Re: Help with IP Addressing/VLSM- work project [7:29160]
Hi Sarah, Since all you need is just five usable subnets, the way I go about it is: 2 raise to the power of 3=8 subnets. (You cannot use 2 raise to the power of 2, cos that would give me 4 subnets but I need at least 5 subnets). It means you can not get exactly five subnets, you will have 3 extra subnets for future use. From above you borrowed 3-bits from the last octet of the given IP address for subnet purposes, then going by the last octet the eight bit have these weights (128, 64, 32, 16, 8, 4, 2, 1), since you are using the first three bits then it add up to be 128+64+32=224, now to get the number of IP addresses in each subnet, 256-224=32. It also means your IP addresses would be multiples of 32. The 8 subnets would now be: 1. 65.85.105.0 255.255.255.224 2. 65.85.105.32 255.255.255.224 3. 65.85.105.64 255.255.255.224 4. 65.85.105.96 255.255.255.224 5. 65.85.105.128 255.255.255.224 6. 65.85.105.160 255.255.255.224 7. 65.85.105.192 255.255.255.224 8. 65.85.105.224 255.255.255.224 It is now up to you which five to utilize first. For documentation purposes and ease of troubleshooting, it will be appropriate you use the first five and leave the rest for future development and expansion. Regards Oletu - Original Message - From: Sarah Parker To: Sent: Thursday, December 13, 2001 8:15 PM Subject: Help with IP Addressing/VLSM- work project [7:29160] > Hello Everyone, > > I am working on a small IP address project and trying > to figure out VLSM. > > Since I am not very good and do not have much > experience with IP addressing, I wanted to send this > to make sure what I have is correct or if I am really > wrong on this one. > Thanks in advance for any feedback or corrections!! > > This is a new network- > Current IP Address=65.85.105.0 > Mask=255.255.255.0 > > I need a total of 5 subnets. > > What I did > Took 65.85.105.0, 255.255.255.128 to subnet into 2 > networks, > This gave me > Subnet 1= 65.85.105.0, hosts 1-126, broadcast 127 > Subnet 2=65.85.105.128, hosts 129-254, broadcast 255 > > Took 65.85,105.128 255.255.255.192 to subnet into 4 > subnets > This gave me > Subnet 1=65.85.105.0. hosts 1-62, broadcast 63 > Subnet 2=65.85.105.64, hosts 54-126, broadcast 127 > Subnet 3=65.85.105.128, hosts 129-190, broadcast 190 > Subnet 4=65.85.105.192, hosts 193.254, broadcast 255 > > So this would give me to use on the network > 1=65.85.105.0 255.255.255.128 (17 mask?) > 2=65.85.105.0 255.255.255.192 (18 mask?) > 3=65.85.105.64 255.255.255.192 > 4=65.85.105.128 255.255.255.192 > 5=65.85.105.192 255.255.255.192 > > > Did I do this correctly? This is based on using subnet > zero. > > I am using a public class A but for security reasons I > did change the actual real address. > > Thanks again for everyones feedback. > > > __ > Do You Yahoo!? > Check out Yahoo! Shopping and Yahoo! Auctions for all of > your unique holiday gifts! Buy at http://shopping.yahoo.com > or bid at http://auctions.yahoo.com _ Do You Yahoo!? Get your free @yahoo.com address at http://mail.yahoo.com Message Posted at: http://www.groupstudy.com/form/read.php?f=7&i=29205&t=29160 -- FAQ, list archives, and subscription info: http://www.groupstudy.com/list/cisco.html Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
Re: Re: Help with IP Addressing/VLSM- work project [7:29160]
Ooops. I can't add. I realized after I sent my reply that the .156 subnet should be .160. Sorry about the confusion. ;-) John Get your own "800" number Voicemail, fax, email, and a lot more http://www.ureach.com/reg/tag On Thu, 13 Dec 2001, John Neiberger ([EMAIL PROTECTED]) wrote: > Hi Sarah, > > Your calculations were correct at the beginning but somewhere > toward the end the train went of the track. :-) > > If you need at least five equal-sized subnets, you're going to > end up with three unused subnets. > > You already figured out that by using two extra bits of > subnetting you'd get four subnets. Add one