Re: Remove-first function

2010-07-26 Thread Mark Engelberg
I expanded on this theme in a blog post:
http://programming-puzzler.blogspot.com/2010/07/translating-code-from-python-and-scheme.html

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Re: Remove-first function

2010-07-25 Thread Mark Engelberg
On Sat, Jul 24, 2010 at 9:07 AM, Gary Fredericks
 wrote:
> (defn remove-first
>   [syb lst]
>   (let [[before after]
>   (loop [b [] a lst]
>     (if (empty? lst)
>   [b a]
>   (if (= syb (first a))
>     [b (rest a)]
>     (recur (cons (first a) b) (rest a)]
>    (concat (reverse before) after)))
>
> user=> (remove-first 4 '(1 5 3 4 2 6 674 4 2))
> (1 5 3 2 6 674 4 2)
>
> I'm interested if somebody comes up with something more efficient, i.e. that
> doesn't require the reversal.

If you change (cons (first a) b) to (conj b (first a), then no
reversal will be required.

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Re: Remove-first function

2010-07-25 Thread Gary Fredericks
Well obviously if you can get something to be tail-recursive you won't have
the stack overflows, and the thing in your code that prevents tail recursion
is having to cons the result of the recursive call. So let's try this:

(defn remove-first
  [syb lst]
  (let [[before after]
  (loop [b [] a lst]
(if (empty? lst)
  [b a]
  (if (= syb (first a))
[b (rest a)]
(recur (cons (first a) b) (rest a)]
   (concat (reverse before) after)))

user=> (remove-first 4 '(1 5 3 4 2 6 674 4 2))
(1 5 3 2 6 674 4 2)

I'm interested if somebody comes up with something more efficient, i.e. that
doesn't require the reversal.

Gary

On Sat, Jul 24, 2010 at 11:41 AM, nickikt  wrote:

> Hallo all,
>
> I'm working trough Essentials of Programming Languages. I'm trying to
> right a function like this one:
>
> (defn scheme-remove-first [syb lst]
>  (if (empty? lst)
>'()
>(if (= (first lst) syb)
>  (rest lst)
>  (cons (first lst) (scheme-remove-first syb (rest lst))
>
> in a idiomatic clojure way (this is just a scheme to clojure 1:1
> version). I don't like that this function produces stack overflows.
>
> I tried some stuff but I it (almost) semantically correct working but
> I didn't like my code. Can anyone come up with a good version?
>
> --
> You received this message because you are subscribed to the Google
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-- 
Gary Fredericks
(660)-623-1095
fredericksg...@gmail.com
www.gfredericks.com

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Re: Remove-first function

2010-07-25 Thread nickikt
@Randy Hudson
Really like that solution.

@Mark Engelberg
Thanks for the explanation


On Jul 25, 4:33 am, ataggart  wrote:
> To add one small addendum to Mark's excellent comment, if you use lazy-
> seq then you don't need to worry about the nil from when
>
> On Jul 24, 12:01 pm, Mark Engelberg  wrote:
>
>
>
> > On Sat, Jul 24, 2010 at 11:45 AM, Mark Engelberg
>
> >  wrote:
> > > The simplest translation is to wrap a lazy-seq around the last line to
> > > avoid the stack overflows.
>
> > Just to clarify, there are at least three reasonable places to place
> > the call to lazy-seq.  You can put lazy-seq around the full body of
> > the function.  You can place it around the cons.  You can place it
> > around the recursive call to scheme-remove-first.  Each choice results
> > in slightly different laziness behavior, i.e., when various elements
> > are computed, but the overall semantics of the sequence remains the
> > same and stack overflows will be avoided.  Placing the lazy-seq around
> > the recursive function call will cause scheme-remove-first to compute
> > the first element right away, and delay the rest.  Placing the
> > lazy-seq around the full body will prevent any computation until it is
> > asked for by a consumer.  Placing the lazy-seq around the cons results
> > in in immediate behavior for the nil and
> > removable-item-at-front-of-list case, and delayed behavior otherwise.
> > All are acceptable choices, but preferences vary.  Probably placing
> > lazy-seq around the full body is the most common style you'll see in
> > Clojure, although I tend to place it where the laziness is actually
> > required (like around the recursive call, or around the cons).
>
> > You've probably noticed from the other samples posted that many
> > Clojurians prefer to use (seq lst) instead of (not (empty? lst)), and
> > organize their code around the not-empty case.
>
> > So (if (empty? lst) empty-case not-empty-case) becomes (if (seq lst)
> > not-empty-case empty-case)
>
> > When the empty case also results in nil, you can replace the if
> > structure with a one-armed when, because when automatically returns
> > nil in the other case.
>
> > So (if (seq lst) not-empty-case nil) becomes (when (seq lst) 
> > not-empty-case).

