Re: Use repeat with a function argument
`repeat` takes a value and returns a sequence of that value. There's another function, `repeatedly`, which takes a function and returns a sequence of values returned by calling that function. -S -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: Use repeat with a function argument
I deleted my answer minutes after posting. The phrase "function argument" is ambiguous ("argument to function", "argument which is a function") and I jumped to the wrong conclusion. On Monday, December 24, 2012 7:00:48 PM UTC+1, Sean Corfield wrote: > > He's repeating a function argument, not a function. > > Meikel is correct that the second expression causes (some #{0} ...) to > return nil when number is not a multiple of 3 or 5, and then zero? fails. > As he suggests... > > (reduce + (filter (fn [number] (some zero? (map mod (take 2 (repeat > number)) [3 5]))) (range 1 1000))) > > ...works (and returns 233168) > > Sean > > On Sun, Dec 23, 2012 at 11:56 PM, Marko Topolnik > > > wrote: > >> *repeat* is not supposed to work with functions, but there's *repeatedly. >> * >> >> >> On Monday, December 24, 2012 4:20:23 AM UTC+1, Andrew Care wrote: >>> >>> I'm trying to use repeat with a function argument. This works: >>> >>> (reduce + (filter (fn [number] (zero? (some #{0} (map mod (take 2 >>> (repeat 9)) [3 5] (range 1 1000))) >>> >>> This doesn't: >>> >>> (reduce + (filter (fn [number] (zero? (some #{0} (map mod (take 2 >>> (repeat number)) [3 5] (range 1 1000))) >>> >>> Why can I use (repeat 9) and not (repeat number)? >>> >> >> -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: Use repeat with a function argument
He's repeating a function argument, not a function. Meikel is correct that the second expression causes (some #{0} ...) to return nil when number is not a multiple of 3 or 5, and then zero? fails. As he suggests... (reduce + (filter (fn [number] (some zero? (map mod (take 2 (repeat number)) [3 5]))) (range 1 1000))) ...works (and returns 233168) Sean On Sun, Dec 23, 2012 at 11:56 PM, Marko Topolnik wrote: > *repeat* is not supposed to work with functions, but there's *repeatedly.* > > > On Monday, December 24, 2012 4:20:23 AM UTC+1, Andrew Care wrote: >> >> I'm trying to use repeat with a function argument. This works: >> >> (reduce + (filter (fn [number] (zero? (some #{0} (map mod (take 2 (repeat >> 9)) [3 5] (range 1 1000))) >> >> This doesn't: >> >> (reduce + (filter (fn [number] (zero? (some #{0} (map mod (take 2 (repeat >> number)) [3 5] (range 1 1000))) >> >> Why can I use (repeat 9) and not (repeat number)? >> > > -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: Use repeat with a function argument
of course repeat works with functions: user=> (take 4 (map #(% 4) (repeat inc))) (5 5 5 5) On Sun, Dec 23, 2012 at 11:56 PM, Marko Topolnik wrote: > repeat is not supposed to work with functions, but there's repeatedly. > > > On Monday, December 24, 2012 4:20:23 AM UTC+1, Andrew Care wrote: >> >> I'm trying to use repeat with a function argument. This works: >> >> (reduce + (filter (fn [number] (zero? (some #{0} (map mod (take 2 (repeat >> 9)) [3 5] (range 1 1000))) >> >> This doesn't: >> >> (reduce + (filter (fn [number] (zero? (some #{0} (map mod (take 2 (repeat >> number)) [3 5] (range 1 1000))) >> >> Why can I use (repeat 9) and not (repeat number)? > > -- > You received this message because you are subscribed to the Google > Groups "Clojure" group. > To post to this group, send email to clojure@googlegroups.com > Note that posts from new members are moderated - please be patient with your > first post. > To unsubscribe from this group, send email to > clojure+unsubscr...@googlegroups.com > For more options, visit this group at > http://groups.google.com/group/clojure?hl=en -- Ben Wolfson "Human kind has used its intelligence to vary the flavour of drinks, which may be sweet, aromatic, fermented or spirit-based. ... Family and social life also offer numerous other occasions to consume drinks for pleasure." [Larousse, "Drink" entry] -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: Use repeat with a function argument
*repeat* is not supposed to work with functions, but there's *repeatedly.* On Monday, December 24, 2012 4:20:23 AM UTC+1, Andrew Care wrote: > > I'm trying to use repeat with a function argument. This works: > > (reduce + (filter (fn [number] (zero? (some #{0} (map mod (take 2 (repeat > 9)) [3 5] (range 1 1000))) > > This doesn't: > > (reduce + (filter (fn [number] (zero? (some #{0} (map mod (take 2 (repeat > number)) [3 5] (range 1 1000))) > > Why can I use (repeat 9) and not (repeat number)? > -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: Use repeat with a function argument
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Hi, Am 24.12.12 04:20, schrieb Andrew Care: > Why can I use (repeat 9) and not (repeat number)? Because you call zero? on nil, which doesn't work. Instead of (zero? (some #{0} ...)) use (some zero? ...). Kind regards Meikel -BEGIN PGP SIGNATURE- Version: GnuPG/MacGPG2 v2.0.18 (Darwin) Comment: GPGTools - http://gpgtools.org Comment: Using GnuPG with undefined - http://www.enigmail.net/ iQIcBAEBAgAGBQJQ2Ao1AAoJEM2sO9pIirXjqVEP/34UYmSbw3P0M22KmCCXR+pZ XKoFOJ3pFbTseBekFPrAIoHwIPARuUxoQTCheBuszU2o8j2bXku2sRr614KR8XE0 2CzNGVswd7dN7X4IeuXoe5O9aknYpSFNmCI38eBDc07PUR8i6m4e0/Y/95/pckTO 1W6jnSf6pOYbUjDKp7U//dfMrfvAZKvOJ5eo40I+mq3qKB4OV4FjWv5m4D/L+rZt fu/5RId+VWukbnxNTWUBInTZ/Z4rlbgPDLZ3EcqJNHQzetRjZlRH+/X6zlmFnF/7 Vffduzf374KdzVPOIWabEzGLE/yi/MFAyo/WCzk4n4qLoFS0Dnhi9lG6QExcwd1S VhOY4ZAc3MbDdBea6tiBUJeLCTG4A9k/48/RGlrtM9UjqkkHiXzQk2d7pK7jfYkh cmLPA4oKDkmccZAqd99J9A0/LS1wpnGXh95POlKrgs3n9PcSEAlyU+OA5UU/KiKD wciXvMwfjllw0SmoFHNvNJZL4rjmAce2vWf88RyitquxF468KUiZtjDy+tLauFH+ QS8mw+P1vAzZ1O3ul3W/YJt3ypi4h7paHllDrhRS4TiPYF7zUSfmj1f5gSCTf8d+ 5EJ9bsMIJINRZ8ByhJzNojVjWBq/t8WdpMbAavObfAZ2hoT8zqFBk2uewPKpM2ve mRVtJejqeU2+Y2y8IPEc =Mqq2 -END PGP SIGNATURE- -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en