more bit and you'll > have eight usable subnets. > > In your last example, you have overlapping subnets: > > 1=65.85.105.0 255.255.255.128 > 2=65.85.105.0 255.255.255.192 > > You must not overlap subnets when doing VLSM. In the end you > should have the following subnets available: > > 65.85.105.0 > 65.85.105.32 > 65.85.105.64 > 65.85.105.96 > 65.85.105.128 > 65.85.105.156 > 65.85.105.192 > 85.85.102.224 > > These all have the same mask, a /27, or 255.255.255.224. > > I can't draw it out in text, but one way to think of subnetting > is to start out with a big circle. That's your /24. Draw a > line down the center and you have two /25s. Draw another line > across the middle and you now have four /26s. Take one of > those /26s and divide it in half and you now have three /26s > and two /27s. You could then further divide the /27 into > two /28s. > > This makes it very simple and helps you not to overlap prefixes > on accident. > > HTH, > John > > > Get your own "800" number > Voicemail, fax, email, and a lot more > http://www.ureach.com/reg/tag > > > On Thu, 13 Dec 2001, Sarah Parker ([EMAIL PROTECTED]) > wrote: > > > Hello Everyone, > > > > I am working on a small IP address project and trying > > to figure out VLSM. > > > > Since I am not very good and do not have much > > experience with IP addressing, I wanted to send this > > to make sure what I have is correct or if I am really > > wrong on this one. > > Thanks in advance for any feedback or corrections!! > > > > This is a new network- > > Current IP Address=65.85.105.0 > > Mask=255.255.255.0 > > > > I need a total of 5 subnets. > > > > What I did > > Took 65.85.105.0, 255.255.255.128 to subnet into 2 > > networks, > > This gave me > > Subnet 1= 65.85.105.0, hosts 1-126, broadcast 127 > > Subnet 2=65.85.105.128, hosts 129-254, broadcast 255 > > > > Took 65.85,105.128 255.255.255.192 to subnet into 4 > > subnets > > This gave me > > Subnet 1=65.85.105.0. hosts 1-62, broadcast 63 > > Subnet 2=65.85.105.64, hosts 54-126, broadcast 127 > > Subnet 3=65.85.105.128, hosts 129-190, broadcast 190 > > Subnet 4=65.85.105.192, hosts 193.254, broadcast 255 > > > > So this would give me to use on the network > > 1=65.85.105.0 255.255.255.128 (17 mask?) > > 2=65.85.105.0 255.255.255.192 (18 mask?) > > 3=65.85.105.64 255.255.255.192 > > 4=65.85.105.128 255.255.255.192 > > 5=65.85.105.192 255.255.255.192 > > > > > > Did I do this correctly? This is based on using subnet > > zero. > > > > I am using a public class A but for security reasons I > > did change the actual real address. > > > > Thanks again for everyones feedback. > > > > > > __ > > Do You Yahoo!? > > Check out Yahoo! Shopping and Yahoo! Auctions for all of > > your unique holiday gifts! Buy at http://shopping.yahoo.com > > or bid at http://auctions.yahoo.com > [EMAIL PROTECTED] [EMAIL PROTECTED] Message Posted at: http://www.groupstudy.com/form/read.php?f=7&i=29169&t=29160 -- FAQ, list archives, and subscription info: http://www.groupstudy.com/list/cisco.html Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
RE: Help with IP Addressing/VLSM- work project [7:29160]
I'm sure the folks at Sonic Rim and Kathy's Cottage ( to name a couple ) appreciate your using their space to illustrate your question ;-> I'll ignore the couple of typos in there. it's late. you have an overlap in your first three subnets. 105.0/25 ( not /17 ) overlaps with 105.0/26 ( not 18 ) and 105.64/26 How many hosts do you need on each subnet? It is sometimes better to work backwards from there. Chuck -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of Sarah Parker Sent: Thursday, December 13, 2001 8:15 PM To: [EMAIL PROTECTED] Subject: Help with IP Addressing/VLSM- work project [7:29160] Hello Everyone, I am working on a small IP address project and trying to figure out VLSM. Since I am not very good and do not have much experience with IP addressing, I wanted to send this to make sure what I have is correct or if I am