site.

The client in this case is looking to have their wall posts (status updates
and the like) show up on the page similar to how people post their own
Twitter posts on their site.  I'm baffled, but there doesn't seem to be
anything out there that does this.  The data is all available through the
graph API and we're "this close" to rolling our own.  Thanks for looking
though.


-Justin



~|
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Re: (ot) jQuery Facebook Wall Display

[Dan O'Keefe]

Justin,

Are you looking for the "Recent Activity" as shown on this site:
http://www.campuscircle.com/

Dan


On Tue, Jan 4, 2011 at 8:04 AM, Justin Scott  wrote:

>
> Is anyone aware of a jQuery plugin (or script which uses jQuery) to pull a
> Facebook feed from their graph API and display it on the page in a manner
> similar to how the Facebook wall is displayed?  We have a client who would
> like to display a "Facebook stream" on their home page similar to how many
> people display their Twitter feed on their home pages.  Unfortunately it
> appears as though all of the social plugins that Facebook makes available
> revolve around the "like" button or showing what a visitor's friends have
> liked or shared on a site.  Essentially they want to take what they post to
> their wall and have it show up on their homepage as well.  Any suggestions?
> My Google-fu is failing me this morning.
>
>
> -Justin
>
>
>
> PS: Yes, we can roll our own but would prefer something we can drop in
> before we spend a lot of time reinventing the wheel if it exists somewhere
> already.  Thanks!
>
>
> 

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RE: (ot) jQuery question

[Rick Faircloth]

Thanks, Matt! :o)

Rick

-Original Message-
From: Matt Quackenbush [mailto:quackfu...@gmail.com] 
Sent: Sunday, December 12, 2010 12:45 PM
To: cf-talk
Subject: Re: (ot) jQuery question


In Charlie's example, 'i' is the current index position of the each loop,
while 'o' is the current item (or object) of the index.  And yes, they are
arguments passed into the function.




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RE: (ot) jQuery question

[Rick Faircloth]

Thanks, Charlie.

I couldn't see why the other code wouldn't work
properly either.

But I'm glad to be making some progress! :o)

Rick

-Original Message-
From: Charlie Griefer [mailto:charlie.grie...@gmail.com] 
Sent: Sunday, December 12, 2010 12:45 PM
To: cf-talk
Subject: Re: (ot) jQuery question


You don't need the i or o arguments for the code I posted.  They were
remnants from copying your original code.

>From the docs (http://api.jquery.com/each/):

.each( function(index, Element) )

so the first argument is the index.  .each() is looping over an array
(the array of selected DOM elements), so for each iteration, 'i' (or
whatever argument you declare) would be the position in the array of
the current element.

The second argument is the element itself, which can optionally be
passed in.  Not sure why I couldn't get it to work using "o" rather
than creating a new instance of $( this ) for each iteration... I'd
imagine passing the element in would be more performant, but probably
not enough of a difference to be noticeable.

