cutting: aabbcc0000

2005-10-11 Thread Uwe Degenhardt
Hi list I
have a value in a db-field like
aabbcc
and I always want
to cut the leading nulls
on the right to get: aabbcc, but only the
four nulls, how can I do this ?
There must be a regular expression
for this, but I can't remember.
Uwe



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RE: cutting: aabbcc0000

2005-10-11 Thread Michael T. Tangorre
 From: Uwe Degenhardt [mailto:[EMAIL PROTECTED] 
 Hi list I
 have a value in a db-field like
 aabbcc
 and I always want
 to cut the leading nulls
 on the right to get: aabbcc, but only the four nulls, how 
 can I do this ?
 There must be a regular expression
 for this, but I can't remember.
 Uwe

Left(string, count)

so...

Left(yourField,6)




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RE: cutting: aabbcc0000

2005-10-11 Thread Robertson-Ravo, Neil (RX)
You mean trailing zeros?  Would they always be trailing? And would there
always be 4?


-Original Message-
From: Uwe Degenhardt [mailto:[EMAIL PROTECTED] 
Sent: 11 October 2005 13:25
To: CF-Talk
Subject: cutting: aabbcc

Hi list I
have a value in a db-field like
aabbcc
and I always want
to cut the leading nulls
on the right to get: aabbcc, but only the
four nulls, how can I do this ?
There must be a regular expression
for this, but I can't remember.
Uwe





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Re[2]: cutting: aabbcc0000

2005-10-11 Thread Uwe Degenhardt
Hello Michael,

Tuesday, October 11, 2005, 2:33:09 PM, you wrote:

 From: Uwe Degenhardt [mailto:[EMAIL PROTECTED] 
 Hi list I
 have a value in a db-field like
 aabbcc
 and I always want
 to cut the leading nulls
 on the right to get: aabbcc, but only the four nulls, how 
 can I do this ?
 There must be a regular expression
 for this, but I can't remember.
 Uwe

MTT Left(string, count)

MTT so...

MTT Left(yourField,6)




MTT 

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RE: cutting: aabbcc0000

2005-10-11 Thread Matthew Small
str = aabbcc


#reverse(right(reverse(str),len(str)-(ReFind(0[^0],reverse(str)#

This will remove all nulls from the right. 

Perhaps there's a more elegant way, but I don't know it.

 
Matthew Small
Web Developer
American City Business Journals
704-973-1045
[EMAIL PROTECTED]
 

-Original Message-
From: Uwe Degenhardt [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, October 11, 2005 8:25 AM
To: CF-Talk
Subject: cutting: aabbcc

Hi list I
have a value in a db-field like
aabbcc
and I always want
to cut the leading nulls
on the right to get: aabbcc, but only the four nulls, how can I do this ?
There must be a regular expression
for this, but I can't remember.
Uwe





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RE: cutting: aabbcc0000

2005-10-11 Thread Matthew Small
Also, one caveat - if the string itself has a length of 0, it will throw an
error.

 
Matthew Small
Web Developer
American City Business Journals
704-973-1045
[EMAIL PROTECTED]
 

-Original Message-
From: Matthew Small [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, October 11, 2005 9:52 AM
To: CF-Talk
Subject: RE: cutting: aabbcc

str = aabbcc


#reverse(right(reverse(str),len(str)-(ReFind(0[^0],reverse(str)#

This will remove all nulls from the right. 

Perhaps there's a more elegant way, but I don't know it.

 
Matthew Small
Web Developer
American City Business Journals
704-973-1045
[EMAIL PROTECTED]
 

-Original Message-
From: Uwe Degenhardt [mailto:[EMAIL PROTECTED]
Sent: Tuesday, October 11, 2005 8:25 AM
To: CF-Talk
Subject: cutting: aabbcc

Hi list I
have a value in a db-field like
aabbcc
and I always want
to cut the leading nulls
on the right to get: aabbcc, but only the four nulls, how can I do this ?
There must be a regular expression
for this, but I can't remember.
Uwe







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application. Start tracking and documenting hours spent on a project or with a 
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RE: cutting: aabbcc0000

2005-10-11 Thread Dave Francis
Won't Rtrim() work?



-Original Message-
From: Matthew Small [mailto:[EMAIL PROTECTED]
Sent: Tuesday, October 11, 2005 10:00 AM
To: CF-Talk
Subject: RE: cutting: aabbcc


Also, one caveat - if the string itself has a length of 0, it will throw an
error.


Matthew Small
Web Developer
American City Business Journals
704-973-1045
[EMAIL PROTECTED]


-Original Message-
From: Matthew Small [mailto:[EMAIL PROTECTED]
Sent: Tuesday, October 11, 2005 9:52 AM
To: CF-Talk
Subject: RE: cutting: aabbcc

str = aabbcc


#reverse(right(reverse(str),len(str)-(ReFind(0[^0],reverse(str)#

This will remove all nulls from the right.

Perhaps there's a more elegant way, but I don't know it.