really wrong on this one. Thanks in advance for any feedback or corrections!! This is a new network- Current IP Address=65.85.105.0 Mask=255.255.255.0 I need a total of 5 subnets. What I did Took 65.85.105.0, 255.255.255.128 to subnet into 2 networks, This gave me Subnet 1= 65.85.105.0, hosts 1-126, broadcast 127 Subnet 2=65.85.105.128, hosts 129-254, broadcast 255 Took 65.85,105.128 255.255.255.192 to subnet into 4 subnets This gave me Subnet 1=65.85.105.0. hosts 1-62, broadcast 63 Subnet 2=65.85.105.64, hosts 54-126, broadcast 127 Subnet 3=65.85.105.128, hosts 129-190, broadcast 190 Subnet 4=65.85.105.192, hosts 193.254, broadcast 255 So this would give me to use on the network 1=65.85.105.0 255.255.255.128 (17 mask?) 2=65.85.105.0 255.255.255.192 (18 mask?) 3=65.85.105.64 255.255.255.192 4=65.85.105.128 255.255.255.192 5=65.85.105.192 255.255.255.192 Did I do this correctly? This is based on using subnet zero. I am using a public class A but for security reasons I did change the actual real address. Thanks again for everyones feedback. __ Do You Yahoo!? Check out Yahoo! Shopping and Yahoo! Auctions for all of your unique holiday gifts! Buy at http://shopping.yahoo.com or bid at http://auctions.yahoo.com Message Posted at: http://www.groupstudy.com/form/read.php?f=7&i=29167&t=29160 -- FAQ, list archives, and subscription info: http://www.groupstudy.com/list/cisco.html Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
RE: Help with IP Addressing/VLSM- work project [7:29160]
Ok, looks like there are some issues. Listed are your results, and comments for each: 1=65.85.105.0 255.255.255.128 (17 mask?) This is a /25, it will allow you to use from 1-126, 127 is broadcast. 2=65.85.105.0 255.255.255.192 (18 mask?) This was already used in the original /25, you cannot use it twice, you now must start at 128, because that is where the first /25 ends. 3=65.85.105.64 255.255.255.192 This was also used in the original /25. 4=65.85.105.128 255.255.255.192 This one is ok, /26, gives you from 129-190 to use, 191 is broadcast. 5=65.85.105.192 255.255.255.192 This one is ok, /26, gives you from 193-254 to use, 255 is broadcast. So, in the end you would have the following: 65.85.105.0/25 65.85.105.128/26 65.85.105.192/26 How many subnets do you want? Do they each have to have a certain number of hosts? -Original Message- From: Sarah Parker To: [EMAIL PROTECTED] Sent: 12/13/2001 11:15 PM Subject: Help with IP Addressing/VLSM- work project [7:29160] Hello Everyone, I am working on a small IP address project and trying to figure out VLSM. Since I am not very good and do not have much experience with IP addressing, I wanted to send this to make sure what I have is correct or if I am really wrong on this one. Thanks in advance for any feedback or corrections!! This is a new network- Current IP Address=65.85.105.0 Mask=255.255.255.0 I need a total of 5 subnets. What I did Took 65.85.105.0, 255.255.255.128 to subnet into 2 networks, This gave me Subnet 1= 65.85.105.0, hosts 1-126, broadcast 127 Subnet 2=65.85.105.128, hosts 129-254, broadcast 255 Took 65.85,105.128 255.255.255.192 to subnet into 4 subnets This gave me Subnet 1=65.85.105.0. hosts 1-62, broadcast 63 Subnet 2=65.85.105.64, hosts 54-126, broadcast 127 Subnet 3=65.85.105.128, hosts 129-190, broadcast 190 Subnet 4=65.85.105.192, hosts 193.254, broadcast 255 So this would give me to use on the network 1=65.85.105.0 255.255.255.128 (17 mask?) 2=65.85.105.0 255.255.255.192 (18 mask?) 3=65.85.105.64 255.255.255.192 4=65.85.105.128 255.255.255.192 5=65.85.105.192 255.255.255.192 Did I do this correctly? This is based on using subnet zero. I am using a public class A but for security reasons I did change the actual real address. Thanks again for everyones feedback. __ Do You Yahoo!? Check out Yahoo! Shopping and Yahoo! Auctions for all of your unique holiday gifts! Buy at http://shopping.yahoo.com or bid at http://auctions.yahoo.com Message Posted at: http://www.groupstudy.com/form/read.php?f=7&i=29166&t=29160 -- FAQ, list archives, and subscription info: http://www.groupstudy.com/list/cisco.html Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