On Sun, Dec 12, 2010 at 10:32 AM, Rick Faircloth
 wrote:
>
> Thanks, Charlie!  That gives me the correct output.
> Now I can move on to the AJAX, JSON, and CF CFC processing
> of data.
>
> Would you be so kind as to actually explain what function
> the "i" and "o" play in "function(i,o)" ?  They're variables/values
> passed into the function, right?
>
> I tested their necessity by taking them out of your
> code and just using function() instead of function(i,o)
> and the code still ran the same.  And even some of the
> example code I found performing this kind of functionality for lists
> used both i and o in the (), but only referenced the "o"
> in the actual function.
>
> I've always been confused about the role these variables
> playing in function(i,o) and whatever was in the ().
> Does the first argument (in this case, "i") always mean something
> specific because it's in the first argument position?  And the
> same with the variable that's in the second position?
>
> I scoured the Internet trying to get a good explanation of using
> these arguments, but haven't found what I needed to understand.
>
> Thanks for any insight you'd share!
>
> Rick
>
>
> -Original Message-
> From: Charlie Griefer [mailto:charlie.grie...@gmail.com]
> Sent: Saturday, December 11, 2010 10:51 PM
> To: cf-talk
> Subject: Re: (ot) jQuery question
>
>
> You're missing a # in your selector for #myTable.
> Even with the #, couldn't get your code to run... but the following
> seems to work:
>
> $( document ).ready( function() {
>        var staffOrder = "";
>
>        $( '#myTable tr' ).each( function( i,o ) {
>                if ( staffOrder.length ) {
>                        staffOrder += "," + $( this ).attr( 'class' );
>                } else {
>                        staffOrder = $( this ).attr( 'class' );
>                }
>        });
>
>        alert('staffOrder = ' + staffOrder);
> });
>
> On Sat, Dec 11, 2010 at 8:36 PM, Rick Faircloth
>  wrote:
>>
>> Hope some of you jQuery and CF users can answer what
>> seems to me should be an easy question, but I can't
>> figure out how to write this jQuery to product a list
>> of values.  (I'll use AJAX and JSON to send the value list
>> to a cffunction for processing).
>>
>> Given this HTML:
>>
>>        
>>
>>                
>>                        1
>>                
>>
>>                
>>                        2
>>                
>>
>>                
>>                        3
>>                
>>
>>                
>>                        4
>>                
>>
>>                
>>                        5
>>                
>>
>>        
>>
>> How can I modify this jQuery to produce
>> a list of the classes of the tr's above?
>>
>> (Output I'm looking for is "1,2,3,4,5" .)
>>
>> I get "staffOrder = " in the alert.  It's as if
>> the "each" function below isn't working at all.
>>
>> Suggestions?
>>
>> Thanks!
>>
>> Rick
>>
>>
>>        $(document).ready(function() {
>>
>>                var staffOrder = '';
>>
>>                $('myTable tr').each(function(i,o) {
>>
>>                        if      (       staffOrder.length
>> )
>>                                {       staffOrder += ',' + o.class;
>> }
>>                        else    {       staffOrder = o.class
>> }
>>
>>                });
>>
>>                alert('staffOrder = ' + staffOrder);
>>
>>        });
>>
>>
>>
>>
>>
>>
>
>
>
> 



~|
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RE: (ot) jQuery question

[Rick Faircloth]

Thanks for the link, Raj.

After I work through those examples, it looks
like the use of those variable should be clear.
(Or at least clearer!) :o)

Rick

-Original Message-
From: Raj Vijay [mailto:vraajku...@rediffmail.com] 
Sent: Sunday, December 12, 2010 12:36 PM
To: cf-talk
Subject: Re: (ot) jQuery question


Hi Rick,
 Take a look at the following jQuery Doc link http://api.jquery.com/each/
The order of the parameters matter. 



~|
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Re: (ot) jQuery question

[Matt Quackenbush]

In Charlie's example, 'i' is the current index position of the each loop,
while 'o' is the current item (or object) of the index.  And yes, they are
arguments passed into the function.


~|
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Re: (ot) jQuery question

[Charlie Griefer]

You don't need the i or o arguments for the code I posted.  They were
remnants from copying your original code.

>From the docs (http://api.jquery.com/each/):

.each( function(index, Element) )

so the first argument is the index.  .each() is looping over an array
(the array of selected DOM elements), so for each iteration, 'i' (or
whatever argument you declare) would be the position in the array of
the current element.

The second argument is the element itself, which can optionally be
passed in.  Not sure why I couldn't get it to work using "o" rather
than creating a new instance of $( this ) for each iteration... I'd
imagine passing the element in would be more performant, but probably
not enough of a difference to be noticeable.

