Re: is it function print has bug?

2015-12-28 Thread Mian Pao
Thanks for answer my question.

On Saturday, December 26, 2015 at 10:59:51 PM UTC+8, Leif wrote:
>
> Hi, Mian Pao.
>
> When you call the macro te, a is bound to the *symbol* 'print, not the 
> *function* print.  So, what the ~(a b c) form is doing is calling the 
> symbol 'print as a function:
> ('print 1 '(2 3)) => '(2 3)
>
> This is because symbols and keywords implement the function interface, and 
> the call above is equivalent to 
> (get 1 'print '(2 3)) => '(2 3) ; Tries to look up 'print in the data 
> structure 1, fails, uses default value '(2 3).
>
> Hope that helps,
> Leif
>
> On Thursday, December 24, 2015 at 8:38:44 AM UTC-5, Mian Pao wrote:
>>
>> I just write a macro
>>
>> ```
>> (defmacro te
>>   [a b & c]
>>   `(print
>>  ~(a b c)))
>> ```
>>
>> and i run
>>
>> ```
>> (macroexpand '(te print 2 3 4))
>> ;=> (clojure.core/print (3 4))
>> ```
>>
>> it get `(clojure.core/print (3 4))` not `(clojure.core/print nil)`
>>
>> iti is mean `(print 2 '(3 4))` return (3 4)?
>>
>

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Re: is it function print has bug?

2015-12-26 Thread Leif
Hi, Mian Pao.

When you call the macro te, a is bound to the *symbol* 'print, not the 
*function* print.  So, what the ~(a b c) form is doing is calling the 
symbol 'print as a function:
('print 1 '(2 3)) => '(2 3)

This is because symbols and keywords implement the function interface, and 
the call above is equivalent to 
(get 1 'print '(2 3)) => '(2 3) ; Tries to look up 'print in the data 
structure 1, fails, uses default value '(2 3).

Hope that helps,
Leif

On Thursday, December 24, 2015 at 8:38:44 AM UTC-5, Mian Pao wrote:
>
> I just write a macro
>
> ```
> (defmacro te
>   [a b & c]
>   `(print
>  ~(a b c)))
> ```
>
> and i run
>
> ```
> (macroexpand '(te print 2 3 4))
> ;=> (clojure.core/print (3 4))
> ```
>
> it get `(clojure.core/print (3 4))` not `(clojure.core/print nil)`
>
> iti is mean `(print 2 '(3 4))` return (3 4)?
>

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Re: is it function print has bug?

2015-12-26 Thread Leif
Hi, Mian Pao.

When you call the macro te, a is bound to the *symbol* 'print, not the 
*function* print.  So, what the ~(a b c) form is doing is calling the 
symbol 'print as a function:
('print 1 '(2 3)) => '(2 3)

This is because symbols and keywords implement the function interface, and 
the call above is equivalent to 
(get 1 'print '(2 3)) => '(2 3) ; Tries to look up 'print in the data 
structure 1, fails, uses default value '(2 3).

Hope that helps,
Leif

On Thursday, December 24, 2015 at 8:38:44 AM UTC-5, Mian Pao wrote:
>
> I just write a macro
>
> ```
> (defmacro te
>   [a b & c]
>   `(print
>  ~(a b c)))
> ```
>
> and i run
>
> ```
> (macroexpand '(te print 2 3 4))
> ;=> (clojure.core/print (3 4))
> ```
>
> it get `(clojure.core/print (3 4))` not `(clojure.core/print nil)`
>
> iti is mean `(print 2 '(3 4))` return (3 4)?
>

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is it function print has bug?

2015-12-24 Thread Mian Pao
I just write a macro

```
(defmacro te
  [a b & c]
  `(print
 ~(a b c)))
```

and i run

```
(macroexpand '(te print 2 3 4))
;=> (clojure.core/print (3 4))
```

it get `(clojure.core/print (3 4))` not `(clojure.core/print nil)`

iti is mean `(print 2 '(3 4))` return (3 4)?

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