Re: Help with IP Addressing/VLSM- work project [7:29160]
Hi Sarah, Your calculations were correct at the beginning but somewhere toward the end the train went of the track. :-) If you need at least five equal-sized subnets, you're going to end up with three unused subnets. You already figured out that by using two extra bits of subnetting you'd get four subnets. Add one more bit and you'll have eight usable subnets. In your last example, you have overlapping subnets: 1=65.85.105.0 255.255.255.128 2=65.85.105.0 255.255.255.192 You must not overlap subnets when doing VLSM. In the end you should have the following subnets available: 65.85.105.0 65.85.105.32 65.85.105.64 65.85.105.96 65.85.105.128 65.85.105.156 65.85.105.192 85.85.102.224 These all have the same mask, a /27, or 255.255.255.224. I can't draw it out in text, but one way to think of subnetting is to start out with a big circle. That's your /24. Draw a line down the center and you have two /25s. Draw another line across the middle and you now have four /26s. Take one of those /26s and divide it in half and you now have three /26s and two /27s. You could then further divide the /27 into two /28s. This makes it very simple and helps you not to overlap prefixes on accident. HTH, John Get your own "800" number Voicemail, fax, email, and a lot more http://www.ureach.com/reg/tag On Thu, 13 Dec 2001, Sarah Parker ([EMAIL PROTECTED]) wrote: > Hello Everyone, > > I am working on a small IP address project and trying > to figure out VLSM. > > Since I am not very good and do not have much > experience with IP addressing, I wanted to send this > to make sure what I have is correct or if I am really > wrong on this one. > Thanks in advance for any feedback or corrections!! > > This is a new network- > Current IP Address=65.85.105.0 > Mask=255.255.255.0 > > I need a total of 5 subnets. > > What I did > Took 65.85.105.0, 255.255.255.128 to subnet into 2 > networks, > This gave me > Subnet 1= 65.85.105.0, hosts 1-126, broadcast 127 > Subnet 2=65.85.105.128, hosts 129-254, broadcast 255 > > Took 65.85,105.128 255.255.255.192 to subnet into 4 > subnets > This gave me > Subnet 1=65.85.105.0. hosts 1-62, broadcast 63 > Subnet 2=65.85.105.64, hosts 54-126, broadcast 127 > Subnet 3=65.85.105.128, hosts 129-190, broadcast 190 > Subnet 4=65.85.105.192, hosts 193.254, broadcast 255 > > So this would give me to use on the network > 1=65.85.105.0 255.255.255.128 (17 mask?) > 2=65.85.105.0 255.255.255.192 (18 mask?) > 3=65.85.105.64 255.255.255.192 > 4=65.85.105.128 255.255.255.192 > 5=65.85.105.192 255.255.255.192 > > > Did I do this correctly? This is based on using subnet > zero. > > I am using a public class A but for security reasons I > did change the actual real address. > > Thanks again for everyones feedback. > > > __ > Do You Yahoo!? > Check out Yahoo! Shopping and Yahoo! Auctions for all of > your unique holiday gifts! Buy at http://shopping.yahoo.com > or bid at http://auctions.yahoo.com [EMAIL PROTECTED] Message Posted at: http://www.groupstudy.com/form/read.php?f=7&i=29164&t=29160 -- FAQ, list archives, and subscription info: http://www.groupstudy.com/list/cisco.html Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
Re: Help with IP Addressing/VLSM- work project [7:29160]