On Sun, Dec 12, 2010 at 10:32 AM, Rick Faircloth
 wrote:
>
> Thanks, Charlie!  That gives me the correct output.
> Now I can move on to the AJAX, JSON, and CF CFC processing
> of data.
>
> Would you be so kind as to actually explain what function
> the "i" and "o" play in "function(i,o)" ?  They're variables/values
> passed into the function, right?
>
> I tested their necessity by taking them out of your
> code and just using function() instead of function(i,o)
> and the code still ran the same.  And even some of the
> example code I found performing this kind of functionality for lists
> used both i and o in the (), but only referenced the "o"
> in the actual function.
>
> I've always been confused about the role these variables
> playing in function(i,o) and whatever was in the ().
> Does the first argument (in this case, "i") always mean something
> specific because it's in the first argument position?  And the
> same with the variable that's in the second position?
>
> I scoured the Internet trying to get a good explanation of using
> these arguments, but haven't found what I needed to understand.
>
> Thanks for any insight you'd share!
>
> Rick
>
>
> -Original Message-
> From: Charlie Griefer [mailto:charlie.grie...@gmail.com]
> Sent: Saturday, December 11, 2010 10:51 PM
> To: cf-talk
> Subject: Re: (ot) jQuery question
>
>
> You're missing a # in your selector for #myTable.
> Even with the #, couldn't get your code to run... but the following
> seems to work:
>
> $( document ).ready( function() {
>        var staffOrder = "";
>
>        $( '#myTable tr' ).each( function( i,o ) {
>                if ( staffOrder.length ) {
>                        staffOrder += "," + $( this ).attr( 'class' );
>                } else {
>                        staffOrder = $( this ).attr( 'class' );
>                }
>        });
>
>        alert('staffOrder = ' + staffOrder);
> });
>
> On Sat, Dec 11, 2010 at 8:36 PM, Rick Faircloth
>  wrote:
>>
>> Hope some of you jQuery and CF users can answer what
>> seems to me should be an easy question, but I can't
>> figure out how to write this jQuery to product a list
>> of values.  (I'll use AJAX and JSON to send the value list
>> to a cffunction for processing).
>>
>> Given this HTML:
>>
>>        
>>
>>                
>>                        1
>>                
>>
>>                
>>                        2
>>                
>>
>>                
>>                        3
>>                
>>
>>                
>>                        4
>>                
>>
>>                
>>                        5
>>                
>>
>>        
>>
>> How can I modify this jQuery to produce
>> a list of the classes of the tr's above?
>>
>> (Output I'm looking for is "1,2,3,4,5" .)
>>
>> I get "staffOrder = " in the alert.  It's as if
>> the "each" function below isn't working at all.
>>
>> Suggestions?
>>
>> Thanks!
>>
>> Rick
>>
>>
>>        $(document).ready(function() {
>>
>>                var staffOrder = '';
>>
>>                $('myTable tr').each(function(i,o) {
>>
>>                        if      (       staffOrder.length
>> )
>>                                {       staffOrder += ',' + o.class;
>> }
>>                        else    {       staffOrder = o.class
>> }
>>
>>                });
>>
>>                alert('staffOrder = ' + staffOrder);
>>
>>        });
>>
>>
>>
>>
>>
>>
>
>
>
> 

~|
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Re: (ot) jQuery question

[Raj Vijay]

Hi Rick,
 Take a look at the following jQuery Doc link http://api.jquery.com/each/
The order of the parameters matter. 

~|
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RE: (ot) jQuery question

[Rick Faircloth]

Thanks, Charlie!  That gives me the correct output.
Now I can move on to the AJAX, JSON, and CF CFC processing
of data.

Would you be so kind as to actually explain what function
the "i" and "o" play in "function(i,o)" ?  They're variables/values
passed into the function, right?

I tested their necessity by taking them out of your
code and just using function() instead of function(i,o)
and the code still ran the same.  And even some of the
example code I found performing this kind of functionality for lists
used both i and o in the (), but only referenced the "o"
in the actual function.

I've always been confused about the role these variables
playing in function(i,o) and whatever was in the ().
Does the first argument (in this case, "i") always mean something
specific because it's in the first argument position?  And the
same with the variable that's in the second position?

I scoured the Internet trying to get a good explanation of using
these arguments, but haven't found what I needed to understand.

Thanks for any insight you'd share!

Rick


-Original Message-
From: Charlie Griefer [mailto:charlie.grie...@gmail.com] 
Sent: Saturday, December 11, 2010 10:51 PM
To: cf-talk
Subject: Re: (ot) jQuery question


You're missing a # in your selector for #myTable.
Even with the #, couldn't get your code to run... but the following
seems to work:

$( document ).ready( function() {
var staffOrder = "";

$( '#myTable tr' ).each( function( i,o ) {
if ( staffOrder.length ) {
staffOrder += "," + $( this ).attr( 'class' );
} else {
staffOrder = $( this ).attr( 'class' );
}
});

alert('staffOrder = ' + staffOrder);
});