Matthew Small
Web Developer
American City Business Journals
704-973-1045
[EMAIL PROTECTED]


-Original Message-
From: Uwe Degenhardt [mailto:[EMAIL PROTECTED]
Sent: Tuesday, October 11, 2005 8:25 AM
To: CF-Talk
Subject: cutting: aabbcc

Hi list I
have a value in a db-field like
aabbcc
and I always want
to cut the leading nulls
on the right to get: aabbcc, but only the four nulls, how can I do this ?
There must be a regular expression
for this, but I can't remember.
Uwe









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application. Start tracking and documenting hours spent on a project or with a 
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RE: cutting: aabbcc0000

2005-10-11 Thread Munson, Jacob
Uew,

One of these removes all zeros from the string, the other removes all
zeros at the end of a string:

cfset myString = aa0bbb0ccc000
cfdump var=#myString#br
cfset removeTrailingZeros = ReReplace(myString,0+$,,all)
cfset removeAllZeros = Replace(myString,0,,all)
cfoutput#removeTrailingZeros#br#removeAllZeros#/cfoutput 

 -Original Message-
 From: Uwe Degenhardt [mailto:[EMAIL PROTECTED] 
 Sent: Tuesday, October 11, 2005 6:25 AM
 To: CF-Talk
 Subject: cutting: aabbcc
 
 Hi list I
 have a value in a db-field like
 aabbcc
 and I always want
 to cut the leading nulls
 on the right to get: aabbcc, but only the
 four nulls, how can I do this ?
 There must be a regular expression
 for this, but I can't remember.
 Uwe








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RE: cutting: aabbcc0000

2005-10-11 Thread Matthew Small
Rtrim only applies to spaces. 

 
Matthew Small
Web Developer
American City Business Journals
704-973-1045
[EMAIL PROTECTED]
 

-Original Message-
From: Dave Francis [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, October 11, 2005 10:39 AM
To: CF-Talk
Subject: RE: cutting: aabbcc

Won't Rtrim() work?



-Original Message-
From: Matthew Small [mailto:[EMAIL PROTECTED]
Sent: Tuesday, October 11, 2005 10:00 AM
To: CF-Talk
Subject: RE: cutting: aabbcc


Also, one caveat - if the string itself has a length of 0, it will throw an
error.


Matthew Small
Web Developer
American City Business Journals
704-973-1045
[EMAIL PROTECTED]


-Original Message-
From: Matthew Small [mailto:[EMAIL PROTECTED]
Sent: Tuesday, October 11, 2005 9:52 AM
To: CF-Talk
Subject: RE: cutting: aabbcc

str = aabbcc


#reverse(right(reverse(str),len(str)-(ReFind(0[^0],reverse(str)#

This will remove all nulls from the right.

Perhaps there's a more elegant way, but I don't know it.


Matthew Small
Web Developer
American City Business Journals
704-973-1045
[EMAIL PROTECTED]


-Original Message-
From: Uwe Degenhardt [mailto:[EMAIL PROTECTED]
Sent: Tuesday, October 11, 2005 8:25 AM
To: CF-Talk
Subject: cutting: aabbcc

Hi list I
have a value in a db-field like
aabbcc
and I always want
to cut the leading nulls
on the right to get: aabbcc, but only the four nulls, how can I do this ?
There must be a regular expression
for this, but I can't remember.
Uwe











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RE: cutting: aabbcc0000

2005-10-11 Thread Matthew Small
That's cool, I didn't know regex enough to know the 0+$ means trailing 0s. 
 
Matthew Small
Web Developer
American City Business Journals
704-973-1045
[EMAIL PROTECTED]
 

-Original Message-
From: Munson, Jacob [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, October 11, 2005 9:55 AM
To: CF-Talk
Subject: RE: cutting: aabbcc

Uew,

One of these removes all zeros from the string, the other removes all zeros
at the end of a string:

cfset myString = aa0bbb0ccc000
cfdump var=#myString#br
cfset removeTrailingZeros = ReReplace(myString,0+$,,all)
cfset removeAllZeros = Replace(myString,0,,all)
cfoutput#removeTrailingZeros#br#removeAllZeros#/cfoutput 

 -Original Message-
 From: Uwe Degenhardt [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, October 11, 2005 6:25 AM
 To: CF-Talk
 Subject: cutting: aabbcc
 
 Hi list I
 have a value in a db-field like
 aabbcc
 and I always want
 to cut the leading nulls
 on the right to get: aabbcc, but only the four nulls, how can I do 
 this ?
 There must be a regular expression
 for this, but I can't remember.
 Uwe








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in error, please immediately contact the sender and destroy the material in
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RE: cutting: aabbcc0000

2005-10-11 Thread Munson, Jacob
Yeah, the '+' means look for 1 or more, and the '$' means match at the
end of the string. 

 -Original Message-
 From: Matthew Small [mailto:[EMAIL PROTECTED] 
 Sent: Tuesday, October 11, 2005 10:53 AM
 To: CF-Talk
 Subject: RE: cutting: aabbcc
 
 That's cool, I didn't know regex enough to know the 0+$ means 
 trailing 0s. 
  
 Matthew Small
 Web Developer
 American City Business Journals
 704-973-1045
 [EMAIL PROTECTED]
  
 
 -Original Message-
 From: Munson, Jacob [mailto:[EMAIL PROTECTED] 
 Sent: Tuesday, October 11, 2005 9:55 AM
 To: CF-Talk
 Subject: RE: cutting: aabbcc
 
 Uew,
 
 One of these removes all zeros from the string, the other 
 removes all zeros
 at the end of a string:
 
 cfset myString = aa0bbb0ccc000
 cfdump var=#myString#br
 cfset removeTrailingZeros = ReReplace(myString,0+$,,all)
 cfset removeAllZeros = Replace(myString,0,,all)
 cfoutput#removeTrailingZeros#br#removeAllZeros#/cfoutput 





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