You almost got it, but it does not seem correct. When you break the 65.85.105.128 255.255.255.192 into 4 subnets, you cut from the 65.85.105.128, not the 65.85.105.0. Also, you cannot cut 4 subnets out of a 65.85.105.128 with a 255.255.255.192 mask. You would only get 2 more. Since you have a 65.85.105.128, you only have 128 hosts left. A 255.255.25.192 mask will give you 64 host subnets. 128/64 is 2. A VLSM lets you subnet a subnet while routing is still sane. Anyway, you have to further slice it using a 255.255.255.224. 65.85.105.128 with 32 host subnets will give you the final 4 since 128 hosts divided by 32 is 4 subnets. I put the masks in both bitcount and dotted decimal notation. Subnet 1 = 65.85.105.0/25 (255.255.255.128) Subnet 2 = 65.85.105.128/27 (255.255.255.224) Subnet 3 = 65.85.105.160/27 (255.255.255.224) Subnet 4 = 65.85.105.192/27 (255.255.255.224) Subnet 5 = 65.85.105.224/27 (255.255.255.224) At 11:15 PM 12/13/01 -0500, Sarah Parker wrote: >Hello Everyone, > >I am working on a small IP address project and trying >to figure out VLSM. > >Since I am not very good and do not have much >experience with IP addressing, I wanted to send this >to make sure what I have is correct or if I am really >wrong on this one. >Thanks in advance for any feedback or corrections!! > >This is a new network- >Current IP Address=65.85.105.0 >Mask=255.255.255.0 > >I need a total of 5 subnets. > >What I did >Took 65.85.105.0, 255.255.255.128 to subnet into 2 >networks, >This gave me >Subnet 1= 65.85.105.0, hosts 1-126, broadcast 127 >Subnet 2=65.85.105.128, hosts 129-254, broadcast 255 > >Took 65.85,105.128 255.255.255.192 to subnet into 4 >subnets >This gave me >Subnet 1=65.85.105.0. hosts 1-62, broadcast 63 >Subnet 2=65.85.105.64, hosts 54-126, broadcast 127 >Subnet 3=65.85.105.128, hosts 129-190, broadcast 190 >Subnet 4=65.85.105.192, hosts 193.254, broadcast 255 > >So this would give me to use on the network >1=65.85.105.0 255.255.255.128 (17 mask?) >2=65.85.105.0 255.255.255.192 (18 mask?) >3=65.85.105.64 255.255.255.192 >4=65.85.105.128 255.255.255.192 >5=65.85.105.192 255.255.255.192 > > >Did I do this correctly? This is based on using subnet >zero. > >I am using a public class A but for security reasons I >did change the actual real address. > >Thanks again for everyones feedback. > > >__ >Do You Yahoo!? >Check out Yahoo! Shopping and Yahoo! Auctions for all of >your unique holiday gifts! Buy at http://shopping.yahoo.com >or bid at http://auctions.yahoo.com -Carroll Kong Message Posted at: http://www.groupstudy.com/form/read.php?f=7&i=29162&t=29160 -- FAQ, list archives, and subscription info: http://www.groupstudy.com/list/cisco.html Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
Help with IP Addressing/VLSM- work project [7:29160]
Hello Everyone, I am working on a small IP address project and trying to figure out VLSM. Since I am not very good and do not have much experience with IP addressing, I wanted to send this to make sure what I have is correct or if I am really wrong on this one. Thanks in advance for any feedback or corrections!! This is a new network- Current IP Address=65.85.105.0 Mask=255.255.255.0 I need a total of 5 subnets. What I did Took 65.85.105.0, 255.255.255.128 to subnet into 2 networks, This gave me Subnet 1= 65.85.105.0, hosts 1-126, broadcast 127 Subnet 2=65.85.105.128, hosts 129-254, broadcast 255 Took 65.85,105.128 255.255.255.192 to subnet into 4 subnets This gave me Subnet 1=65.85.105.0. hosts 1-62, broadcast 63 Subnet 2=65.85.105.64, hosts 54-126, broadcast 127 Subnet 3=65.85.105.128, hosts 129-190, broadcast 190 Subnet 4=65.85.105.192, hosts 193.254, broadcast 255 So this would give me to use on the network 1=65.85.105.0 255.255.255.128 (17 mask?) 2=65.85.105.0 255.255.255.192 (18 mask?) 3=65.85.105.64 255.255.255.192 4=65.85.105.128 255.255.255.192 5=65.85.105.192 255.255.255.192 Did I do this correctly? This is based on using subnet zero. I am using a public class A but for security reasons I did change the actual real address. Thanks again for everyones feedback. __ Do You Yahoo!? Check out Yahoo! Shopping and Yahoo! Auctions for all of your unique holiday gifts! Buy at http://shopping.yahoo.com or bid at http://auctions.yahoo.com Message Posted at: http://www.groupstudy.com/form/read.php?f=7&i=29160&t=29160 -- FAQ, list archives, and subscription info: http://www.groupstudy.com/list/cisco.html Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