On Sat, Dec 11, 2010 at 8:36 PM, Rick Faircloth
 wrote:
>
> Hope some of you jQuery and CF users can answer what
> seems to me should be an easy question, but I can't
> figure out how to write this jQuery to product a list
> of values.  (I'll use AJAX and JSON to send the value list
> to a cffunction for processing).
>
> Given this HTML:
>
>        
>
>                
>                        1
>                
>
>                
>                        2
>                
>
>                
>                        3
>                
>
>                
>                        4
>                
>
>                
>                        5
>                
>
>        
>
> How can I modify this jQuery to produce
> a list of the classes of the tr's above?
>
> (Output I'm looking for is "1,2,3,4,5" .)
>
> I get "staffOrder = " in the alert.  It's as if
> the "each" function below isn't working at all.
>
> Suggestions?
>
> Thanks!
>
> Rick
>
>
>        $(document).ready(function() {
>
>                var staffOrder = '';
>
>                $('myTable tr').each(function(i,o) {
>
>                        if      (       staffOrder.length
> )
>                                {       staffOrder += ',' + o.class;
> }
>                        else    {       staffOrder = o.class
> }
>
>                });
>
>                alert('staffOrder = ' + staffOrder);
>
>        });
>
>
>
>
>
> 



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Re: (ot) jQuery question

[Charlie Griefer]

You're missing a # in your selector for #myTable.
Even with the #, couldn't get your code to run... but the following
seems to work:

$( document ).ready( function() {
var staffOrder = "";

$( '#myTable tr' ).each( function( i,o ) {
if ( staffOrder.length ) {
staffOrder += "," + $( this ).attr( 'class' );
} else {
staffOrder = $( this ).attr( 'class' );
}
});

alert('staffOrder = ' + staffOrder);
});

On Sat, Dec 11, 2010 at 8:36 PM, Rick Faircloth
 wrote:
>
> Hope some of you jQuery and CF users can answer what
> seems to me should be an easy question, but I can't
> figure out how to write this jQuery to product a list
> of values.  (I'll use AJAX and JSON to send the value list
> to a cffunction for processing).
>
> Given this HTML:
>
>        
>
>                
>                        1
>                
>
>                
>                        2
>                
>
>                
>                        3
>                
>
>                
>                        4
>                
>
>                
>                        5
>                
>
>        
>
> How can I modify this jQuery to produce
> a list of the classes of the tr's above?
>
> (Output I'm looking for is "1,2,3,4,5" .)
>
> I get "staffOrder = " in the alert.  It's as if
> the "each" function below isn't working at all.
>
> Suggestions?
>
> Thanks!
>
> Rick
>
>
>        $(document).ready(function() {
>
>                var staffOrder = '';
>
>                $('myTable tr').each(function(i,o) {
>
>                        if      (       staffOrder.length
> )
>                                {       staffOrder += ',' + o.class;
> }
>                        else    {       staffOrder = o.class
> }
>
>                });
>
>                alert('staffOrder = ' + staffOrder);
>
>        });
>
>
>
>
>
> 

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Re: (ot) jQuery and char sets

[Dominic Watson]

Side track, and probably something you're doing already, but one little
trick is to explicitly disable debug output in these things (saves you time
going barmy when you/someone else uses cf debug output and your ajax stuff
stops working). I.e.




Dominic

On 10 December 2010 15:29, Rick Root  wrote:

>
> On Fri, Dec 10, 2010 at 10:23 AM, Rick Root  wrote:
>
> >
> > I have a jquery.getJSON() call that is failing to call the result handler
> > when the JSON dataset being returned contains an ASCII 132 character (an
> > "e"
> > with a backtick above it) ... in this case, it's part of someones last
> > name.
> >
> > It's not generating any kind of javascript error either.. the json data
> is
> > being returned, jquery just either isn't dealing with it or is failing
> > silently (as jquery is known to do)
> >
> > What should I do here?
> >
> >
> Well Rick, that's easy.. just set your content type you're returning like
> this!
>
> 
>
> You sound very smart, why didn't you just google this first?
>
> Rick
>
>
> 

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Re: (ot) jQuery and char sets

[Rick Root]

On Fri, Dec 10, 2010 at 10:41 AM, Marc Funaro wrote:

>
> >You sound very smart, why didn't you just google this first?
>
> Called out and thrown under the bus ("no disrespect"):)
>

Yeah, but I threw myself under the bus there ;)  Suicide?


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Re: (ot) jQuery and char sets

[Marc Funaro]

>You sound very smart, why didn't you just google this first?

Called out and thrown under the bus ("no disrespect"):) 

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Re: (ot) jQuery and char sets

[Rick Root]

On Fri, Dec 10, 2010 at 10:23 AM, Rick Root  wrote:

>
> I have a jquery.getJSON() call that is failing to call the result handler
> when the JSON dataset being returned contains an ASCII 132 character (an
> "e"
> with a backtick above it) ... in this case, it's part of someones last
> name.
>
> It's not generating any kind of javascript error either.. the json data is
> being returned, jquery just either isn't dealing with it or is failing
> silently (as jquery is known to do)
>
> What should I do here?
>
>
Well Rick, that's easy.. just set your content type you're returning like
this!