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Re: Remove-first function

2010-07-24 Thread ataggart
To add one small addendum to Mark's excellent comment, if you use lazy-
seq then you don't need to worry about the nil from when

On Jul 24, 12:01 pm, Mark Engelberg  wrote:
> On Sat, Jul 24, 2010 at 11:45 AM, Mark Engelberg
>
>  wrote:
> > The simplest translation is to wrap a lazy-seq around the last line to
> > avoid the stack overflows.
>
> Just to clarify, there are at least three reasonable places to place
> the call to lazy-seq.  You can put lazy-seq around the full body of
> the function.  You can place it around the cons.  You can place it
> around the recursive call to scheme-remove-first.  Each choice results
> in slightly different laziness behavior, i.e., when various elements
> are computed, but the overall semantics of the sequence remains the
> same and stack overflows will be avoided.  Placing the lazy-seq around
> the recursive function call will cause scheme-remove-first to compute
> the first element right away, and delay the rest.  Placing the
> lazy-seq around the full body will prevent any computation until it is
> asked for by a consumer.  Placing the lazy-seq around the cons results
> in in immediate behavior for the nil and
> removable-item-at-front-of-list case, and delayed behavior otherwise.
> All are acceptable choices, but preferences vary.  Probably placing
> lazy-seq around the full body is the most common style you'll see in
> Clojure, although I tend to place it where the laziness is actually
> required (like around the recursive call, or around the cons).
>
> You've probably noticed from the other samples posted that many
> Clojurians prefer to use (seq lst) instead of (not (empty? lst)), and
> organize their code around the not-empty case.
>
> So (if (empty? lst) empty-case not-empty-case) becomes (if (seq lst)
> not-empty-case empty-case)
>
> When the empty case also results in nil, you can replace the if
> structure with a one-armed when, because when automatically returns
> nil in the other case.
>
> So (if (seq lst) not-empty-case nil) becomes (when (seq lst) not-empty-case).

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Re: Remove-first function

2010-07-24 Thread Mark Engelberg
On Sat, Jul 24, 2010 at 11:45 AM, Mark Engelberg
 wrote:
> The simplest translation is to wrap a lazy-seq around the last line to
> avoid the stack overflows.

Just to clarify, there are at least three reasonable places to place
the call to lazy-seq.  You can put lazy-seq around the full body of
the function.  You can place it around the cons.  You can place it
around the recursive call to scheme-remove-first.  Each choice results
in slightly different laziness behavior, i.e., when various elements
are computed, but the overall semantics of the sequence remains the
same and stack overflows will be avoided.  Placing the lazy-seq around
the recursive function call will cause scheme-remove-first to compute
the first element right away, and delay the rest.  Placing the
lazy-seq around the full body will prevent any computation until it is
asked for by a consumer.  Placing the lazy-seq around the cons results
in in immediate behavior for the nil and
removable-item-at-front-of-list case, and delayed behavior otherwise.
All are acceptable choices, but preferences vary.  Probably placing
lazy-seq around the full body is the most common style you'll see in
Clojure, although I tend to place it where the laziness is actually
required (like around the recursive call, or around the cons).

