Re: OSPFadjacencies

2001-01-13 Thread Curtis Call

I'm not positive at what you're looking for, but if you are talking about 
the number of adjacencies that would be required to be fully meshed on a 
broadcast or NBMA network then the formula you're looking for is (N * (N-1) 
) / 2.  Of course this doesn't happen in OSPF since it uses DRs and BDRs in 
order to avoid having to have so many full adjacencies, so in OSPF each 
router (excluding the DR and BDR) has only two full adjacencies, one with 
the DR and one with the BDR and it is in a 2-way state with the rest of 
it's neighbors.

Did that answer your question?

At 01:38 PM 1/12/01 -0600, you wrote:
Hello,

I am drawing a blank and am trying to remember the formula to figure the
number of adjacencies a router would have.

I know it's a simple question, I am just drawing a blank.

Thank You,

-Eric

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Re: OSPFadjacencies

2001-01-12 Thread Phil Barker

It will depend on the number of interfaces that are
configured on the routers for OSPF operation.

The main point to remember is that not all Routers
will become adjacent. For a broadcast network such as
Ethernet you may have N Routers. 2 of these Routers
will be elected DR and BDR and will form an adjacency.
So we have N-2 Routers left. These N-2 Routers will
also try to form adjacencies with the DR and BDR, but
these N-2 Routers will not form adjacencies with DR
OTHER Routers. This saves on Network resources and
computational Resources.

HTH,

Phil.
--- Eric Gunn [EMAIL PROTECTED] wrote:  Hello,
 
 I am drawing a blank and am trying to remember the
 formula to figure the 
 number of adjacencies a router would have.
 
 I know it's a simple question, I am just drawing a
 blank.
 
 Thank You,
 
 -Eric
 
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 http://www.groupstudy.com/list/cisco.html
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