You sound very smart, why didn't you just google this first?

Rick


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Re: (ot) jQuery get() and 401 Unauthorized

[Tony Bentley]

Nice Dave, not only did you answer the question but you also interpreted
incorrect acronyms. :)


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Re: (ot) jQuery get() and 401 Unauthorized

[Dave Watts]

> Has anyone seen this?  I have some jQuery that is runninga get() to a cold 
> fusion page.
>
> The website is locked down with an NTFS user because it isunder development 
> and we don't want the public to get in yet.
>
> On most calls to this get() in Firebug I see three "401Unauthorized" errors.  
> The get() works and I get the data from thecoldfusion page.
> Sometimes I get a "200 OK", it is not very consistent.
>
> This does not happen on my development site, but it does nothave an NTFS user 
> locking down the site.  Anonymous users are allowed in.
>
> These three errors are slowing down the page and making mycode look bad to 
> the customer.

If your code isn't designed to work within an authenticated
environment, you probably shouldn't be testing it within an
authenticated environment. There are lots of other ways you can limit
access to development environments.

But anyway, you need to make sure that the user authenticates against
the server before any of the AJAX requests are made. The browser won't
typically prompt a user for credentials for an AJAX request, it'll
just fail with a 401 response. You should be able to see the
appropriate authorization header from the browser for all requests
made, by using a tool like Firebug.

Also, you need to make sure that permissions have been properly
applied on the server - it may be the case that the user account in
question has permission to make some requests but not others.

Dave Watts, CTO, Fig Leaf Software
http://www.figleaf.com/
http://training.figleaf.com/

Fig Leaf Software is a Veteran-Owned Small Business (VOSB) on
GSA Schedule, and provides the highest caliber vendor-authorized
instruction at our training centers, online, or ons

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Re: (ot) jQuery get() and 401 Unauthorized

[Dave Watts]

> What is an NTFS user? NTFS is a file system format, which has nothing to do
> with user permissions. Do you mean to say that you are mapped to a NTFS
> drive like an external hard disk?

No, the original poster means NTLM (Windows authentication).

Dave Watts, CTO, Fig Leaf Software
http://www.figleaf.com/
http://training.figleaf.com/

Fig Leaf Software is a Veteran-Owned Small Business (VOSB) on
GSA Schedule, and provides the highest caliber vendor-authorized
instruction at our training centers, online, or onsite.

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Re: (ot) jQuery get() and 401 Unauthorized

[Tony Bentley]

What is an NTFS user? NTFS is a file system format, which has nothing to do
with user permissions. Do you mean to say that you are mapped to a NTFS
drive like an external hard disk?


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RE: (ot) jQuery

[Chad Gray]

Thanks Tony, your code looks a lot better than mine.  I will try it out.

Chad

-Original Message-
From: Tony Bentley [mailto:cascadefreehee...@gmail.com] 
Sent: Thursday, October 21, 2010 3:41 PM
To: cf-talk
Subject: Re: (ot) jQuery


Really, you need to detect when the image is finished loading completely.

Here, check out my source code: http://tonybentley.com/test/test.html




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Re: (ot) jQuery

[Tony Bentley]

Really, you need to detect when the image is finished loading completely.

Here, check out my source code: http://tonybentley.com/test/test.html


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RE: (ot) jQuery

[Chad Gray]

AH... son of gun...  You have to .hide() first.

$("#beautyImage").hide().html(data).fadeIn('slow');

Thanks for all the help guys.  I just needed to bounce this off someone.

Chad


-Original Message-
From: Chad Gray [mailto:cg...@careyweb.com] 
Sent: Thursday, October 21, 2010 3:00 PM
To: cf-talk
Subject: RE: (ot) jQuery


I mocked up some test code.  Just place an image "beautyImage1.jpg" in the same 
folder as the code.  The image is placed in the DIV but does not fade in.





function swapImages() {
$("#beautyImage").html('<img src="beautyImage1.jpg">').fadeIn('slow');
}












-Original Message-
From: Chad Gray [mailto:cg...@careyweb.com] 
Sent: Thursday, October 21, 2010 2:52 PM
To: cf-talk
Subject: RE: (ot) jQuery


If I do this it snaps into place also.  No fade in.

function swapImages(imageName) {
$("#beautyImage").html('').fadeIn('slow');
}



-Original Message-
From: Michael Grant [mailto:mgr...@modus.bz] 
Sent: Thursday, October 21, 2010 2:43 PM
To: cf-talk
Subject: Re: (ot) jQuery


I don't see why it wouldn't be. Does fadeIn() work if you do it on it's own?