You've probably noticed from the other samples posted that many
Clojurians prefer to use (seq lst) instead of (not (empty? lst)), and
organize their code around the not-empty case.

So (if (empty? lst) empty-case not-empty-case) becomes (if (seq lst)
not-empty-case empty-case)

When the empty case also results in nil, you can replace the if
structure with a one-armed when, because when automatically returns
nil in the other case.

So (if (seq lst) not-empty-case nil) becomes (when (seq lst) not-empty-case).

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Re: Remove-first function

2010-07-24 Thread Mark Engelberg
The simplest translation is to wrap a lazy-seq around the last line to
avoid the stack overflows.

On Sat, Jul 24, 2010 at 8:41 AM, nickikt  wrote:
> (defn scheme-remove-first [syb lst]
>  (if (empty? lst)
>    '()
>    (if (= (first lst) syb)
>      (rest lst)
>      (cons (first lst) (scheme-remove-first syb (rest lst))

becomes

(defn scheme-remove-first [syb lst]
 (if (empty? lst)
   '()
   (if (= (first lst) syb)
 (rest lst)
 (lazy-seq (cons (first lst) (scheme-remove-first syb (rest lst)))


Also, you can omit the ' in front of the () if you like.

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Re: Remove-first function

2010-07-24 Thread Andrew Boekhoff
Hi, 

One way to prevent the stack overflows is to wrap it in a lazy seq.
For example:

(defn remove-first [x coll]
   (lazy-seq
 (when (seq coll)
   (let [[y & ys] coll]
 (if (= target y) 
 ys  
 (cons y (remove-first x ys)))

On Saturday 24 July 2010 11:41:58 nickikt wrote:
> Hallo all,
> 
> I'm working trough Essentials of Programming Languages. I'm trying to
> right a function like this one:
> 
> (defn scheme-remove-first [syb lst]
>   (if (empty? lst)
> '()
> (if (= (first lst) syb)
>   (rest lst)
>   (cons (first lst) (scheme-remove-first syb (rest lst))
> 
> in a idiomatic clojure way (this is just a scheme to clojure 1:1
> version). I don't like that this function produces stack overflows.
> 
> I tried some stuff but I it (almost) semantically correct working but
> I didn't like my code. Can anyone come up with a good version?

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Re: Remove-first function

2010-07-24 Thread Randy Hudson
Here's my take:

(defn remove-first [x coll]
  (let [[pre post] (split-with #(not= x %) coll)]
(concat (pre (rest post

On Jul 24, 11:41 am, nickikt  wrote:
> Hallo all,
>
> I'm working trough Essentials of Programming Languages. I'm trying to
> right a function like this one:
>
> (defn scheme-remove-first [syb lst]
>   (if (empty? lst)
>     '()
>     (if (= (first lst) syb)
>       (rest lst)
>       (cons (first lst) (scheme-remove-first syb (rest lst))
>
> in a idiomatic clojure way (this is just a scheme to clojure 1:1
> version). I don't like that this function produces stack overflows.
>
> I tried some stuff but I it (almost) semantically correct working but
> I didn't like my code. Can anyone come up with a good version?

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Remove-first function

2010-07-24 Thread nickikt
Hallo all,

I'm working trough Essentials of Programming Languages. I'm trying to
right a function like this one:

(defn scheme-remove-first [syb lst]
  (if (empty? lst)
'()
(if (= (first lst) syb)
  (rest lst)
  (cons (first lst) (scheme-remove-first syb (rest lst))

in a idiomatic clojure way (this is just a scheme to clojure 1:1
version). I don't like that this function produces stack overflows.

I tried some stuff but I it (almost) semantically correct working but
I didn't like my code. Can anyone come up with a good version?

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