On Thu, Oct 21, 2010 at 2:40 PM, Chad Gray  wrote:

>
> Thanks for the suggestions, but still now luck.  Maybe the get() is not
> compatible with fadeIn()?
>
>
>
> -Original Message-
> From: Tony Bentley [mailto:cascadefreehee...@gmail.com]
> Sent: Thursday, October 21, 2010 2:39 PM
> To: cf-talk
> Subject: Re: (ot) jQuery
>
>
> function swapImages(imageName) {
>$.get('/shop/act_getBeautyImage.cfm?beautyImage='+ imageName +
> '&width=372&height=465',{},function(data) {
>$("#beautyImage").html(data).fadeIn('slow');
>});
> }
>
>
>
>
> 







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RE: (ot) jQuery

[Chad Gray]

I mocked up some test code.  Just place an image "beautyImage1.jpg" in the same 
folder as the code.  The image is placed in the DIV but does not fade in.





function swapImages() {
$("#beautyImage").html('<img src="beautyImage1.jpg">').fadeIn('slow');
}












-Original Message-
From: Chad Gray [mailto:cg...@careyweb.com] 
Sent: Thursday, October 21, 2010 2:52 PM
To: cf-talk
Subject: RE: (ot) jQuery


If I do this it snaps into place also.  No fade in.

function swapImages(imageName) {
$("#beautyImage").html('').fadeIn('slow');
}



-Original Message-
From: Michael Grant [mailto:mgr...@modus.bz] 
Sent: Thursday, October 21, 2010 2:43 PM
To: cf-talk
Subject: Re: (ot) jQuery


I don't see why it wouldn't be. Does fadeIn() work if you do it on it's own?

On Thu, Oct 21, 2010 at 2:40 PM, Chad Gray  wrote:

>
> Thanks for the suggestions, but still now luck.  Maybe the get() is not
> compatible with fadeIn()?
>
>
>
> -Original Message-
> From: Tony Bentley [mailto:cascadefreehee...@gmail.com]
> Sent: Thursday, October 21, 2010 2:39 PM
> To: cf-talk
> Subject: Re: (ot) jQuery
>
>
> function swapImages(imageName) {
>$.get('/shop/act_getBeautyImage.cfm?beautyImage='+ imageName +
> '&width=372&height=465',{},function(data) {
>$("#beautyImage").html(data).fadeIn('slow');
>});
> }
>
>
>
>
> 





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Re: (ot) jQuery

[Michael Grant]

What about this:

function swapImages(imageName) {

$("#beautyImage").html('textaroo').fadeIn('slow');

}

On Thu, Oct 21, 2010 at 2:52 PM, Chad Gray  wrote:

>
> If I do this it snaps into place also.  No fade in.
>
> function swapImages(imageName) {
> $("#beautyImage").html(' src="/output/9305B06559F4D04C37ED27103EBFB959.jpg"
> style="margin-left:5px;">').fadeIn('slow');
> }
>
>
>
> -Original Message-
> From: Michael Grant [mailto:mgr...@modus.bz]
> Sent: Thursday, October 21, 2010 2:43 PM
> To: cf-talk
> Subject: Re: (ot) jQuery
>
>
> I don't see why it wouldn't be. Does fadeIn() work if you do it on it's
> own?
>
> On Thu, Oct 21, 2010 at 2:40 PM, Chad Gray  wrote:
>
> >
> > Thanks for the suggestions, but still now luck.  Maybe the get() is not
> > compatible with fadeIn()?
> >
> >
> >
> > -Original Message-
> > From: Tony Bentley [mailto:cascadefreehee...@gmail.com]
> > Sent: Thursday, October 21, 2010 2:39 PM
> > To: cf-talk
> > Subject: Re: (ot) jQuery
> >
> >
> > function swapImages(imageName) {
> >$.get('/shop/act_getBeautyImage.cfm?beautyImage='+ imageName +
> > '&width=372&height=465',{},function(data) {
> >$("#beautyImage").html(data).fadeIn('slow');
> >});
> > }
> >
> >
> >
> >
> >
>
>
>
> 

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RE: (ot) jQuery

[Chad Gray]

If I do this it snaps into place also.  No fade in.

function swapImages(imageName) {
$("#beautyImage").html('').fadeIn('slow');
}



-Original Message-
From: Michael Grant [mailto:mgr...@modus.bz] 
Sent: Thursday, October 21, 2010 2:43 PM
To: cf-talk
Subject: Re: (ot) jQuery


I don't see why it wouldn't be. Does fadeIn() work if you do it on it's own?

On Thu, Oct 21, 2010 at 2:40 PM, Chad Gray  wrote:

>
> Thanks for the suggestions, but still now luck.  Maybe the get() is not
> compatible with fadeIn()?
>
>
>
> -Original Message-
> From: Tony Bentley [mailto:cascadefreehee...@gmail.com]
> Sent: Thursday, October 21, 2010 2:39 PM
> To: cf-talk
> Subject: Re: (ot) jQuery
>
>
> function swapImages(imageName) {
>$.get('/shop/act_getBeautyImage.cfm?beautyImage='+ imageName +
> '&width=372&height=465',{},function(data) {
>$("#beautyImage").html(data).fadeIn('slow');
>});
> }
>
>
>
>
> 



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RE: (ot) jQuery

[Chad Gray]

Basically the action page is using a function I built to resize the image then 
display the image in a  tag.













-Original Message-
From: Tony Bentley [mailto:cascadefreehee...@gmail.com] 
Sent: Thursday, October 21, 2010 2:44 PM
To: cf-talk
Subject: Re: (ot) jQuery


Show the code on your request page. It's probably because you need an event
to fire from the request page after the image is finished loading.




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Re: (ot) jQuery

[Tony Bentley]

Show the code on your request page. It's probably because you need an event
to fire from the request page after the image is finished loading.


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Re: (ot) jQuery

[Michael Grant]

I don't see why it wouldn't be. Does fadeIn() work if you do it on it's own?

On Thu, Oct 21, 2010 at 2:40 PM, Chad Gray  wrote:

>
> Thanks for the suggestions, but still now luck.  Maybe the get() is not
> compatible with fadeIn()?
>
>
>
> -Original Message-
> From: Tony Bentley [mailto:cascadefreehee...@gmail.com]
> Sent: Thursday, October 21, 2010 2:39 PM
> To: cf-talk
> Subject: Re: (ot) jQuery
>
>
> function swapImages(imageName) {
>$.get('/shop/act_getBeautyImage.cfm?beautyImage='+ imageName +
> '&width=372&height=465',{},function(data) {
>$("#beautyImage").html(data).fadeIn('slow');
>});
> }
>
>
>
>
> 

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RE: (ot) jQuery

[Chad Gray]

Thanks for the suggestions, but still now luck.  Maybe the get() is not 
compatible with fadeIn()?



-Original Message-
From: Tony Bentley [mailto:cascadefreehee...@gmail.com] 
Sent: Thursday, October 21, 2010 2:39 PM
To: cf-talk
Subject: Re: (ot) jQuery


function swapImages(imageName) {
$.get('/shop/act_getBeautyImage.cfm?beautyImage='+ imageName +
'&width=372&height=465',{},function(data) {
$("#beautyImage").html(data).fadeIn('slow');
});
}




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Re: (ot) jQuery

[Tony Bentley]

function swapImages(imageName) {
$.get('/shop/act_getBeautyImage.cfm?beautyImage='+ imageName +
'&width=372&height=465',{},function(data) {
$("#beautyImage").html(data).fadeIn('slow');
});
}


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RE: (ot) jQuery

[Chad Gray]

I tried that also.  Still no luck.



-Original Message-
From: Michael Grant [mailto:mgr...@modus.bz] 
Sent: Thursday, October 21, 2010 2:31 PM
To: cf-talk
Subject: Re: (ot) jQuery


Perhaps try changing your chain.

$("#beautyImage").html(data).show('slow');


On Thu, Oct 21, 2010 at 2:29 PM, Chad Gray  wrote:

>
> Ya I tried fadeIn() also, but the image just snaps into place.  It does not
> fade in slowly.
>
> -Original Message-
> From: Michael Grant [mailto:mgr...@modus.bz]
> Sent: Thursday, October 21, 2010 2:27 PM
> To: cf-talk
> Subject: Re: (ot) jQuery
>
>
> http://api.jquery.com/fadeIn/
> <http://api.jquery.com/fadeIn/>
>
> On Thu, Oct 21, 2010 at 2:23 PM, Chad Gray  wrote:
>
> >
> > I am trying to write some jQuery that will go get a resizedimage from a
> CF
> > page then show that data in a div (#beautyImage) slowly.  Iwant it to
> fade
> > in.
> >
> > This works, but it does not fade in.  I just quicklyreplaces the image.
> >
> > 
> > function swapImages(imageName) {
> >$.get('/shop/act_getBeautyImage.cfm?beautyImage='+
> imageName
> > + '&width=372&height=465',{},
> >  function(data,status) {
> >
> > $("#beautyImage").show('slow').html(data);
> >  });
> > }
> > 
> >
> > Any suggestions?
> >
> > Thanks
> > Chad
> >
> >
>
>
>
> 



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Re: (ot) jQuery

[Michael Grant]

Perhaps try changing your chain.

$("#beautyImage").html(data).show('slow');


On Thu, Oct 21, 2010 at 2:29 PM, Chad Gray  wrote:

>
> Ya I tried fadeIn() also, but the image just snaps into place.  It does not
> fade in slowly.
>
> -Original Message-
> From: Michael Grant [mailto:mgr...@modus.bz]
> Sent: Thursday, October 21, 2010 2:27 PM
> To: cf-talk
> Subject: Re: (ot) jQuery
>
>
> http://api.jquery.com/fadeIn/
> <http://api.jquery.com/fadeIn/>
>
> On Thu, Oct 21, 2010 at 2:23 PM, Chad Gray  wrote:
>
> >
> > I am trying to write some jQuery that will go get a resizedimage from a
> CF
> > page then show that data in a div (#beautyImage) slowly.  Iwant it to
> fade
> > in.
> >
> > This works, but it does not fade in.  I just quicklyreplaces the image.
> >
> > 
> > function swapImages(imageName) {
> >$.get('/shop/act_getBeautyImage.cfm?beautyImage='+
> imageName
> > + '&width=372&height=465',{},
> >  function(data,status) {
> >
> > $("#beautyImage").show('slow').html(data);
> >  });
> > }
> > 
> >
> > Any suggestions?
> >
> > Thanks
> > Chad
> >
> >
>
>
>
> 

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RE: (ot) jQuery

[Chad Gray]

Ya I tried fadeIn() also, but the image just snaps into place.  It does not 
fade in slowly.

-Original Message-
From: Michael Grant [mailto:mgr...@modus.bz] 
Sent: Thursday, October 21, 2010 2:27 PM
To: cf-talk
Subject: Re: (ot) jQuery


http://api.jquery.com/fadeIn/
<http://api.jquery.com/fadeIn/>

On Thu, Oct 21, 2010 at 2:23 PM, Chad Gray  wrote:

>
> I am trying to write some jQuery that will go get a resizedimage from a CF
> page then show that data in a div (#beautyImage) slowly.  Iwant it to fade
> in.
>
> This works, but it does not fade in.  I just quicklyreplaces the image.
>
> 
> function swapImages(imageName) {
>$.get('/shop/act_getBeautyImage.cfm?beautyImage='+ imageName
> + '&width=372&height=465',{},
>  function(data,status) {
>
> $("#beautyImage").show('slow').html(data);
>  });
> }
> 
>
> Any suggestions?
>
> Thanks
> Chad
>
> 



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Re: (ot) jQuery

[Michael Grant]

http://api.jquery.com/fadeIn/


On Thu, Oct 21, 2010 at 2:23 PM, Chad Gray  wrote:

>
> I am trying to write some jQuery that will go get a resizedimage from a CF
> page then show that data in a div (#beautyImage) slowly.  Iwant it to fade
> in.
>
> This works, but it does not fade in.  I just quicklyreplaces the image.
>
> 
> function swapImages(imageName) {
>$.get('/shop/act_getBeautyImage.cfm?beautyImage='+ imageName
> + '&width=372&height=465',{},
>  function(data,status) {
>
> $("#beautyImage").show('slow').html(data);
>  });
> }
> 
>
> Any suggestions?
>
> Thanks
> Chad
>
> 

~|
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